Put those values into an array, remove duplicate values, and then compare that array to the original array. If they're the same there are no duplicates. $values = explode(',', $data); var_dump($values == array_unique($values)); Demo...
java,string,if-statement,while-loop,duplicates
You can put all the string token in Set and check if that token contain in Set befor you process further as below :- // Declration .... Set courseSet = new HashSet(); ... // Check befor you process further if(!courseSet.contains(course)) { ... // Your Code... ... courseSet.add(course) } ...
excel,vba,delete,duplicates,add
It is generally recommended to disable events inside event processing code if you are likely to trigger the event you are processing. Delete will cause the Selection to change which will cause this event to fire again. See this excellent post on the topic. To resolve, add Application.EnableEvents = False...
c#,entity-framework,asp.net-mvc-5,duplicates,many-to-many
I'd say you are on the right track. If tag names are unique theres no need to "Count" though. Just get the first one if it exists. Swap out dupes and do nothing for uniques // check for duplicate entries foreach (var tag in post.Tags.ToList()) { var dupeTag = uwork.TagRepository.GetAll().FirstOrDefault(t...
c++,loops,duplicates,do-while,getchar
A quick fix: do{ puts("Menu"); std::cin >> option; } while (option != '3');...
You can try library(data.table)#v1.9.4+ setDT(yourdf)[, .N, by = A] ...
sql,ms-access,duplicates,group
You can create a union query: SELECT Field1 AS FieldValue FROM MyTable UNION ALL SELECT Field2 AS FieldValue FROM MyTable UNION ALL SELECT Field3 AS FieldValue FROM MyTable Now use this query as source in a query similar to your original....
keeping the spirit of what you tried: my %seen; my @result = grep {! $seen{(split "_",$_)[0]}++} <DATA>; print @result; __DATA__ revised_1.4_1.4-1.05-jan revised_1.5_1.8-before revised_1.5_1.8-after revised_1.5_0.7-mid deleted&reviewed_0.9-0.8-1.05-jan deleted&reviewed_1.6_1.6-before deleted&reviewed_0.5_1.8-after deleted&uploaded_0.8_1.9-midweek deleted&uploaded_1.0_1.3-offweek accessedbeforesecondquarter_0.8._1.6-jan accessedbeforesecondquarter_0.9_1.7-feb result: revised_1.4_1.4-1.05-jan...
r,data.frame,duplicates,conditional
Looks like a job for aggregate(). # Input data frame df <- data.frame(Gene=c("AKT", "MYC", "MYC", "RAS", "RAS", "RAS", "TP53"), Expression=c(3, 2, 6, 1, -4, -1, -3)) # Maximum absolute value of Expression by Gene maxabs <- with(df, aggregate(Expression, list(Gene=Gene), FUN=function(x) max(abs(x)))) # Combine with original data frame df <- merge(df,...
android,gradle,duplicates,project,sync
i think that i found the source of my problem it was a virtual machine problem. so the solution is : open file -> settings clic to : compiler in the VM option field put te following value: -Xmx512m That's all...
You could use an insert-select statement. To just duplicate the rows: INSERT INTO mytable SELECT * FROM mytable WHERE <some condition> To duplicate with a different style: INSERT INTO mytable SELECT col1, col2, 'someString' AS style FROM mytable WHERE <some condition> ...
python,duplicates,nested-lists
Assuming you're looking for a specific target (your question was unclear): def find_dupe(lists, target): seen = set() for lst in lists: for item in lst: if item == target and item in seen: return True seen.add(item) DEMO: >>> find_dupe([[20, 21, 22], [17, 18, 19, 20], [10, 11, 12, 13]], 20)...
Not sure if I understand what you are trying to do. You'll probably need a library for random selection: import random Now here is your input string: s = "AppleStrawberryBananaCitrusOrange" print s You can use random.randint to select a random position and extract a 4-character word: i = random.randint(0, len(s)...
I would use ave to write a simple function like this: myFun <- function(vector, thresh) { ind <- ave(rep(1, length(vector)), vector, FUN = length) vector[ind > thresh + 1] ## added "+1" to match your terminology } Here it is applied to "v": myFun(v, 1) # [1] "c" "c" "c"...
You can count occurrences of a and return values>1 for duplicated rows. In [25]: df[(df.groupby('a').transform('count')>1).values] Out[25]: a b 0 1 a 1 1 s 2 1 d ...
excel,excel-formula,duplicates
do you mean the data you have looks like this: column A column B column C ABC 5 ABC-123 3 ABC-543 2 if so, you can select column A then go to data then text to columns then delimited select other by putting - sign, next and finish. result must...
mongodb,indexing,duplicates,unique-constraint
Writes can not be applied simultaneously to the dataset. When a write is sent to a MongoDB instance, be it a shard or a standalone server, here is what happens A collection wide write lock (which resides in RAM) is requested When the lock is granted, the resulting data to...
One important point to consider here: First, because you need to sum values AND change the values you're summing, you're going to get a circular reference if you try to do this dynamically. One way to get around this is to add a third column, with the formula =SUMIF(A:A,A1,B:B) If...
vb.net,visual-studio,textbox,duplicates
You could use a HashSet(Of String) + String.Join: Dim uniqueUrls As New HashSet(Of String) For Each curElement As HtmlElement In theElementCollection If curElement.GetAttribute("href").Contains("/watch") Then uniqueUrls.Add(curElement.GetAttribute("href")) End If Next TextBox1.Text = String.Join(vbCrLf, uniqueUrls) ...
ruby,delete,duplicates,readfile
I would do it like this: require 'set' def copy_unique_lines(source, target) lines = Set.new File.open(target, 'w') do |out| File.open(source, 'r').each_line do |line| if lines.add?(line) out << line end end end end In which source and target are file paths: copy_unique_lines('path/input.txt', 'path/output.txt') ...
sql,oracle,select,duplicates,distinct
try this: SELECT * FROM myTable WHERE ID IN(SELECT MIN(ID) FROM myTable GROUP BY Code) ...
javascript,arrays,recursion,duplicates
This is how I would do it: var permute = (function () { return permute; function permute(list) { return list.length ? list.reduce(permutate, []) : [[]]; } function permutate(permutations, item, index, list) { return permutations.concat(permute( list.slice(0, index).concat( list.slice(index + 1))) .map(concat, [item])); } function concat(list) { return this.concat(list); } }()); function...
mysql,duplicates,group-concat,self-join
This is a rather unorthodox solution, but hey... SELECT MIN(x.id) id , GROUP_CONCAT(DISTINCT y.id) duplicates FROM duplicates x JOIN duplicates y ON y.name = x.name AND y.id > x.id GROUP BY x.name ...
c#,linq,list,object,duplicates
var distinctItems = myList.GroupBy(x => x.prop1).Select(y => y.First()); ...
excel,duplicates,serial-number
Sort your column A then insert the number 1 in cell B2 and the following function in cell B3 and copy down. in cell B2=1 function in cell B3: =if(A3=A2, B2, B2+1) Update ...
Try: library(dplyr) df %>% group_by(Group) %>% mutate(eventNumber = row_number()-1) ...
compile 'com.android.support:support-v4:22.1.1' compile ('com.android.support:appcompat-v7:22.1.1') { exclude module: 'support-v4' } compile ('com.facebook.android:facebook-android-sdk:4.2.0') { exclude module: 'support-v4' } compile ('com.github.navasmdc:PhoneTutorial:[email protected]') { exclude module: 'support-v4' } ...
regex,algorithm,count,find,duplicates
One way is splitting your text based on your n then count the number of your elements that all is depending this counting you can use some data structures that use hash-table like dictionary in python that is much efficient for such tasks. The task is that you create a...
Assuming that you are using a separator such as ,, you can use String.split() method which gives you an array of Strings and loop through all this strings, here's the code you need: String[] strArray = str.split(","); for(String string : strArray) { char [] charArray = string.toCharArray(); for (Character c...
You can try with group by: select Firstname , Lastname , case when count(*) > 1 then '**ERROR**' else age end from Table group by Firstname , Lastname , age; Or in case you want to return all rows with duplicates: select t.Firstname , t.Lastname , case when (select count(*)...
This is quick and dirty, but find-dup should return the first duplicated item (in this case a sublist) in the list. to go let listA [[-9 2] [-9 1] [-9 0][-9 -1][-9 -2][-9 -3][-9 -4][-8 0][-9 0]] show find-dup listA end to-report find-dup [ c ] ;returns the first duplicated...
Someone mentions for N=[1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 1] it will get [[1], [2, 2], [3, 3, 3], [4, 4, 4, 4], [5, 5, 5, 5, 5], [1]] In other words, when numbers of the list isn't in order or...
We can use Reduce with intersect in base R lapply(my.list, function(x) x[with(x, Letters %in% Reduce(intersect, split(Letters, Numbers))),]) Or using dplyr library(dplyr) lapply(my.list, function(x) x %>% group_by(Letters) %>% filter(n_distinct(Numbers)==2)) Instead of having a list, it can be changed to a single dataset with an additional grouping column and then do the...
sql,postgresql,sql-update,duplicates,distinct
When you use GROUP BY you cannot include in the select list a column which is not being ordered. So, in your query it's impossible to inlcude Id in the select list. So you need to do something a bit more complex: SELECT Id_Category, Id_Theme, (SELECT Id FROM Words W...
You can wrap a map and provide additional methods, that check item version. Here is put method, for example. class MyMap<ID, E> extends HashMap<ID, E extends Versioned & HasId<ID>> { public void put(E elem) { if (containsKey(elem.getId()) { E exist = get(elem.getId()); if (elem.version.isGreater(exist.version)) super.put(elem.getId(), elem); } else { super.put(elem.getId(),...
java,arraylist,duplicates,array-merge
You can use the List#retainAll(Collection<?> c) method, which: Retains only the elements in this list that are contained in the specified collection (optional operation). In other words, removes from this list all of its elements that are not contained in the specified collection. List<Point> first = ... List<Point> second =...
Store your numbers in a collection, such as a list. Then you can check if new numbers are already in the collection before adding more. integers = [] while len(integers) < 10: a = input("Enter an integer: ") if a in integers: print("Sorry, that number was already entered.") else: integers.append(a)...
You can use the run length encoding lengths to pick out the rows you want. If used raw in a cumsum it will give you the last value in a sequence, but you can get the first by subtracting the lengths from the cumulative sum and adding one. x <-...
We could get the index of rows (.I[which.min(..)) that have minimum 'VALUE' for each 'SYMBOL' and use that column ('V1') to subset the dataset. library(data.table) dt[dt[,.I[which.min(VALUE)],by=list(SYMBOL)]$V1] Or as @DavidArenburg mentioned, using setkey would be more efficient (although I am not sure why you get error with the original data) setkey(dt,...
java,arraylist,duplicates,syntax-error
Arrays don't have the get(int) method. Instead, they use the [int] syntax: if (data[i].equals(data[j])) { return true; } ...
This will work: var source = [['bourbon', 2], ['bourbon', 1],['scotch', 2]]; var hash = {}; var consolidated = []; source.forEach(function(item) { hash[item[0]] = (hash[item[0]] || 0) + item[1]; }); Object.keys(hash).forEach(function(key) { consolidated.push([key, hash[key]]); }); jsFiddle...
java,hashmap,duplicates,hashset
Give this a try... It utilizes a HashMap of Lists public static void main(String[] args) { List<String> inputs = new ArrayList<>(); inputs.add("Apple: 0 1"); inputs.add("Apple: 4 5"); inputs.add("Pear: 0 10"); inputs.add("Pear: 11 13"); inputs.add("Apple: 5 10"); inputs.add("Apple: 2 4"); Map<String, List<Fruit>> fruits = new HashMap<>(); for (String input : inputs)...
javascript,jquery,json,duplicates
var asset = [ { value1: "1", value2: "2", value3: "3" }, { value1: "1", value2: "5", value3: "7" }, { value1: "6", value2: "9", value3: "5" }, { value1: "6", value2: "9", value3: "5" } ]; function countEqual(oo, pp) { var count = 0; oo.forEach(function (el) { var i,...
duplicates,expression,adobe,after-effects
You might end up wanting to organize your comp differently, but, given your example (and exactly those name lengths), this position expression will work to find the appropriate 'target layer': //base name to work from: baseName = "Layer"; //length of that: nameLen = baseName.length; //this layer's name: myName = thisLayer.name;...
You need to empty the value of input on your clone like this $(document).ready(function() { var id = 1; // get item var item = $("#addparts"); var before = $('#div_button'); // initalize event click $('#addMore').on('click', function() { // clone addparts var clone = item.clone(true); // remove id clone.attr('id', ''); //...
I think you want something like - gives you all rows with 3 or more records SELECT category, measure, date FROM my_table t1 inner join ( SELECT category, measure FROM my_table group by category, measure having count(*) >= 3 ) t2 on t2.category = t1.category and t2.measure = t1.measure To...
This is how I would do it. mylist = ["name", "state", "name", "city", "name", "zip", "zip"] from collections import Counter # Counter counts the number of occurrences of each item counts = Counter(mylist) # so we have: {'name':3, 'state':1, 'city':1, 'zip':2} for s,num in counts.items(): if num > 1: #...
sql,oracle,group-by,duplicates,candidate-key
You can use min in analytical version here, it is fast: select TGroup, min(Group_Desc) over (partition by tgroup) from t SQLFiddle demo first_value is also the option: select TGroup, first_value(Group_Desc) over (partition by tgroup order by subgroup) gd from t ...
java,format,return,duplicates,string.format
If you store usernames using %03d, i.e. with leading zeros, you also should use this when you compare the string in your userNameList: userNameList.get(i).equals(String.format("%s%s%03d", p1, p2, p3)) ...
php,mysql,ajax,insert,duplicates
You just need a simple SELECT call before inserting. $conn = new mysqli($servername, $username, $password, $dbname); $conn->set_charset("utf8"); if($conn->connect_error){ die("Connection failed: " . $conn->connect_error); } $email = $_POST["email"]; $dob = $_POST["dob"]; $sql = "SELECT email FROM Users WHERE email = " .$email; $query = $conn->query($sql); if (mysqli_num_rows($query) > 0){ echo "There...
formatting,duplicates,conditional,highlight,partial
Thanks to a genius over at the Google Product Support Forums named Isai Alvarado I finally have the solution... =if(C2<>"",ArrayFormula(countif(left($C$2:$Z$18,4),left(C2,4)))>1) I hope this helps anyone else trying to highlight partial duplicates across multiple columns. ...
c++,opengl,vector,find,duplicates
You can't compare floating point values simply using a simple x == y expression as if they were integers. You have to compare them using a "threshold", a "tolerance", e.g. something like: // Assuming x and y are doubles if (fabs(x - y) < threshold) { // x and y...
You could do: library(dplyr) df %>% # create an hypothetical "customer.name" column mutate(customer.name = sample(LETTERS[1:10], size = n(), replace = TRUE)) %>% # group data by "Parcel.." group_by(Parcel..) %>% # apply sum() to the selected columns mutate_each(funs(sum(.)), one_of("X.11", "X.13", "X.15", "num_units")) %>% # likewise for mean() mutate_each(funs(mean(.)), one_of("Acres", "Ttl_sq_ft", "Mtr.Size"))...
You can use match and negative indexing. v[-match(x, v)] produces [1] "d09" "d01" "d02" "d13" match only returns the location of the first match of a value, which we use to our advantage here. Note that %in% and is.element are degenerate versions of match. Compare: match(x, v) # [1] 6...
Use TRIM in the select and GROUP BY clauses: SELECT COUNT(*) AS nb_duplicates, our_ref, TRIM(BOTH '\n' FROM partner_ref), partner_tag FROM partners_entries GROUP BY our_ref, TRIM(BOTH '\n' FROM partner_ref), partner_tag HAVING COUNT(*) > 1 Use an extended TRIM syntax to remove the newlines and other symbols from your data SQL Fiddle...
library(dplyr) test%>%group_by(fact,id)%>%distinct(id) ...
sql-server,duplicates,time-series,sql-delete
You can do this using a CTE and ROW_NUMBER: SQL Fiddle WITH CteGroup AS( SELECT *, grp = ROW_NUMBER() OVER(ORDER BY MS) - ROW_NUMBER() OVER(PARTITION BY Value ORDER BY MS) FROM YourTable ), CteFinal AS( SELECT *, RN_FIRST = ROW_NUMBER() OVER(PARTITION BY grp, Value ORDER BY MS), RN_LAST = ROW_NUMBER()...
Getting all the repeated elements of a vector is a costly operation (you would have to iterate for each vector element through all the rest of the vector) and won't be an "easy" way to do it (talking about iterations) but transforming into a set and back don't seem a...
One method is to use exists: select t.* from table as t where date between #2014-01-01# and #2014-12-31# and exists (select 1 from table as t2 where date between #2014-01-01# and #2014-12-31# and t2.sn = t.sn and t2.date <> t.date ); However, this will not find an sn that has...
web-services,rest,post,duplicates,idempotent
This a common problem with concurrent users. One way to solve it is to enforce conditional requests, requiring clients to send the If-Unmodified-Since header with the Last-Modified value for the resource they are attempting to change. That guarantees nobody else changed it between the last time they checked and now....
Your code would need to iterate over all elements. If you want to make sure that there are no duplicates simple method like public static <T> boolean containsUnique(List<T> list){ Set<T> set = new HashSet<>(); for (T t: list){ if (!set.add(t)) return false; } return true; } would be more efficient....
python,pandas,duplicates,dataframes,matching
This idea should work: Self join DF on c,d Apply condition of opposite values... A quick and dirty code ndf = merge(left=df1,right=df1,on=('c','d'),how='inner') out = ndf[(ndf.a_x == (-1)*ndf.a_y) & (ndf.b_x == (-1)*ndf.b_y)] Please let me know if this works...
PL/SQL isn't strictly required to find data sharing one attribute but having consecutive values on another attribute. Using your general table structure, the following will locate any transaction pair sharing the same BIZ_DATE and AMT, with adjacent TRANS_IDs. After creating and loading the table: CREATE TABLE MY_TABLE ( BIZ_DATE DATE...
php,arrays,multidimensional-array,duplicates
What about adding a count field to your result array... foreach ($reviews as $val) { if (!isset($result[$val['sku']])) { $result[$val['sku']] = $val; $result[$val['sku']]["count"] = 1; } else{ $result[$val['sku']]['rating'] += $val['rating']; $result[$val['sku']]["count"] ++; } } foreach($result as $k => $v) { $result[$k]['avg'] = $v['rating']/$v['count']; } ...
c++,osx,duplicates,x86-64,symbols
You have instantiated a Game instance in your header file "Game.h", and since this is being included in multiple files you end up with multiple instances of game at link time. Change: class Game { public: ... }game; to: class Game { public: ... }; extern Game game; and then...
You have to make a third array that handles the resultant value i.e the full name. The following example will return two arrays, duplicates array and fullnames array without duplicates: <?php $firstname = array ( "John", "Tom", "Ben", "John", "David", "Julie", "David"); $lastname = array ("Kennedy", "Hyde", "Hughes", "Harper", "Walter",...
sql-server,sql-server-2012,duplicates
Try this one: SQL Fiddle WITH CteUpdate AS( SELECT *, base = REPLACE(Name, 'x', ''), xxName = REPLICATE('x', ROW_NUMBER() OVER( PARTITION BY REPLACE(Name, 'x', '') ORDER BY ID ) + 1 ) + REPLACE(Name, 'x', '') FROM TestData WHERE REPLACE(Name, 'x', '') IN( SELECT Name FROM TestData WHERE [Update] =...
Let say your column is column A with IDs from row A2-A26, on A28 try this formula: =SUMPRODUCT((A2:A26<>"")/COUNTIF(A2:A26,A2:A26&"")) It worked for my other project. It doesn't need to create another column or table. ...
With row_number window function: with cte as(select *, row_number() over(partition by UserID, clockin, clockout order by RecordID ) as rn from TableName) delete from cte where rn > 1 ...
Include exclude 'lib/armeabi-v7a/libmp3lame.so' as well in the PackagingOption section. packagingOptions { exclude 'META-INF/DEPENDENCIES' exclude 'META-INF/LICENSE' exclude 'META-INF/LICENSE.txt' exclude 'META-INF/license.txt' exclude 'META-INF/NOTICE' exclude 'META-INF/NOTICE.txt' exclude 'META-INF/notice.txt' exclude 'META-INF/ASL2.0' exclude 'lib/armeabi-v7a/libmp3lame.so' } ...
ng <- length(V)/2 table(sapply(split(V,rep(1:ng,each=2)),paste0,collapse="&")) # -1&-1 -1&1 1&-1 1&1 # 1 1 1 1 Here is a better alternative that also uses split, following the pattern of @MartinMorgan's answer: table(split(V,1:2)) # 2 # 1 -1 1 # -1 1 1 # 1 1 1 ...
$ awk 'cnt[$0]++{$0=$0" variant "cnt[$0]-1} 1' file I am a test line She is beautiful need for speed Nice day today I am a test line variant 1 stack overflow is fun I am a test line variant 2 stack overflow is fun variant 1 I have more sentences I...
excel,vba,excel-vba,duplicates
To delete the duplicate you can just click the "Remove duplicate" button at Data Ribbon > Data Tools. Following is the demo: I have the data like this in the worksheet: I would like to have unique data at column A click the "Remove duplicate" button and following screen prompted...
java,for-loop,arraylist,duplicates,element
The last element is not being added to HM, you're adding a reference to the same list to HM. Iteration 1: HM = ["a"] Iteration 2: HM = [["a", "b"], ["a","b"]] Iteration 3: HM = [["a", "b", "c"], ["a", "b", "c"], ["a", "b", "c"]] This is easily fix by instead...
sql,select,duplicates,distinct,rows
Its a very subtle change (> vs your !=), but what you want to do is use a diagonal elimination approach, whereby you exclude any reviewer with a rid lower than the current one: SELECT DISTINCT re1.name, re2.name FROM reviewer re1 INNER JOIN rating ra1 ON re1.rid=ra1.rid CROSS JOIN reviewer...
c++,arrays,input,duplicates,output
To give you a better understanding of how to solve this, i'll try to show you what is going on via an example. Lets say you have just entered the 6 numbers you request via cin, and your a[] variable now looks like this in memory: a[] = { 5,...
Your code currently only crawls through one array (let's call it A) and pushes in all the A values that don't exist in B. You never go the other way and push in the B values that don't exist in A. There's also no need to have different behavior based...
You can use LEAD, LAG window functions in order to locate records that have been split: SELECT Name, MIN(ArrivalDate) AS ArrivalDate, MAX(DepartureDate) AS DepartureDate FROM ( SELECT Name, ArrivalDate, DepartureDate, CASE WHEN ArrivalDate = LAG(DepartureDate) OVER (PARTITION BY Name ORDER BY ArrivalDate) OR DepartureDate = LEAD(ArrivalDate) OVER (PARTITION BY Name...
java,swing,duplicates,jcombobox
Create POJO which represents the basic properties of the Piece... public class Piece { private Image image; private String name; public Piece(String name, Image image) { this.image = image; this.name = name; } public Image getImage() { return image; } public String getName() { return name; } } Add these...
Explicit function template specialisations are subject to the One Definition Rule, just as regular functions are. Add inline to allow definitions in a header; or define them in a source file, with declarations in the header.
In each iteration of your loop, when: if not(chain in line): contain+=line print(contain) since you concatenate each line in contain, when you print it, it will show you the first sentece, from the first iteration, then the first+second sentences in the second iteration, and so on. Hence the duplication. Replacing...
This should work for you: Just get your file into an array and then grab the paths out of each line. <?php $lines = file("test.txt", FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); $directorys = array_unique(array_map(function($v){ preg_match("/.*? : \[.*?\] \"(.*?)\"/", $v, $m); return $m[1]; }, $lines)); print_r($directorys); ?> output: Array ( [0] => home/club/member [1]...
python,reference,duplicates,igraph
Assign statements do not copy objects in Python. You might want to use copy.deepcopy() function. More details about copy.shallow() and copy.deepcopy() can be found in this answer Also Graph objects have inherited copy method which make deep copies. Use this code copy1 = fullGraph.copy() copy2 = fullGraph.copy() ...
sql,postgresql,exception,duplicates,upsert
The INSERT will just insert all rows and nothing special will happen, unless you have some kind of constraint disallowing duplicate / overlapping values (PRIMARY KEY, UNIQUE, CHECK or EXCLUDE constraint) - which you did not mention in your question. But that's what you are probably worried about. Assuming a...
You can use ROW_NUMBER() for this: ;WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY [First],[Last],[Title],[Grade] ORDER BY Replicate) AS UPD_Replicate FROM Table1 ) SELECT * FROM cte Demo: SQL Fiddle Or to UPDATE the field: ;WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY [First],[Last],[Title],[Grade] ORDER BY Replicate) AS UPD_Replicate FROM Table1 )...
Another option could be Proc SQL, no pre-sort needed: proc sql; create table want as select * from have group by a, b, c, d having count(*)>1; /*This is to tell SAS only to keep those dups*/ quit; ...
Try this code: . Option Explicit Public Sub showDuplicateRows() Const SHEET_NAME As String = "Sheet1" Const LAST_COL As Long = 3 ' <<<<<<<<<<<<<<<<<< Update last column Const FIRST_ROW As Long = 2 Const FIRST_COL As Long = 1 Const DUPE As String = "Duplicate" Const CASE_SENSITIVE As Byte = 1...
You want an aggregation: aggregate(B~A, df, FUN=sum) ...
Just use a pivot table: Select all the data (including headers) in columns Latitude, Longitude, and Data. Choose Insert > PivotTable. Drag Latitude and Longitude into the Row Labels section. Choose PivotTable Tools > Design > Report Layout > Show in Tabular Form and Repeat All Item Levels. Also choose...
This was something close to what you were looking forward to, by just using formula than a macro/script. Essentially done using a concatenate function and VLOOKUP. Step 1. concatenate value from your database and add it under Col A. Step 2. Use VLOOKUP as in the image and compare using...
excel,vba,excel-vba,duplicates
To change case in VBA, you have LCase and UCase, which will respectively change all of your string into lower case or upper case. Here is your code with the change and got ride of the useless (and ressource-greedy) select at the end : Sub tarheel() LastRow = Range("A10000").End(xlUp).Row +...
I'll assume that your goal is to delete certain lines from your textual input, not actually to delete the files. Like this: awk '! seen[$1]++' This reads from standard input. If the input is in a file, you can do: awk '! seen[$1]++' inputfile.txt Or, if it's the output of...