You are missing a closing parenthesis on the preceding line: result = factorial(n) / (factorial(k)*factorial(n-k) # ^ ^ ^ ^ ^? # 1 2 2 2 21 ...
ruby-on-rails,ruby,terminal,syntax-error,rake
You have a typo on line 16th: Location.create(area: 'College Ave', should be Location.create(area: 'College Ave') ...
The name attribute of your input fields are what is used for the index of the $_POST array in PHP. You did not set the name attributes in your HTML code. For this reason, e.g. $_POST['name'] cannot be resolved, which causes the message. To fix this, actually fill in the...
The answer is not simply "because Go doesn't need parentheses"; see that the following example is a valid Go syntax: j := 9 if (j > 0) { fmt.Println(j) } Go Spec: If statements: IfStmt = "if" [ SimpleStmt ";" ] Expression Block [ "else" ( IfStmt | Block )...
sql,syntax-error,ms-access-2010
Problem is that your table names include space and so query parser/engine taking it as two different literal names. You should escape them using []. Also, notice that I have used table alias (am,cp,ae) for ease of reading. Your query should look like SELECT am.* FROM [Archivo Maestro] am INNER...
In order for the compiler to know if the , belongs to the constructor call or to the method signature of the delegate, you should add parenthesis around the delegate signature: var addCar = new Action<string, decimal>((number, test) => { } ); Now it reads the delegate as (number, test)...
sql,oracle,syntax-error,nested-queries
Altering the posting layout for clarity reveals that this line is the immediate problem: ORDER BY dat DESC ) table2 tb2 You need one alias, not two. So it should be ORDER BY dat DESC ) table2 You also need to put an alias on the outer nested query: (select...
mysql,stored-procedures,syntax-error,declare
You must define IN for the parameters. DELIMITER $$ CREATE PROCEDURE spInsertEmployee ( IN Employee_Name nvarchar(20), IN Employee_Surname nvarchar(20), IN Department_Name nvarchar(20) ) BEGIN declare Department_Id INT; select Id into Department_Id from tblDepartment WHERE tblDepartment.Department_Name=Department_Name; insert into tblVeri(Employee_Name,Employee_Surname,Department_Id) VALUES(Employee_Name,Employee_Surname,Department_Id); END; ...
c,compiler-errors,syntax-error
The compiler doesn't know that che is a type.Include the appropriate header file. OR As you know,The compiler parses the file from top to bottom.Make sure a type is defined BEFORE using it into another....
javascript,php,onclick,syntax-error
That makes no sense. You are assigning a URL to a onclick, that is wrong. If you want to go to a page, you need to set the window location or wrap the button in an anchor. onclick="window.location.href='http://www.example.com';" Using inline events is bad practice....
php,include,syntax-error,require
If you really wanted this type of functionality. You could try using nikics php parser to see if you can successfully parse the file or not. $code = file_get_contents('yourFile.php'); $parser = new PhpParser\Parser(new PhpParser\Lexer\Emulative); try { $stmts = $parser->parse($code); // $stmts is an array of statement nodes // file can...
sql-server,stored-procedures,datatable,syntax-error,sql-insert
You need the form of insert that takes a select rather than a values: insert into theTable (col1, col2, ...) select col1, col2, ... from ... where... All the features of a select are available (column aliases, grouping, joins, sub queries, ...)....
c#,vector,syntax-error,expected-exception
You're using object initializer syntax. The compiler is correct. You would place a comma there, instead of the semicolon, if you were to initialize more than one property. The comma is also legal even after the last property being initialized, but a semicolon is not legal. So either of the...
php,session,header,syntax-error,session-variables
The error message shows exactly the problem: at the given line of the given php file, output has been produced already. After starting output, you cannot set headers any more because they have to be set before any document data. In order to solve the problem, check what output is...
The condition should be like below -- => is solely for associating keys & values within arrays if(strlen(trim($_POST[$fieldname])) >= $maxlength){ ...
c,header,syntax-error,missing-data
Change: typedef struct Portion{ char *pName; float pPrice; float pQuantity; Portion *next; }Portion; to: typedef struct Portion{ char *pName; float pPrice; float pQuantity; struct Portion *next; // <<< }Portion; Also note that you shouldn't cast the result of malloc in C, so change e.g. Portion *newPortion = (Portion*)malloc(sizeof(Portion)); to: Portion...
Because else if should be before else, like this: var compare = function(choice1,choice2){ if(choice1===choice2){ return("The result is a tie!"); }else if(choice1==="rock"){ if(choice2==="scissors"){ return("rock wins"); }else if(choice1==="paper"){ if(choice2==="rock"){ return("paper wins"); } } else{ return("paper wins"); } } ...
0.34 >= computerChoice < 0.67 is not valid in JavaScript. Use something like computerChoice >= 0.34 && computerChoice < 0.67 instead. the last block of else [else (0.67 >= computerChoice <= 1)...] should be else if. So your corrected code should be like this: alert ("CAN YOU BEAT VALERIE...
java,sql,sql-server,syntax-error
Couldn't find a query that works on multiple tables, so I queried the data in each table and saved it to my local server and the used the query above and it worked fine.
java,generics,compiler-errors,syntax-error
It's required by the Java Language Specification. MethodInvocation: MethodName ( [ArgumentList] ) TypeName . [TypeArguments] Identifier ( [ArgumentList] ) ExpressionName . [TypeArguments] Identifier ( [ArgumentList] ) Primary . [TypeArguments] Identifier ( [ArgumentList] ) super . [TypeArguments] Identifier ( [ArgumentList] ) TypeName . super . [TypeArguments] Identifier ( [ArgumentList] ) The...
This is likely because short_open_tag is disabled when you test locally. This setting controls whether or not <? ?> among other tags are interpreted as PHP during parsing. The result is that this block: <? $fields = array("email", "pass"); for ($i=0 ; $i<count($fields) ; $i++) { if ($form->Error($fields[$i]) != "")...
Consider the condition x in (select something from somewhere). It returns true if x is equal to any of the somethings returned from the query - regardless of whether it's the first, second, last, or anything in the middle. The order that the somethings are returned is inconsequential. Adding an...
\ is an escape character, it tells Python that the next character may need to be ignored. In Python code, outside string literals, it is used to create logical line continuations: foo = 'This is a longer string ' \ 'wrapped across more than one line' Using it in the...
syntax,dart,syntax-error,questionmark
The feature existed at some point in Dart's development, but it was removed again because it caused more complication than it removed, without solving the problem that actually needed solving - forwarding of default parameters. If you have a function foo([x = 42]) and you want a function to...
python,exception,python-3.x,exception-handling,syntax-error
It seems like you're using python 3.x. Use following syntax (using as): except ValueError as Argument: Reference: try statement - Python 3 documentation...
javascript,html,css,for-loop,syntax-error
You really have an illegal character after the last curly brace, see what i got copy-pasting that code on jsfiddle, notice the red dot. button[i].innerHTML = i; }* Open that file with another editor, e.g. vim an check for weird characters with :set list....
eclipse,syntax-error,keyboard-shortcuts
There is no one short cut to do what you require, but you could use a combination. Windows Short Cuts Go to the next error: Ctrl + . Go to the previous error: Ctrl + , Then Comment that error: Ctrl + / Extra If you really wanted you could...
python,tkinter,attributes,syntax-error,trackback
Spelling? Try subMenu.add_separator().
java,arraylist,duplicates,syntax-error
Arrays don't have the get(int) method. Instead, they use the [int] syntax: if (data[i].equals(data[j])) { return true; } ...
javascript,syntax-error,feedback
This line: if (userReady = "yes" || "Yes") { does not do what you expect it to. First, you cannot use = to compare values (it means assignment in Javascript). So you can use ===. Second, the || joins two independent conditions, not values. So you can write: if (userReady...
mysql,stored-procedures,syntax-error,prepared-statement
The reason is A statement prepared in stored program context cannot refer to stored procedure or function parameters or local variables because they go out of scope when the program ends and would be unavailable were the statement to be executed later outside the program. As a workaround, refer instead...
Your scanner pretty well guarantees that two newline characters will be sent at the end of the input: one from the newline present in the input, and another one as a result of your trapping <<EOF>>. However, your grammar doesn't appear to accept unexpected newlines, so the second newline will...
sql,postgresql,syntax,syntax-error,explain
It should not work - DDL statements has no plan - so EXPLAIN has nothing to show.
linux,bash,perl,syntax-error,use
As has been told in the comments, your script for some reason is getting executed via shell. You can study why it is so and fix it. Or you can work around using the following trick: #!/usr/bin/perl eval 'exec /usr/bin/perl "$0" "[email protected]"' if 0; # not running under some shell...
import re from collections import Counter from prettytable import PrettyTable words = re.findall('\w+',open('MusicTaste2.csv').read().lower()) for label, data in ('Word', words): pt = PrettyTable(field_names=[label, 'Count']) c = Counter(words) [pt.add_row(kv) for kv in c.most_common()[:100]] print (pt) First problem is indent your code properly Second problem is missing of : in the follwing line...
Simply adding parentheses around &TestStruct::operator>> will force MSVC to parse it correctly. This code compiles with MSVC 19.00.23008.0 : template <class T, void(T::*)(int)> struct TemplateMagic {}; struct TestStruct { void operator>> (int) {} }; int main() { TemplateMagic<TestStruct, (&TestStruct::operator>>) >* ptr; } The "trick" of adding parentheses will work in...
You'll probably find the syntax select runner name is being treated as the shorthand form of select runner as name which would make the following as rather problematic. Even if they're not being interpreted that way, standard SQL will treat Runner and Name as two distinct tokens unless you tell...
c,compiler-errors,macros,syntax-error,c-preprocessor
#define is a preprocessor MACRO which acts as a textual replacement in the preprocesssing stage. In your case, with a MACRO like #define N 10 and then with a function like void displayMatrix(int *arr,int M, int N); it turns out to be void displayMatrix(int *arr,int M, int 10); //note the...
java,initialization,syntax-error
As with so many of these questions, it's because the JLS says so. 8.3.2.3 Restrictions on the use of Fields during Initialization The declaration of a member needs to appear textually before it is used only if the member is an instance (respectively static) field of a class or interface...
android,sqlite,login,syntax-error
Replace this code: String selectQuery = "SELECT id FROM " + TABLE_USER + " WHERE " + KEY_EMAIL + " & " + KEY_PASSWORD+ " =?" + email + password; Log.e(LOG, selectQuery); Cursor c = db.rawQuery(selectQuery, null); By this one: String[] columns = {KEY_ID}; String where = KEY_EMAIL+"=? AND "...
The SQL syntax used to retrieve rows from a table is select, not get: SLEECT * FROM items WHERE pubDate < ? ...
html,console,syntax-error,token
You need to set the type of <script> correctly: <script id="custom-reports-table" type="text/x-handlebars-template"> If you're telling the browser to evaluate HTML as Javascript, of course you'll get syntax errors from the Javascript interpreter....
It seems your bootstrap.py is outdated and tries to access a URL that does not exist any longer. You can update your bootstrap like this: $ rm bootstrap.py $ wget http://downloads.buildout.org/1/bootstrap.py $ python2.7 bootstrap.py $ bin/buildout ...
Your update query has an extra , comma before where "UPDATE minty_config SET name='%s', value='%s', WHERE ID=%d" ^^^ It should be "UPDATE minty_config SET name='%s', value='%s' WHERE ID=%d" ^^ I've just removed that extra comma. This'll work for you....
You have a bracket mismatch on the previous line, due to which Python continues parsing into the next line, and hence throws the error in the next line. To correct this, use: tests = average(student("tests")) * .6 Instead of: tests = average(student(("tests")) * .6 ...
c#,database,ms-access,syntax-error,insert-update
I believe you have an extra comma right before your where clause and an extra quote before the ID. Also, always use parameters, to avoid Sql Injection attacks: conn.Open(); cmd.CommandText = "update [Employe] set [UserName] [email protected], [Password] [email protected], [Authorization] [email protected] where [Id] = @id"; cmd.Connection = conn; cmd.Parameters.AddRange(new OleDbParameter[] {...
sql,sql-server,select,join,syntax-error
You're missing a comma between the two CTEs. Also, drop the alias - you don't need them when defining a CTE: ;WITH q1 AS ( select * from ReservationList WHERE [Market Segment Code] <> 'COMP' AND NOT ([Status] = 'CANCELED' OR [Status] = 'NOSHOW' OR [Status] = 'WAITLIST') AND NOT...
echo '<a href="?page_id=26" class="get_quote">get quote</a>'; ...
Use the format() string method: print "Your total trip cost is: {}".format(trip_cost(city, days, spending_money)) ...
access-vba,syntax-error,runtime-error
Most probably the error is because of spacing issue in your query. You need a space as shown below & " FROM tbl_Contacts " _ ^---- Here Otherwise, your query string looks like SELECT TOP 1 tbl_Contacts.ID, tbl_Contacts.idSite, tbl_Contacts.role, tbl_Contacts.name, tbl_Contacts.email, tbl_Contacts.phone, tbl_Contacts.involvement, tbl_Contacts.TakenFROM tbl_Contacts ^-- ERROR Here ...
ruby-on-rails,json,syntax-error,illegal-characters,to-json
If this is in a .erb file you can do the following: var home = <%= @home.to_json %>; Otherwise (haml or something else) you could use the parseJSON method from jQuery in combination with Ruby's string interpolation: var home = $.parseJSON("#{@home.to_json}"); More information about the parseJSON method can be found...
php,mysql,sql,datetime,syntax-error
As I said, I see no reason to use YEARWEEK function. You need start date set to today which is CURDATE() and plus 2 weeks period which is DATE_ADD(CURDATE(), INTERVAL 2 WEEK) and then we just check if starttime between those 2 dates. SELECT id, date_format(starttime, '%d-%m-%Y %H:%i') AS formatted_start,...
c,if-statement,syntax-error,expression
Your code has various syntax errors (If instead of if, semicolon after if-condition). Additionally, your code has a logical problem where you read an int and then compare against a string. This version works and is properly indented: #include <stdio.h> int main (){ int answers_eight[] = {8,16,24,32,40,48,56,64,72,80,88,96}; int answer ;...
c#,github,visual-studio-2013,dns,syntax-error
The code here looks like the DnsServer takes those 4 arguments. Are you sure you have the correct binaries? How did you install? If you are using the codeplex version then it doesn't look like it take a ProcessQuery parameter....
sql,sql-server,sql-server-2008,syntax-error
You should escape your interpolated varchar variable @vector with single quotes and use insert instead of update statement: set @sql = 'insert into #Test ' + 'values (coalesce(''' + @vector + ''', ''''))' SQLFiddle...
javascript,sql,node.js,syntax-error
This function will generate SQL code which is missing quotes around the datetime variable, resulting in invalid SQL code. function sendShipPosition(position) { var input = ''; if (position.moving === true) { var currentdate = new Date(); var datetime = currentdate.getFullYear() + "-" + (currentdate.getMonth()+1) + "-" + currentdate.getDate() + "...
The error is here: if [ "$PREVIP" == "$EXIP"]:then ^^ you need to add spaces around [ and ] and finally use semicolon: if [ "$PREVIP" == "$EXIP" ]; then ^^^ More generally, you can always use a tool called Shellcheck to check if your script has these common errors....
visual-studio,error-handling,syntax-error,basic
On Error Resume Next For x = 0 to 2000 err.raise x If not err.description = "Unknown runtime error" then wscript.echo err.number & " " & err.description End If err.clear Next Help has a full list of runtime and syntax errors. Above vbs prints out all runtime errors....
You made a mistake apparently. In the doc (http://php.net/manual/en/features.file-upload.errors.php), you'll find : UPLOAD_ERR_INI_SIZE and you did specify in your script : UPLOAD_ERR_INT_SIZE That's why the script tells you this constant does not exist :)...
javascript,jquery,syntax-error,parentheses
The parenthesis aren't the problem, it's the lack of quotes inside the function. formResults += "<a onclick='openForm(\'" + this.displayText + "," + this.ID + "\');'>" + this.displayText + "</a>"; This below snippet (from yours) `openForm(Example Form...`) Will throw an error because it's looking for variables Example and so on, quote...
javascript,html,arrays,regex,syntax-error
You have broken HTML and invalid Javascript. <script language="JavaScript"> For your DOCTYPE of html, there is no need to specify any attributes to a <script> tag except src, and that is only needed if you are loading an external script file. And there is no attribute language. You likely meant...
r,string,text,syntax-error,formula
The <text>:2:10080 is giving you the location of the error. 2nd line, 10080th character. Consider: parse(text="1 + 1 + 2\n a - 3 b") # Error in parse(text = "1 + 1 + 2\n a - 3 b") : # <text>:2:8: unexpected symbol Here, the error is with b, which...
c++,oop,interface,syntax-error
You are not allowed to use qualified names in class member declarations. I.e. when declaring the constructor of class Human inside class Human, you are not allowed to call it Human::Human(). It should be just Human(). The same applies to all other methods. Trying to declare method int IPc::Attack()...
There is an error in your SQL statement. You should change string query = "SELECT * FROM dbo.ispiti WHERE [email protected], [email protected], [email protected]"; to string query = "SELECT * FROM dbo.ispiti WHERE [email protected] AND [email protected] AND [email protected]"; ...
The less than and greater than operators in Java (and frankly, in most programming languages) are <= and >=, respectively, not =< and => like your code currently has. Additionally, you cannot apply to comparison operators to a single variable/value - you'd need to have two separate conditions with a...
java,mysql,jdbc,syntax-error,quotes
To use prepared statements correctly, you need to use parameter placeholders (?) and set the values on the statement. This will automatically give you protection against SQL injection. You need to change your code to: String sql = "INSERT INTO posts VALUES (?, ?)"; try (PreparedStatement statement = conn.prepareStatement(sql)) {...
mysql,sql-update,syntax-error,sql-injection
MySQL allows writing a literal ' within a string literal quoted with ' by two consecutive '': There are several ways to include quote characters within a string: A “'” inside a string quoted with “'” may be written as “''”. […] So the '' immediately after the opening '...
After removing those (error) markers, there are two actual syntax errors in your script: Missing closing parens ) in for var in range(length(list2): Assignment = instead of equality check == in if count = length(list2): Apart from that, there are some other issues, but those are not syntax errors: Should...
ruby-on-rails,ajax,syntax-error
The syntax error is in the url param of the Ajax method. You are missing closing ")".
Just move them to two separate lines if minutes >= 60: hours += 1 minutes -= 60 From PEP 8 Compound statements (multiple statements on the same line) are generally discouraged. For the sake of completeness, I will tell you that you can add ; to terminate a statement, so...
sql-server,stored-procedures,syntax-error
When handling dates in this way you will need to encapsulate them in quotation marks! It's failing to identify the type of data that you have and believes that you are sending a string.
group is a reserved keyword in MySQL and needs to be escaped by backticks. SELECT * FROM diploms LEFT JOIN student ON diploms.student_id = student.student_id LEFT JOIN `group` ON student.group_id = `group`.group_id LEFT JOIN speciality ON `group`.speciality_id = speciality.speciality_id ORDER BY CASE WHEN speciality.name IS NULL THEN 1 ELSE 0...
Remove the extra semicolon. SELECT site_name FROM example_tbl WHERE active = 1 AND site_code IN (SELECT TRIM(LEADING '/var/www/html/' FROM site_path) FROM example_tbl); ...
python,if-statement,syntax-error
if statement is indented inwards in for loop. And also = means assignment use == instead for item in data_indices: flag= search_object(item,data,obj_value_min,obj_value_max) if flag == True: #here indent this if one step back file_writer.write('frame0: ' + str(item[0]+1)+' ' + str(item[1]+1) + '\n') ##He ...
In C++, a condition is tested for before each iteration of a while loop. Verbatim from the C++ reference: condition - any expression which is contextually convertible to bool or a declaration of a single variable with a brace-or-equals initializer. This expression is evaluated before each iteration, and if it...
php,mysql,syntax-error,sql-insert,mysql-error-1064
You cannot have a dash (-) in your column identifier unless you wrap it in ticks. Otherwise it is seen as a subtraction operator: INSERT INTO submittedforms (firstname, lastname, email, `youtube-v`, `youtube-c`, `portfolio-link`, `picture-link` It is best practice to not use dashes in your identifiers. You should use an underscore(_)...
unity3d,syntax-error,shader,compute-shader
"kernel", not "kernal". See: Unity Compute Shaders [email protected] -> RWTexture2D will be your next compile error. Followed by "Reult" -> "Result", and then "id,xy" -> "id.xy"....
It looks like Fix-it blew it. Swift uses brackets around the type. The correct version is this: var tasks = [task]() This is the shorthand notation; there is a longer version: var tasks = Array<task>() but the shorthand version is preferred....
java,android,xml,syntax-error,logcat
Remove this line: navDrawerItems.add(new NavDrawerItem(navMenuTitles[10], navMenuIcons.getResourceId(10, -1))); And consider replacing that block of near-identical calls with a for loop: for (int i = 0; i < 10; ++i) { navDrawerItems.add(new NavDrawerItem(navMenuTitles[i], navMenuIcons.getResourceId(i, -1))); } ...
php,session,syntax-error,warnings
The problem is that you are sending the DOCTYPE on the first line, before the session starts. <!DOCTYPE html> <?php include('session.php'); ?> <?php include('dbcon.php'); ?> <html lang="en"> Change to <?php include('session.php'); ?> <!DOCTYPE html> <?php include('dbcon.php'); ?> <html lang="en"> Make sure the include is the first line...
Original answer: Could you create the table like this instead? Note the use of IDENTITY... create table if not exists account( userAccID IDENTITY, userAccName VARCHAR(20) NOT NULL, userIP VARCHAR(16) NOT NULL DEFAULT '-1', userEmail VARCHAR(64) NOT NULL DEFAULT '-1', userPasswd VARCHAR(64) NOT NULL DEFAULT '-1', userPremium INT NOT NULL DEFAULT...
javascript,numbers,syntax-error
The expressions 0.0 and 00.0 are parsed differently. 0.0 is parsed as a numeric literal 1 00.0 is parsed as: 00 – octal numeric literal 2 . – property accessor 0 – identifier name Your code throws syntax error because 0 is not a valid JavaScript identifier. The following example...
You are missing a { in the below line success: function (data) Make it success: function (data) { Edit You are having parsing the data incorrectly , do it as below $.ajax({ url: "test.html", dataType: 'json', mimeType: "application/json", success: function (data) { var item = []; $.each(data, function (key, val){...
syntax-error,vhdl,tri-state-logic
Two things. There is no is needed after process. And more importantly, when can't be used like that. You can do what you want to concurrently: TriOut <= A when S = '1' and T = '0' else B when S = '0' and T = '1' else ... or...
javascript,jquery,syntax,syntax-error
The line number of the error is wrong. The problem is at the end, you never close the function you're passing into ready or the call to it. Add }); at the end. If that's missing only because you quoted a ...snippet of the beginning of the code... ...then the...
php,sql,wordpress,wordpress-plugin,syntax-error
You cant just move a wordpress site by copy and pasting. Also exporting and importing Database will cause errors like this. Use all in one migration plugin. First install a wordpress site in your live server then export a backup from your dev server with the plugin and import same...
java,android,nullpointerexception,syntax-error
-First of All you have to check whether you are getting Json response properly or not and then check if response is right then you are storing in proper object or not i.e:- shop_title is not null check here. -Let me know if issue exist more Thanks...
When you insert parameters into a query string, you have to make sure that any characters in the inserted data are properly encoded so that they don't interfere with characters that have special meaning to the query language, such as the single quotes used to denote string literals. You typically...
python,python-2.7,printing,syntax-error
You have unbalanced parentheses on the previous line: min = int(raw_input("Input the next number of minutes (0 to exit): ") ...
python,python-2.7,syntax-error
Your sorted method isn't correct. In python, somelist.sort() sorts the list in place and returns None, so you end up erasing your list. You can either do words = sorted(words) or just words.sort() but doing words = words.sort() ends up setting words to None. Also, your split words is most...
Your syntax is invalid, use INSERT INTO ... SELECT and remove the values part like this: INSERT INTO invoices(invuid, linenumber) SELECT ?, max(linenumber)+1 FROM invoices WHERE invuid=? ...
You're using + to concatenate strings, that doesn't work in PHP. You have to use .. There is probably some strange arithmatic going on that produces 103.5, like 2.5 + "," + 100. Where "," is converted to int(1) or something....