The procedure to convert from base b to base 10 is to multiply each digit in position k (from right to left, starting at 0) by b^k. I won't give away all of the answers but for 25 in base s, it is 2 * s^1 + 5 * s^0...

java,algorithm,sorting,comments,radix

I'll answer your questions in reverse order... mask = 1 << bit; Due to precedence rules, you could write this as mask = (1 << bit); Which is a bit more obvious. Take the integer 1 (0x01), shift it left by the bit position, and assign it to mask. So...

You can do it with a recursive function that takes ImplTrie and returns an int. The base case checks if ImplTrie is NULL, in which case the function returns 0. Otherwise, the function walks in a loop through children, calls itself, picks the max value, and returns the max value...

A number N in any base B is just a series of digits range [0, B-1]. Since we don't have enough symbols to represent all the digit in human writing system, don't think about how it's written in characters. You'll need to store the digits seperately For example 255 in...

c++,algorithm,radix-sort,radix

Answer The number of iterations in MSD radix depends on the input size, whereas the number of iterations in LSD radix sort depends on the key length. This often leads to MSD radix sort requiring significantly fewer iterations than LSD radix sort and is therefore faster. Memory allocations are not...

algorithm,sorting,asymptotic-complexity,radix

Assuming we use bucket sort for the sorting on each digit: for each digit (d), we process all numbers (n), placing them in buckets for all possible values a digit may have (b). We then need to process all the buckets, recreating the original list. Placing all items in the...

Binary literals (0b01010110101) have been added in C++14. Other bases aren't supported, but they can be emulated using the templated raw form of user-defined literals and constexpr. Andrzej Krzemienski describes it here: https://akrzemi1.wordpress.com/2012/10/23/user-defined-literals-part-ii/...

That's because floats are stored as binary fractions (a number divided by a power of 2), and 73/100 cannot be expressed as a non-repeating fraction in binary. Thus internally, it's storing a value close to 0.73 but not exactly equal. That's why you get so many digits in the toString()...

c++,algorithm,sorting,recursion,radix

Another update, converted to template for array type. Tmp array is now passed as a parameter. The copy steps were eliminated and a helper function added to return the buffer that the sorted data ends up in. Tested with 4 million 64 bit unsigned integers, it works but it's slow....

I believe that Numeric_Precision_Radix is specified in the Information_Schema.Columns table as specified by the SQL-99 standard. It will be different for each DBMS. according to this link it is specified as: If data_type identifies a numeric type, this column indicates in which base the values in the columns numeric_precision and...

c++,algorithm,floating-accuracy,radix

The internal representation of double is not decimal, it's already binary, and it's defined by an international standard, IEEE 754. So double is 64-bit and consists of 3 parts: the sign (1 bit), the exponent (11 bits) and the significand (52 bits). Roughly saying, this separation allows to store both...

new BigInteger(b, 16).toString(); Sample program: public static void main(String[] args) { final BigInteger original = new BigInteger("27"); final String converted = original.toString(16); final BigInteger convertedBack = new BigInteger(converted, 16); System.out.println("original = [" + original.toString() + "]"); System.out.println("converted = [" + converted + "]"); System.out.println("convertedBack = [" + convertedBack.toString() + "]");...