If you search a bit, you find that the maximum range is RAND_MAX, an implementation defined value guaranteed to be at least 32767.

That is what you get for using deprecated random number generation. rand produces a fixed sequence of numbers (which by itself is fine), and does that very, very badly. You tell rand via srand where in the sequence to start. Since your "starting point" (called seed btw) depends on the...

Within the glibc sources for srandom_r (which is aliased to srand), line 179: /* We must make sure the seed is not 0. Take arbitrarily 1 in this case. */ if (seed == 0) seed = 1; It's just an arbitrary decision basically....

c,random,pthreads,srand,usleep

"putting the code: srand(timeDelay) in a for loop". You don't put srand() in a loop. You call it once at the beginning of your program, typically with a time argument, so the random sequence you get from rand() is different each time you run the program. #include<stdio.h> #include<stdlib.h> #include<time.h> int...

You should call srand(time(NULL)); only once.

Well, your problem here is due to multiple way of making random numbers in C with the standard libraries. Basically, there is two sets of functions to generate a random number : From the rand(3) manual: #include <stdlib.h> int rand(void); int rand_r(unsigned int *seedp); void srand(unsigned int seed); From the...

Just use a hash function. A classic is hash_pjw, unsigned hash_pjw (const void *str) { const char *s = str; unsigned int g, h = 1234567u; while (*s != 0) { h = (h << 4) + *s++; if ((g = h & (unsigned int) 0xf0000000) != 0) h =...

c++,random,integer,srand,time.h

If you create the numbers in A as a vector, there is an algorithm header with sort, so somthing like: #include <vector> #include <algorithm> int main() { std::vector<int> numA(5); srand( time(NULL) ); for( unsigned int i(0); i < numA.size(); ++i ) numA[i] = (rand()%49+1); //After you create the vector and...

Notice your first for loop: for(i<0;i<28;i++) And notice your: res = rand() % 27; ... should be 28. The range of % N is 0 to (N-1), hence your 27 results with the range 0-26....

You declare a[25] but you access any of 26 elements since n=rand()%26;, so declare instead int i=0,n,a[26]={0},b[26]={0},cntr=0; BTW, compile with all warnings and debug info (e.g. gcc -Wall -Wextra -g). Then use the debugger (gdb). A watchpoint would have helped....

There are several approaches. For example you can use standard algorithm std::random_shuffle declared in header <algorithm> For example #include <algorithm> #include <iterator> //... int main() { int a[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; std::random_shuffle( std::begin( a ), std::end( a ) ); for...

x == y may result in 0 or 1, depending on their true or false value. Then 0 or 1 is compared with z, this why the given result is false. The correct method is to check if x equals z and y equals z, which of course also means...

Your problem is on every "if", you're doing an assignation, not a test. Moreover, in a test an assignation will always return the result of the assignation. For example: if (x = 0) // will never be here because 0 is false in a test else if (x = 42)...