I have a bash shell script (AIX) that is the following..
for i in ('cat somefile.txt') do
do something with $i
end
The variables that get passed to $i are in the form of (content of somefile.txt)..
PUB.table1 PUB.CustTable
How can I remove the "PUB." text so that what's passed is only table1...CustTable....etc ?
Thanks.
You can use cut:
cut -d '.' -f2 file | while read i; do echo "$i"; done
table1
CustTable
Or using process substitution:
while read i; do
echo "$i"
done < <(cut -d '.' -f2 file)
Using sqlite3 from bash on OS X seems fairly straightforward (I'm no expert at this, by the way). You will need to find out which table you need. You can do this with an interactive session. I'll show you with the database you suggested: /Users/fredbloggs> sqlite3 ~/Library/Application\ Support/Dock/desktoppicture.db SQLite version...
Try this to create a string variable n, with no leading whitespace (thanks @011c): n="10.0.0.135.527" wget http://infamvn:8081/nexus/content/groups/LDM_REPO_LIN64/com/infa/com.infa.products.ldm.ingestion.server.scala/"$n"-SNAPSHOT/com.infa.products.ldm.ingestion.server.scala-"$n"-20150622.210643-1-sources.jar ...
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awk -F'|' '{for(i=1;i<=NF;i++)if(!($i%3))print $i}' file this awk one-liner shoud do. With your example, the cmd outputs: 3 6 9 ...
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sql,postgresql,shell,hadoop,sqoop
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linux,shell,command-line,awk,sed
Almost same as the other answer, but printing 0 instead of blank. AMD$ awk -F, 'NR>1{a[$2]+=$3;b[$2]++} END{for(i in a)print i, a[i], b[i]}' File pear 1 1 apple 2 3 orange 0 1 peach 0 1 Taking , as field seperator. For all lines except the first, update array a. i.e...
unix,encryption,freebsd,boot,zfs
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