file,asp.net-mvc-4,button,upload,submit
@using(Html.BeginForm("Upload","Home",new {@id="frm"})) { <input type="file" id="upld" /> <input type="button" value="upload" id="btn" /> } <script> $('#btn').click(function(){ var has_selected_file = $('#upld').filter(function(){ return $.trim(this.value) != '' }).length > 0 ; if(has_selected_file){ $('#frm').submit(); } else{ alert('No file selected'); } }); I hope this is your requirement ...
A quick look at your PHP code I see the following: This: if(null!==($email = $_POST["email"])) will fail because you are running a check against nothing. it should be: if(null!==($_POST["email"])). You have an undefined variable here: $email_from = '$Email'; this will simply output "$Email". It should be $email_from = $email; (as...
ajax,ruby-on-rails-4,submit,reload
Perhaps the reason in wrong html. about_me_change partial may look like this: <div id="AboutMeForm"> <div class="UserEditsJS"> <%= simple_form_for(@user, remote: true) do |f| %> <%= f.field :about, as: :text %> <%= f.button :submit %> <% end %> </div> </div> Pay your attention that simple_form_for method receives a block which will be...
First time the $url is empty so the browser is requesting same page, then the $url is changed, then injected to form so the next post will redirect to your preview.php file. Just sent header for redirect. header("Location: /preview.php?id=".$id); so it will be: <?php if ($_POST['submit']) { mysql_connect ("localhost", "root",...
jquery,asp.net,forms,submit,parsley.js
Had help from @Learner with this one who made this fiddle - jsfiddle.net/ukgvam9k/26
see this tutorial: php_forms echo '<form action="action.php" method="post">'; echo '<div>'; echo '<img src="'. ($image) .'" alt=""/>'; echo '</div>'; echo'<LABEL FOR="C1">Fashion</LABEL>'; echo'<INPUT TYPE="Checkbox" Name="fashion" ID="C1" Value="Fashion">'; echo'<LABEL FOR="C2"> Non Fashion </LABEL>'; echo'<INPUT TYPE="Checkbox" Name="nfashion" ID="C2" Value="Non Fashion">'; echo'<input type="submit" value="submit" action = "action.php">'; echo '</form>'; ...
put this piece of code inside the submitText controller div <div> <p ng-repeat="text in outputArr">{{text}}</p> </div> then you whole code should be like <div ng-controller="submitText"> <form method="get" action="#"> <input type="text" name="input" ng-model="inputText" required/> <button ng-click="print(inputText)">Submit</button> </form> <div> <p ng-repeat="text in outputArr">{{text}}</p> </div> </div> here is the Plunker in your case...
javascript,jquery,twitter-bootstrap-3,submit
this keyword refers to data object itself not #edit-template-form. So store the variable this before using it like below: $('#edit-template-form').submit(function (e) { e.preventDefault(); var form = $(this); var data = { id: form.parent().val(form.data('id')), name: $('#edit-template-name').val() }; console.log(data); return false; }); ...
You could format your form names like this. First question name="respuestaAlumno[0][]" name="respuestaAlumno[0][]" ... name="idPregunta[0]" name="tipo[0]" Second question name="respuestaAlumno[1][]" name="respuestaAlumno[1][]" ... name="idPregunta[1]" name="tipo[1]" You would end up with three arrays in your $_POST....
You should not use a click event to submit. Since the page is unloaded by the submit, you need to use a cookie to save the time and hide the submit button : For example test page <style> #subbut { display:none } </style> <script> window.onload=function() { // when the...
javascript,text,three.js,submit
It really depends on various aspects. What I did was simple. //In the html.html The object: <input type="text" id="inputFile"> <input type="button" id="submitBtn" onclick="loadTheFile()"> Now when the button is clicked, it will trigger a function in your javascript file. All you have to do now is to create the loadTheFile function...
javascript,button,submit,radio
Using only Javascript Test it online: http://jsfiddle.net/OscarGarcia/t70prkda/ HTML test code: <form name="form" onsubmit="return check()"> <p><input type="radio" name="bg" value="no" /> Desactivate</p> <p><input type="radio" name="bg" checked="checked" value="yes" /> Activate</p> <input type="submit" /> </form> Javascript code: function check() { if (document.form.bg.value == "yes") { document.body.style.background = "red"; } else { document.body.style.background = "";...
jquery,forms,magento,submit,form-submit
There's no way of preventing the user from interacting with their browser. Issues with the user navigating away or canceling the request before it completes are usually handled by instructional messaging while the request is being processed (i.e. "Please wait while we process your request. Do not press your browser's...
javascript,php,html,submit,contenteditable
Now i can think of 2 ways: as you said, writing the text from the contenteditable div to the input; and with ajax. 1.hidden input way so the workflow here is that you copy what html is inside the contenteditable div to a hidden input with javascript. when you click...
ruby-on-rails,button,text,submit
It's defined in the Rails Framework. Whenever the new method is called the params[:action] = 'new', So, for the form we use f.submit. This f object is the instance of that new method. Thus the framework decides to show the button name 'New Article'. Article is the object and new...
Oh well i fixed that :D public function actionCreate() { $model = new Koszyk(); $model->setAttributes($_GET); if ($model->save()) { return $this->redirect(['view', 'id' => $model->id]); } else { $m =$_GET; return $this->render('create', [ 'model' => $model,'param'=>$m ]); } } ...
javascript,jquery,forms,zip,submit
You can assign an onsubmit event on the form which will run when the form attempts to submit which will include hitting enter when inside the form. Here is the altered code with changes in comments: <h1 id="header">Are you in our delivery area?</h1> <!-- Added id field to form so...
Could you reformulate please ? Not very clear, here... By the way, if you want to get the value of "textbox" with the following instruction " var txt = document.getElementById("textbox"); " , then you need to correct it like this : var txt = document.getElementById("textbox").value;...
javascript,html,forms,random,submit
All your radio buttons have the same name, hence belong to the same group. Give them different names and you should be fine: str+='<table>'+ '<tr><td id="a1"><input type="radio" name="radio' + i + '" />'+' '+quizObj[rand].choice[0]+'</td></tr>'+ '<tr><td id="a2"><input type="radio" name="radio' + i + '" />'+' '+quizObj[rand].choice[1]+'</td></tr>'+ '<tr><td id="a3"><input type="radio" name="radio' + i +...
php,html,forms,function,submit
Inside your first PHP function, echoForm, you are trying to open an HTML form element, but your code for doing that is missing the form tag. This is what you have : function echoForm($action){ echo "<method = 'post' action = '$action'>"; } The browser interpretes that as a <method> tag,...
php,html,post,drop-down-menu,submit
First thing would be to change your form tags to divs to keep your formatting. <div class="Menu1" id="Menu1"> <p> Lembaga</p> <div style="margin-top:-20px;margin-left:-2px;"> <select name="DropLembaga" autofocus required id="DropLembaga"> <option value="no" selected="selected">---Choose one---</option> <option value="FlashCom">FlashCom</option> <option value="InterNusa">InterNusa</option> <option value="HexaCompare">HexaCompare</option> </select>...
javascript,html,angularjs,submit
You can pass the data you want to use in the function's parameters: <button ng-click="Age(a.age)">This Age</button> $scope.Age = function(age) { $http.post('api/age', {age: age}) .success(function (response) { console.log(response) }) .error(function (error) { console.log(error) }); } ...
the best point is default value for the field in table definition. you must define that field as follow: timeStampField TIMESTAMP DEFAULT CURRENT_TIMESTAMP also you can define field type as DATETIME notice that this will work for mySql version MySQL 5.6.5 and higher....
javascript,jquery,submit,enter,onkeyup
You need to rename your submit button, you are overridding the submit method. Change <input id="submit" type="submit" name="submit" value="Send" /> to <input id="btnSubmit" type="submit" name="btnSubmit" value="Send" /> and change $('#form').submit(); to $('#form')[0].submit(); or $('#form').get(0).submit(); ...
Use the String Replace function to replace all occurrences of a space in a string with an empty string (nothing): <?php $string = 'My Name'; $noSpaces = str_replace(' ', '', $string); echo $noSpaces; // echos 'MyName' ?> ...
This is not an issue with bootstrap. Your form submit behaviour is being intercepted via javascript in a script named contact_me.js. What this script was supposed to accomplish, I don't know, but you might want to check that out. For instance, inn line 11 of this script you have var...
Try <button type="submit" class="btn btn-default"> <i class="fa fa-shopping-cart"></i> Buy Now </button> ...
javascript,jquery,forms,jsp,submit
This can help <form:form id="reviewApprvDisapprvForm" modelAttribute="updateProofingForm" method="post"> <input id="approveButton" onclick="submitForm('approve')" type="image" src="/images/buttons/samplesApprovedButton.png" /> <br /> <input id="disapproveButton" onclick="submitForm('notApprove')" type="image" src="/images/buttons/samplesNotApprovedButton.png" /> </form> and then function submitForm(buttonVal){ if(buttonVal=='approve'){...
javascript,asp.net,forms,submit,synchronous
They will both run as if they were written in a JS block one after the other
jquery,forms,validation,submit
You can prevent form to be submitted with following code: $(document).ready(function() { $('form').on('submit', function(e){ // validation code here if(!AllFieldsAreValid) { e.preventDefault(); } }); }); You can define AllFieldsAreValid as True or False when all fields are filled correctly or not....
php,mysql,arrays,checkbox,submit
You can use an IF statement if the checkbox is checked or not. for ($j = 0; $j < count($_POST['selected_item']); $j++) { if(!empty($_POST['selected_item'][$j])){ /* CHECK IF CHECKBOX IS SELECTED */ answer = mysql_real_escape_string($_POST['dynamic'][$j]); // returns multiple answers $check_answer = "SELECT id, answer FROM answers WHERE answer = '$answer'"; $check_answer =...
javascript,html,forms,submit,form-submit
This is probably being caused by the required attribute used in <input type="text" name="schoolname" id="schoolid" placeholder="Please Specify" required style='display:none;'/> This requires the input field to contain a value before the form can be submitted, since the display is set to none this will obviously conflict. Remove the required attribute and...
Try this in scripts.js: $('#contactform button[type=submit]').click(function(e){ e.preventDefault(); $('.confirmation').show(); setTimeout(function(){ $('#contactform').submit(); }, 5000); }); 5000 means it will show the message for 5000 milliseconds (5 seconds) then submit the form. (All the other files can stay like they originally were)...
angularjs,forms,datepicker,submit
Your second button is included in a div with another controller. Your newTrip variable gets updated in the DatepickerDemoCtrl controller, not in TripControlle; I checked by adding $scope.$watch('newTrip',function(newValue, oldValue){ console.log(newValue); }); as the first line in DatepickerDemoCtrl. Hope that helps finding a path for an answer :-)...
You can make the call server side using a library such as cURL Which will work fine if it's an API that responds with some json or xml. If their page renders something like a html thank you page, you would have to parse that to ensure it worked and...
php,forms,search,onclick,submit
in your js file you can check if the value of the textbox is equal to the cityname you want. if it is then submit the form. Attach the function to your a tag function SubmitRightCity(){ if(document.getElementById('search').value == "citynamehere"){ document.forms["form"].submit(); } } in html <a onClick="submitRightCity()">City</a> In the case where...
coldfusion,submit,export-to-excel
You need to just put your form in an if statement like this: <cfif NOT (structKeyExists(form, "nav") AND form.nav EQ "export")> <form> ................. ................. </form> </cfif> The above code will ensure that the form (and hence any form elements) is not available when user chooses to export the table to...
Use array $temp = array() if(isset($_POST['publicar'])){//to run PHP script on submit if(!empty($_POST['check_list'])){ echo "<tr><td>Sites a Publicar</td><td>Valor</td></tr>"; foreach($_POST['check_list'] as $selected){ echo"<tr><td>".$selected."</td><td><input type=number name=valor_site[]></td></tr>"; $temp[]=$selected; } $_SESSION['lista_public'] = $temp; echo"<tr><td><input type='submit' name='submit_valor' value='Submit'...
c#,winforms,datagridview,submit
Assuming your DataGridView has only two columns, and that it's DataSource property is not bound to some collection or a DataTable, this should work: private void btnAddInputToGrid_Click(object sender, EventArgs e) { // add the new row, get its index var newIndex = dataGridView1.Rows.Add(txtEmail.Text, txtPass.Text); // select just the new row...
java,spring,forms,many-to-many,submit
I manage to solve this issue changing the Property Editor class to this: @Component public class ProdutoEditor extends PropertyEditorSupport { @Override public void setAsText(String text) { if (!text.equals("")) { ProdutoService serv = new ProdutoService(); ApplicationContextHolder.getContext().getAutowireCapableBeanFactory().autowireBean(serv); Produto produto = serv.getObject(text); setValue(produto); } else { setValue(null); } } } which work with...
javascript,jquery,html,forms,submit
$('.suspend-user') is finding all of the forms and submitting them all. You need to submit the form you are on. It looks like the plug-in passes the button that was clicked so: confirm: function(button) { $(button).closest('form').submit(); }, ...
javascript,angularjs,forms,submit
element with id='mc-embedded-subscribe' is an input, but you need to "submit()" a form. this line document.getElementById('mc-embedded-subscribe').submit(); should be changed for document.getElementById('mc-embedded-subscribe-form').submit(); Here you have a new fiddle with this changes, and it works! http://jsfiddle.net/kx8dn8wc/...
Here is an example using JQuery. Not sure if this helps answer your question, but here is a jsfiddle that should hopefully point you in the right direction. http://jsfiddle.net/e5bq3x2z/ HTML <button class="zoom" id="zoom1" type='submit' value="1" >Zoom 1</button> <br/> <br/> <button class="zoom" id="zoom2" type='submit' value="2" >Zoom 2</button> <br/> <br/> <input id="myinput"...
You could check whether default was prevented before calling submit by using event.defaultPrevented var a = document.forms[0]; var b = document.createEvent('UIEvent'); b.initEvent('submit', !0, !0, window, 1); a.dispatchEvent(b); if (!b.defaultPrevented) { a.submit(); } return !0; In your case, you are dispatching an event, but that has nothing to do with the...
Usually once you exit the review queue, you will have to queue up again for another week. Its uncommon but possible that apple will expedite a review, although apple does not explicitly mention so. One common scenario is apps containing Apple Watch apps that will be prioritized in the review...
Your form is missing an action value, which prevents submitting the form at the end. But in the mid-time you should correct this code: $(document).ready(function() { $('#cars').on('change', function() { document.forms[myFormName].submit(); }); }); You can also submit a form by triggering submit button click event: $(document).ready(function() { $('#cars').on('change', function() { var...
If you want multiple inputs with the same name use name="id[]" for the input name attribute. $_POST will then contain an array for name with all values from the input elements. Then you can then loop over this array. Example: <form method="post"> <input type="hidden" name="id[]" value="foo"/> <input type="hidden" name="id[]" value="bar"/>...
Your issue arises from this line : <Form Name ="form1" Method ="POST" ACTION = "app\views\supermarkets\search.php"> The action must be a callable URL. Instead, you are providing a path to the view file. Using the Yii MVC convention, you will need to generate a controller function and point the form action...
try this $response = $_Client->doHallo($_username.' '.$_lastname);.
Your HTML code is bad because the name attribute for the select can`t be in the option <select name="lelo" id="lelo"> <optgroup label="Radeon HD Series"> <option value="Radeon3470">Radeon HD 3470</option> <option value="Radeon3650">Radeon HD 3650</option> </optgroup> <optgroup label="Radeon R7 Series"> <option value="R7240">Radeon R7 240</option> <option value="R7250">Radeon R7 250</option> </optgroup> </select> ...
forms,mongodb,meteor,insert,submit
Just convert it to an integer prior to the insert: var playerScoreVar = parseInt(event.target.playerScore.value, 10); or var playerScoreVar = Number(event.target.playerScore.value); You can see the differences explained here;...
ios,apple,submit,provisioning-profile
They can not submit it and neither could you with that kind of a profile. You need to sign it with their profile / account. They first need to create an iOS distribution certificate for distributing to the app store. They then will create a provisioning profile for app store...
ios,xcode,app-store,submit,runtime-error
Check your certificate again. Are you sure you are using correct certificate? Production environment certificate? Refer these links ERROR ITMS-9000: "Missing Code Signing Entitlements. No entitlements found in bundle" - How to change app ID name Getting errors when trying to upload an app using Application Loader...
Use the prompt() dialog box method and then pass the value entered by the user using GET method with your php script. To see how to use prompt() go here: www.w3schools.com/js/js_popup.asp
$_SESSION is going to be shared across all open browser windows on a machine. So, if you opened up Firefox, and logged in, every other Firefox window you have open is also logged into that service. What you likely want is a token in the page that gets submitted along...
You can use the parents() function here. Try this: JSFIDDLE $("input").focus(function(){ $('input[name="changebutton"]').prop('disabled', true); $(this).parents('form').find('input[name="changebutton"]').prop('disabled', false); }); ...
you have to use this code. <a href="index.php?page=test"> Test </a> <br><br> <form action="index.php" method="get"> <input type="text" placeholder="enter text"> </input> <input type="hidden" name="page" value="test"> <button type="submit">Send</button> </form> ...
jquery,ajax,forms,click,submit
I don't see the need to submit the form if you're using it only to retrieve the action link. I would take off the form submit entirely. $(document).ready(function() { $(document).on('click', '.favtrigger', function() { var favid = $(this).attr('id'); var form = $(this).find('#form' + favid); var action = form.attr('action'), method = form.attr('method'),...
jquery,if-statement,submit,recaptcha
the best way to do this IMO, would be using the callback function from the widget. <script> var fnSubmit = function(){ //code for submit } </script> <div class="g-recaptcha" data-sitekey="your_site_key" data-callback="fnSubmit"></div> let me know if it works. :)...
Your html is missing a closing bracket on the Login input. Should be: String s="<h1>Welcome</h1><p><form action=\"Main\" method=\"post\"></p> <p>User: <input type=\"text\" name=\"user\"><br></p><p>Password: <input type=\"password\" name=\"pass\"><br></p><p><input type=\"submit\" value=\"Login\"></form></p>"; ...
Here is what worked for me: Select the Target Go to Build Phases Expand the Copy Bundle Resources Go to the bottom of the panel and select the + sign. Add each of the missing resources. ...
As you're using XCode6.1 you can submit your build using Application Loader. Open XCode Menu -> Open Developer Tools -> (Select) Application Loader That's it, and follow the instruction. You may need to read, Submitting the App....
The server response needs to be something like: { success: true } Here's a fiddle that shows this working: https://fiddle.sencha.com/#fiddle/fc6 If you put some logging in your failure handler you should see that it's being called......
forms,codeigniter,validation,submit
you have to use the callback validation function you have to pass id also $this->form_validation->set_rules('title', 'Title', 'required|xss_clean|trim|callback_check_title'); function check_title($title) { if($this->input->post('id')) $id = $this->input->post('id'); else $id = ''; $result = $this->news_model->check_unique_title($id, $title); if($result == 0) $response = true; else { $this->form_validation->set_message('check_title', 'Title must be unique'); $response = false; } return...
php,button,submit,radio,retain
I think your looking for something like this: <?php session_start(); if(isset($_POST['submit'])) { if(!empty($_POST['diet'])) $_SESSION['diet'] = $_POST['diet']; } if(isset($_SESSION['diet'])) echo $_SESSION['diet'] ?> <form action="" method="post"> <strong>Dietary Requirements:</strong> <br><br> Vegetarian <input type="radio" name="diet" <?php if (isset($_POST['diet']) && $_POST['diet']=="Vegetarian") echo "checked";?> value="Vegetarian"> <br><br> Vegan <input...
c#,ajax,json,model-view-controller,submit
@Html.HiddenFor(m => m.MakeCalculations, new { @Value = "true" }) If you have to do it in the form. But that is probably not the best way.. if it's always true then why do you need to set it?...
You cannot submit a form with Beautifulsoup. For this you should use Mechanize. See here an example of how to use it for form submitting.
after a little googling, disabled forms don't post to the action page. replace disabled with readonly and you should be fine.
java,spring,jsp,spring-mvc,submit
Maybe this will be helpful. Why you don't want to use submit button? If you just wanted to look it like a label/link just use css similar to http://jsfiddle.net/adardesign/5vHGc/ Html: <button> your button that looks like a link</button> Css: button { background:none!important; border:none; padding:0!important; /*optional*/ font-family:arial,sans-serif; /*input has OS specific...
javascript,php,forms,submit,casperjs
you can achieve what you need with casperjs alone by using the js setinterval and a neat little feature in most linux boxes, called screen. In ubuntu you would install it like so: sudo apt-get install screen Now in order to use it: Create a new file with .js extension...
try this DEMO <form id="sForm"> <input type="text" name="search" id="search" /> <input type="submit" /> </form> jquery code $(document).ready(function(e){ $('#sForm').on('submit',function(){ alert( $('#search').val() ); }); }); ...
php,foreach,submit,social-networking
As far as I am aware the submit button will only submit the form that it is in. In fact it is very hard to submit more than one form at a time. I suspect the problem is that the form submits the reply and that it is not bound...
Not sure but it may be an issue with java 8. From typesafe blog for scala 2.11 The Scala 2.11 series targets Java 6, with (evolving) experimental support for Java 8. In 2.11, Java 8 support is mostly limited to reading Java 8 bytecode and parsing Java 8 source. We...
javascript,jquery,submit,bpm,bonita
The simplest onclick tag on Submit button doesn't work for bonita portal. So I had to work around and put these tags for it to work: <button type="button" class="btn btn-primary" onclick="if(confirm('Are you sure you want to Submit ?')){document.getElementById('Submit') .getElementsByTagName('button')[0].click();}">Submit</button> Here Submit is a bonitasoft submit type. I have to hide...
If it is HTML, you can use iframe code to display your form on the page. http://www.w3schools.com/html/html_iframe.asp Can be helpfull. <iframe src="Put the contact form URL here." width="200" height="200"></iframe> ...
Say you are showing the second step. Now the user clicks the submit button and $_POST['submit2'] will be set. However, $_POST['submit1'] won't be set anymore (as the user didn't click on it). So your code will never activate step2() which is needed for step3() to be called. You can resolve...
javascript,submit,getelementbyid
your error is that you're passing the varForm without the quotes, try this: <form name="form<?php echo $x . $y; ?>" id="form<?php echo $x . $y; ?>" action="/index.php" method="post"> <a href="#" onclick="confirmDelete('<?php echo $x . $y; ?>'); return false;"><p><?php echo $aryClientInfo[$x][1][$y * 3]; ?></p></a> <input type="hidden" name="values<?php echo $x; ?>" value="<?php...
I think you have to look at the life-span of the script When the user hits First button: Form submitted script runs (sets your variable) script terminates (as does all things related) Second button: Form submitted script runs (does not set second variable) script terminates (as does all things related)...
javascript,html5,canvas,submit,watermark
I made some little changes to your Fiddle Added these 2 functions to add text and clear the canvas: function drawText() { var x = canvas.width / 2; var y = canvas.height / 2; context.font = '30pt Calibri'; context.textAlign = 'center'; context.fillStyle = 'blue'; context.fillText('Hello World!', x, y); } function...
php,forms,symfony2,doctrine2,submit
Form Types are used so you don't have to keep creating the same form, or just to keep things separate. Form actions are still handled in the controller. Given your example form type class, something like; public function taskAction(Request $request) { // build the form ... $type = new Task();...
I would just replace this ... Set form = ie.document.getElementsbytagname("input") Set button = form(2).onsubmit form(2).submit ...with this... Set form = ie.document.getElementsbytagname("input") For Each btn In form If btn.Value = "Login >" Then btn.Click Exit For End If Next Why? Because you know that on the button there is always written...
html,get,submit,enter,preventdefault
Try changing your keypress event to keydown because the default behavior of the Enter key is captured on keydown so you have to prevent it at the point where it starts doing its default action. Here's a working sample: <!DOCTYPE html> <html> <script> function selecting_key(whatKey){ if(whatKey.keyCode==13){ whatKey.preventDefault(); } } </script>...
javascript,html5,checkbox,submit
I solved this way: <input id="dati[3]" type="hidden" name="dati[3]" value="1"> <input id="IarITK0MIY" type="checkbox" checked value="1" onclick="var x3=document.getElementById('dati[3]').value; if (x3=='1') {document.getElementById('dati[3]').value='0'; } else {document.getElementById('dati[3]').value='1';}"> now it works as supposed in my code, i can send "dati[3]" with 1 or 0 depending on the value of check box checked or not. thank you...
javascript,excel-vba,webforms,submit,username
Thans to @nhee for helping me find a solution. The working code looks like this: Sub EMO_login() Dim ie As Object Dim sht As Worksheet Set sht = Sheet8 Set ie = CreateObject("InternetExplorer.application") With ie .Visible = True .navigate "www.emo.no" Do While .Busy Or _ .readyState <> 4 DoEvents Loop...
jquery,ajax,forms,submit,reload
Please do not use submit, instead use change function <script type="text/javascript"> $(document).ready(function() { $('form').on('change', function() { $.ajax({ url: 'form.php', type: 'post', data: {'id':jQuery('select[name=id]').val()}, success:function(data) { $('form').html(data); } }); }); }); </script> ...
Well you can do something like this for sure by triggering Angular submit event: $scope.change = function($event) { $timeout(function() { angular.element($event.target.form).triggerHandler('submit'); }); }; where <input type="checkbox" name="foo" value="bar" ng-click="change($event)" /> However I think it's better to simply use the same function in ngClick as used in ngSubmit. Demo: http://plnkr.co/edit/tJIYD9ZVjYzwA2aXJobo?p=preview...
java,javascript,jquery,checkbox,submit
By default only the checked checkboxes are sent. You do need to give the checkboxes a value, for instance value="1". <input type='checkbox' class="urlCheckBox" name='checkbox-1' style='margin-left: 15px; float: left;' value="1"> ...
javascript,html,function,input,submit
https://jsfiddle.net/hmfcLsf2/1/ <body> <script> function func1 (x,y){ var z=parseInt(x)+parseInt(y) alert(z) } </script> <form > first input:<br> <input id="y_field" type="text" y="Y" value=85> <br> second input:<br> <input id="x_field" type="text" x="X" value=15> <br><br> </form> <button type="button" onclick="func1(document.getElementById('x_field').value,document.getElementBy Id('y_field').value)">Try it</button> Use getElementById. See the...