image,matlab,matrix,binary,divide

The graythresh function in the Image Processing Toolbox implements Otsu's method. Furthermore, as Otsu's method only cares about the values of the pixels and not their position, you can rearrange the pixels of interest in a one-dimentional array before applying graythresh. In pratice, this gives the -compact- following code :...

You can use CASE as to check if the dividing value is 0 or not. CASE WHEN CONVERT(decimal(18,0),[Lost]) <> 0 THEN CONVERT(decimal(18,0),[Lost])/CONVERT(decimal(18,0),[Total Projects Signed]) ELSE 0 END AS [Loss Ratio], z1QReportProjectOverview2.[Completed], CASE WHEN CONVERT(decimal(18,0),([Completed]+[Implemented]+[Lost])) <> 0 THEN (CONVERT(decimal(18,0),([Completed]+[Implemented]))/CONVERT(decimal(18,0),([Completed]+[Implemented]+[Lost]))) ELSE 0 END AS [Success Ratio], ...

Since you are using Double for your arithmetic, why not use the compareTo(Double anotherDouble)? Not sure if this is the source of your trouble, but it could be the == behaving in a way that you did not intend it to and returning false hence, the zero......

Assume that there is no negative values. Only use assign, loop, increment, sub, add. Div(A, B) { temp = 1; result = -1; loop(A) { temp = 0; increment(result) A = sub(A, B) } return add(result, temp); } ...

delphi,math,numbers,pascal,divide

You need to calculate the remainder of zahl/i but your code calculates the remainder of i/zahl. So, instead of i mod zahl = 0 you need to test zahl mod i = 0 The function should be written like so: function FindeTeiler(Zahl: Integer): Integer; var i: Integer; begin Result :=...

int[][] bigMatrix = new int[9][9]; // initialize bigMatrix int[][][] smallMatrices = new int[3][3][3]; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { for (int k = 0; k < 3; k++) { smallMatrices[i][j][k] = bigMatrix[3*i+j][3*i+k]; } } } //...

Prior to above and my correct understanding this is a problem that is solved all the time. The pseudo code would go something like this.. fn sortObjects(List objects) { var sortedParentHashMap = new HashMap(); foreach(object in objects) { // If the HashMap entry for the current parentId does not exist...

mov ebp, 3 ;ebp = 3(constant) mov eax, edx ;eax = edx(sum from previous calculation) mov ecx,3 ;load upper half of dividend with zero div ecx ;divide double register ecx eax by 3 It seems like your doing the division the wrong way! The code does not what the comments...

I'm assuming that: you want to split your input string into individual paths based on substrings starting with //[Development/], either at the start of the string, or, if inside, preceded by a single space. regardless of whether the strings between //[Development/] instances contain spaces or not. str='//Development/graphic/release/CM //Development/graphic/release/GManager //Development/graphic/release/Notification //Development/graphic/release/Core...

you can try something like this: $string =~ m|^(.*)/(.*)$|; ($stringA,$stringB) = ($1,$2); print "stringA = $stringA\n"; print "stringB = $stringB\n"; = edit: = restrict to certain values of stringB: if($string =~ m|^(.*)/(.*\.pl)$|) { ($stringA,$stringB) = ($1,$2); print "stringA = $stringA\n"; print "stringB = $stringB\n"; } ...

You're dividing 2 32-bit numbers by 2 separately, not 1 64-bit number by 2. mult $t0, $t1 mflo $t0 mfhi $t1 sra $t0,$t0,1 sra $t1,$t1,1 sw $t0,s sw $t1,s You need to shift the whole 64-bit values. That means the shifted out bit of the higher part must be shifted...

The reason the division didn't work is because the grouped df is a different shape, so one way would be to call transform so that it returns a series with an index aligned to the original df and then you perform the division: In [165]: import numpy.random as npr rng...

ios,tableview,alphabetical,sections,divide

You can iterate through the array to create a dictionary with the first letter as the key and an array of names as a value: In Swift var nameDictionary: Dictionary<String, Array<String>> = [:] for name in nameArray { var key = name[0].uppercaseString // first letter of the name is the...

shell parsing is useful only for integer division: var1=8 var2=4 echo $((var1 / var2)) output: 2 instead your example: var1=3 var2=4 echo $((var1 / var2)) ouput: 0 it's better to use bc: echo "scale=2 ; $var1 / $var2" | bc output: .75 scale is the precision required...

NSNumber is an object which holds a value that can be retreived as different types by using its properties such as floatValue, integerValue and so on. NSNumber So by doing nsnumber1 / nsnumber2 would be like doing uiview1 / uiview2...

java,rounding,bigdecimal,divide

It all has to do with the scales of the BigDecimals involved. When you specify exponential format in the constructor that takes a String, the scale may be negative. This indicates that the significant digits don't extend all the way down to unity. BigDecimal oneEPlus8 = new BigDecimal("1.0E+8"); System.out.println(oneEPlus8.scale()); This...

Use this as a basis to solve your problem: $("#your_filed_id").on("focusout", function(){ // Do whatever checking you like here }); ...

The reason the calculation returns zero is that the double value computed by the expression is less than one. It looks like you have placed the parentheses incorrectly - currently, you divide speed by hundred times rightMotor, which is bound to produce a value less than 1. You need to...

You could do something like this: void dct(unsigned char **m, int baserow, int basecol) { for (int row = baserow, endrow = baserow + 8; row < endrow; ++row) for (int col = basecol, endcol = basecol + 8; col < endcol; ++col) ; // operate on m[row][col] } int...

java,decimal,bigdecimal,divide

You can do it like that: Double result=Double.parseDouble(s_dd + "." + s_mm); NumberFormat formatter = new DecimalFormat("#0.000000"); return formatter.format(result); ...

If you divide by a Series (by selecting that one row of the second dataframe), pandas will align this series on the columns of the first dataframe, giving the desired result: In [75]: df1 / df2.loc['q'] Out[75]: A B C D x inf 2 1.000000 2 y inf 6 2.333333...

You can use ranking functions and slice the inner results into quarters and then partition again for a final pivot on quarter. The quarters are not random but evenly distributed. In a table with 100 rows Row 1,25,50 and 100 would go into column1. However, using a guid and some...

You don't state if it matters if the first half are 1 and the second half are 5s only that 50% should be each. If it doesn't matter then you can do something like this: UPDATE tb1 SET rating = (CASE WHEN itemId <= (SELECT MAX(itemID) FROM (SELECT TOP (50)...

php,arrays,math,multidimensional-array,divide

Assuming $arr is your initial array, and $new_arr will be the new one. $new_arr = array(); foreach ($arr as $i=>$ar) foreach ($ar as $j=>$a) $new_arr[$i][$j] = round(($a/array_sum($ar))*100, 1); ...

Well easy enough, found the solution. Using AVG(). My code: SELECT CardCode, avg(DocRate) DocRate FROM OPCH WHERE DocRate > 1 AND DocStatus = 'O' AND DocDate >= '20140101' GROUP BY CardCode ...

From the error message given in the comments to the question: py:21: RuntimeWarning: divide by zero encountered in log return (np.sum(-data[:,-1]*np.log(1.0/(1.0+np.exp(-np.dot(data[:,:-1],theta.transpose()))))-(1-data[:,-1])*np.log(1-1.0/(1.0+np.exp(-np.dot(data[:,:-1],theta.transpose())))))+np.sum(theta[1:]**2)*lamda/2.0)*1.0/data.shape[0] it appears that you are computing np.log(0). E.g. >>> import numpy as np >>> np.log(0) __main__:1: RuntimeWarning: divide by zero encountered in log -inf >>> And...

Here is an illustrative demonstration of your fixed element. If you use position: fixed, and then set the offsets to auto, left: auto and right: auto, then the CSS engine will position the element as it would appear if it were a normal static positioned element. As a result, the...

algorithm,divide,partition-problem

This is the 3-partition problem variant of the partition problem, the difference being that the classic partition problem splits the set into two sets (not three) whose sums are equal to each other. This problem is NP-complete, so you're almost certainly not going to find a polynomial time solution for...

javascript,jquery,replace,separator,divide

How can I convert selected values from comma separated values to dot separated values? From that, I take it that the values you get from $('.lot2').text() and $('span.Price').text() will use , as the decimal point rather than . (as is the case in some locales). I assume that you...

sql,tsql,sum,divide,week-number

Hope this works : SELECT t.Week AS WEEK, t.Bin_Code AS BIN_CODE, t.Item_No AS ITEM_NO, SUM(CASE WHEN items.Item_No = t.Item_No THEN items.Quantity ELSE 0 END) AS QUANTITY FROM your_table as t CROSS JOIN (SELECT DISTINCT Item_No FROM your_table) AS items GROUP BY t.Week, t.Bin_Code ORDER BY 1,2,3 ...

php,wordpress,woocommerce,divide

depending on what you want ( a float or an integer ) use the following : echo intval($product->get_composited_item_price_string( $component_id, $product_id )) / 2; echo floatval($product->get_composited_item_price_string( $component_id, $product_id )) / 2; ...

Try this: A = randi([0, 100],randi(50),2); %// replace with your actual matrix padSize = ceil(size(A,1)/5)*5 - size(A,1); A = vertcat(A,nan(padSize,2)); out1 = mat2cell(A,ones(1,size(A,1)/5)*5,2); %// Desired cell array If you want it as a 3D matrix (as they all are of same size 5x2), you could use out = permute(reshape(A,5,size(A,1)/5,[]),[1 3...