java,arrays,sorting,round-robin

If I understand the question correctly I would restate it as "how do I obtain from a given list a new list of random and unique pairs". Let me know if that's incorrect. If so then it can be split into a few separate problems. Firstly how do you obtain...

process,operating-system,scheduler,round-robin

Your understanding is pretty close to the mark. Round robin means that the scheduler picks each process in turn. So if there are only two processes, the scheduler will pick one and then the other (assuming both are ready). As to your first question, process P2 actually gets more CPU...

Using itertools.cycle and zip: >>> num = [1,2,3,4] >>> names = ['shiva','naga','sharath','krishna','pavan','adi','mulagala'] >>> import itertools >>> for i, name in zip(itertools.cycle(num), names): ... print('{} for {}'.format(i, name)) ... 1 for shiva 2 for naga 3 for sharath 4 for krishna 1 for pavan 2 for adi 3 for mulagala ...

java,multithreading,priority-queue,java.util.concurrent,round-robin

I feel like it's more straightforward to implement this with one Queue for each producer. One thread can't wait on multiple Queues, but you could combine all of the Queues into one helper class so that it doesn't need to. import java.util.ArrayList; import java.util.Iterator; import java.util.LinkedHashMap; import java.util.List; import java.util.Map;...

Add an emailedLast column (timestamp) and when you email a lead to a rep, set it to the current timestamp (now()) Then your query to look up the next rep to email would be: select * from reps where active = 'y' order by date asc limit 1; ...

This code: PCB *pcb_temp = *pcb_head; PCB *next = (*pcb_head)->next;//get the next value since it will be the next head //store all the heads values int storepid = pcb_temp->pid; int storeat = pcb_temp->AT; int storepriority=pcb_temp->priority; int storebt=pcb_temp->BT; int storert=pcb_temp->RT; int storewt=pcb_temp->wT; needs to be done on every loop not just...

python,list,sum,sublist,round-robin

Here's a simple implementation. First, sort the input list by weight, then enumerate, adding each item to the least full bucket. def EvenlyDistribute(lst, n): """Distribute items in lst (tuples of (val, weight)) into n buckets""" buckets = [[] for i in range(n)] weights = [[0, i] for i in range(n)]...

First, your math is wrong: if there are four devices (A, B, C, and D), then the worst case time is 20*4 + 10 = 90ms. By process of elimination, though, it can't be 85, 35, or 25 (since the provided times are all multiples of 10), so the "correct"...

sql,tsql,sql-order-by,round-robin

Thanks guys for your efforts but I think I find the solution: SELECT TOP 1 [Date],[Domain] FROM ( SELECT [Date] ,[Domain], ROW_NUMBER() OVER (PARTITION BY [Domain] ORDER BY [Date]) AS recID FROM Delivery ) AS r ORDER BY recID, (CASE WHEN domain >@LASTUSEDDOMAIN THEN domain ELSE domain + (select top...

java,algorithm,cpu,scheduler,round-robin

The problem is in calculating your sum. sum = sum - (4 * 6); You subtract 24 in every iteration even if processes finish earlier(like in 1 quantum of time) or are already finished. What you should subtract from sum in every iteration is the total time spent on actual...