How to retain special characters after transformation?

Tag: java,xml,xslt,special-characters,transformation

I am working on XML transformation using XSL in Java program. This is the sample XML

<root>
 <head>Heading goes here</head>
 <middle>Some text goes here</middle>
 <body>Body goes here &#x2019; with special characters</body>
</root>

The XSL has identity template and it just removes a <middle> element.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>
  <!-- the identity template -->
  <xsl:template match="@* | node()" name="identity">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()" />
    </xsl:copy>
  </xsl:template>

<!-- template to remove middle element -->

</xsl:stylesheet>

The transformation is done through Java program (Transformer class). After transformation, ’in the body is converted to ’ char. I want to retain the ’ instead of ’ char. Please let me know how to achieve this?

Thank you in advance.

Best How To :

Typically the transformer will output characters as literals unless they cannot be represented in the selected output encoding. If you want to keep non-ASCII characters as character references then tell your stylesheet to use US-ASCII as the output encoding:

<xsl:output method="xml" encoding="US-ASCII" omit-xml-declaration="yes"/>

and now all non-ASCII characters will have to be serialized as references.

This won't necessarily preserve the input byte for byte, for example the serializer might choose to use decimal references rather than hex.

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