python,numpy,suppress-warnings,divide-by-zero

You can disable the warning with numpy.seterr. Put this before the possible division by zero: np.seterr(divide='ignore') That'll disable zero division warnings globally. If you just want to disable them for a little bit, you can use numpy.errstate in a with clause: with np.errstate(divide='ignore'): # some code here ...

geometry,coordinate-systems,divide-by-zero

When you calculate center point of an arc that is passing through 3 points, you definitely need to check if these points lies on the same line. But rewrite expression if (py2-py1)/(px2-px1) = (py3-py2)/(px3-px2) to avoid dividing Det = (py2-py1) * (px3-px2) - (py3-py2) * (px2-px1) if Det = 0...

Mathematically it's most certainly not infinity. if it was obtained from limit x^2/x as x -> 0, it should be 0, for instance. x/x^2 would give infinity, though. It's an indeterminate form, and in some sense more indeterminant than 1/0, 2/0 etc. In short, much more of your math would...

c,integer-division,divide-by-zero,integer-arithmetic,ppc

Division by zero is undefined behaviour, see C11 standard 6.5.5#5 (final draft). Getting a trap or SIGFPE is just a courtesy of the CPU/OS. PowerPC as typical RISC CPU does not catch it, as it can safely be detected by a simple check of the divisor right before doing the...

user-interface,user-experience,divide-by-zero

Because your users are business folks wanting to know their advertising conversion rate, and none is available since there were no conversions, I would suggest: n/a By the way, as I see it, you're not giving them conversion rate per se. You're giving them cost per conversion, which should then...

You can simply avoid this problem by using a continue statement: def f(x): return 1 / (exp(x) - 1) f_values = {} for i in range(-5,5): if i == 0: continue f_values[i] = f(i) print f_values >>> {1: 0.5819767068693265, 2: 0.15651764274966565, 3: 0.05239569649125595, 4: 0.01865736036377405, -2: -1.1565176427496657, -5: -1.0067836549063043, -4:...

You should not be returning 0. You should return float.NegativeInfinity (if b is negative) or float.PositiveInfinity (if b is positive), and float.NaN if both a and b are 0. Note that this is the same behavior that you would get if you did this in your code: return a /...

sql-server,case,divide-by-zero

CASE WHEN(SUM(CASE WHEN J.Description <> 'I' THEN 1 ELSE 0 END)) = 0 THEN 1 ELSE SUM (CASE WHEN J.Description <> 'I' THEN 1 ELSE 0 END)) END AS 'MTBUR' Needed another END to end nested case...

c#,exception,dllimport,divide-by-zero,floating-point-exceptions

int a = 0; var b = 5/a; You are performing integer arithmetic here and so masking floating point exceptions has no effect on this expression. ...

exception,fractions,divide-by-zero

The statement bottom % top yields a divide by zero error when top is zero. You can fix it by changing the first line of your simplify() method to this: if (top != 0 && bottom % top == 0) { ...

java,exception,throw,divide-by-zero,throws

The problem is that you're throwing an Exception that's undeclared in your method: Exception myException = new ArithmeticException("You can't divide by zero!"); throw myException; //here you throw Exception You can solve this by any of these: Declare that your method throws an Exception: void printResults(int a, int b) throws Exception...