c,pointers,linked-list,double-pointer
There is a issue with your insert function in the first code snipper where you move the *head so by the time you insert the last node to the list the head is pointing to one before the last node a->b->c->d | | Head is at c now So you...
Use const while typecasting the datatype. myfunc((const my_char**)mydata); You are getting that value as a const in a function....
You should pass pointers by reference if you have to modify the pointer rather than the object that the pointer is pointing to. Using double pointers is also a similar case. Here is a more detailed article: http://www.codeproject.com/Articles/4894/Pointer-to-Pointer-and-Reference-to-Pointer...
pointers,malloc,openmp,double-pointer
void matrix_vector_gen(int size, double **matrix, double **matrix2){ int i,j; for(i=0; i<size; i++) for(j=0; j<size*size; j++) matrix[i][j] = ((double)rand())/5307.0; matrix2[i][j] = ((double)rand())/65535.0; } when you leave braces out only the next statement after the "for" statement is executed in the loop, so the "matrix2" line is executed after the loops end,...
c,arrays,pointers,free,double-pointer
double **Array2D (int ny, int nx, int dsize) { double **v; int j; for (j=0; j<ny; j++) v[j] = Array1D(nx, dsize); v object is never initialized in your function....
c,pointers,struct,compiler-warnings,double-pointer
Look exactly at your struct declaration. You declare a typedef named directory. You do not anywhere declare a struct directory. But you are using "struct directory" inside the untagged struct that you declare. The compiler has no way to guess that you mean the typedef named "directory" when you write...
c++,file,input,fstream,double-pointer
The size of your matrix is wrong: matrix = new int *[edgeCount]; // wrong size wage = new int *[edgeCount]; // wrong size for (int i = 0; i < vertexCount; i++) { matrix[i]=new int[edgeCount]; wage[i]=new int[edgeCount]; } When you define the matrix you should use vertexCount instead, like this:...
c,arrays,pointers,double-pointer
You should not do that because in this case there will be a memory leak because you already allocated memory for pointer array and the assignment will overwrite the value stored in the pointer. Write the function simpler void function(int **arr) { int *tmp = *arr; tmp[0]=1; tmp[1]=2; tmp[2]=3; tmp[3]=4;...