The first task is usually solved by applying Minkowski difference to your map and robot. This implies you know the profile of your robot. For the second task common approach is to use 2D Snap Rounding. You can find a lot of papers on that topic at scholar.google.com. However it...

1) You are setting the value of the item in array motor at index motorA to be equal to 50. 2) Multiple in-line assignments are evaluated from right to left, so this is the same as speed = 127; motor[rightMotor] = speed; motor[leftMotor] = motor[rightMotor]; ...

sockets,networking,tcp,labview,robotics

A couple of points: Did you get the provided desktop GUI working? That's always the first step. The pic is helpful, but we need to know what you are trying to send (i.e. the data). What you are trying to send should be a command from what I called the...

It is difficult to say just looking at a binary (or even assembly) code... Personally, I think they could have done two things: 1) They could be using a high-level, interpreted language (Python for example) with some library built ad hoc for their projects, so as to make data and...

There are one problematic position, where intersections of two circles (described below) has one point. In this situation (we suppose it is planar situation (gravity is perpendicular to all arm) and static situation) there isn't any force, which move with second non-controlled joint. In dynamic we choose another solution for...

c++,opencv,computer-vision,robotics

Answers in order: 1) "r" is the pixel's radius with respect to the distortion center. That is: r = sqrt((x - x_c)^2 + (y - y_c)^2) where (x_c, y_c) is the center of the nonlinear distortion (i.e. the point in the image that has zero nonlinear distortion. This is usually...

matlab,matrix,simulink,robotics,matlab-coder

You can't have the last dimension as 1 because MATLAB treats any matrix of dimension [m,n,1] as [m,n]. See size() returns 1 where matrix dimension should not exist for more details. Try defining R of size [n_robots,3,3] and then re-arrange the matrix inside your code (I assume you are using...

As far as I know there is no difference. They should all give you the same end result, but be consistent. pick one form and stick with it. The main problem comes when you are trying to reverse the process. Using method 1 to got from time t to t+1...

What you probably want is to cut your moves in increments, and check the sensors in between each of these increments: while (distance > 0 && !Obstacle){ forward(step); distance-=step; check_sensors(); } With multithreading, you could make those operations (moving and sensing) work asynchronously, and use some kind of event posting...

Technically, you can't have two sketches on one board. It's not really a different program. The switch automatically: You don't even need any extra hardware for this approach. Just turn on the pullup resistors in your board with this code: pinMode(pin, INPUT); // set pin to input digitalWrite(pin, HIGH); //...