No sum is necessary. I think you just need second condition "until that row": select e.*, (select count(*) from `events` as e2 where e2.country = e.country ) as times, (select count(*) from `events` as e3 where e3.country = e.country AND e3.id <= e.id ) as accumulated from `events` as e...

In each loop, you are appending characters to formSoFar. What you want to do instead is have it start with some value and edit it as you go: formSoFar = ['-'] * len(formula) while not game_over and wrong_guesses < max_guesses: guess = raw_input(...) if guess in formula: for i, c...

java,java-8,reduce,java-stream,accumulate

The combiner does not reduce a list of 0's and 1's. When the stream is not run in parallel it's not used in this case so that the following loop is equivalent: U result = identity; for (T element : this stream) result = accumulator.apply(result, element) return result; When you...

You seem to want the sum of all values to the end of the list after each element summed=[] den_list = map(int,den_list) for i,j in enumerate(den_list[:-1]): summed += j,sum(den_list[i+1:]) If you don't want to keep the original values in the list summed=[sum(num_list[i+1:])for i,j in enumerate(num_list[:-1])] ...

I know this will not directly address your question, but I'll get back to that. I highly recommend writing out the logic you need to complete your goal. Do this on paper, and feel free to make arrows pointing between what's related, what criteria is needed to accomplish goals, and...

matlab,vectorization,accumulate,accumarray

Given: CylCoorsSample = [263.0000 184.2586 10.0000 264.0000 183.0417 10.0000 264.0000 182.1572 10.0000 82.0000 157.4746 11.0000 80.0000 158.2348 11.0000 86.0000 157.3507 11.0000 84.0000 157.7633 11.0000] PointValuesSample = [0.4745 0.5098 0.5020 0.4784 0.4510 0.4431 0.5804] You can use accumarray as follows (using the third output of unique to generate the required subs...

You have to accumulate the value for each year, which means for 12 consecutive elements in your input vector. Each time you hit the 12th elements, your accumulator has the expected value. double currentrain = 0; for(int i = 0; i < rainfall.size(); ++i) { // accumulate rain this year...

New solution: template <bool J> using disable_if=enable_if<!J>; template <typename T,typename... Tail> struct getHead { typedef typename decay<T>::type type; }; template<typename... Args,typename = typename disable_if<is_same<typename getHead<Args...>::type,Point<T,N> >::value >::type > Point(Args&&... args) : std::array<T,N> {{args...}} { //... } I believe this solution is perfect.We stop forwarding reference variable parameter constructor only when...

python,list,dictionary,tuples,accumulate

You can use defaultdict: from collections import defaultdict mylist = [('birthday', 1), ('ramen', 2), ('cake', 1), ('ramen', 1), ('cake', 2), ('ramen', 1)] d = defaultdict(int) for k,v in mylist: d[k] += v print(d) # defaultdict(<type 'int'>, {'cake': 3, 'birthday': 1, 'ramen': 4}) ...