unexpected output while using strlen function
strlen simply counts the number of bytes whose value are not 0x00 (also known as NULL, which the C standard uses for string terminator). Since calloc initializes memory to 0x00 after allocating it, strlen returns 0 because the first byte is already NULL....
typedef pointer using fgets to input data, but takes last fgets
strdup will allocate a properly sized buffer and make a copy of the string, e.g. array[n].street = strdup( line ); As it is, street, city and state all point to line, which gets overwritten every time you call fgets....
Calloc a Two-Dimensional Array
Use: int ** own; // int**, not int* own = calloc(mem_size, sizeof(int*)); //int*, not int // And remove the explicit cast. ...
Freeing a multidimensional array when allocation fails
Since you are exiting the program in case of allocation failure, therefore no harm in doing this. You can use second snippet. C does not provide direct support for error handling, aka exception handling. On MSVC you can try this (Note that this is not the part of C standard):...
“Heap corruption detected” when using free()
You are overwriting beyond the bounds of array here: rev[len] = '\0'; You have allocated only len chars. Instead you can allocate len +1 chars. Thus causing undefined behaviour. This probably resulted the corruption of meta data which results in free()'s failure. Also, don't cast the return of malloc()/calloc() etc....
Why does calloc always returns NULL when I pass a “big” size?
You've said that sizeof (size_t) == 2 (this is for MS-DOS 6.22). That means that the maximum value of size_t is 65535. unsigned long buffSize = 65536; /* 64 KB */ No problem so far. unsigned long must be at least 32 bits (and is 32 bits on your system),...
Segmentation fault in 2D array unsigned char using calloc in C
There is a typo in this statement. Instead of sizeof( unsigned char ) you have to use sizeof( unsigned char * ) newmatriz = (unsigned char**) calloc(width, sizeof(unsigned char *)); ^^^^^^ Also this if statement is incorrect if ( newmatriz[j] = calloc(witdh, sizeof(unsigned char) ) == NULL){ In this statement...
Allocating memory of a 3 Dimentional array using calloc in c
c,arrays,dynamic-memory-allocation,calloc
What value of SIZE did you use? 0 or 1 would cause a crash, and more than 2 would make it crash. Are you using SIZE everywhere you really to? Otherwise you are only calloc - ing 2 and other uses of the hard coded '2'...should be changed to SIZE...
calloc created array is not acting as expected
c++,pointers,memory-management,calloc
Probably your debugger doesn't know how big buffer_buffer is, since that variable is simply declared as being a pointer to an int. (That's not correctly typed; buffer_buffer is used to hold values of buffer which is an int*, so buffer_buffer must be an array of int*, which means that you...
Failing to alloc memory received by a pointer linux
Priority Nr 1 After looking at your code a bit more, I suspect you're casting as much as you do, because you kept getting compiler warnings about "incompatible [pointer] types" and the like. Those warnings exist for a reason: there's an issue, a possible source for bugs there. Don't hush...
C Array Behaviour - Global / Local / Dynamic
c,arrays,malloc,dynamic-arrays,calloc
In the first code block you've allocated memory and saved the pointer to it in 'x_values'. In the second block you change 'x_values' to point to the 'x' array. The 'x' array already has memory allocated to it for 100 floating point values. You will no longer have a pointer...
Some calls to “calloc” are suspiciously fast [duplicate]
It can confirm that the second calloc takes much shorter time. It seems that Linux decides to postpone some of the actual work. On my system, the first calloc takes around 0.7 seconds. If I then iterate over the allocated memory area, setting it to something other than zero, this...
Unable to properly free malloc of another malloc [duplicate]
c,malloc,free,dynamic-memory-allocation,calloc
In your code RESERV[i]="Iambananananananananananana"; creates the problem. It overwrites the memory allocated by malloc(). Thus, You face memory leak, because the malloc()ed pointer is lost. You cannot call free() with the changed pointer. It invokes undefined behaviour. Solution: In C, you don't assign strings, instead, you can use strcpy() to...
Malloc/calloc allocates an already allocated address
c,pointers,memory,malloc,calloc
sizeof rr is the size of the pointer. But you need to allocate enough memory for the struct. Use sizeof *rr or sizeof(rr_scheduler) to do that. As it stands in your program, you don't allocate enough memory for the struct and so write beyond the end of the block, thus...
Initialize dynamically allocated structures within dynamically allocated structures
you did not declare myDynamicMembersBinArray: struct dynamicbin* myDynamicMembersBinArray = calloc(1, sizeof(struct dynamicbin)); struct bin *binpointer = (struct bin*)calloc(N, sizeof(struct bin)); should be (*myDynamicMembersBinArray).binPointer = calloc(N, sizeof(struct bin)); (the parentheses around *myDynamicMembersBinArray are important) or better myDynamicMembersBinArray->binPointer = calloc(N, sizeof(struct bin)); and last but not least printf("%f\n", (*(*myDynamicMembersBinArray).binPointer+i).size); should be printf("%f\n",...