The question is, if I have got 100 entries in my Database and want them all getting displayed on my page, how can I only show a selected Number like it's the case in webshops etc. There you've got 37 products e.g. and after 10 products you have to select number 2 of the entry list.Its all split up in a few sites, but its still the same site.How can i achieve this.
You can achieve the pagination either by client side implementations or server side. Client side (using Java Script/JQuery) and Server Side (using PHP) is preferable.
For client side, just the following link
For Server side
The background colour changes when the browser width is less than 1200px wide. You have specified the background-color for the selector .td-grid-wrap within a media query: What you need to do is move the background-color property to the non-media-queried selector .td-grid-wrap or perhaps .td-page-wrap. ...
If I understand correctly you have a unix timestamp in a varchar field and you can't change this. If you compare the unix timestamp directly you will only get results that match the exact second of the timestamp. You can use FROM_UNIXTIME() to convert the timestamp in a date value...
No need to use union as it will give a lots of duplicate data What you want to achieve can be done with simple left join or inner join SELECT m.issue_name ,m.issue_type , m.priority ,m.status,m.description , m.start_date,m.end_date,m.duration, s.name as server_name,p.name as product_name from mod_networkstatus as m LEFT JOIN tblservers as...
php,email,codeigniter-2,phpmailer,contact-form
Don't do that. It's effectively forging the from address and will fail SPF checks. Instead, use your own address as the From address, and add the submitted address as a reply-to address. In PHPMailer: $mail->From = '[email protected]'; $mail->addReplyTo($POST['emailfrom']); ...
Trigger the click event like this: $('._repLikeMore').trigger('click'); ...
Let suppose on button click you are calling ajax method <button onclick="LoadData();"/> before ajax call show image and onComplete ajax method hide this image function LoadData(){ $("#loading-image").show(); $.ajax({ url: yourURL, cache: false, success: function(html){ $("Your div id").append(html); }, complete: function(){ $("#loading-image").hide(); } }); } ...
If it's responsive, use percentage heights and widths: html { height: 100%; width: 100%; } body { height: 100%; width: 100%; margin: 0; padding: 0; } div.container { width: 100%; height: 100%; white-space: nowrap; } div.container img { max-height: 100%; } <div class="container"> <img src="http://i.imgur.com/g0XwGQp.jpg" /> <img src="http://i.imgur.com/sFNj4bs.jpg" /> </div>...
HAML equivalent is %i{class:"fa fa-search"} You can look at http://codepen.io/anon/pen/BNwbEP and see the compiled view ...
html,css,twitter-bootstrap,flexbox
Set display: flex for the <ul class="nav">, not for items. Also use align-items: center for vertical aligment: .nav { height: 70px; display: flex; justify-content: center; align-items: center; } <link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet"/> <div class="container"> <nav class="navbar navbar-default navbar-fixed-top"> <ul id="nav_pills" class="nav nav-pills" role="tablist"> <li role="presentation"> <a href="/">About</a> </li> <li...
Okay so I have got a probable solution, the catch is, you won't be able to use img tags. You can use images as background-image and animate background on :hover NOTE: Fade in effect can be removed by playing with animation. HTML <div class="image-box"></div> CSS .image-box { height: 200px; width:...
nextAll and first: $(this).nextAll('.hidden').first().slideToggle(...); This question has more about this: Efficient, concise way to find next matching sibling?...
Closures work just like a regular function. You need to inject your outer scope variables into function's scope. Mail::send('invoices.mail', array($pinvoices,$unpinvoices), function($message) use ($email) { $message->to($email , 'Name')->subject('your invoices '); }); ...
javascript,jquery,html,arrays,contains
You can use :contains selector. I think you meant either one of those values, in that case var arr = ['bat', 'ball']; var selectors = arr.map(function(val) { return ':contains(' + val + ')' }); var $lis = $('ul li').filter(selectors.join()); $lis.css('color', 'red') <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <ul> <li>cricket bat</li> <li>tennis ball</li> <li>golf ball</li>...
table{border-collapse:collapse;width:100%} table tr td{padding:5px;border:1px solid #000; background:#FFF } table tr:hover td{padding:5px;border:1px solid #000; background:transparent } table{ background:...
Put your header inside the body. And don't apply styles to the body but use a container. + You should have one single header in your page. <body> <header> <nav><ul> <li class="active"><a href="#">Home</a></li> <li><a href="#">Solutions & Services</a> <ul> <li><a href="#">Internet</a></li> <li><a href="#">Networking</a></li> <li><a href="#">Website</a></li> <li><a href="#">Home...
have you tried using header('location') function? example : <?php if (isset($_POST['putonline'])) { $query = "UPDATE user SET status= '1' WHERE id= '$new_id'"; $result = $cid-> query($query); if ($result== TRUE) { header("location:EidEmp.php"); die(); } else { echo "Failed"; } } ?> Edited : Maybe Change Your header function with javascript function...
php,forms,symfony2,runtime-error
You have not included the Symfony EnityRepository class at the top of your form file so PHP is looking for it in the same directory as your form class. Hence the error message. Add this to your form class (or qualify EntityRepository inline): use Doctrine\ORM\EntityRepository; ...
I would change if ( $dir->isDir() ) to if ( $dir->isDir() && $dir != $root) to remove the root directory...
autoload should be moved out of require-dev: { "require-dev":{ "phpunit/phpunit":"4.5.*" }, "autoload":{ "psr-0":{ "Yii\\":"yii-1.1.14.f0fee9/" } } } You can test your composer.json file using composer validate. Your original file returned: ./composer.json is invalid, the following errors/warnings were found: require-dev.autoload : invalid value, must be a string containing a version constraint...
javascript,jquery,html,json,html5
the first "A" in AJAX stands for "Asynchronous" that means, it is not executed right after it has been called. So you never get the value. Maybe you could first, get the os list and then output what you need, like this: function createCheckBoxPlatform(myDatas) { $.ajax({ url: "/QRCNew/GetOS", type: "post",...
You done need to do anything with your controller. Add this change your view to <script> function calculate() { var myBox1 = document.getElementById('crop_quantity').value; var myBox2 = document.getElementById('per_rate').value; var result = document.getElementById('income_amount'); var myResult = myBox1 * myBox2; result.value = myResult; } window.onload = calculate(); </script> <div class="control-group"> <label class="control-label">Crop Quantity</label>...
file_exists: http://php.net/manual/en/function.file-exists.php is_dir: http://php.net/manual/en/function.is-dir.php Best way to do that is use dirname(__FILE__) which gets the directory's full path of the current file in ether unix of windows format. Then we use realpath() which conveniently returns false if file does not exist. All you have to do is specify a relative...
$query = "INSERT INTO `myDatabaseForAll`.`users` (`id`, `firstname`, `lastname`, `username`, `password`) VALUES (NULL, $firstname, $lastname,$username,$password)"; you need single quote around text feilds in sql queries change above query to $query = "INSERT INTO `myDatabaseForAll`.`users` (`id`, `firstname`, `lastname`, `username`, `password`) VALUES (NULL, '$firstname', '$lastname','$username','$password')"; ...
You need to join by account_id and also question_id SELECT * FROM `quiz_questions` INNER JOIN `quiz_answers` ON `quiz_questions`.`account_id` = `quiz_answers`.`account_id` AND `quiz_questions`.`question_id` = `quiz_answers`.`question_id` WHERE `quiz_questions`.`account_id` = '1840979156127491' ORDER BY `quiz_questions`.`question_id` ASC LIMIT 5 ...
You need some css for that #printOnly { display : none; } @media print { #printOnly { display : block; } } ...
.pencil{ width: 200px; height: 40px; border: 1px solid #000; position: relative; } .pencil:before{ content: ''; display: block; margin: 10px 0; width: 100%; height: 10px; border: 6px solid #000; border-width: 6px 0; } .pencil:after{ content: ''; display: block; height: 10px; border: 1px solid #000; border-width: 1px 1px 0 0; width:...
Your PHP is checking if $_POST['submit'] contains a value. Your form does not contain a form element with the attribute name="submit", so therefore it fails and moves straight to the else statement. If you want to check if the form was posted then you should instead check for: if (!empty($_POST))...
Actually, you should reserve in config/app.php file. Then, you can add In the Service Providers array : 'Menu\MenuServiceProvider', In the aliases array : 'Menu' => 'Menu\Menu', Finally, you need to run the following command; php artisan dump-autoload I assume that you already added this package in composer.json Sorry, I didn't...
Try: $.ajax({ url: "functions.php", dataType: "JSON", data: {id: id}, type: 'POST', success: function(json){ for(var i=0;i<json.length;i++){ alert(json[i].fname); } } }); ...
You can use 3-Events: - Start (Start-Sliding) -> Stop Player - End (End-Sliding) -> Start Player - Slide (Sliding) -> Move Player-Position $("#range").slider({ range: "min", start: function(event, ui) { player.pauseVideo(); }, stop: function(event, ui) { player.playVideo(); }, slide: function(event, ui) { player.seekTo(ui.value,true); return false; } }); Demo: http://codepen.io/anon/pen/EjwMGV...
Posting some more code would be nice. This should work. Use some jQuery or AngularJs or any other framework to make the .overlay initially hidden, then to make it visible when needed. If you need help, comment. If it helps, +1. EDIT $(function() { $('[data-toggle="popover"]').popover({ placement: 'bottom' }); $("#buttonright").click(function() {...
Note: You can just make a single file out of it to achieve your wanted output Use mysql_real_escape_string() to sanitize the passed-on value to prevent SQL injections You should use mysqli_* instead of the deprecated mysql_* API Form them in a single file like this (display.php): <html> <form method="post" name="display"...
Only values that are sent by a form will be in the GET or POST array. From what you are showing I conclude that you don't want to show the field in your form, so make it hidden. Add this inside your form tag: <input name="price" type="hidden" value="'.$price.'" class="inputClass"> Also,...
php,html,select,drop-down-menu
It is because you aren't ending the value attribute, so your selected option becomes <option value="optionvalueselected" -- 'optionvalue' being the value of your selected option, and 'selected' being the attribute you want to set, but won't be set because you never ended value The following should work: <select name="course_id" id="course_id">...
<?php $duration="1H10M5S"; $display=str_replace(array('H','M','S'), array(' Hour(s) ',' Minute(s) ',' Seconds'), $duration); echo $display; Output 1 Hour(s) 10 Minute(s) 5 Seconds Fiddle...
jquery,html,css,drop-down-menu
Firefox has some problems with select-background. You can try this code - it'll remove the arrow, and then you can add a background image with your arrow (I took an icon from google search, just put you icon instead) I get this on FireFox (You can use any arrow icon...
Your local host must be Windows, that doesn't differentiate between upper and lower case in file names and your web server Unix Based which does, simple as that.
javascript,php,jquery,html,css3
Ok, so i tried to decypher what you meant with your Question. To Clarify: He has this one page setup. inside the div Our Project, there are two Buttons or links Visit more. When clicked, he wants the About Section to be shown. All in all it is impossible for...
This looks like a job for glob, which returns an array of file names matching a specified pattern. I'm aware of the other answer just posted, but let's provide an alternative to regex. According to the top comment on the docs page, what you could do is something like this:...
php,sql-server,pdo,odbc,sqlsrv
Change it to: $this->link = new PDO( "sqlsrv:Server={$this->serverName},{$this->port};Database={$this->db};", $this->uid, $this->pwd ); The default SQL Server port is 1433. Note the curly brackets, they allow for class variables....
php,image-processing,imagemagick
I think you can locate the shape pretty accurately with a simple threshold, like this: convert image.jpg -threshold 90% result.jpg and you can then do a Canny edge detection like this: convert image.jpg -threshold 90% -canny 0x1+10%+30% result.jpg The next things I would be looking at are, using the -trim...
This is one way to do it, using preg_match: $string ="SomeStringExample"; preg_match('/^[b-df-hj-np-tv-z]*/i', $string, $matches); $count = strlen($matches[0]); The regular expression matches zero or more (*) case-insensitive (/i) consonants [b-df-hj-np-tv-z] at the beginning (^) of the string and stores the matched content in the $matches array. Then it's just a matter...
php,mysql,mysqli,sql-injection,sql-insert
In the New PHP code snippet, you are still vulnerable to injections. You are using a prepared statement in the insert part, but you are not actually using the preparations strengths correctly. When creating a prepared statement, you create a query in which you add placeholders instead of the raw...
Try this solution: var notrem = []; $('#Table1 tr').each(function(){ var currentRowHTML = $(this).find("td:first").html(); $('#Table2 tr').each(function(i){ var c= $(this).find("td:first").html(); if(c == currentRowHTML ){ notrem.push(i); } }); }); $('#Table2 tr').each(function(i){ if(notrem.indexOf(i) < 0){ $(this).remove(); } }); Explanation: First gather all indexes of Table2 that are equal and are not to be removed....
jquery,html,css,drop-down-menu
I have created a working example for you. You can find the jsfiddle in here This piece of code uses JQuery. (Remember, for these type of tasks, JQuery is your friend =] ). HTML <select id="dropDownMenu"> <option value="option1" selected="selected">yes</option> <option value="option2">no</option> </select> <br> <img id="picture" src="https://upload.wikimedia.org/wikipedia/commons/thumb/f/f5/House_Sparrow_mar08.jpg/220px-House_Sparrow_mar08.jpg"> Javascript function changeStyle(){...
$x and $y are only defined within the scope of the function. The code outside of the function does not know what $x or $y are and therefore will not print them. Simply declare them outside of the function as well, like so: <?php function sum($x, $y) { $z =...