In the UML class diagram the interface is equivalent to the interface concept in programming languages (a set of methods that the class that implement the interface should implement). I want to know if the interface in the component diagram has the same meaning. Are the interfaces mentioned in the component diagram the same interfaces that are detailed in the class diagram or should I treat every method in the component diagram as a separate interface?
There is actually no real difference between both. You can realize an interface with a class as well as with a component. Also you can show the realization in both cases with the socket/lollipop notation.
Components are not much different to classes. You can think of a component as a container that hosts a number of different classes. And if one of those classes realizes an interface you can expose that through the component (if you so wish). Additionally a component can have a lot of internal interfaces for its hosted classes.
Maybe can put contactsAppModel.init(); on the first line of your contactsApp.init() method.
A bigger question is; why is there no class file for int[]? Without such a class file there is no where to put such a method, so it is purely a language feature. It looks like a field of int[] but it not. They could have made it look like...
Without really knowing the particulars of your situation, the classic answer is this: if your class initializer requires a whole bunch of arguments, then it is probably doing too much, and it should be factored into several classes. Take a Car class defined as such: class Car: def __init__(self, tire_size,...
<?php abstract class abc { protected $te; } class test extends abc { public function __construct() { $this->te = 5; } public function team() { $this->te += 100; } public function tee() { return $this->te; } } $obj = new test(); $obj->team(); echo $obj->tee(); -- edit: to make at least...
How about this <?php class MyClass { public $myArray=array(); public $htm = NULL; public function __construct(&$format=NULL) { //.. //Mysql query as $stmt //.. $this->myArray=$stmt->fetchAll(PDO::FETCH_ASSOC); $i=0; foreach($this->myArray as $row) { switch ($format) { case 'Page1' : $this->htm .= $this->format1($row); break; case 'Page2' : $this->htm .= $this->format2($row); break; default: $this->htm .= $this->format_default($row);...
We commonly use StopWatch from Apache Commons StopWatch check the pattern how they've provided. IllegalStateException is thrown when the stop watch state is wrong. public void stop() Stop the stopwatch. This method ends a new timing session, allowing the time to be retrieved. Throws: IllegalStateException - if the StopWatch is...
These are Rails methods: You can find valid? here and its code on Github. Likewise with new_record?, you can find a description and its source code here. Also, here is a link to the Rails repository on Github. These methods are not defined in the project, they are defined in...
If I understand you correctly, you're saying that you want an inheritance hierarchy in your interfaces as well as your classes. This is how you'd achieve such a thing: public interface IBase { // Defines members for the base implementations } public interface IDerived : IBase { // Implementors will...
It looks alright for a basic implementation, beside that you shouldn't echo something inside a class. If you want see a well implemented solution, have a look into eloquent created by taylor otwell. That should give you heaps of ideas how to improve your code. https://github.com/laravel/framework/blob/4.2/src/Illuminate/Database/Connection.php...
c#,oop,architecture,software-design,code-design
Place a UserControl on each tab.
java,class,oop,methods,casting
When using inheritance within classes, overriding a method will ALWAYS call the child method regardless of casting. You can never change the type of an object, so a RockMusician - although it is an extension of Musician - is still a RockMusician and will be called by its type, not...
Use Getters and Setters. The below code will let the $mesh_name property be read, but not written by external code. class MyObject { protected $mesh_name = 'foo'; protected $accessible = ['mesh_name']; protected $writable = []; public function __get($name) { if( in_array($name, $this->accessible) ) [ return $this->name; } else { //...
Generally speaking, since this refers to the current instance, how is it possible that Fireball.onChat(PlayerChatEvent) is registered too? Because when you're constructing an instance of Fireball, this refers to the Fireball being constructed at execution time. The compile-time type of this is Spell, but if you print out this.getClass()...
Use array_object[i]->get_data(); instead of array_object[i].get_data();. The DOT(.) operator is used when an object try to access its class member functions/variables whereas Arrow(->) operator is used if the object is a pointer. Now, you declared Matrix *array_object[100]; Which means array_object is an array of Matrix pointers. Hence you need to use...
I would create a list of all your matrices using mget and ls (and some regex expression according to the names of your matrices) and then modify them all at once using lapply and colnames<- and rownames<- replacement functions. Something among these lines l <- mget(ls(patter = "m\\d+.m")) lapply(l, function(x)...
Answer: None of the above. Try something like this: function Car(loc) { this.loc = loc; } Car.prototype.move = function () { this.loc++; }; var obj = new Car(someLoc); obj.move(); This uses object prototyping which is JavaScript's implementation of object-oriented programming. You can read more about prototypes and inheritance here on...
php,class,oop,laravel,laravel-5
That's simple php stuff. Set the attribute as static and access it with ::. class LanguageMiddleware { public static $languages = ['en','es','fr','de','pt','pl','zh','ja']; } @foreach (App\Http\Middleware\LanguageMiddleware::$languages as $lang) ... @endforeach You should not have that in a middleware though. You'd better add a configuration (i.e in /config/app.php) with that array, and...
You can't use type hints with scalar values ( in you case string - check the docs) Change your constructor in this way: public function __construct($scheme, $hostname, $www) { $this->scheme = $scheme; $this->hostname = $hostname; $this->www = $www; } and it should work...
java,oop,object,inheritance,immutability
They are called enumarations. You can find detailed info here they are defined as: public enum Day { SUNDAY, MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY, SATURDAY } and used as: public class EnumTest { Day day; public EnumTest(Day day) { this.day = day; } public void tellItLikeItIs() { switch (day) {...
Yes, you can use only underscore for the class name. class _{ function __construct(){ echo 'It works!'; } } new _(); Output: It works! DEMO...
Assuming your EntityQuery.groovy ( model )looks like : private String typeName private Order order Assuming you have Order.groovy ( model ) that looks like : private String fieldName; private String orderType; private String orderName; use these model chain as a parameter, I think that is still strongly-typed (correct me). Your...
You can use get_class() passing it the current object reference, like so: class Base_class { function __construct() { $calledClassName = get_class($this); } } Edit: You can find more info on get_class() in the PHP manual http://php.net/manual/en/function.get-class.php...
The only way to do exactly what you're asking for is to subclass python build-in class list. This should help....
python,function,class,oop,methods
Not sure I got your question right, but you may want to try: def getStats(self): return "width: %s\nheight: %s\narea: %s\nperimeter: %s" % (self.width, self.height, self.area(), self.perimeter()) To satisfy requirements 4 and 6, I would suggest something like: class Shape(object): def area(self): raise NotImplementedError def perimeter(self): raise NotImplementedError class Rectangle(Shape): def...
javascript,class,oop,object,methods
Welcome to the world of javascript where you are not using it to just paint and moves boxes :) Coming to your question: //Initialize objects var spaceButton = new Navigation('#spaceWarp'); var stars1 = new Stars('#stars1'); var stars2 = new Stars('#stars2'); var stars3 = new Stars('#stars3'); The initialization of your objects...
Your posted sample code has syntax errors. Fix those and the code does what you're wanting. public class Customers { private List<String> names; public Customers(List<String> names) { this.names = names; } public List<String> getNames() { return names; } @Override public String toString() { StringBuilder sb = new StringBuilder(); for (String...
python,python-2.7,oop,properties,encapsulation
You need to use self. when accessing member variables: def __init__(self): self.__pro = 1 @property def pro(self): return self.__pro *10 ...
You are trying to print print witch.enemy_name But the attribute is self.name = enemy_name So you should be calling print witch.name ...
An Actor by definition is external to the system under consideration. Therefore if you are writing use cases for the system Facebook then Facebook itself cannot be an Actor....
This will solve the problem, seasonMap contains values in the order you need (assuming classes implement Comparable) Map<Season, Map<Building, List<Info>>> seasonMap = new TreeMap<>(); for (Building building : buildings) { for (Map.Entry<Season, List<Info>> e : building.infosBySeason.entrySet()) { Season season = e.getKey(); List<Info> infos = e.getValue(); if (!seasonMap.containsKey(season)) { seasonMap.put(season, new...
I have no idea how or whether this is possible with VP (I know for sure that you can't do it with Enterprise Architect which is pretty much UML2.x compliant). But you could hook the link near the position in the appropriate compartment (EA also has a feature to lock...
You're doing two conflicting things $con= new mysqli('localhost','root','','afiliate'); $query="SELECT * FROM product WHERE ID=? "; $stmt->bind_param("i",$ID); /* $ID has a value, it's ok */ $stmt->execute(); So at this point $stmt is a mysql_stmt object. If you have mysqlnd installed you can do this $result = $stmt->get_result(); while($row=$result->fetch_row()){ echo $row['name']; }...
ruby-on-rails,ruby,uml,enterprise-architect
You can assign a stereotype to the database column like <<column>>. That will clearly differentiate between columns and instance variable. In EA you can create properties for a couple of languages, but not for Ruby. What EA does in those cases is to create <property get> and <property set> stereotyped...
Create a variable to store your prepared statement then execute that. $connection = MYSQLDatabase::getInstance()->getConnection(); $statement = $connection->prepare("INSERT INTO users etc etc......."); $insertArray = $statement->execute(array( ":username" => $_POST["username"] )); ...
I think the problem is in this line: currentNodePtr->data = &new_car; of the function void StringOfCar::push(Car & new_car). That should be currentNodePtr->data = currentCarPtr; ...
When you create a class instance, the metaclass's (whose instance the class is) __call__ is called. # Instantiate class. StandardClass() # StandardClass.__call__ is not called! When you create a class instance and then "call" the instance, then the class's __call__ is called. I don't think decorating __call__ with classmethod will...
lorem is a method of an anonymous sub-class of B. Therefore you can't call it by using a reference of class B, and since it's anonymous, you can't cast b to a type that contains lorem.
$role = userrole::get_premium_subscritpion(1); I notice that you are trying to call a non-static function in a static way You may either change the function to static or change the way you call this function public static function get_premium_subscritpion { or $obj = new userrole(); $role = $obj->get_premium_subscritpion(1); ...
There are a lot of questions on dynamic_cast here on SO. I read only a few and also don't use that method often in my own code, so my answer reflects my opinion on this subject rather than my experience. Watch out. (1.) Why is casting up/down considered bad design,...
It depends on whether you have many fields specific to agenda (not to month). If you do, it's better to have one separate model for agenda. BTW, It seems user and agenda are many-to-many relationship. In this case, you need one intermediate model between user and agenda. ...
You're doing it wrong First thing is that PHP4-style constructors are deprecated, use __construct method to define a costructor. Second is that you must not return from constructor but rather keep the connection object inside class as instance property. Third is that you must call parent methods using parent keyword....
With CommonJS (Browserify), what you export will be what you get when you call require (however, be careful with assuming what you export is a singleton, it's not always the case from my experience). So in this case, you want to export the Human class directly. Then in each file...
You can use at least three ways to do it: property_exists() isset() ReflectionClass::hasProperty() All of these are demonstrated below: <?php class myClass { public $a=1; public $b=2; public $c=3; } $myObj = new myClass(); $reflectionClass = new ReflectionClass($myObj); foreach (['a', 'b', 'c', 'd'] as $property) { printf("Checking if %s exists:...
Design patterns are solutions to programming problems that automatically implement good design techniques. Someone has already faced the issues you’re facing, solved them, and is willing to show you what the best techniques are. Answer to your question is - Design patterns are higher level than libraries. Design patterns tell...
Here is an example of a swift program that deals with pets. I found it on here. It has a protocol Animal that defines parts to an animal, with int legs, and boolean domesticated. protocol Animal { var legs: Int { get set } var domesticated: Bool { get }...
Your solution is perfectly valid for Java. You are actually using the design pattern Use Composition Over Inheritance. As @Naruto_Biju_Mode says in a comment, if you are using Java 8, you can move the implementation to a default method of Transformable however you would have to make the helper class...
Simply create a normal class without static methods, ditch the singleton pattern aside, and create an instance. The burden of singleton pattern usually outweigh any benefit....
Modify your addError function: public function addError($error, $key=false){ if($key){ self::$_errors[$key] = $error; }else{ self::$_errors[] = $error; } } Then it will go like this: if(strlen($value) < $rule_value){ $this->addError("More than {$rule_value} characters are needed as {$item}.", 'min_notmet'); } If you don't provide $key parameter, it will just add the element as...
Because scope in which function2 is defined does not contain definition of object1. Then when you try to access object1.object2 it throws error because object1 is not defined
You dont need to add two function to do same work all you need to do is pass parameter to function public function getResultsByID($userID = null,$flag){ $sqlParams = array(); if (!$userID) { throw new Exception("No User ID Provided"); } $sqlParams['userID'] = $userID; if($flag=value1){ $sql = "SELECT t.user_id,t.owner_id,t.store_id FROM users t...