How can I read a text file, search for commas, treat commas as new lines, and export it to a new file using Java?
java,text,bufferedreader,filereader
So the entire file is just one line? If that is the case, all you would have to do is the following: import java.util.Scanner; import java.io.*; public class convertToNewline { public static void main(String[] args) throws IOException { File file = new File("text.txt"); File file2 = new File("textNoCommas.txt"); PrintWriter writer...
Java wrapper for ROOT. OutputStreamReader is blocking
java,bufferedreader,root-framework
The C++ output statements are without newlines, which will not flush the lines. cout << "ROOT:: loop iteration" << endl; cin >> in_str; cout << "ROOT:: received string " << in_str << endl; The other problem is that the cin never "sees" a line sent from the Java program. You...
Java Read Text file with condition
Something like: line = it.nextLine(); if (line.contains("specific string")) continue; test = StringUtils.split(line,(",")); Why are you using StringUtils to split a line? The String class supports a split(...) method. I suggest you read the String API for basic functionality....
How parse string into map,the string read from a file location using java
java,dictionary,hashmap,bufferedreader,filereader
The space characters around the number caused a NumberFormatException, and there are space characters around city names so change this line amap.put(pair[i], Integer.parseInt(pair[1 + i])); to this amap.put(pair[i].trim(), Integer.parseInt(pair[1 + i].trim())); It's a really bad practice to leave catch blocks empty, it hides the problem (the NumberFormatException in this case)....
Issue with BufferedReader.read while reading from InputStream
While debugging found that "connection reset" was happening in middle hence data lose. Handled the exception to make a controlled retry for the same request and problem got resolved. Hope it helps to somebody.
Trying to read a data.txt file and do calculations
java,bufferedreader,filereader
I was able to find that bug very easily, when you get NullPointerException always try to print it out in the console before doing something to it, just to make sure. I've just added System.out.println(line) before Integer.parseInt(), remember to do this and it will make your life much much easier...
Taking input using bufferedreader
usage: -prize <Itemprize> will be printed only if this condition will fail if (list.length != 2 || (list[0].compareTo("-prize") != 0)) so only if user didn't provided two elements, and if first element is not -prize. Since for -price aaa both conditions are fulfilled so user will not see this info,...
Should BufferedReaders be passed a dynamic FileReader?
java,performance,bufferedreader,filereader,java-io
No, it's not necessary. buffReader.close() will close the FileReader as well. For some reason, this doesn't seem to be mentioned in the Javadoc. However, if you look at the source code for BufferedReader, you'll find close is defined as: public void close() throws IOException { synchronized (lock) { if (in...
Splitting a text file into multiple files by specific character sequence
java,text,split,bufferedreader,stringbuilder
You want to find the lines which match "I n". The regex you need is : ^.I \d$ ^ indicates the beginning of the line. Hence, if there are some whitespaces or text before I, the line will not match the regex. \d indicates any digit. For the sake of...
Java extract text from text file from a certain point on the text
java,filter,inputstream,bufferedreader,inputstreamreader
Assuming there's only one : symbol in the string you can go with id = ligne.substring(ligne.lastIndexOf(':') + 1); ...
How can i pass all integers i this loop and stop before the last line
java,linked-list,bufferedreader,stringtokenizer,parseint
I would just use try-catch: ArrayList<Integer> nums = new ArrayList<Integer>(); String lastLine = ""; try { while ((lastLine = in.readLine()) != null) { StringTokenizer st2 = new StringTokenizer(lastLine); graph.addEdge(Integer.parseInt(st2.nextToken()), Integer.parseInt(st2.nextToken())); } } catch (NumberFormatException e) {} System.out.println(lastLine); ...
String get text at the end of line
java,regex,string,substring,bufferedreader
You can use the String#substring(beginIndex) method which would get the substring starting at the specified index until the end of the string: String x = line.substring(line.indexOf("size") + 6); ...
Read from file and write it to another file
java,algorithm,file,bufferedreader
You can count the lines in the template.. store the 1st and nth value loop the file content if 1 or n matches with the line number .. store them separately... perform string manipulations... append all variable and write them into another file......
BufferedReader not visible to other functions
Please don't use StringBuffer, these were replaced by StringBuilder ten years ago. don't initialise a StringBuilder with an empty String. This only hurts performance. don't create dummy values for StringBuilders which you discard. don't pass variables via static fields. I suggest you pass it as an argument. Also don't ignore...
Write Object to File “Persons.obj”
java,file,bufferedreader,filereader,printwriter
For simply writing a small number of strings to a file, I'd recommend using the class "PrintWriter". It wraps itself around a standard Writer and allows you to write any primitive data type and some Objects to a given "Writer" (In our case a FileWriter). This isn't the only way...
How to store content from text file to arraylist
java,arraylist,static,bufferedreader
You declared all properties of Employee_Info as static fields. These are not bound to an instance of the class but rather to the class itself. Therefore, all instances of the class share the same values. Remove the static keyword from both the fields and the methods. You should use an...
How to store strings of text files for later use in Java
java,bufferedreader,jfilechooser
This code snippet should be a solution to your problem. printLines is used to start printing lines after your organism has been found. The while loop continues round and if another organism is not found, then the line is printed. But when a new organism is reached (denoted by >...
(Java) BufferedReader returning null when reading a file that isn't empty
Try the while loop while reading using BufferedReader: while ((savedChar = brSave.readLine()) != null) { System.out.println(savedChar); } If your files Contains text it will definitely show: Do not also leave the BufferedReader Open. Once you are done reading Close it: if (brSave != null)br.close(); ...
Java - Writing and Reading ArrayList to and from .txt file - BufferedWriter
java,bufferedreader,filereader,filewriter,bufferedwriter
The for loop work like this.To read the data back, you could read the whole string example: weapon1,item2,item99 into a String object and then split the String with a delimiter "," using split function of string class and then build the new array.example. String text="weapon1,item2,item99"; String parts[]=text.split(","); for(int i=0;i<parts.length();i++) Inventory.add.parts[i]...
Common way to use System.in several times without closing
Pass the BufferedReader into your method(s) (or make it a shared field), that way you don't have to re-create it. Also, you are correct that closing System.in (or something wrapping System.in) will cause you issues. Instead of public void foo() something like public void foo(BufferedReader reader) ...
Listening for incoming messages from TCP server causes StackOverflow
java,tcp,bufferedreader,stack-overflow,message-loop
Don't call run() within run(). This is not a recursive function. If you want to keep reading until some condition, wrap this in a while loop. By calling the method you are executing while you are executing it, you are creating another stack frame. What you really want is just...
how to read every rows in excel and save in map
java,json,excel,apache-poi,bufferedreader
A small addition to your input reading: String hline; while( (hline = fileReader.readLine()) != null){ line = hline; while( ! hline.endsWith( "}" ) ){ hline = fileReader.readLine(); line += hline; } This should be put into a separate method, but I leave this to you - I don't want to...
Buffered reader not accessable by other methods
Define BufferedReader at instance level just after declaring your path variable like BufferedReader buff; And in your method open, initialize it like buff = new BufferedReader(read); ...
Java - open txt file and clear all multiple spaces
java,bufferedreader,bufferedwriter
you are reading the file and at the same time writing contents on it..it is not allowed... so better way to read the file first and store the processed text in another file and finally replace the original file with the new one..try this br = new BufferedReader(new FileReader("C:\\Users\\Chris\\Desktop\\file_two.txt")); bw...
Why is my BufferedReader reading text that dosn't exit in the given file?
java,string,byte,bufferedreader
What you see is the UTF-8 BOM Convert your input file to be without BOM....
Android http request readline
java,android,httprequest,bufferedreader,readline
There is no default method to parse all the html and extract the needed portion. You can save all html in webPage as String and then parse the string to get price out by using code like this: String toFind = "product-card__price\">"; String str1 = webPage.substring(webPage.indexOf(toFind) + toFind.length()); String priceString...
Data stored in different lines on a file, how to load them as parameters to a class?
java,initialization,bufferedreader,readline
You should create a new Sentence instance only if the english string was found and declare it outside the while loop: Sentence sentenceClass = null; while(line!=null) { // file reading part if (lang.equals("EN")){ sentenceClass = new Sentence(); sentences.add(sentenceClass); sentenceClass.setFraseENG(sentence); } else { sentenceClass.setTranslation(readLine[1]); } line=reader.readLine(); } ...
How do I read next line with BufferedReader in Java?
You only read the first line. The line variable didn't change in the while loop, leading to the infinite loop. Read the next line in the while condition, so each iteration reads a line, changing the variable. BufferedReader br = new BufferedReader (new FileReader ("num.txt")); String line; while( (line =...
stdin Java Input
You should use Scanners for this. Here is an example implementing scanners: Scanner scanner = new Scanner(System.in); String s = scanner.nextLine(); String s2 = scanner.nextLine(); System.out.println(s + ":" + s2); //Close scanner when finished with it: scanner.close(); Here is the full documentation for further reading and examples: Oracle documentaion...
Skip a line using BufferedReader (skip, but not read it)
java,file,file-io,bufferedreader
If you care about the memory wasted in the intermediate StringBuffer, you can try the following implementation: public static void skipLine(BufferedReader br) throws IOException { while(true) { int c = br.read(); if(c == -1 || c == '\n') return; if(c == '\r') { br.mark(1); c = br.read(); if(c != '\n')...
Understanding how BufferedReader works in Java
java,bufferedreader,filereader
Your understanding of how this block should work: The while loop goes through each line of text until the condition is no longer true Correct :-) . Each line is stored in the BufferedReader Not correct. The bufferedReader does not store any data, it just reads it (Thats why it's...
Implementing Iterator interface with exception handling
java,unit-testing,iterator,bufferedreader,factory-pattern
A finally block always executes if there is a try-block before it. So yours always throws a NoSuchElementException(). finally { // return null; throw new NoSuchElementException(); } You should do something in it and not throw an Exception....
How to read a file continuously?
Your best bet might be to recreate the BufferedReader once readLine() returns null. For example: String filename = "[filename]"; BufferedReader reader = new BufferedReader(new FileReader(filename)); while (true) { String line = reader.readLine(); if (line != null) // Use line else { reader.close(); reader = new BufferedReader(new FileReader(filename)); } } This...
BufferedReader seems to infinitely read the first line
java,process,bufferedreader,handbrake
Call builder.redirectErrorStream(true); before creating the process (this will merge the input and the error stream into one: the input stream), and only read from the InputStream. That should solve the problem of the error stream running out of data before the input stream. If you do want to keep them...
BufferedReader reading each newline a comma
You forgot to reverse the arrayList itself. You only reverse each StringBuilder. Collections.reverse(arrayList); Anyways, there seems to be no use for a list at all. Just append directly to the StringBuilder. Something like this should do the trick: // ... StringBuilder sb = new StringBuilder(); while((line = in.readLine()) != null...
What does this condition do (BufferredReader and InputStreamReader)?
java,bufferedreader,inputstreamreader
Seems like your eyes are glancing over a pair of parentheses: while ( (userInput = stdIn.readLine() ) != null) { } I've attempted to make it more clear above. The variable userInput is being assigned stdIn.readLine(). And while userInput isn't null following that assignment, the loop continues. It's just a...
Reading a large text file faster
Stop trying to build up aisLines as a big String. Use an ArrayList<String> that you append the lines on to. That takes 0.6% the time as your method on my machine. (This code processes 1,000,000 simple lines in 0.75 seconds.) And it will reduce the effort needed to process the...
NullPointerException caused by Reading from File used for indexing using Google Guava [duplicate]
java,indexing,guava,bufferedreader,multimap
Why are you calling readLine() inside the while loop? while (((line = br.readLine()) != null)) { line = br.readLine(); When you call readLine() and it is not null, the line would have been read into line variable. Then inside the while loop you are making a second call to readLine()....
How to read a large file of Strings in chunks, each time from different offset, in Java?
java,file,memory,bufferedreader
The BufferedReader effectively takes care of reading the lines in chunks. So really your choice is between: after each call to readLine(), call your method to process it after each call to readLine(), add the line to a list, and then every time the list gets to some size, call...
Array of Buffered Readers in JAVA
If you change BufferedReader() to BufferedReader[] it is possible: BufferedReader[] b = new BufferedReader[5];//<-- correct size declaration of array b[0] = new BufferedReader(new FileReader("foo")); BufferedReader(5) results in a compiler error in your IDE.....
Buffered Reader read text until character
java,file,while-loop,bufferedreader,readline
It would be much easier to do with a Scanner, where you can just set the delimiter: Scanner scan = new Scanner(new File("/path/to/file.txt")); scan.useDelimiter(Pattern.compile(";")); while (scan.hasNext()) { String logicalLine = scan.next(); // rest of your logic } ...
java bufferedreader read line after another line, not under it
java,console,line,bufferedreader
I made a simple programm and it worked with Eclipse by just changing the System.out.println(...) to System.out.print(...). But you will have the problem to separate the numbers e.g. Enter number(s): 1 2 3 will return 1 2 3 as one string. Therefore I would suggest you to use a Scanner...
File Reader Method
java,logic,bufferedreader,filereader
If you want to read the entire file twice, you will have to close it and open new streams/readers next time. Those streams/readers should be local to the method, not members, and certainly not static. ...
java hadoop: FileReader VS InputStreamReader
java,hadoop,bufferedreader,filereader,inputstreamreader
i have found the problem. i have get a checksum exception. now i delete all .crc files from my input file. in this way i get no checksum exception and the buffered reader work fine (uncommented code part, upstairs).
Get page content from URL in java
As my above comment , you need to set user agent header by setRequestProperty method as below. String a = "http://kissanime.com"; URLConnection connection = new URL(a).openConnection(); connection .setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.95 Safari/537.11"); connection.connect(); BufferedReader r = new BufferedReader(new InputStreamReader(connection.getInputStream(), Charset.forName("UTF-8"))); StringBuilder sb =...
BufferedWriter can't desire change data
java,arrays,file,bufferedreader,bufferedwriter
Have a look at these modifications, you would want to replace data1 right after you detect it's different, then just read the rest of the lines and append them to your StringBuilder public static void main(String[] args) throws Exception { test("aaa", "bbb"); } public static void test(String DATA1, String DATA2)...
Scanning and getting runtime error
With int testcase = br.read(); you read the first character from the input. And if your whole input is only one character, the entire line is already read, so that str = br.readLine(); has nothing to to and the first output you see is: String #1 You can change reading...
BufferedReader and InputStreamReader from URL
android,url,inputstream,bufferedreader
Have a look at URLConnection Also, in the future, avoid using .plist as it something specific to ios and osx. By using another format (like json) you won't have to implement your own parsing....
Java: BufferedReader Keeps Writing Values 128-159 as 63 When Converting to Char
java,bufferedreader,filereader,filewriter,bufferedwriter
When you use FileReader and FileWriter, they will use the default encoding for your platform. That's almost always a bad idea. In your case, it seems that that encoding doesn't support U+0092, which is fairly reasonable given that it's a private use character - many encodings won't support that. I...
Finding the same value at multiple indexes
You can also use StringBuilder if all you care is to output the indexes. StringBuilder sb = new StringBuilder("array" + xx +" is found at index: "); for (x = 0; x < v; x++) { if (c[x] == xx) { sb.append(x).append(","); } } if (sb.charAt(sb.length() - 1) == ',')...
Buffered Writer and Reader Proper order/use
java,logic,bufferedreader,bufferedwriter
readLine() can return null, which means end of stream: in this case, end of file. Your code doesn't allow for that possibility, and it also doesn't allow reporting that possibility to the caller when it happens. I would get rid of the readFile() method altogether, and in its place call...
System.in and Scanner object
java,input,system,bufferedreader,println
System.in is a BufferedInputStream, such a Stream can be any input stream (for instance a network socket, or a file), but also the standard input channel stdin. stdin is the content you type in the command line, so obviously, it doesn't show anything. When you create a Scanner as shown...
Improve Data Transfer through socket from desktop to android service
java,android,sockets,bufferedreader,data-transfer
The answer is in the comments. The transfer of file name and size and using a sleep() is no good. You now send for instance myfile.txt:3456. But you better send a line like myfile.txt:3456\n and remove the sleep(). Then in the client you use readLine() to read the line. Also...
Confusion about String's replaceAll method
java,parsing,bufferedreader,bufferedwriter,replaceall
replaceAll doesn't modify the string you call it on, it returns a new string. Make sure you capture its return value. currentLine = currentLine.replaceAll(" ", "\n"); currentLine = currentLine.replaceAll(";", "\n;"); currentLine = currentLine.replaceAll("\\(", "\n(\n"); currentLine = currentLine.replaceAll("\\)", "\n)\n"); (In fact Strings are immutable, so this is true of all String...
Using Java bufferedreader to get html from URL
java,html,url,character-encoding,bufferedreader
The Server has changed his transfer mode to compressed data, what you can see in response header from server: Connection:keep-alive Content-Encoding:gzip Content-Type:text/html; charset=utf-8 Date:Mon, 09 Mar 2015 09:34:41 GMT Server:nginx Transfer-Encoding:chunked Vary:Accept-Encoding X-Powered-By:PHP/5.5.16-pl0-gentoo As you can see the content encoding is set to gzip Content-Encoding:gzip. So you have to decode...
How do I create separate Strings from a .txt file using a BufferedReader with char separations? Main concern w format
string,loops,char,bufferedreader
Can you try something like this: String output = ""; while ((line = bufferedReader.readLine()) != null) { output += line; } String parsedOutput = output.split(); You are reading everything into a String and then split it by defining the * to be the separator....
How do I structure text file?
You can have a pre-defined list of which entries you would like to remove. List<String> entriesToRemove = new ArrayList<String>(); entriesToRemove.add("header"); entriesToRemove.add("end-details"); entriesToRemove.add("end-numberDetails"); if(!entriesToRemove.contains(line)){ //your code to write on a new file }else{ for(String entry: entriesToRemove){ if(line.contains(entry)){ line = line.replace(entry, ""); //your code to write on a new file } }...
Java read from one file and write into another file using methods
java,file-io,bufferedreader,bufferedwriter
You can write to another file using: outputStream.write(). And when you are done just outputStream.flush() and outputStream.close(). Edit: public void readAndWriteFromfile() throws IOException { BufferedReader inputStream = new BufferedReader(new FileReader( "original.txt")); File UIFile = new File("numbers.txt"); // if File doesnt exists, then create it if (!UIFile.exists()) { UIFile.createNewFile(); } FileWriter...
Reading from a file Russian characters(javaSE)
You need to specify the encoding to be able to read the russian character. Don't use FileReader as it will use default platform encoding. Instead use new BufferedReader(new InputStreamReader(fileDir), "UTF8"); ...
Reading N lines from a file in java?
java,arrays,file,java.util.scanner,bufferedreader
byte[] inputBytes = "line 1\nline 2\nline 3\ntok 1 tok 2".getBytes(); Reader r = new InputStreamReader(new ByteArrayInputStream(inputBytes)); BufferedReader br = new BufferedReader(r); Scanner s = new Scanner(br); System.out.println("First line: " + br.readLine()); System.out.println("Second line: " + br.readLine()); System.out.println("Third line: " + br.readLine()); System.out.println("Remaining tokens:"); while (s.hasNext()) System.out.println(s.next()); and add a while...
readLine of BufferedReader does not change file pointer even if buffer size is small
java,android,bufferedreader,randomaccessfile
In order to update the file pointer in a RandomAccessFile you need to use the read() methods that are part of the RandomAccessFile object. Making a separate Reader won't update it. If you need to use BufferedReader you can always wrap a RandomAccessFile in your own InputStream implementation so reads...
Java reading a string from a text(txt) file
java,string,bufferedreader,filereader
You're breaking the loop if the name exists, so you should only print the "not exists" message if the loop doesn't break: Scanner in = new Scanner(System.in); out.print("Enter name: "); String name = in.nextLine(); BufferedReader br = new BufferedReader(new FileReader("name.txt")); String line; boolean nameFound = false; while ((line = br.readLine())...
How would I go about searching for a string of words across multiple lines
java,parsing,input,io,bufferedreader
I think that either you: Normalize your key phrases and names (represent "word\nplus\nword" as "line n has word, line n+1 has plus, line n+2 has word") Process newlines as part of the matching characters (process byte by byte instead of line by line) From your current strategy, option 1 would...
is there any way to reset a previously initialised `bufferedReader` to the beginnig of the stream?
java,inputstream,bufferedreader,fileinputstream
To be able to use reset() in such a way, the whole file must fit into the buffer of the BufferedReader. That means you must either create a BufferedReader with a buffer that is large enough or create a new instance when you want to read the file again....
Java BufferedReader.readLine() returning null when reading file
java,nullpointerexception,null,bufferedreader
You're setting the value to null explicitly: String[] returnVal = null; Since you don't know how many elements it'll contain, you should use an ArrayList instead*: ArrayList<String> returnVal = new ArrayList<>(); * See the API to know what methods you should use to add objects to it...
Why is eclipse complaining when I try to close BufferedReader in finally block?
java,eclipse,exception,bufferedreader,try-catch-finally
Both code examples should have compiler errors complaining about an unhandled IOException. Eclipse shows these as errors in both code examples for me. The reason is that the close method throws an IOException, a checked exception, when called in the finally block, which is outside a try block. The fix...
Why is my BufferedReader not “Ready”?
java,java.util.scanner,bufferedreader
@EJP's answer is spot on. I just want to add that code that attempts to use the ready() method of input streams and readers is usually broken in one way or another. And in this case, the ready() call is not achieving anything useful. It is better to just call...
Chaining InputStream in Java
java,inputstream,bufferedreader
This kind of question already answered : http://stackoverflow.com/a/15799469/3480200 With some opinion from others i conclude that: It's not ok to use buffered inside another buffered in my case. It's useless....
Why we need to use BufferedReader instead of String while getting the response from server
java,android,httpclient,bufferedreader
Why using the BufferedReader method? Is there any advantage for using this? The java.io.BufferedReader class reads text from a character-input stream, buffering characters so as to provide for the efficient reading of characters, arrays, and lines. Buffering can speed up IO quite a bit. Rather than read one character...
How to convert VCard to JSON Array
Okay, here it is... Using this library should solve your problem: https://code.google.com/p/ez-vcard/ --- approach using your InputStreamReader (more exactly: Reader) VCard vcard = Ezvcard.parse(reader).first(); (where reader is of Type "Reader", which InputStreamReader is) and export it to JSON with the following snippet: String json = Ezvcard.writeJson(vcard).go(); ...
Android BufferedReader does not read the whole response
java,android,url,bufferedreader
How do you know that it's only half of the response? If you rely on what is printed with System.out.println() then you should be aware that Logcat has a limitation that prevents it from printing more than 4,000 characters. Anything after that is truncated. To check how much of the...
Android not gtting file through FileINputStream?
java,android,bufferedreader,fileinputstream,filechannel
Try following code. File sdCard = Environment.getExternalStorageDirectory(); File dir = new File(sdCard.getAbsolutePath() + File.separator + "/imotax"); dir.mkdirs(); File f= new File(dir, fileToCreate); if(!f.exists()){ f.createNewFile(); } fis = new FileInputStream(f); ...
How to convert multi-line text to image using Java [closed]
java,image,image-processing,bufferedreader
Hi here I am writing multiple lines on JPanel. And you can write code which create Image from JPanel. package Stakeoverflow.swingFrame; import java.awt.Color; import java.awt.Font; import java.awt.FontMetrics; import java.awt.Graphics; import java.awt.Graphics2D; import java.awt.RenderingHints; import java.awt.image.BufferedImage; import java.io.BufferedReader; import java.io.File; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.util.logging.Level; import java.util.logging.Logger; import...
BufferReader populating 2D array missing last line
java,multidimensional-array,bufferedreader
You are storing the newlines in the array. Given that code, and that file, and that outArray contains [7][4] elements, outArray should end up containing: outArray[0][0] == 'a' outArray[0][1] == 'b' outArray[0][2] == 'c' outArray[0][3] == 'd' outArray[1][0] == '\n' outArray[1][1] == 'e' outArray[1][2] == 'f' outArray[1][3] == 'g' outArray[2][0]...
Read and Write to a File, An Arraylist which contains objects with an ArrayList
java,bufferedreader,bufferedwriter
try this: public class test1 { public static void main(String args[]) throws IOException{ StringBuffer sb = new StringBuffer(); String filepath = "test.txt"; List<String> list = new ArrayList<String>(); list.add("1"); list.add("2"); list.add("3"); list.add("4"); list.add("5"); list.add("6"); Iterator<String> it = list.iterator(); while(it.hasNext()) { sb.append(it.next()); sb.append(","); } BufferedWriter bw = new BufferedWriter(new FileWriter(filepath)); bw.write(sb.toString()); bw.flush();...
Line when reading a file is empty but the line is not null
You get a null only when you have exhausted the stream. But the first line of the stream (your file) is just an empty line - and you load it, the result of the empty line, is an empty string (""). It can be easily solved by skipping lines with...
writing and reading a txt content using java
To append to existing file use FileWriter with append = true argument in constructor: FileWriter fileWriter= new FileWriter(fileName,true); BufferedWriter bufferWriter = new BufferedWriter(fileWriter); bufferWriter.write(inputString); bufferWriter.close(); Read more about FileWriter here...
Android URL connection java.io.FileNotFoundException
java,android,email,httprequest,bufferedreader
There's an issue with URL encoding. Take a look at This Link String query = URLEncoder.encode("apples oranges", "utf-8"); String url = "http://stackoverflow.com/search?q=" + query; ...
How to change a file reader to a directory scanner?
java,loops,directory,bufferedreader,inputstreamreader
I can see you want to read the content into another file... the following classes are used for writing/reading data to files. FileOutputStream,FileInputStream; as you can see, FileOuputStream is used in writing data to a file and FileInputStream is used in reading data from a file. the data can be...
Why is this method returning an ArrayList with all the same objects? JAVA
java,file,csv,arraylist,bufferedreader
How many times do you call new User()? That's how many User objects you've created: exactly one, and you do this once before the loop. Solution, call this inside of the loop -- this way you create a new User for each item that you add to the list....
File reading/writing proper order
java,file,bufferedreader,bufferedwriter
Be sure you add bw.flush(); to your code after the write to flush the buffer and get the data into the file to be able to read it back....
How do I create a 2 dimensional array from a text file in Android?
android,multidimensional-array,bufferedreader
OK thank you for all your help! I did what CyberGeek.exe suggested but I modified it a bit. Here is my code: public static int[][] tileArray; public static void loadTileMap(String fileName, int height, int width) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(GameMainActivity.assets.open(fileName))); String line; tileArray = new int[width][height];...
Trying to insert text from file to 2D array. Java. Text is different formats
So you want to do it using array only. You can consider below example as reference - import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; public class TitanicApp { int size = 10; int colCount = 6; String[][] array = null; public static void main(String[] args) { TitanicApp app = new TitanicApp();...
Reading .ini File When Converted into Runnable Jar File
java,bufferedreader,filereader,ini,ini4j
When you want to load the config from the jar, you can use the path getResource() and getResourceAsStream() functions. The NullPointerException indicates (most likely, because it is always hard to tell with many statements on one line) that the resource was not found (which silently returns null) If you want...
Assigning instances of objects to an array
java,arrays,bufferedreader,java-io
public class Pool { private int teamCounter; ... public Pool(String aName) { super(); this.poolName = aName; this.teams = new Team[NOOFTEAMS]; teamCounter=0; } ... public void loadTeams() { ... //somewhere here I need to add the aTeam object to the array this.teams[teamCounter++]=aTeam; } } ...
How to store text from a certain column in an arraylist?
All you need to do is just to split each line using whitespace as a delimiter and keep the first token, and repeat that for every line: This can be achieved using the following line of code which uses the split function (see more info here http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#split(java.lang.String)) line.split("\\s+"); Then, the...
BufferedReader found specific word in line, take the data from that line
java,arrays,file,bufferedreader
Please try this code: public static void main(String[] args) { BufferedReader reader = null; String line; String name,pwd,contactNo,email; try { reader = new BufferedReader(new FileReader("src/files/temp2.txt")); String foundWord = "dod"; while ((line = reader.readLine()) != null) { String[] words = line.split(","); for (String word : words) { if (word.equals(foundWord)) { name...
How to use BufferedReader correctly with sockets
java,android,sockets,chat,bufferedreader
You're using a BufferedReader and read it with in.readLine(), which, surprise surprise, will return the next line in the response. A line is a string terminated by a newline character, so your BufferedReader will have to wait until it sees a newline until it can return your line. If you...
Java BufferedReader - empty line issue
java,file,javafx,line,bufferedreader
As it turned out in the discussion, the problem is that with readLine() the following files will behave the same way: File A: "Hello\n" File B: "Hello" 1st readLine() --> "Hello" 2nd readLine() --> null ==> we cannot know if there was a '\n' after the last line or not...
Accents aren't print after UTF encoding/decoding
java,unicode,encoding,inputstream,bufferedreader
UTF-8 is a multi-byte encoding. That means that one character might have a representation that is more than one byte long, especially if it is not a US-ASCII kind of character. You are specifically decomposing the string into bytes for reasons that are not clear, and appending them. So you...
BufferedWriter NOT writing to .txt file [JAVA] [duplicate]
java,client-server,bufferedreader,bufferedwriter
You never call flush or close on the instance of BufferedWriter, in fact, you ignore it completely. Also, you resource management is none existent. If you open a resource, you should close it. For example... FileReader file = new FileReader("client-temp.txt"); try (BufferedReader tc = new BufferedReader(file)) { try (BufferedWriter bw...
BufferedWriter is not writing text to text file
java,bufferedreader,bufferedwriter
You need to either flush the buffer post writing the data to buffer like bw.flush(); or close the writer like bw.close();//handle exception if you are not using AutoCloseable feature. ...
Java Accessing Hexidecimal Text Files For HashMaping
java,iterator,hashmap,hex,bufferedreader
here is your code modified to read the file and populate a HashMap, in this case I am using a TreeMap to sort the hex fields in order, see if this works for you, public class FP extends JFrame implements ActionListener { private TreeMap<String, String> buttonColors; // Constructor public FP()...
Buffered Reader: Reset won't reset
I see a couple of issues in the code: Inside the second while() loop you are still splitting the string "line", but the while loop assigns the input to "checkLine". You don't reset "exit" to false - this should probably happen after the br.reset(). ...
Read all lines with BufferedReader
java,bufferedreader,infinite-loop,inputstreamreader
The idiomatic way to read all of the lines is while ((line = buffer.readLine()) != null). Also, I would suggest a try-with-resources statement. Something like try (InputStreamReader instream = new InputStreamReader(System.in); BufferedReader buffer = new BufferedReader(instream)) { long length = 0; String line; while ((line = buffer.readLine()) != null) {...
BufferedReader space separated input
Try this, StringTokenizer tk = new StringTokenizer(input.readLine()); int m = Integer.parseInt(tk.nextToken()); String s = tk.nextToken(); this is faster than string.split(); ...
Reading java file with escape characters for newline
java,escaping,bufferedreader,unicode-escapes
You can use a Scanner with a custom delimeter. The delimeter I use is set to match \n but not \u0001\n (where \u0001 represents CTRL+A): try { PrintWriter writer = new PrintWriter("dboutput.txt"); Scanner sc = new Scanner(new File("dbinput.txt")); sc.useDelimiter(Pattern.compile("^(?!.*(\\u0001\\n)).*\\n$")); while (sc.hasNext()) { writer.println(sc.next()); } scanner.close(); writer.close(); } catch (FileNotFoundException e)...
Download and View PDF inside android application from Webservice
android,web-services,pdf,bufferedreader,filereader
I am trying to download and open a PDF file inside android application i.e. without using any other application(pdf viewer,etc) installed on phone. Not according to the code in your question. You are specifically attempting to open the PDF file in "other application(pdf viewer,etc) installed on phone". Using the...
Read text file using java , eclipse kepler [duplicate]
java,jsp,bufferedreader,eclipse-kepler
You can achieve it this way: while ((line = reader.readLine()) != null) { if (line.trim().length() == 0) { continue; } if (line.equals("Success")) { break; } else { // perform required operation } } ...