Thanks to Robert Crovella, it turns out I was using the "Debug" mode that is notoriously slow instead of "Release" mode.

probability,scilab,cumulative-sum

The sum of all the probabilities of PMF is not 1 You could not possibly add all the probabilities, because the geometric distribution assigns nonzero probabilities to all positive integers. If you run the sum up to n=10, the sum of probabilities is appreciably less than 1. If you...

parent-child,mdx,cumulative-sum,iccube

The current version of icCube - 4.8.2 - does not support the Aggregate function for measures with Aggregation type 'unary operator'. See Aggregation function doc here. The Aggregate function is a bit dodgy if you're using many-2-many relations as well as special measure aggregation types. For example : Aggregate( {...

I don't think you want "cumulative quantity", you just want the sum: select location, sum(quantity) from db2 group by location having sum(quantity) < 10; "cumulative" would imply a running sum or cumulative sum....

sql-server,sql-server-2008,cumulative-sum

OP wants specific output - so I comply: DECLARE @items TABLE ([date] DATETIME, title VARCHAR (100), price MONEY) INSERT @items VALUES ('20150310','A',100), ('20150201','B',25 ), ('20140812','C',225), ('20130406','D',110), ('20150607','E',645), ('20120410','F',450), ('20130501','G',325), ('20150208','H',175) ;WITH p_cte AS ( SELECT * , RowNo = ROW_NUMBER() OVER (ORDER BY DATE) FROM @items ), p2_cte AS (...

javascript,json,cumulative-sum

If I understood your question right, the function you want is: data3 = data1.map(function(obj, i) { var sum = {}; for (var key in obj) { sum[key] = typeof obj[key] === 'number' ? obj[key] + data2[i][key] : obj[key]; } return sum; }); It will make new object data3, that will...

If by "most earlier" (which in English is more properly written "earliest") you mean the nearest, which is what is implied by your expected output, then what you're talking about is a cumulative sum. You can apply cumsum() separately to each group of txt with ave(): dd <- data.frame(txt=c(rep("a",4),rep("b",5),rep("c",3)), val=c(1,2,3,4,1,2,3,4,5,1,2,3)...

Ignore Alexandre's comment, you've obviously had a go, structured a solid qu and people can always choose not to answer. It's actually a bit of a minefield doing cumulatives using @ variables across groups in MySQL. I'd take the approach of getting the non-cumulatives first and then using the @...

python,dictionary,histogram,cumulative-sum,cumulative-frequency

The following should at least run (which your code as posted won't): import collections, itertools with open('text') as infile: letters = list(infile.read()) # not just letters: whitespace & punct, too letter_freqs = collections.Counter(letters) letter_sum = len(letters) letters_set = sorted(set(letters)) d = {l: letter_freqs[letter]/letter_sum for l in letters_set} cum = itertools.accumulate(d[l]...

sql,sas,counting,proc,cumulative-sum

As I understand it, you really want to produce two tables: A list of all visits, with number of days until submission/creation for each A list of all dates, with number of visits per date, including how many were submitted 0-14 days after If that is what you meant, this...

apache-pig,window-functions,cumulative-sum

Use full package path of Stitch and Over command. ie, replace Stitch with org.apache.pig.piggybank.evaluation.Stitchand Over with org.apache.pig.piggybank.evaluation.Over if you want to avoid the above lengthy package name in your pig script then define your own macro something like this and use it in your pig script. DEFINE MYOVER org.apache.pig.piggybank.evaluation.Over; DEFINE...

Please correct me if I'm misunderstanding, but I believe you simply want this: I <- cumsum(sqrt(1 - U^2)) It is unclear why you want to use for loops....