sql-server,tsql,insert,datetime-format,datetime2
As pointed out the syntax with the convert is a little off. The syntax should be like below: SELECT CONVERT(datetime,'Sep 09 12:18:52 2014') ...
c#,date,datetime,datetime-format
Place a new line char in the format string, it worked for me DateTime.Now.ToString( string.Format("dddd, d MMM {0}'hour.' HH:mm", System.Environment.NewLine) , culture); ...
The problem is that the object nwdate is not a string. As a hack you might try this: (""+nwdate).replace(pattern, replacement); However this is very dependend on the system of the user....
sql-server,vb.net,datetime,datetime-format
SQL Server doesn't store a DateTime in any string format - it's stored as an 8 byte numerical value. The various settings (language, date format) only influence how the DateTime is shown to you in SQL Server Management Studio - or how it is parsed when you attempt to convert...
python,datetime,datetime-format
You can use string split to remove the timezone import datetime intstring = int( ('1433140740000+0200').split('+')[0]) print( datetime.datetime.fromtimestamp(intstring/1000).strftime('%Y-%m-%d %H:%M:%S') ) I had to change it to this to make it work intstring /1000...
javascript,angularjs,datetime-format,angularjs-filter,datetime-comparison
Comparison between the current date and date in JSON data works. To compare the JSON date with the current date we could use javascript .getTime() method that returns the number of milliseconds between midnight of January 1, 1970 and the specified date. http://www.w3schools.com/jsref/jsref_getTime.asp We could use the same thing by...
sql-server-2008,tsql,datetime-format
I didn't realize that smalldatetime doesn't store seconds. KekuSemau's answer wasn't quite the right answer, but it did make me realize I wasn't trying to do the right thing, given the datatype of the column I had to update (No, I couldn't change the datatype of the column). All I...
.net,xml,vb.net,date,datetime-format
First, you need to parse the original to be an instance of the DateTime struct. It just holds the date and time data, not any format: Date_Creation = Date.Parse(noeudEnf.InnerText.ToString) Then you can format it as a string: SomeString = Date_Creation.ToString("dd/MM/yyyy") ...
Change to SimpleDateFormat srcDf = new SimpleDateFormat( "dd.MM.yyyy HH:mm:ss"); So that is match your String. The symbols are explained here http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html Letter Date or Time Component Presentation ExamplesG Era designator Text AD y Year Year 1996; 96 Y Week year Year 2009; 09 M Month in year Month July; Jul;...
.net,oracle,oracle-sqldeveloper,datetime-format
MI in format means minute.. Hope you got it as month and i. I put it here as 10 for example. Same as AM in format means am or pm. INSERT INTO ITEMAPPROVAL ( REQUESTITEMID, USERID, APPROVALSTATUS, REQUESTSTATUSID, ITEMAPPROVALDATE, ITEMAPPROVALNOTE , APPROVEDAMOUNT) VALUES ('132568', '15', '1', '4', TO_DATE('06/02/1436:10:10:41am', 'mm/dd/yyyy:hh:mi:ssam'), ''...
javascript,json,date,datetime,datetime-format
You may format the json string into new Date() then use js methods to get month,day,year or what exactly you need. //format string to datetime var DispatchDt = new Date(this.DispatchDt); // then use this methods to fetch date,month, year needed //getDate() // Returns the date //getMonth() // Returns the month...
sql,sql-server,datetime,datetime-format,sqldatetime
Try this: INSERT INTO TABLE (FIELD) VALUES CONVERT(DATETIME, '2015-06-02T11:18:25.000', 126) 126 relates to ISO8601, which is the format yyyy-mm-ddThh:mi:ss.mmm. This is the same format as the string '2015-06-02T11:18:25.000'. For more information, see here. For dates with a datetimeoffset (for example '2015-06-02T11:14:06+02:00' - note the +02:00 at the end), you will...
php,mysql,datetime,datetime-format
change $lastsaving = date("2013-2-9"); to $lastsaving = date("2013-02-9"); Here, you can see the working one : http://codepad.org/uI0R6TvC The guy above me is right as well :) that would work too while(strtotime($lastsaving) < strtotime($date7)) { tested here : http://codepad.org/OY36ij3U...
mongodb,datetime,aggregation-framework,datetime-format
Oldest: db.posts.find({ "name" : "John" }).sort({ "date_time" : 1 }).limit(1) Newest: db.posts.find({ "name" : "John" }).sort({ "date_time" : -1 }).limit(1) Index on { "name" : 1, "date_time" : 1 } to make the queries efficient....
javascript,datetime,datetime-format
Unless you use a library there is no way to convert the value without manually splitting the string. var year = +oDate.slice( 0, 4); var month = +oDate.slice( 4, 2) - 1; // Month is zero-based. var day = +oDate.slice( 6, 2); var hour = +oDate.slice( 8, 2); var minute...
vb.net,datetime,datetime-format
You can use DateTime.ParseExact like: string str = "Mon Apr 14 03:31:15 +0000 2014"; DateTime dt = DateTime.ParseExact(str, "ddd MMM dd HH:mm:ss zzz yyyy", CultureInfo.InvariantCulture); For more information see: Custom Date and Time Format Strings For converting the parsed date to your required format do: string formattedOutput = dt.ToString("dd-MMM-yyyy HH:mm:ss",...
Try like this : Dim dt As DateTime = (New DateTime()).AddDays(0.559861111) it working for me it returns : 13:26:12 from 0.559861111 Hope it helps
sql,database,oracle,timestamp,datetime-format
You will want to use a command like this one TO_CHAR(date_value, 'DD/MM/YYYY hh24:mi:ss') This will convert the date to the format you're looking for, if not then you should be able to work with the command to alter it to the correct format. This does assume that the column is...
In this case the problem is caused becaus variables are case-sensitive, so $checkIndate and $checkInDate are two different variables. Correct this and you should be fine.
java,java-8,datetime-format,datetime-parsing,java-time
Okay I'm going ahead and posting it as an answer. One way is to create the class that will holds the patterns. public class Test { public static void main(String[] args){ MyFormatter format = new MyFormatter("dd.MM.yyyy", "M/dd/yyyy"); LocalDate date = format.parse("3/30/2014"); //2014-03-30 LocalDate date2 = format.parse("30.03.2014"); //2014-03-30 } } class...
javascript,date,datetime,datetime-format
Use Date methods to set and retrieve time and construct a time string, something along the lines of the snippet. [edit] Just for fun: added a more generic approach, using 2 Date.prototype extensions. var now = new Date(); now.setHours(now.getHours()+2); var isPM = now.getHours() >= 12; var isMidday = now.getHours() ==...
Try this.. $seconds = strtotime("2012-10-10 02:40:03") - strtotime("2010-12-25 05:15:02"); echo $days = floor($seconds / 86400); echo "</br>"; echo $hours = floor(($seconds - ($days * 86400)) / 3600); echo "</br>"; echo $minutes = floor(($seconds - ($days * 86400) - ($hours * 3600))/60); echo "</br>"; echo $seconds = floor(($seconds - ($days *...
php,mysql,datetime,datetime-format,date-manipulation
use in mysql: from_unixtime($yourvariable / 1000) Mysql timestamps are not in ms , but in seconds....
vb.net,.net-3.5,datetime-format
This has nothing to do with the conversion, which is OK. When the date is written to the console it is formatted (i.e. converted to a string) with a default format that happens to include the time part. Specify the desired format when printing: Console.WriteLine("{0:dd/MM/yyyy}", dt) or Console.WriteLine(dt.ToString("dd/MM/yyyy")) Note: the...
xml,url,uri,datetime-format,time-format
2015-04-27T00%3A00%3A00 apparently is the URL encoded (conforming to RFC 3986) form of 2015-04-27T00:00:00 (%3A encodes the colon :). This, in turn, is the standard ISO 8601 representation for 12:00 AM on April, 27th 2015 UTC. "2015-04-27 at 5:30pm CST" could hence be represented as 2015-04-27T17:30:00-06:00 in ISO, or 2015-04-27T17%3A30%3A00-06%3A00 in...
android,date,datetime,datetime-format,android-calendar
Set calendar time using simpleDateFormat.parse() and get field value from calendar : SimpleDateFormat simpleDateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss"); Calendar calendar = Calendar.getInstance(); try { calendar.setTime(simpleDateFormat.parse("11/20/2014 8:10:00 AM")); Log.e("date", "" + calendar.get(Calendar.DAY_OF_MONTH)); Log.e("month", ""+calendar.get(Calendar.MONTH)); Log.e("year", ""+calendar.get(Calendar.YEAR)); Log.e("hour", ""+calendar.get(Calendar.HOUR)); Log.e("minutes", ""+calendar.get(Calendar.MINUTE));...
vba,datetime,ms-access-2010,datetime-format,datetimeformatinfo
I have found one solution that I tested and it seems to work well in my database. I created a new field within the query - 'Format([DateOfEnquiry], "mm")' - and used this field for sorting.
c#,datetime,devexpress,datetime-format
You can use the appropriate properties of DateTime: Date and TimeOfDay: TimeSpan time = timeEdit1.Time.TimeOfDay; DateTime date = dateEdit2.Date; If you want to store them in one DateTime: DateTime dateAndTime = dateEdit2.Date + timeEdit1.Time.TimeOfDay; Now you have both in one, you can extract them as shown in my first snippet....
xpages,converter,datetimepicker,datetime-format
Is your page displaying a pre-saved value or is it just defaulting to the current date? If the former, you may be misunderstanding what the converter does. The job of the converter is to convert the server-side date/time value to a text string and vice versa. The converter code all...
java,java-8,datetime-format,java-time,jsr310
After some source digging, I found out that these are pre-defined in a private static final Map, called FIELD_MAP, which is a member of the DateTimeFormatBuilder class: /** Map of letters to fields. */ private static final Map<Character, TemporalField> FIELD_MAP = new HashMap<>(); static { // SDF = SimpleDateFormat FIELD_MAP.put('G',...
sql,sql-server-2008,datetime-format
You can use datepart(): select (case when datepart(hour, EndTime) = datepart(hour, getdate()) and datepart(minute, EndTime) = datepart(minute, getdate()) then 1 else 0 end) as status You can also put this into an update, if that is what you really want. EDIT: The update would be: update table set status =...
java,datetime,java-8,datetime-format
It turns out Java does not accept a bare Date value as DateTime. Using LocalDate instead of LocalDateTime solves the issue: DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd"); LocalDate dt = LocalDate.parse("20140218", formatter); ...
You could convert to the string first, then str_replace to correct the format? function apStyle($date){ $date = strftime("%l:%M %P", strtotime($date)); $date = str_replace(":00", "", $date); $date = str_replace("m", ".m.", $date); return $date; } ...
javascript,date,datetime-format
The fourth argument to Date.UTC is hours (0 to 23) so in your case it's 03:00:00 if you are located in the "zero" timezone. The MSDN example was probably written by someone sitting in e.g. Seattle.
axapta,datetime-format,dynamics-ax-2012,dynamics-ax-2012-r3
I fixed this issue. I changed the Property of "TimeZoneIndicator " property to "Never" on form field level. That fixed the issue.
c#,datetimepicker,datetime-format
Use the DateTime.Parse() method: var datePickerDate = dateTimePicker.Value; var comboboxTime = comboBox.SelectedText; var dateTimeString = String.Format("{0} {1}", datePickerDate, comboboxTime); var combinedDate = DateTime.Parse(dateTimeString); I'm not sure if you are writing a windows or web application, but the solutions are the same. Also you might want to use one of the...
With verrsion 4.6 and earlier you must parse the datetime strings 'manually' with strptime: set xdata time plot 'file1.dat' using (strptime('%Y.%m.%d', strcol(1))):2,\ 'file2.dat' using (strptime('%Y.%m.%d-%H:%M', strcol(1))):2 With gnuplot version 5 you can directly give a time format to the timecolumn function, so that you can use as much formats as...
The problem is, that STR_TO_DATE( 'Fri 07:16 AM', '%a %h:%i %p' ) results in 0000-00-00 07:16:00 and this happens to all your "dates". This means you loose the day-of-the-week information. You can fix this by replacing the day of the week by a date. E.g. You can use 2015-06-01 as...
I don't see a clear way to do this. The problem is that these are not actually ISO8601 values, at least according to SAS. SAS recognizes two versions of ISO: Basic (B8601DZ.) and Extended (E8601DZ.). Basic has no colons/dashes/etc., and Extended has all possible ones. Basic: 20130119T094039812+0000 Extended: 2013-01-19T09:40:39.812+00:00 (see...
php,wordpress,datetime,datetime-format
Try this. In php there is function date() and strtotime(). I made this to work good, but didn't test <li> <strong> <?php _e("Start Date:" , SH_NAME); ?> </strong> <span> <?php echo date("m-d-Y", strtotime(sh_set( $settings, 'start_date' )));?></span> </li> ...
python-2.7,date,datetime-format
Use %y instead of %Y: >>> d2 = datetime.datetime.strptime(d1,'%d.%m.%y').strftime('%Y-%m-%d') >>> d2 '2015-05-22' ...
vb.net,datetime,datetimepicker,datetime-format
I got the answer working fine. adding the following code to form load event served my purpose Dim dt = DateTime.Now.AddMonths(-1) me.DateTimePicker.Value = dt Thanks plutonix for your help....
python,python-2.7,datetime,datetime-format
Use strptime to create a datetime object then use strftime to format it they way you want: from datetime import datetime s= "2015-05-31 21:02:36.452000" print(datetime.strptime(s,"%Y-%m-%d %H:%M:%S.%f").strftime("%d-%b-%Y %H:%m:%S")) 31-May-2015 21:05:36 The format string is the following: %Y Year with century as a decimal number. %m Month as a decimal number [01,12]....
You can add the literal GMT surrounded by quotes: new SimpleDateFormat("EEE dd MM yyyy HH:mm:ss 'GMT'Z (zzzz)", Locale.ENGLISH); ...
jquery,date,jquery-plugins,datetimepicker,datetime-format
I added following method to set the current Date and Time to the DateTimePicker. It helped me to solve the issue. I have done some tricks to get the exact same format that I need. //Set Current Date & Time to "txtStart" var currentdate = new Date(); var datetime =...
c++,boost,time,datetime-format,time-format
Indeed, this seems a strange omission from the library. Then again, it doesn't look that strftime has the goods: http://en.cppreference.com/w/cpp/chrono/c/strftime So, what would it take to patch the time_facet implementation to get this? Here's the patch against boost 1.57's boost::date_time::time_facet.hpp (applied). 1d0 < 39a39 > static const char_type fractional_seconds_3digits[3]; //...
First: your pattern is invalid: @"\d{2}:\d{2}:d{2}" it must be: @"\d{2}:\d{2}:\d{2}" you missed one backslash \ before the last d Second: I guess by absolute value you mean the long dnt variable? If so then you need to parse the date by using one of the overloads and get the DateTime.Ticks....
java,timezone,java-8,datetime-format,java-time
I am not sure why it does not work (probably because your input does not have time/time zone information). A simple way is to parse your date as a LocalDate first (without time or time zone information) then create a ZonedDateTime: public static ZonedDateTime convertirAFecha(String fecha) { DateTimeFormatter formatter =...
php,string-formatting,datetime-format,php4
Have you ever tried strtotime? print date('d.m.Y H:i', strtotime('2003-07-23 10:15:00')); Code running on PHP 4...
The ToString() (and Format, etc) needs a culture to format the dates/times. It can't do without it. So if you don't pass an explicit culture to use, it just takes the current thread's default culture. Fortunately, you can change the current thread's culture pretty easily - just set System.Threading.Thread.CurrentThread.CurrentCulture. Note...
asp.net,date-format,datetime-format
You will have to escape the quote using a backslash. To avoid escaping the backslash I have used verbatim string literal (prefixed with @): @"ddd, MMM dd \'yy" ...
java,java-8,datetime-format,java-time,jsr310
It's been asked on the mailing list and the answer is that it is not possible because the original pattern is not retained. The same thread suggests using a DateTimeFormatterBuilder which does have the information....
filter,logstash,datetime-format,grok
The is malformed at "Mar/2014:15:36:43 +0100" part of the error message indicates that the timestamp parser has a problem with the month name. This suggests that the default locale is something other than English (specifically, a language where the third month isn't abbreviated "Mar"). This can be solved by explicitly...
The pattern you're looking for is: "YYYY-MM-DD HH:mm:ss.S", the key difference being the symbol used for minutes (you told it to parse them as months). From the javadoc of DateTimeFormat: M/L month-of-year number/text 7; 07; Jul; July; J m minute-of-hour number 30 ...
You could probably write/read DateTime to the registry with the following methods These methods are storing the DateTime in the QWORD registry format (A 64-bit binary number) public static void SetDate(string keyName, string valueName, DateTime dateTime) { Registry.SetValue(keyName,valueName, dateTime.ToBinary(), RegistryValueKind.QWord); } public static DateTime GetDate(string keyName, string valueName) { var...
There are several example apps included with Core Plot that demonstrate working with dates. See, for example, the "Date Plot" demo in the Plot Gallery app. You need to convert the date value to numeric values and use those for the x-values instead of the data index. Be sure to...
You should first parse the strings to TimeSpan TimeSpan start = TimeSpan.ParseExact(startTime, "hhmm", CultureInfo.InvariantCulture); TimeSpan close = TimeSpan.ParseExact(closeTime, "hhmm", CultureInfo.InvariantCulture); then you can use this LINQ query: List<TimesInfo> inRange = list .Where(ti => ti.startTime.TimeOfDay >= start && ti.closeTime.TimeOfDay <= close) .ToList(); ...
c#,datetime,asp.net-mvc-5,datetime-format,tryparse
If your iMapLocationDate.displayMapLocationStartDate value is "12/30/2015 3:09:32 PM" and you expect it to be always in this format, then use a format that exactly match it. Please try this format instead: string format = "MM/dd/yyyy h:mm:ss tt"; ...
ruby-on-rails,ruby,json,rspec,datetime-format
The solution was embarrassing simple — I had specify that the dates should be formatted using ISO 8601 using the to_formatted_s() method. Below is the correct, passing version: require 'spec_helper' describe 'GET /v1/tasks/:id' do it 'returns an task by :id' do task = create(:task) get "/v1/tasks/#{task.id}" expect(response_json).to eq( { 'id' =>...
ruby,sinatra,datetime-format,irb,rackup
Thanks for sharing your class, the issue is that Peep is expecting a Time object but you're sending it a formatted string. It be better practice to do this: class Peep include DataMapper::Resource property :peep_timestamp, Time def format_time self.peep_timestamp.strftime("%I:%M%p") end end now you can still instantiate the class with: @peep...
sql,sql-server,tsql,sql-server-2005,datetime-format
As the docs for CONVERT state, use 103 if you want the century and 3 if you dont: REPLACE(CONVERT(CHAR(10), ChargeArrival.CreatedAt, 3), '/', '') ...
Try this select TO_DATE(TO_CHAR(A.DATE,'DD/MM/YYYY') || ' ' || A.TIME,'DD/MM/YYYY HH24:MI:SS') from dual , TAB A This will work only if data in your A.TIME column is in format HH24:MI:SS. You should use case-when to deal with boolean expressions in select list. Select case when TO_DATE(TO_CHAR(A.DATE,'DD/MM/YYYY') || A.TIME,'DD/MM/YYYY HH24:MI:SS') < (TO_DATE('20/04/2015','DD/MM/YYYY')...
The problem is that the timestamp you are getting is in miliseconds, but PHP uses seconds. Simply divide what ever you get by 1000 and it will work. $timstamp = 1410290399037; $date = date('m-d-Y', $timstamp/1000); echo $date; ...
Well, then if your string data is ordered (and that's a big if) you could try with this code string data = "2:30, 3:00, 4:00, 5:00, 6:00, 7:00, 8:00, 9:00, 10:00, 11:00, 12:00, 1:00, 2:00, 3:00, 4:00, 5:00, 6:00, 7:00, 8:00, 9:00, 10:00, 11:00, 12:00, 1:00, 2:00"; string[] parts =...
java,date,datetime,datetime-format
You format string has a couple of mistakes: Y means the week year, not the year, which is y D means the day of the year. You should have used d, which means the day of the month. h means a 12-hour notation time of day. Since you have 14...
sql-server-2012,datetime-format
You could try converting that INT first to a VARCHAR and then using the 112 "Style" (noted on the MSDN page for Cast and Convert), convert that to a real DATETIME. For example: SELECT CONVERT(DATETIME, CONVERT(VARCHAR(10), 20150115), 112) Of course, doing that alone would invalidate an index on the [run_date]...
c#,datetime,timezone,datetime-format
Per W3C: [..] the "T" appears literally in the string, to indicate the beginning of the time element, as specified in ISO 8601. ...
php,sql,oracle,datetime-format,to-char
max (p.navi_date) To display the date in your desired format, use TO_CHAR along with proper format model. For example, SQL> SELECT to_char(SYSDATE, 'MM/DD/YYYY HH24:MI:SS') dt FROM dual; DT ------------------- 06/11/2015 14:28:04 SQL> Your modified query would look like: SELECT to_char(max(p.navi_date), 'MM/DD/YYYY HH24:MI:SS')... NOTE TO_CHAR converts DATE into STRING to...
I finally got it to work. My solution: //declare the AX utcdatetime type from the cs class generate with: //xsd C:\...\SharedTypes.xsd C:\..\AIFschema.xsd /Classes /Out:C:\location\of\csfile\ AxType_DateTime datetime = new AxType_DateTime(); //Ax store the time in GMT with an optional local time. My XML can have any timezone. datetime.timezone = AxdEnum_Timezone.GMT_COORDINATEDUNIVERSALTIME; //I...
To match exactly what SAS outputs for default datetime structure, you need to use as.POSIXct as was mentioned in comments, and additionally use the tz=UTC argument: sasDateTimes <- c(1706835972, 1716835972, 1726835972, 1736835972, 1746835972, 1756835972, 1766835972, 1776835972, 1786835972, 1796835972, 1806835972, 1816835972, 1826835972, 1836835972, 1846835972, 1856835972, 1866835972, 1876835972, 1886835972, 1896835972, 1906835972, 1916835972,...
postgresql,datetime-format,postgresql-8.4
You can use to_char function: select to_char(cast('05:03:00' as time), 'HH24h MIm SSs'); This will produce 05h 03m 00s ...
sql-server,datetime,sql-server-2008-r2,datetime-format
You can use the STUFF() method to insert characters into your string to format it in to a value SQL Server will be able to understand: DECLARE @datestring NVARCHAR(20) = '20120225143620' -- desired format: '20120225 14:36:20' SET @datestring = STUFF(STUFF(STUFF(@datestring,13,0,':'),11,0,':'),9,0,' ') SELECT CONVERT(DATETIME, @datestring) AS FormattedDate Output: FormattedDate ======================= 2012-02-25...
The second is definitely UTC, however, the first could be UTC + offset or it could be Local + offset (it looks like the latter the more I examine it). The best tool you have in your armoury for parsing specific dates is the ParseExact method. Based on your edit,...
sorting,datetime,kendo-ui,datetime-format,kendo-datasource
I imagine this occurred because the value was converted to a string in the parse function so it was no longer sorting like a date so I removed the parsing code from the field: sort: { field: 'dateTime', dir: 'asc' }, schema: { model: { id: 'Id', fields: { dateTime:...
c#,asp.net,.net,c#-4.0,datetime-format
long.Parse(DateTime.Now.ToString("yyyyMMdd")+ID.ToString()); ...
python,mysql,python-2.7,datetime,datetime-format
[Edited following suggestion in the comments] Using Ben Alpert's answer to How can I convert a datetime object to milliseconds since epoch (unix time) in Python we can do the following: from datetime import datetime def unix_time(dt): epoch = datetime.utcfromtimestamp(0) delta = dt - epoch return delta.total_seconds() def unix_time_millis(dt): return...
sql-server-2008-r2,datetime-format
SELECT REPLACE(REPLACE(REPLACE(CONVERT(VARCHAR(19), CONVERT(DATETIME, getdate(), 112), 126), '-', ''), 'T', ''), ':', '') ...
java,gson,datetime-format,java-8
There's a Java 8 library here: https://github.com/gkopff/gson-javatime-serialisers Here's the Maven details (check central for the latest version): <dependency> <groupId>com.fatboyindustrial.gson-javatime-serialisers</groupId> <artifactId>gson-javatime-serialisers</artifactId> <version>1.1.1</version> </dependency> And here's a quick example of how you drive it: Gson gson = Converters.registerOffsetDateTime(new GsonBuilder()).create(); SomeContainerObject original = new...
parsing,date,elasticsearch,jodatime,datetime-format
This works for me on ES 1.4.4 PUT hilden1 PUT hilden1/type1/_mapping { "properties": { "dt": {"type": "date", "format": "yyyy-MM-dd HH:mm:ss,SSS"} } } POST hilden1/type1 { "dt": "2015-02-09 02:10:05,245" } GET hilden1/type1/_search ...
java,date,datetime,datetime-format
Offset Part of the ISO8601 standard. If the time is in UTC, add a Z directly after the time without a space. Z is the zone designator for the zero UTC offset. "09:30 UTC" is therefore represented as "09:30Z" or "0930Z". "14:45:15 UTC" would be "14:45:15Z" or "144515Z". Fraction Of...
If your input string format from that datepicker has like that: 21 December 2012 - 03:45 PM You need to convert the format first that is applicable for your DATETIME field which is: YYYY-MM-DD HH:MM:SS The DATETIME type is used for values that contain both date and time parts. MySQL...
You can try this : SELECT CAST('2014-12-04' AS DATE) (FORMAT 'dd.mm.yyyy') (CHAR(10)) I hope help you...
If you need to remove time than you rather use Date# function instead of timestamp#? Below one is the sample one:- Date#( DateField, 'M/D/YY') ...
sql,regex,hadoop,hive,datetime-format
I'm going to assume that the 12 is month and that 3 is day since you didn't specify. Also, you said you want HH:MM:SS but there is no seconds in your example so I don't know how you're going to get them in there. I also changed 8:37pm to 8:37am...