java,android,date,date-format,simpledateformat
Simple: don't use the deprecated new Date(String) constructor. Instead, create a SimpleDateFormat with the right format, and use the parse method. DateFormat format = new SimpleDateFormat("yyyy-MM-dd", Locale.US); format.setTimeZone(TimeZone.getTimeZone("etc/UTC")); Date date = format.parse("2015-02-07"); Always look at compiler warnings such as when you're using deprecated members. They're usually deprecated for a reason!...
c#,excel,datagridview,date-format
If you are using SQL Server, try to set the datatype of those columns to Date instead of DateTime.
i don't know if i fully understand the problem but please try this: $date = date("M y", strtotime($s_event_start_month.' '.$s_event_start_year)); or $date = date("M y", mktime(0, 0, 0, $s_event_start_month, 1, $s_event_start_year)); about mktime...
The easiest way to get the output you need is to use the DateTime class, in particular: DateTime::createFromFormat: $date = DateTime::createFromFormat('m/j/y', $_GET['datepicker']); //now to get the outpu: $arr[$i] = $date->format('Y-m-d'); There is a procedural-style alternative, too: $date = date_create_from_format('m/j/y', $_GET['datepicker']); //note, date_create_from_format returns an instance of DateTime $arr[$i] = date_format($date,...
Try like this: SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd"); Date c= sdf.parse("2015-05-26"); String date=sdf.format(c); System.out.println(date); To format the current date in yyyy-MM-dd format you can try like this Date date = new Date(); String str = new SimpleDateFormat("yyyy-MM-dd").format(date); Kindly refer SimpleDateFormat...
date,date-format,modx,modx-revolution
http://rtfm.modx.com/display/revolution20/Input+and+Output+Filters+%28Output+Modifiers%29 - you need :strtotime modificator before :date - [[+mydate:strtotime:date=`%Y-%m-%d`]] ...
Try with this code, NSDateFormatter *dateFormatter = [NSDateFormatter new]; [dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss"]; [dateFormatter setTimeZone:[[NSTimeZone alloc] initWithName:@"Europe/London"]]; return [dateFormatter dateFromString:dateString]; ...
java,date,date-format,simpledateformat
Try with SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX"); Notice that MM represents months, while mm represents minutes. if you want to have 24h format use HH, hh is for 12h format XXX represents time zone in format like -08:00 to add literal like T in format you need to surround it...
java,date-format,simpledateformat
You should make the following modification : System.out.println("DOB of " + nameOne + ": " + format.format(dobOne) + "."); System.out.println("DOB of " + nameTwo + ": " + format.format(dobTwo) + "."); SimpleDateFormat has the format(Date date) method for this purpose....
try using the Calendar class, instantiate one using the current time, and the other using the members birthday, then use the add method to figure out the age. Remember that you will have to compare the month and day as well otherwise you will end up just with the age...
mysql,date,date-format,str-to-date
How about stuffing the characters you need into the string? Something like this: select str_to_date(insert(col, 1, 1, '20'), '%X%u') ...
sql,sqlite,date-format,date-formatting
If the fields in the date string are properly padded with zeros, you can extract them as substrings: UPDATE MyTable SET MyDate = substr(MyDate, 7, 4) || '-' || substr(MyDate, 1, 2) || '-' || substr(MyDate, 4, 2) ...
excel,date,phpexcel,date-format
For clarity if other people encounter this problem: Spreadsheet contains date 02/04/2014 You/Client/Boss entered date to be: m/d/y or February 4th, 2014 PHPExcel sees it as: d/m/y or April 2nd, 2014 The solution is to avoid the situation altogether by using the correct date formatting when the spreadsheet is created...
java,datetime,timezone,date-format
Just set the time zone you want the time to be displayed in using DateFormat#setTimeZone(TimeZone) Date now = new Date(System.currentTimeMillis()); DateFormat EXPIRE_FORMAT = new SimpleDateFormat("MMM dd, yyyy h:mm a z"); EXPIRE_FORMAT.setTimeZone(TimeZone.getTimeZone("America/Montreal")); // or whatever relevant TimeZone id System.out.println(EXPIRE_FORMAT.format(now)); AFAIK, there is no EST currently. It's all EDT in Spring. The...
php,symfony2,doctrine2,date-format
I have solved it by setting query like this : if (!empty($departureDate)) { $date = new \DateTime; $qb->andWhere('t.departureDate <= :departureDate') ->setParameter('departureDate', $date->createFromFormat('d/m/Y',$departureDate)); } ...
java,datetime,date-format,simpledateformat
There are a few problems with your code: You never initialize date to anything other than null, thus you'll get a NullPointerException at System.out.println("date = " + date);. The date string you provide is Tue, 27 Jan 2015 07:33:54 GMT, yet you ask the output to be Tue, 27 Jan...
Yes, it is ISO 8601. 2006-09-01T07:00:00.000+0000 is the first day of the ninth month of the year 2006, 7 hours, 0 minutes, 0.000 seconds offset 0 hours from UTC. Whether or not decimals are allowed is up to the parties exchanging dates (which is a fancy way of ISO saying...
java.util.Date doesn't have format. Its just Date. You can make it print its values in any form you want, by using SimpleDateFormat...
I solved this this way final String format = Settings.System.getString(getContentResolver(), Settings.System.DATE_FORMAT); if (format.contains("MM-dd")) { //US date format //do something } Also check this post because the format is sometimes empty string....
php,date,date-format,strtotime
You could try the DateTime object function createFromFormat $date = DateTime::createFromFormat('D - M d, Y', 'your date here'); echo $date->format('Ymd'); ...
java,date-format,simpledateformat,java.util.date
If I understand your question, then yes. Using the pattern letters given in the documentation for SimpleDateFormat and something like public static void main(String[] args) { String fmtString = "EEEE MMM d, yyyy 'at' h:mm a"; // E - Day name in week // M - Month in year //...
Use Weekday and WeekdayName functions WeekdayName(Weekday(startDate)) Weekday , which returns a number that indicates the day of the week of a particular date. It considers the ordinal value of the first day of the week to be one. WeekdayName , which returns the name of the week in the current...
date_format takes a date and converts it to a string, which means you are comparing two strings, forcing lexicographical comparison instead of comparing real dates. Instead, you should user str_to_date to convert meta_value to a date before you compare it to the current date: STR_TO_DATE(ds_postmeta.meta_value, '%m/%d/%Y') >= CURDATE() ...
java,date-format,simpledateformat,jdatechooser
The y (lowercase Y) format means "year". Y (uppercase Y) you were using means "WeekYear". Just use y and you should be OK: DateFormat target=new SimpleDateFormat("MMM dd, yyyy"); String P_date="2014-11-18"; Date test1 = new SimpleDateFormat("yyyy-MM-dd").parse(P_date); String converted_date=target.format(test1); Date test=target.parse(converted_date); ...
java,date,date-format,simpledateformat
replace XXX with Z, String dateTimestr = "2014-06-09T00:01+0200"; SimpleDateFormat s = new SimpleDateFormat("yyyy-MM-dd'T'HH:mmZ"); s.parse(dateTimestr); to print, System.out.println(s.format(s.parse(dateTimestr))); using Java 8, OffsetDateTime dateTime = OffsetDateTime.parse("2014-06-09T00:01+02:00"); System.out.println(dateTime.toString()); Note that OffsetDateTime.parse would only work if your string is proper ISO8601 date format. If your date is in different format then you have to...
ios,datetime,nsdate,nsdateformatter,date-format
Check your device settings for 24 hour time. If it is on, turn it off. Your code is perfectly fine. I am getting output as shown below : Today's Time: 04:31:58 PM If you don't want to show seconds use this code : [formatter setDateFormat:@"hh:mm a"]; ...
Found this Right way to do this. DateTimeFormatter formatter = new DateTimeFormatterBuilder() .append(null, new DateTimeParser[]{DateTimeFormat.forPattern("yyyy-MM-dd").getParser(), DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss").getParser()}) .toFormatter(); ...
As you are using attribute in lower case like (%a,%d,%i...) instead of using %H you also can use %k for 24 hour format so use SELECT date_format(str_to_date('Fri Jan 31 22:06:30 UTC 2014','%a %b %d %k:%i:%s UTC %Y'),'%D %b %Y');...
javascript,php,datetime,date-format
I worked on building this API. Mark is correct, the issue was on our end and not with the request you were making. I've made some updates now so it should be able to handle any valid string that can be passed into the javascript Date constructor. I'm also not...
java,date-format,simpledateformat
I use SimpleDateFormat in changing date formats. Try this: String OLD_FORMAT = "yyyy-MM-dd"; String NEW_FORMAT = "dd-MMM-yyyy"; String oldDateString = "2015-04-08"; String newDateString; SimpleDateFormat sdf = new SimpleDateFormat(OLD_FORMAT); Date d = sdf.parse(oldDateString); sdf.applyPattern(NEW_FORMAT); newDateString = sdf.format(d); ...
asp.net,asp.net-mvc-5,jquery-ui-datepicker,date-format,datefield
Your problem lies in the fact that you have not set proper Culture for your application. Your request end-up executing under culture that has month-day-year order (probably under en-US) causing you a problem. The easiest solution is to set set the culture that actually has day-month-year order and . as...
I would use the overload of parse which takes a ParsePosition - you can then check the position afterwards: import java.util.*; import java.text.*; public class Test { public static void main(String[] args) throws Exception { DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); dateFormat.setLenient(false); System.out.println(parseFully(dateFormat, "2015-02-02")); System.out.println(parseFully(dateFormat, "2015-02-02 23:23:23")); } private static Date...
java,date,date-format,simpledateformat
Minutes are set up by m not M Years are set up by y not Y Days (in month) are set up by d not D (in year) SimpleDateFormat format2 = new SimpleDateFormat("yyyyMMddHHmm", Locale.ENGLISH); Source...
var d = new Date(1397639141184); alert(d.getDate() + '/' + (d.getMonth()+1) + '/' + d.getFullYear()); ...
javascript,angularjs,date-format,angular-ui-bootstrap,timezoneoffset
I think it is a TZ issue, b/c the difference between your GMT+0100 and your StartDate=2014-06-09T23:00:00.000Z is 5 hours. . The issue: Your local time is currently BST (British Summer Time) equivalent to GMT +1 This is going to be the default time when you make your API call. However,...
java,android,datetime,date-format,simpledateformat
This issue has been resolved by using joda time The code snippet for the same is: public static long tokenTimeDuration(String loginTime, String expiryTime){ DateTimeFormatter FMT = DateTimeFormat.forPattern("EEE MMM dd HH:mm:ss a z yyyy"); final DateTime dt1 = new DateTime(FMT.parseDateTime(loginTime).withZone(DateTimeZone.getDefault())); Log.i("du_loginTimeAfterParsing",dt1.toString()); final DateTime dt2 = new DateTime(FMT.parseDateTime(expiryTime).withZone(DateTimeZone.getDefault())); Log.i("du_expiryTimeAfterParsing",dt2.toString());...
c#,string,date,date-format,culture
Your string format is wrong. It has to match your string format exactly. You can use dd-MMM-yy hh:mm:ss tt format instead. Here an example in LINQPad. string s = "16-Aug-78 12:00:00 AM"; var date = DateTime.ParseExact(s, "dd-MMM-yy hh:mm:ss tt", CultureInfo.InvariantCulture); date.Dump(); Custom Date and Time Format Strings Or, since dd-MMM-yy...
java,mysql,date,datetime,date-format
This works Perfectly SELECT * FROM attendance_entry WHERE absent_date=STR_TO_DATE('Fri Feb 20 00:00:00 IST 2015','%a %b %d %H:%i:%s IST %Y'); ...
java,android,date,date-format,simpledateformat
Use SimpleDateFormat: http://developer.android.com/reference/java/text/SimpleDateFormat.html SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yy"); Log.i("DATE", sdf.format(new Date())); You should store your instance of sdf, if you are planning to be formatting your dates repeatedly. Outside a loop, or as a class member variable, for example....
If I understand your question correctly you can hack around this as follows: $format = 'd/M/Y\tH:i'; $format = str_replace('\t', "\t", $format); echo date($format); You can see the fiddle here....
java,date-format,simpledateformat,args
This for loop goes over the command line arguments and searches for a pair of arguments in the form of -date 16/11/81 (the given date is just an example, of course). Once it finds it, it parses the second argument (16/11/81, in this case) to a java.util.Date object and stores...
javascript,jquery,jquery-ui,datepicker,date-format
In your case I would suggest to check the language like var userLang = navigator.language || navigator.userLanguage; // detect browser language but not a decent one if (userLang === "en-US") { $( ".selector" ).datepicker( "option", "dateFormat", "mm/dd/yyyy" ); } else { $( ".selector" ).datepicker( "option", "dateFormat", "dd/mm/yyyy" ); } Update:...
java,date-format,date-formatting
There are two elements to this question. First you need to calculate the appropriate Date value from your input format, which you should be able to do using java.util.Calendar: Calendar cal = new GregorianCalendar(); cal.clear(); cal.set(Calendar.YEAR, year + 2000); cal.set(Calendar.DAY_OF_YEAR, dayNumber); cal.add(Calendar.SECOND, numSeconds); // add handles overflow from one field...
import java.text.SimpleDateFormat; import java.util.Date; String your_date = "2014-12-15 00:00:00.0"; DateFormat format = new SimpleDateFormat ("yyyy/MM/dd",Locale.ENGLISH); Date new_date = format.parse(your_date); System.out.println(new_date); ...
jquery,css,asp.net-mvc,date-format,datetimepicker
I ended up using xdsoft datetimepicker as @StephenMuecke suggested. This is an excelent tutorial for that purpose with everything that xdsoft datetimepickler offers: http://xdsoft.net/jqplugins/datetimepicker/ I had difficulties because I included the jquery scripts in my Layout and my _Create PartialView, so if you are using Partial view, be careful. ...
asp.net,date-format,datetime-format
You will have to escape the quote using a backslash. To avoid escaping the backslash I have used verbatim string literal (prefixed with @): @"ddd, MMM dd \'yy" ...
sql,substring,date-format,getdate
Try this: CONVERT(VARCHAR(8),GETDATE(),12) The list of available formats can be found here: http://msdn.microsoft.com/en-us/library/ms187928.aspx...
You would do some kind of join between the the two tables and select entries from the join. A simple cartesian join can be achieved by comma-separating the tables you are querying from. create table holidays ( name text not null, fromdate text not null, todate text not null );...
java,date,calendar,timezone,date-format
The reason that cal.getTime() is still printing EST is because java's Date object (which is what cal.getTime() returns) does not contain timezone information. The String representation of a Date object is misleading, as it includes the timezone of your computer (in your case, EST). I live in Oregon, so if...
java,date,netbeans,int,date-format
I don't follow how your format is a SSN, but you could read it as a String. public static void main(String[] args) throws FileNotFoundException { Scanner iScanner = new Scanner(System.in); System.out.println("Enter your SSN in the formate YYDDMM:\n"); String ssn = iScanner.nextLine(); System.out.println(ssn.substring(ssn.length() - 2)); } The issue with trying to...
mysql,date,timestamp,date-format
If you want to consider one week back from now including the hour-min-sec using date_sub function you can get it as mysql> select date_sub(now(), interval 1 week) as d ; +---------------------+ | d | +---------------------+ | 2015-05-26 15:33:15 | +---------------------+ 1 row in set (0.01 sec) So the query becomes...
If you want the ISO year as well as the ISO week, use the IYYY format model: select to_char(sysdate,'IYYYIW') from dual; TO_CHAR(SYSDATE,'IYYYIW') ------------------------- 201501 Mixing ISO and non-ISO will give you odd results. You can see the difference this makes with something like: with t as ( select date '2014-12-19'...
.net,vb.net,date,date-format,cultureinfo
If you know the format of the string and this won't change you should use DateTime.TryParseExact using the InvariantCulture Imports System.Globalization Dim dateString As String = "31.12.1901" Dim dateValue As Date Dim dateFormat As String = "dd.MM.yyyy" If DateTime.TryParseExact(dateString, dateFormat, CultureInfo.InvariantCulture, DateTimeStyles.None, dateValue) Then 'In the format expected Else 'NOT...
android,date-format,simpledateformat
First your formatter should be: SimpleDateFormat formatter = new SimpleDateFormat("E , d MMM yyyy",loc); The capitalazion rules for italian might be different, if you still want to change it one option is to use the wordutils from apache commons , add de dependency to your gradle.build compile 'org.apache.commons:commons-lang3:3.4' and then...
javascript,mysql,json,date,date-format
You didn't prepared your json string good enough, so you have: {"sommer":[{"event_name":"testevent","DATE_FORMAT (beginn, '%d.%m.%Y')":"28.01.2015","DATE_FORMAT (ende, '%d.%m.%Y')":"30.01.2015"}]} that's mean that your property name is "DATE_FORMAT (ende, '%d.%m.%Y')" but in your js code you are trying to get: item.beginn that has no sense. So my suggestion is to change your json string...
Oneliner with Regular Expression and .replace var timeStampArranged = timeStamp.replace(/([0-9]{4})\/([0-9]{2})\/([0-9]{2})/, "$2/$3/$1"); ...
m is the modifier for months. i is the modifier for minutes. Getting this wrong will obviously cause issues. Change: $thedate = date_create_from_format("m/d/Y h:m a", $thestring); to: $thedate = date_create_from_format("m/d/Y h:i a", $thestring); ...
Looks like you're using the wrong MySQL functions here. You're looking for STR_TO_DATE() which will convert that date string into a date value which MySQL can work with. You can then use DATE_FORMAT() to convert it to a new date string of your choosing. SELECT DATE_FORMAT(STR_TO_DATE(date, '%d/%m/%Y'), '%Y/%m/%d') AS t...
you have also milliseconds: SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US); ...
The problem will be if Range("A1") is not a number. So if it does have . in it then you cannot put that value into a long. declare l as string not a long and your code will work
php,datetime,date-format,utc,epoch
You forgot the backslashes in your format, and the dollar sign before startDateText in the dump: $start = new DateTime(date('r', '1372190184')); $startDateText = $start->format('Y-m-d\TH:i:s\Z'); var_dump($startDateText); Also, if you're looking for microseconds, add the u format character....
xml,xslt,date-format,simpledateformat
Now I only want the date without the time. Why don't you simply use: <xsl:value-of select="substring-before(@DeliveryTime, ' ')"/> This is assuming you want to keep the existing date format....