database,user,user-profile,date-of-birth,fullcontact
Usually the "Birthday Represent the date of birth while the "Anniversary" represents the day of marriage.
sql-server,formula,date-of-birth
It looks like the original code is not taking today into account, it always starts tomorrow, which may be one reason why your new code is finding more people. However, consider your logic: DATEPART(DY,dateOfBirth) - DATEPART(DY, CURRENT_TIMESTAMP) > 0 According to this, if my date of birth was January 1st...
java,date,hsqldb,dayofweek,date-of-birth
The first use of INTERVAL is incorrect syntax. You can modify it like this: SELECT * FROM contacts WHERE DATE_ADD(dob, (CURDATE() - dob) YEAR) BETWEEN CURDATE() AND DATE_ADD(CURDATE(), INTERVAL 7 DAY); ...
The least verbose way to do this is with the DateTime classes and specifically with the DateTime::diff method. Note you should ensure the times are midnight for each date, then test if the birthday this year has already occurred. <?php $birthday = "1980-06-24"; // get date of birthday this calendar...
javascript,jquery,html,drop-down-menu,date-of-birth
If you want to do this manually.. This code should suffice (I'm pretty sure the pattern supports dd/mm/yyyy). function checkDateTime(newDate) { var pattern = '^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$'; var regex = new RegEx(pattern); if (typeof...
android,notifications,alarmmanager,date-of-birth
You could replace 'HERE' with a method that determines if the following February from today is in a leap year, and then returns the value 365 or 366 days (in the form of milliseconds mind you) based on those checks. private long millisUntilNextYear(){ //Set days in a year for Leap...
From the comments of this blog entry, I found the age_calc function in the eeptools package. It takes care of edge cases (leap years, etc.), checks inputs and looks quite robust. > library(eeptools) > x <- as.Date(c("2011-01-01", "1996-02-29")) > age_calc(x) # default is age in months [1] 46.73333 224.83118 >...
javascript,validation,date-of-birth
The reason you see many examples using a "return" goes along with the advantages of structuring your code into functions. This would be a good next step for you in learning to program. Functions will allow you to create chunks of code that are reusable and also easier to read...
ios,objective-c,uitextfield,date-of-birth
1) in the .h file of your view controller make sure you assign textfield delegate: @interface YourViewController : UIViewController <UITextFieldDelegate> and also have an IBOutlet of the birthday Textfield 2) declare a date picker as a class variable to make it accessible from all different methods in class. in the...
python,django,date,filter,date-of-birth
You'll have to check against a datetime.date that is the maximum allowed birth date: anyone born after that day will be younger than the min age: from datetime import date min_age = 24 max_date = date.today() try: max_date = max_date.replace(year=max_date.year - min_age) except ValueError: # 29th of february and not...
Try indx <- round(as.numeric(difftime(Sys.Date(), df$DOB, unit='weeks'))/52.25) df$grp <- cut(indx, breaks=c(0,13,18,25,Inf), labels=c('kid', 'Teen', 'Young Adult', 'Old') ) ...