boolean-expression,simplification,boolean-algebra

You can first start by distributivity of multiplication over addition: !X + (!Y + !Z)*(Y + Z) = !X + !Y*Y + !Z*Y + !Y*Z + !Z*Z Then, we can use complementation to remove elements of the form !p*p: = !X + 0 + !Z*Y + !Y*Z + 0 And...

python-3.x,simplify,simplification

One of your examples is not like the others. The and form can easily be simplified: if x == 1 and y == 2 and z == 3: becomes: if (x, y, z) == (1, 2, 3): However, the or form can't be made any neater. It could be rewritten...

MariaDB applied one of the http://en.wikipedia.org/wiki/De_Morgan%27s_laws . Why do you think it is not correct?

You are right. (a*b*)* can match any string of a's and b's, so can (a U b)*, therefore they are equivalent. (a U b)* intersect a* is a* so a* is a subset of (a U b)*. Consequently, the whole expression can be simplified to (a U b)*.

javascript,import,three.js,simplification

no it does not take forever, http://jabtunes.com/labs/3d/bunny/ This is the answer to your question, edit the SimplifyModfier.js to suit your needs. I did that and it took around 80 seconds for simplifying a mesh with 25K triangles to 1K triangles. Let me know in case you need further assistance :-)...

vb.net,simplify,simplification

You can use TypeOf so as to know what Class is your object. Example If TypeOf obj Is black Then Dim m As Black = TryCast(obj, black) ElseIf TypeOf obj Is green Then Dim m As green = TryCast(obj, green) ElseIf TypeOf obj Is blue Then Dim m As blue...

android,data,firebase,simplification

This will retrieve a random message from the object you've shown in your question. function getRandomMessage(data) { if( !data ) { return null; } var keys = Object.keys(data); var randomKey = keys[ Math.floor(Math.random()*keys.length) ]; return data[randomKey]; } Keep in mind that this assumes you have a small number of records....