strlen code not working
You have not allocated any memory for str. Declare a buffer, for example char str[50], but be aware of buffer overflows.
What is the purpose of strlen($query)-2;
This is what those functions do exactly: substr() is used to generate a sub-string of specified length from another string. strlen() will return the length of the provided string. Code substr($query,0,strlen($query)-2) removes comma and space from foreach Loop....
difference between sizeof and strlen in C linux
Because the contents of frame is not initialized, which means it is not a valid C string, so strlen(frame) could return any value, or crash. Actually, its behavior is undefined in this case. Because frame is an array of 20 characters, therefore sizeof(frame) will return 20 * sizeof(char), which...
how does strlen count unicode in c
strlen() counts number of bytes until a \0 is encountered. This holds true for all strings. For Unicode, note that the return value of strlen() may be affected by the possible existing \0 byte in a valid character other than the null terminator. If UTF-8 is used, it's fine because...
why is -1>strlen(t) true in C? [duplicate]
Anyone got an idea what i'm doing wrong strlen() returns a size_t, which is an unsigned integer type. -1 interpreted as an unsigned integer is a large value, so it ends up being greater than the length of your string. You can use the -Wsign-compare flag in gcc and...
Why is strlen slower when I return its results from a method?
If the compiler can determine that the result of a function like strlen will only be used in certain ways, it may substitute other code which will be sufficient for such purposes. For example, if code were to say if (strlen(p) >= 2) ... a compiler could legitimately substitute if...
Need to Evaluate strlen of an XML
Im not sure what you want to achieve,anyway if you want to get the lenght of the string that represents the xml, you can do it like this: $xml = simplexml_load_file("feed-url-here"); if ($xml != "") { if (strlen($xml->asXML()) > 600) { perform some actions here; } } ...
How to count length of string in bytes with unicode characters of more than 1 byte?
What do you mean by unicode? If it's UTF-8 (dirent.h is a part of POSIX API, so it should be UTF-8), it can't contain '\0' in the middle. strlen will do exactly what you need. If you are using some non-standard version of dirent (maybe some strange port for Windows)...
segmentation fault while calling strlen with a previously allocated pointer
c,pointers,char,segmentation-fault,strlen
strlen() will dereference a pointer, which may cause some problems when this pointer,i.e optarg, is not valid. For example, in case of optarg=NULL and c='f', your code will be executed as: case 'f': wfiles = optarg; //Now wfiles=NULL strlen(wfiles) will be: strlen(NULL) and segmentation fault happens. See this related question...
C: Count letters until specific entry inserted
Remove \n from first scanf() scanf("%s\n", word); #---------^ Thanks to @remyable, \n has different meaning in scanf() - not the one you are expecting here to read newline. Refer C-faq 12.17 Also, checking for input for more than 50 chars that is not correct. You would get into buffer overrun....
Time limit exceeded error when using strlen()? [duplicate]
c,segmentation-fault,strlen,time-limiting
char s[1000001] Depending on OS, this might be too large for the stack. You should either allocate that dynamically using malloc() or at file-scope. Even if the stack is large enough, it is not good practice to have such large arrays on the stack. Apart from that: strlen() is evaluated...
strlen returning wrong value
You are not copying the nul terminator, a c string needs a '\0' at the end, so if it has 4 characters it uses 5 bytes, the last one being '\0' which is not copied in your loop. You should however use strcpy() instead of copying they bytes one by...
strings don't function properly
You have to reset found in each iteration of the while loop. Also you have to exit loop for(i = 0; i < strlen(token); i++){ if((token[i] >= '0') && (token[i] <= '9')) found++; //If found a number } if a digit was found in the string. This loop could be...
Segmentation fault while using printing output of strlen in C++ 4.8.1 [closed]
You need to initialize str by allocating space for it: char *str = (char *)malloc(SIZE); Otherwise it will invoke undefined behavior. Also, declare l of size_t type because strlen returns type is size_t and change %d to %zu in printf...
warning: incompatible implicit declaration of built-in function 'strlen' and 'strcpy' [duplicate]
You need to use #include <string.h> to get strcpy() and strlen()...
Sizeof and Strlen
strlen is going to walk down the pointer you gave it and count the number of bytes until it reaches a null byte. In this case, your char array of 8 bytes has no null bytes, so strlen happily continues past the boundary into a region of memory beyond the...
Counting the characters of all my posts
This should do it. <?php $total = 0; foreach($posts as $post) { $total += strlen($post->post_content); } echo $total; ...
PHP if only 1 character - Get All Days In a Year
Untested: <?php function daysInMonth($year) { $dates = array(); for($i = 1; $i <= 12; $i++) { $num = cal_days_in_month(CAL_GREGORIAN, $i, $year); for($a = 1; $a < $num+1; $a++) { $dates[] = sprintf('%02d%02d%04d', $i, $a, $year); } } return $dates; } $datesInYear = daysInMonth(2014); This uses sprintf() to handle the formatting...
Writing to a char array after fgets call causes it to be empty according to strlen
c,variable-assignment,fgets,strlen
You have char choice[1]; but then you call fgetsTrim(choice, 2). That then calls fgets(choice, 2, stdin) causing a buffer overflow (and thus undefined behaviour). To fix this, make choice bigger. However your code has a lot of magic numbers in it. Use sizeof where possible, and use #define constants in...
Count number of chars excluding \n [closed]
use this first replace all new line character by null and than count length. echo strlen(str_replace(array("\n", "\r\n", "\r"), '', $string)); ...
Wondering if this would work as a single if() statement [closed]
You should make two different statements if you want to show two different error messages, for example: if ($password != $password_confirm) { $error_register = 'Passwords do not match'; } elseif (strlen($password) < 8) { $error_register = 'Password is under less that 8 characters'; } else { //finish inserting user into...
How does strlen giving the same output for {'1','1'} and {'1','1','\0'}?
The former is undefined behavior; it could output 2, it could also output 500, terminate your program or destroy your computer.
Input returns the correct string but doesn't run the function
c,string,malloc,getline,strlen
In your code, you need to change char *cm = (char*)malloc(strlen(cmd)); to char *cm = malloc(strlen(cmd) + 1); to have space for terminating null character. The strlen() does not count the terminating null and if you don't allocate memory for holding the null during copying, you'll be facing memory overrun...
C - Reading strings from a text file and arranging them by size
fgets() does not read C strings. It reads chars until encounters a '\n' ( or EOF condition, or IO error or the buffer is nearly filled). Then it appends a '\0' to the buffer, making the buffer a C string. After calling fgets(), good to check its return value -...
strlen() shows wrong character when trim the title wordpress
php,wordpress,character-encoding,char,strlen
For unicode characters you need to use mb_strlen() and mb_substr() Rewrite the above line to $title = (mb_strlen($title,'utf-8')<60) ? $title : mb_substr($title,0,50,'utf-8')."..."; ...
Remove array element based on its character length
php,arrays,unset,strlen,array-unset
You can simply use it using array_filter only along with strlen $array = array("Linda","Chadwick","Bari","Angela","Marco"); $result = array_filter($array,function($v){ return strlen($v) > 4; }); print_r($result); $result = array(); array_walk($array,function($v) use (&$result){ if(strlen($v) > 4){$result[] = $v;} }); print_r($result); array_filter array_walk...
Does strlen() always correctly report the number of char's in a pointer initialized string?
What strlen does is basically count all bytes until it hits a zero-byte, the so-called null-terminator, character '\0'. So as long as the string contains a terminator within the bounds of the memory allocated for the string, strlen will correctly return the number of char in the string. Note that...
How to determine if a byte is null in a word
From the famous "Bit Twiddling Hacks" page By Sean Eron Anderson, a description of what is currently used in the glibc implementation you're referring to (Anderson calls the algorithm hasless(v, 1)): The subexpression (v - 0x01010101UL), evaluates to a high bit set in any byte whenever the corresponding byte in...
Character array doesnt conform to new size
Instead of this: for (i = 0; i <= strlen(ch); i++) { write this: for (i = 0; i < strlen(ch); i++) { With <= it also copies the \0, which makes strlen(newStr) return only the length of the first line (because there is \0 after the first line)....
issue in rewriting strlen from C to Assembly
There are several mistakes in your code 1) strlen is officially declared as size_t strlen(const char *s);. Argument is a pointer to a string. With push dword [str] you don't pass a pointer, but the first 4 bytes of the string. Change it to push str. NASM (unlike MASM) calculates...