spring,spring-security,active-directory,ldap
Finally, the only way to solve this problem is to modify the code since the method org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider.searchForUser() is wired to pass the bindPrincipal to SpringSecurityLdapTemplate.searchForSingleEntryInternal() which actually recover the record for the user using the search filter defined in the XML or set with setSearchFilter(). Since the bindPrincipal is actually...
spring-mvc,spring-security,thymeleaf
Finally, I have found the difference with my working spring 3 project. It wasn't the spring version, it was this missing class public class SpringSecurityInitializer extends AbstractSecurityWebApplicationInitializer { } After I added it the "sec" attributes works correctly....
java,spring,spring-mvc,spring-security
"How can I check whether the user is logged or not, when he clicks on "Book now" button ? Is there any simple way to do this ?" When the submit button is pressed; the form will be posted to the URL you have given it (as a POST) example:...
rest,spring-security,spring-boot,restful-authentication,jwt
Okay - so this is pretty ridiculous, but it seems like it's an issue with the way I was invoking the request (via the POSTMAN Chrome Extension) Postman seems to fire in 2 requests, one with headers, one without. There's an open bug report describing this here : https://github.com/a85/POSTMan-Chrome-Extension/issues/615 The...
spring-security,oauth-2.0,cors,single-page-application,restful-authentication
I can just answer your questions in theory: So why is that an OPTIONS request from /oauth/token responses with 401 status even when it shouldn't? It won't let us authorize ourselves because it get's stuck at OPTIONS request in which we can't add authorization header. This is because the default...
spring,spring-security,redirect-loop
when you first access login; the user doesnt have any role(since he isnt logged in spring security yet) the login page should not restricted by role; it should be available to all user.
spring-mvc,spring-security,spring-java-config
Your domains localhost and 192.168.1.206are considered to be different origins, and you cant send ajax request from different origins without additional setup. For enabling cross origin requests in Spring MVC you should add a filter that will explicitely allow request origins, by applying the proper headers in the response, an...
That is by design. Javadoc for AbstractAuthenticationProcessingFilter is clear on that : Event Publication : If authentication is successful, an InteractiveAuthenticationSuccessEvent will be published via the application context. No events will be published if authentication was unsuccessful, because this would generally be recorded via an AuthenticationManager-specific application event. (emphasize mine)...
java,spring,security,spring-mvc,spring-security
First of all. Taking password from database from server side application is not vulnerable. Because if you can access the table data then there is no use of it. Wrong concepts - Spring security is not about returning result code from database. Its about authentication and authorization. You can enable...
java,spring,jsp,spring-mvc,spring-security
I did ROLES and OPERATION in my Application. Look at this answer, it helped me: Difference between Role and GrantedAuthority in Spring Security Basically what the article said is there is no difference between roles and permissions both are granted authorities and need to be placed in top of the...
java,spring,session,spring-security
Well after days of looking how to do it. Reading the documetation and everything. I found my answer. In my jsf page i put this code <meta http-equiv="refresh" content="${session.maxInactiveInterval}"/> Then I modify my springsecurity.xml <session-management invalid-session-url="/index.html" /> ...
java,spring,grails,spring-security,spring-annotations
The spring Security has an default UserDetailsService, which assigned the Roles to an User. You could debug it to see what going wrong. Or You create your own: https://grails-plugins.github.io/grails-spring-security-core/guide/userDetailsService.html HTH...
spring,security,spring-security,basic-authentication,postman
Use the standard exception of spring security, it will handle by itself if you already have an exception handler to transform the messages into Json response. catch (Exception exception) { throw new AuthenticationCredentialsNotFoundException("Fields must not be empty", exception); } ...
spring,spring-security,spring-boot
If you use basic authentication, the browser stores the authentication until you close it (or exit the incognito mode, if you used it). There is no possibility to delete the session on server side, since the browser would just reauthenticate. If you want to be able to logout, use form...
testing,spring-security,jhipster
In my project, I have a repository that uses #{principal.username} in one of its queries. Here's what it looks like: public interface BlogRepository extends JpaRepository<Blog, Long> { @Query("select blog from Blog blog where blog.user.login = ?#{principal.username}") List<Blog> findAllForCurrentUser(); } My BlogResource controller calls this as follows: @Timed public List<Blog> getAll()...
spring,spring-security,spring-boot
Do not encode the password in the set method of your Entity. you only need to do this on creat new user . Spring security will deal with the rest
The problem was in the program I tested my service with. The program was SoapUI 5.1.3.
java,spring,oauth,spring-security,spring-security-oauth2
I found the "solution". There was a version mismatch in my pom files. While my auth server was running spring-security-oauth2-2.0.5.RELEASE my resource server was running spring-security-oauth2-2.0.7.RELEASE . The versions declare the response differently. ...
java,spring,spring-mvc,spring-security
According to the docs, the logout URL ins Spring Security 4 is just /logout, so it should work if you change your form action. I would also drop the auto-config attribute and just set what you want to use explicitly, following the examples in the manual....
spring,spring-security,spring-session
Both your ContextLoaderListener and DispatcherServlet are loading the same configuration. This results in loading your whole application twice, which in turn leads to your Spring Security using a different SessionRegistry instance then your controller, the latter is always going to be empty. You should split your configuration in one that...
java,spring,spring-mvc,spring-security
When using Spring Security with Java based configuration the name of the request parameters are username and password and not j_username and j_password anymore. You can either fix your login form <form action="/login/process" method="POST"> <input name="username" id="j_username" type="text" /> <input name="password" id="j_password" type="password" /> <input type="submit" value="Login" /> </form> or...
java,spring,authentication,spring-security,ldap
Finally I found the solution. in the spring-security.xml, I remove the configuration <security:ldap-authentication-provider group-search-filter="member={0}" group-search-base="ou=groups" user-search-base="ou=people" user-search-filter="uid={0}" /> ...
The container will only create a single instance of the filter, so having any mutable instance variables is not thread safe. Any concurrent request can cause inconsistent state for your instance variable. You should look into HttpSession. In response to comment: It's not so much that you have to use...
spring,filter,exception-handling,spring-security,spring-boot
As specified by the java servlet specification Filters execute always before a Servlet is invoked. Now a @ControllerAdvice is only useful for controller which are executed inside the DispatcherServlet. So using a Filter and expecting a @ControllerAdvice or in this case the @ExceptionHandler, to be invoked isn't going to happen....
java,spring-mvc,spring-security
You have changed the username parameter and password parameter in security config. But in form you are using the default one. change the name of inputs in your form to "username" and "password" and check it again.
grails,spring-security,spring-boot,bcrypt,grails-3.0
I have the following code in grails-app/conf/spring/resources.groovy import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder beans = { bcryptEncoder(BCryptPasswordEncoder) } and I have a java file which does the configuration as described by spring-security. It should be possible to do it in groovy too, but I did it in java. import org.springframework.beans.factory.annotation.Autowired; import org.springframework.context.annotation.Configuration; import...
java,spring,spring-security,ldap,remember-me
From the Spring Docs Remember-Me If you are using an authentication provider which doesn't use a UserDetailsService (for example, the LDAP provider) then it won't work unless you also have a UserDetailsService bean in your application context. Try adding below in your applicationContext.xml:- Add RoleVoter. From Spring Docs Votes if...
spring-security,saml,spring-saml
There is no standard SAML WebSSO mechanism which would allow SP to request assertion for a specific user by providing her credentials. You might want to look into WS-Trust standard which covers such use-cases using its Request security token methods (RST/RSTR calls). Another quite standardized way to do this is...
I think you need have only one xml configuration file (my-servlet.xml as your servlet name is "my" so filename must be "my-servlet.xml") in web-xml and then refer others in that file. Refer to xmls below. <xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0"> <listener>...
java,spring-security,spring-boot
Try to add the @Configuration annotation to your Application class @Configuration @ComponentScan (basePackages = { "com.test" }) @EnableAutoConfiguration(exclude = {MetricFilterAutoConfiguration.class, MetricRepositoryAutoConfiguration.class}) @Domain(basePackages = { "com.test.domain" }) public class Application { //some code } ...
java,logging,spring-security,spring-boot,dependency-management
i figured out compile("org.springframework.boot:spring-boot-starter-security"){ exclude module: "spring-boot-starter-logging" exclude module: "logback-classic" } compile("org.springframework.boot:spring-boot-starter-thymeleaf"){ exclude module: "logback-classic" } ...
You can use the isAuthenticated either in xml format or annotation format: xml spring configuration: <intercept-url pattern="/pattern/page.html" access="isAuthenticated()" /> Annotation: @PreAuthorize("isAuthenticated()") ...
rest,spring-mvc,gradle,spring-security,thymeleaf
Yes you can do both have REST controllers, and also have other controllers that serve up Thymeleaf pages.
java,spring,spring-mvc,spring-security,spring-boot
This appears to work but seems significantly heavier, so maybe their's a lighter/faster answer? I added @SpringBootApplication public class Application { } and loaded it, as well as adding @WebAppConfiguration and my WebSecurityConfig classes, @RunWith( SpringJUnit4ClassRunner.class ) @WebAppConfiguration @SpringBootApplication @SpringApplicationConfiguration( classes = { MockServletContext.class, HttpSessionConfig.class, WebSecurityConfig.class, Application.class } ) public...
Here's a working sample code from Spring Security OAuth github. https://github.com/spring-projects/spring-security-oauth/tree/master/tests/annotation/jwt You probably don't even need to mess with the filters as shown in the above example. If you've custom needs, please post some sample code....
You're trying to query a list of items that a user may not be the owner of but should be able to access anyways, yes? Like shared documents or some-such. If that is the case, you need to upgrade to Spring Security 4 . It allows for SpEL expressions with...
spring,authentication,spring-security,crud
Simple. Authentication auth = SecurityContextHolder.getContext().getAuthentication(); String username = auth.getName(); Object credentials = auth.getCredentials(); To access the credentials, i.e. the password, you need to set erase-credentials to false: <security:authentication-manager erase-credentials="false"> ... </security:authentication-manager> ...
spring,spring-security,spring-boot
Well, I figured this thing out, and I feel kind of like an idiot. For posterity, here was my actual issue: I had created a login form and logout process using the following code: .formLogin() .loginProcessingUrl("/login") .loginPage("/auth") .defaultSuccessUrl("/") .permitAll() .and() .logout() .logoutUrl("/logout") .logoutSuccessUrl("/") .invalidateHttpSession(true); .permitAll() What I didn't realize was...
The problem was an incompatibility between my version of Spring and the JDK. I used Spring 3.2 and JDK 1.8. When I changed to JDK 1.7, everything worked fine.
spring,spring-mvc,spring-security
It was silly mistake. Problem was with url url/resources/login that I was posting to authenticate the resource. It should be url/j_spring_security_check. As filterProcessUrl set inside UsernamePasswordAuthenticationFilter is <beans:property name="filterProcessesUrl" value="/j_spring_security_check" />. Anything other than this URL will reflect to entry-point-ref tag. My client is android app, posting request with HttpUrlConnection....
spring,spring-security,oauth-2.0,spring-security-oauth2
As "AuthorizationCodeResourceDetails" which is based on auth2 "authorization_code" flow doesn't accept extra parameters. Therefore, to fix this I did workaround by providing the parameter in the authorization url itself. For eg. if the authorization url is http://localhost:8080/idp/oauth/authorize than I have appended my extra parameter to that url like following http://localhost:8080/idp/oauth/authorize?startPoint=register...
angularjs,spring-security,popup,basic-authentication,www-authenticate
Extend default ExceptionTranslationFilter that returns an HTTP 401 for all ajax requests instead of a basic authentication challenge: package mypackage; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.AuthenticationException; import...
java,maven,servlets,spring-security
Just add the javax.servlet API to the compile time dependencies. You don't need to include it in the build, it's already provided by the target servlet container. Your current pom suggests that you're deploying to a barebones servlet container (Tomcat, Jetty, etc) instead of a full fledged Java EE application...
spring,spring-mvc,spring-security,spring-boot
According to the Spring Guide: Building a RESTful Web Service A key difference between a traditional MVC controller and the RESTful web service controller above is the way that the HTTP response body is created. Rather than relying on a view technology to perform server-side rendering of the greeting data...
spring,spring-security,spring-boot
There are 2 things flawed in your setup. You should post to /login instead of /j_spring_security_check as that is the new URL when using java config (and in Spring 4 for XML config also). You have set the usernameParameter to name and your form still has username. Fix those flaws...
java,spring-mvc,spring-security
I have similar "requirements" as you and for my it is working fine. My setup is as follows @Configuration protected static class AuthenticationConfiguration extends GlobalAuthenticationConfigurerAdapter { @Autowired private UserDetailsService userDetailsService; @Autowired private PasswordEncoder passwordEncoder; @Override public void init(AuthenticationManagerBuilder auth) throws Exception { auth.userDetailsService(userDetailsService).passwordEncoder( passwordEncoder); } } My guess is that...
java,spring,spring-mvc,spring-security,csrf
You seem to have upgraded Spring Security to 4.x as well (evidenced by xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-4.0.xsd). Unfortunately, Spring Security 4.x is not a drop-in replacement for 3.x. You will need to review the Official Migration Guide for configuration elements that need to be tweaked. However, some of the ones that stand...
facebook,grails,spring-security,spring-social
The documentation for the 'email' field of the 'user' object ( https://developers.facebook.com/docs/reference/api/user/ ) clarifies the expected behaviour here, which is: "this field will not be returned if no valid email address is available" There is a detailed explanation about different situations where an email won't be sent. Please check it...
spring,spring-mvc,tomcat,spring-security,spring-boot
Got it working! Spring Security docs ( http://docs.spring.io/spring-security/site/docs/3.1.x/reference/security-filter-chain.html ) say: "Spring Security is only interested in securing paths within the application, so the contextPath is ignored. Unfortunately, the servlet spec does not define exactly what the values of servletPath and pathInfo will contain for a particular request URI. [...] The...
java,spring-mvc,file-upload,spring-security
I got the answer by changing public ModelAndView addbanners(@ModelAttribute Banner banner,@RequestParam("file") MultipartFile file) to public ModelAndView addbanners(@ModelAttribute Banner banner,@RequestParam("uploadBanner") MultipartFile file) and change <form:input name="uploadBanner" type="file" id="uploadBanner" path="bannerImage"/> to <input name="uploadBanner" type="file" id="uploadBanner" path="bannerImage"/> and thank you @Akash Rajbanshi to help me to find my mistake....
It's actually a problem with my current firefox browser. Even if I remove all the navigation and cache data, it keeps happening, but not with other browsers as Chrome or IE, not even with other FF browsers.
I suspect something is wrong in your CustomWebSecurityExpressionHandler. Did you forget to set an AuthenticationTrustResolver?...
java,spring,jboss,spring-security,wildfly
Since this question is a bit tough, I assume you are already familiar with the Spring Security Kerberos samples that show how to configure kerberos auth with a form auth as fallback. I have no evidence that it'll work but I think you should be able to chain your kerberos...
spring-security,spring-java-config
The solution is to mimic the good old namespace way of having multiple <http ...> blocks. With Java configuration, you can also have multiple classes extending WebSecurityConfigurerAdapter. Spring Security Reference Manual has an example for that. Extracts : @EnableWebSecurity public class MultiHttpSecurityConfig { @Autowired public void configureGlobal(AuthenticationManagerBuilder auth) { 1...
java,spring,spring-mvc,spring-security,tiles-3
I would highly suggest you to follow either Java or XML config. I personally prefer Java config. Remove all Spring Security related XML configs and create following files. Amend the permission addresses to whatever you have. public class MessageSecurityWebApplicationInitializer extends AbstractSecurityWebApplicationInitializer { //register the springSecurityFilterChain with the war } public...
java,spring,spring-security,openid-connect
The jwtstore configuration was causing an issue with the spring security configuration.Moved the relevant code to another class and it got working.
grails,spring-security,geb,remote-control
Put Below code in your config.groovy grails.plugin.springsecurity.securityConfigType = 'InterceptUrlMap' grails.plugin.springsecurity.interceptUrlMap = [ '/grails-remote-control/**': ['IS_AUTHENTICATED_ANONYMOUSLY'] ] ...
spring,spring-security,spring-security-oauth2,spring-security-ldap
As advised by Dave Syer, I created a custom LdapUserDetailsService. The working solution can be found under the following tag. Application Context <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd...
spring,authentication,spring-security,spring-boot
hyness answer worked if I changed: .. .antMatchers(managementContextPath + "/**").hasRole(ADMIN_USER) .antMatchers("/**").hasRole(API_USER) to .. .requestMatchers(request -> !request.getContextPath().startsWith(managementContextPath)).hasRole(API) .antMatchers("/**").not().hasRole(API) .antMatchers(managementContextPath + "/**").hasRole(ADMIN) ...
From the spring-security documentation: isAuthenticated() Returns true if the user is not anonymous isFullyAuthenticated() Returns true if the user is not an anonymous or a remember-me user So fullyAuthenticated() only validates if the extra spring-security 'remember-me' feature is applied in addition to the user being successfully authenticated/logged-in...
Ensure that you have something like <filter> <filter-name>springSecurityFitler</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSeurityFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> in your web.xml descriptor file. See http://docs.spring.io/spring-security/site/docs/4.0.x/reference/html/security-filter-chain.html for more info. Also...
spring-security,saml-2.0,spring-saml
The secret to figure all this stuff out is to look at the sample apps context files and paste in everything, then remove the stuff you don't need. There is a ton of stuff in the sample app that isn't mentioned in the docs. I was able to get it...
spring,spring-mvc,spring-security,spring-session
If the only thing you need is the full name just use an AuthenticationSuccessHandler to retrieve the user and add the name to the session (or the full user if you need more then that). @Override public void onAuthenticationSuccess(HttpServletRequest req, HttpServletResponse res, Authentication auth) throws IOException, ServletException { User user...
java,spring,spring-security,spring-boot,basic-authentication
It's probably CSRF, which spring security enables by default. Look for a X-XSRF-TOKEN header in your GET request, and use that header and value in your POST. Think twice before you do this, but you can disable csrf with http.csrf().disable() http://docs.spring.io/spring-security/site/docs/current/reference/html/csrf.html...
java,c#,winforms,spring-mvc,spring-security
Authentication can be setup in many ways with Spring Security. For example: <http pattern="/webservice/**" create-session="stateless" realm="TestRealm"> <http-basic/> <intercept-url pattern="/**" access="ROLE_USER"/> </http> Then it is as simple as this to authenticate from C#: var request = (HttpWebRequest)WebRequest.Create(url); request.Credentials = new NetworkCredential(username, pwd); ...
Yes, you can provide a custom bean that implements the RestAuthenticationSuccessHandler. Take a look at the API documentation for the class to see what you need to implement. Then it's as simple as overriding the bean in your application context: // Resources.groovy restAuthenticationSuccessHandler(MyCustomRestAuthenticationSuccessHandler) { renderer = ref('accessTokenJsonRenderer') } It might...
spring,spring-security,saml-2.0,spring-saml
Your IDP is re-using information that user has authenticated earlier (at time identified by Authentication Instant) and Spring SAML is by default configured to not let user login if she's been authenticated more than 7200 seconds ago. It's a security measure - if it's a long time ago since the...
spring,authentication,spring-security,ldap,spring-ldap
I've finally figured it out from this post. I still don't know how to set the group filters, but at least now I can bind to the server. @Bean public ActiveDirectoryLdapAuthenticationProvider activeDirectoryLdapAuthenticationProvider() { ActiveDirectoryLdapAuthenticationProvider provider = new ActiveDirectoryLdapAuthenticationProvider("pop.corp.local", "ldap://tcp-prd.pop.corp.local:389"); provider.setConvertSubErrorCodesToExceptions(true); provider.setUseAuthenticationRequestCredentials(true); return provider; } @Bean public LoggerListener...
spring,spring-security,integration,spring-data
We have a similar use case in our spring-data-examples: @Query("select o from BusinessObject o where o.owner.emailAddress like ?#{hasRole('ROLE_ADMIN') ? '%' : principal.emailAddress}") List<BusinessObject> findBusinessObjectsForCurrentUser(); In your case you could try something like that (in the context of the mentioned spring-data-examples project) The repository method: @Query("select o from BusinessObject o where...
java,spring,spring-security,spring-data-rest
If you are using Spring security integration you can use ACL (maybe to heavy) or simple postFilter like following: public interface ShoppingItemRepository extends CrudRepository<ShoppingItem, Long> { @PostFilter("filterObject.user.getId() == principal.id") @Override Iterable<ShoppingItem> findAll(); } ...
java,spring,jsp,spring-mvc,spring-security
I just solved my question. Just changed the url pattern of the form in above jsp page. I changed it as action='/flight-demo/flight-reservation.html'. In here flight-reservation.html is the page that needed to be redirected after I logged in to the system. I have already created this jsp file. No need to...
Found a solution here. It seems to be that Spring Security brings wrong (old) dependencies with itself. The solution I've found completely resolved the problem. ...
java,spring,spring-mvc,spring-security,tiles
Change <filter-name>SpringSecurityFilterChain</filter-name> to <filter-name>springSecurityFilterChain</filter-name> in both filter-name tags...
java,spring,spring-security,spring-security-oauth2
The client needs authorizedGrantType "refresh_token". Try this @Override public void configure(ClientDetailsServiceConfigurer clients) throws Exception { clients.inMemory() .withClient("resource-serv") .scopes("read") .resourceIds("my-resource") .secret("secret123") .and() .withClient("app") .authorizedGrantTypes("client_credentials", "password", "refresh_token") .scopes("read") .resourceIds("my-resource") .secret("appclientsecret"); } ...
It completely slipped my mind that the allowed roles are listed in web.xml as well for j2ee container authentication to work. So any user without a least one of those roles was just being rejected by the container. Otherwise the first, simplest, method works fine. Hopefully my mistake will help...
javascript,jsp,security,browser,spring-security
On successful login put some value in sessionStorage.setItem('userId',userId) and when ever user open new tab and tries to login check if sessionStorage.getItem('userId') is available if null it means it is a new tab / redirect to login page. Session storage is tab specific and data are not shared between different...
As it is for Spring Security, I think that the simplest way is to use spring security to restrict /logout to authenticated users. Using the namespace it would be : <intercept-url pattern="/logout" access="IS_AUTHENTICATED_REMEMBERED"/> Using Java configuration, it would be : protected void configure(HttpSecurity http) throws Exception { http .authorizeRequests() .antMatchers("/logout").authenticated()...
spring,security,spring-security,spring-boot
Actually i manage to find a solution to my issue. I added successHandler on successfulAuthentication was missing ! And a failureHandler too on unsuccessfulAuthentication methods. Here is my new Authentication filter : public class TwoFactorAuthenticationFilter extends UsernamePasswordAuthenticationFilter { private static final String LOGIN_SUCCESS_URL = "{0}/bleamcards/{1}/home"; private static final String LOGIN_ERROR_URL...
java,spring,spring-mvc,spring-security
When using permitAll it means every authenticated user, however you disabled anonymous access so that won't work. What you want is to ignore certain URLs for this override the configure method that takes WebSecurity object and ignore the pattern. public void configure(WebSecurity web) throws Exception { web.ignoring.antMatchers("/api/v1/signup"); } And remove...
spring-security,cors,jwt,spring-security-oauth2
Found the reason for my Problem! I just needed to end the filterchain and return the result immediatly if a OPTIONS request is processed by the CorsFilter! SimpleCorsFilter.java @Component @Order(Ordered.HIGHEST_PRECEDENCE) public class SimpleCorsFilter implements Filter { public SimpleCorsFilter() { } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws...
The final solution based on the remarks provided by the people in this post, is that it is not possible to use HTTPBasicConfigurer with XML configuration. But there are other ways to perform almost the same thing that is implemented now in HTTPBasicConfigurer. My final solution used is mainly based...
I'm answering my own question here. I've solved the problem by using a HandlerInterceptorAdapter. I'm not sure it is the most Spring-idiomatic way to achieve the result, but it's good enough for me. public class MvcPreAuthorizeAnnotationCheckerInterceptor extends HandlerInterceptorAdapter { final HandlerMethod hm; if (handler instanceof HandlerMethod) { hm = (HandlerMethod)...
You cannot do that because ant matchers and @PreAuthorize work at different level. The ant matchers works at http security level. Spring security filter looks at the request, and if it find that access should be denied, it does not even pass the request to the dispatcher servlet, and directly...
java,spring,spring-mvc,spring-security,spring-boot
You can configure your TestApplication to include just the beans that you would like to test. In other words, make sure that your WebSecurityConfig is not part of the test configuration. If you read the javadoc of @SpringBootApplication you will notice that it is a composite annotation that consists of...
spring-security,spring-java-config
You got the postprocessor on the wrong object. Please rewrite the post processor with the following .anyRequest().authenticated().withObjectPostProcessor(new ObjectPostProcessor<FilterSecurityInterceptor>() { public <O extends FilterSecurityInterceptor> O postProcess( O fsi) { FilterInvocationSecurityMetadataSource newSource = new MyFilterSecurityMetadataSource(); fsi.setSecurityMetadataSource(newSource); return fsi; } }) ...
java,spring-mvc,spring-security,integration-testing
In the Spring security Reference, section 10.1 states that in order to be able to test the spring security features, you need to integrate the security filter chain in your MockMvc object, as shown in this example in the @Before setup method. import static org.springframework.security.test.web.servlet.setup.SecurityMockMvcConfigurers.*; @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration @WebAppConfiguration public class...
spring,authentication,spring-security,authorization,intercept
<security:intercept-url pattern="/**" access="hasRole('enabled') and hasRole('view')" /> ...
java,spring,spring-mvc,spring-security,spring-bean
I managed to solve it! I just had to add an encoder bean to authenticationProvider: <beans:bean id="encoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"/> <beans:bean id="authenticationProvider" class="com.setelog.spring.handler.LimitLoginAuthenticationProvider"> <beans:property name="userDetailsService" ref="customUserDetailsService" /> <beans:property name="userDetailsDao" ref="userDetailsDao" /> <beans:property name="passwordEncoder" ref="encoder" />...
I am posting my solution thanks a lot for your help. This approach is simple and easy you just need to call the logout method from your request variable from your logout controller. def roles = SpringSecurityUtils.getPrincipalAuthorities() for (String role in roles) { if (role.equals("ROLE_ADMIN")) { request.logout() redirect uri :...
java,spring,spring-mvc,spring-security
I had the same problem, this was the solution for me: @Override protected void configure(AuthenticationManagerBuilder authManagerBuilder) throws Exception { ... .userDetailsService(userDetailsService()); ... } The problem where the brackets after userDetailsService - removed them and it works as expected. From your code snippet I can't be sure where you get the...
java,spring-mvc,spring-security
Finally after help from java_dude and SergeBallesta I got the resolution for my query. After a lot of debug I saw that when isPasswordValid method was getting called inside DaoAuthenticationProvider class instead of calling method 1 it was calling method 2 from org.springframework.security.authentication.encoding.PlaintextPasswordEncoder which one is depreciated and on second...
mysql,spring-security,spring-boot,thymeleaf
Lets take a step back focus on restless state first. For your form use this: <form th:object="${goal}" th:action="@{/addGoal}" method="post"> <div> <label> Enter Minutes : <input type="text" th:field="*{minutes}" /> </label> </div> <div> <input type="submit" value="Submit" /> </div> </form> Next change: @RequestMapping(value = "addGoal", method = RequestMethod.GET) public String addGoal(Model model, HttpSession...
spring,spring-mvc,spring-security
I believe that the problem is in the order of your rules: .antMatchers("/admin/**").hasRole("ADMIN") .antMatchers("/admin/login").permitAll() The order of the rules matters and the more specific rules should go first. Now everything that starts with /admin will require authenticated user with ADMIN role, even the /admin/login path (because /admin/login is already matched...
java,spring,spring-mvc,spring-security
I can explain you via XML files and some Java code. Here is how I do login and assign the role. You can also query the DB for roles. security-applicationContext.xml : <security:authentication-manager alias="authenticationManager"> <security:authentication-provider user-service-ref="LoginServiceImpl"> <security:password-encoder ref="encoder"/> </security:authentication-provider> </security:authentication-manager> <beans:bean id="daoAuthenticationProvider"...
spring-security,spring-boot,spring-ws,ws-security
Ok I figured this out so though I would post for anyone trying this in the future. I resolved this problem by changing my spring boot class to: @SpringBootApplication @EnableGlobalMethodSecurity(securedEnabled = true) public class SwitchxApplication extends WebMvcConfigurerAdapter { @SuppressWarnings("unused") private static final Logger log = LoggerFactory.getLogger(SwitchxApplication.class); @Bean public ApplicationSecurity applicationSecurity()...