node.js,web-scraping,http-post,reddit
In short, when you click YES button, the form sends over18=yes parameter to url http://www.reddit.com/over18?dest=http%3A%2F%2Fwww.reddit.com%2Fr%2Fnsfw using POST method. Then, server responds with an 302 Redirection header, cookie with value over18=1 and finally redirects to url http://www.reddit.com/r/nsfw using GET request. THen, server just checks if youa have a cookie with needed...
linux,http-post,fiddler,latency,simulate
I have been able to find a workaround for testing this. I took help from this answer. While httpbin is an amazing project it was missing the ability to delay the response of a POST request. Thus I forked their repository, and added the required endpoint myself. The fork is...
You are doing an HttpPost so you should get your data via POST and not GET //Code verifications $Code = $_POST['Code']; //Variables for SQL INSERT $Section = $_POST['Section']; $Gender = $_POST['Gender']; $WinningTeam = $_POST['WinningTeam']; $LosingTeam = $_POST['LosingTeam']; $FixtureD = $_POST['FixtureD']; $FixtureT = $_POST['FixtureT']; $Venue = $_POST['Venue']; $Court = $_POST['Court']; $Texts...
android,json,imageview,http-post,bytearray
The Answer For My Question... image_file=jsonObject.getString("IMGFILE1"); Gson gson = new Gson(); Type collectionType = new TypeToken<byte[]>(){}.getType(); byte[] parsed = gson.fromJson(image_file, collectionType); bmp1 = BitmapFactory.decodeByteArray(parsed, 0, parsed.length); I was able to do that by downloading the GSON library to execute this issue......
I correct my code and it's worked. Thank you guys for your help. Ajax Code: function checkuser() { var myObject = new Object(); myObject.username = $('#username').val(); myObject.password = $('#password').val(); $.ajax({ url: 'http://10.252.84.159/ajaxrecivelogin/', type: 'POST', data: JSON.stringify(myObject), context: this, dataType: 'json', success: function (data) { alert( data.status ); }, error: function...
c#,http-post,web-api,asp.net-web-api2,frombodyattribute
Your JSON is slightly malformed - you have "Url" = "http://localhost...", rather than "Url" : "http://localhost...", i.e. you have = instead of :...
php,web-services,http-post,http-get
A wise way would be to stubbornly check all possible methods: if(function_exists('curl_init')) use curl else if ini_get('allow_url_fopen') use files else if function_exists('fsockopen') use sockets else echo 'hey, it's about time to change the hoster!' Specifically to Wordpress, it heavily relies on server-to-server communication (think updates, pingbacks, Akismet etc), therefore most...
You can use base64 encoding to convert binary data to string and then put it in your query string, but its not recommended. For sending binary data its better to use post method and its data in your http request. like this, or ^, ^, ^. and the code: public...
javascript,c#,angularjs,asp.net-web-api,http-post
You should be posting the object on the form body, not on the querystring. In addition, your Web API controller should receive a strongly typed object that mirrors the data that you're passing. public class Data { public string Color { get; set; } public string Name { get; set;...
php,http,post,http-post,httprequest
First, you're going to want to look into the cURL library for PHP. http://php.net/manual/en/book.curl.php It's basically a library to help you connect and communicate over various protocols, including HTTP using the POST method. There's a very simple example on using the library on this page: http://php.net/manual/en/function.curl-init.php Second, you're going to...
php,curl,http-post,asterisk,telnet
I highly recommend you use already writed library For php that is phpagi libs. http://phpagi.sourceforge.net/ In this example you not respect protocol. Protocol say have be Action. http://www.voip-info.org/wiki/view/Asterisk+manager+API...
Your method is async method,you can not get return from this. You can pass in a block to handle your action with return func postData(url: String, query: NSDictionary,finished:(NSObject)->()) { var error: NSError? var result: NSObject? = nil let dest = NSURL("http://myUrl.com") let request = NSMutableURLRequest(URL: dest!) request.HTTPMethod = "POST" request.HTTPBody...
javascript,c#,asp.net-mvc-5,http-post,asp.net-mvc-views
you can try to recover the value at the click of the button submit, or if that 'testHiddenField' is defined in your model , you need to put the name attribute of input , example : assuming your property in the model is called the 'testHiddenField' public String testHiddenField; when...
android,string,http-post,jsonobject
Try using URL Connection : public JSONObject readJSONFromURL(String urlString, JSONObject param){ String response = null; JSONObject jObject = null; try { URL url = new URL(urlString); URLConnection conn = url.openConnection(); conn.setDoOutput(true); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("dmode", param.toString())); OutputStream os = conn.getOutputStream(); BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));...
c#,asp.net,asp.net-mvc,entity-framework,http-post
Firstly, do not pass a complex object as a parameter to a GET method. Properties that are complex objects or collections will not bind (they will be null), you may exceed the query string limit (crashing your app) and then there the ugly url it creates. Just initialize a new...
php,mysql,database,post,http-post
from and to are reserved words in SQL you have to add backticks arrond: $sql="INSERT INTO pending_req (`To`, `From`) VALUES ('$usernamebeingreq', '$username')"; or better rename the column. Hint: use prepared statement. it is much more safty....
android,http-post,query-parameters
use this code : List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(4); nameValuePair.add(new BasicNameValuePair("page", "/OrderHandlingServlet?api=login")); nameValuePair.add(new BasicNameValuePair("txtDomain", "MyDomain")); nameValuePair.add(new BasicNameValuePair("txtUid", "user1")); nameValuePair.add(new BasicNameValuePair("txtPwd", "pwd1")); HttpParams params = new BasicHttpParams(); HttpConnectionParams.setConnectionTimeout(params, INSERTCONNECTIONTIMEOUT); HttpClient client = new...
Thanks to JoErNanO, I create a mcve and find my answers by myself. For that I write this : // Detect if we got a file "lock" $nb_file_lock = 0; if($folder = opendir($GLOBALS['chemin']."XML")){ while(false !== ($file = readdir($folder))){ if($file != '.' && $file != '..' && $file != 'datas.xml'){ $nb_file_lock++;...
angularjs,resources,http-post,asp.net-web-api2
IMHO This is not the way the $resouce is works at its best and that's because you're not really sticking to REST principles. The idea of $resource, is to get an object, modify it and then $save it again, which maps to a GET and POST calls in which the...
android,mysql,facebook,http-post,facebook-login
Some users may not have valid emails or birthdays (even if they give you permission), so you always need to handle empty fields. The only guarantee you'll get is a unique ID per user.
android,apache,tomcat,http-post
Okay , the problem has been solved . As answered by both Codemon and Jayesh , in order to use real device to run the app from Android Studio , you have to use the ip address of the server in place of 10.0.2.2 and make sure your phone device...
arrays,asp.net-mvc,asp.net-mvc-5,http-post
Posting a Collection of Primitives With ASP.NET MVC To post a collection of primitives the inputs just have to have the same name. That way when you post the form the request's body will look like listStrings=a&listStrings=b&listStrings=c MVC will know that since these parameters have the same name they should...
c#,asp.net,vb.net,http-post,namevaluecollection
Found this code and this did the job at the end. <form action="TestPageLOAD.aspx" method="post" enctype="multipart/form-data"> <input type="file" name="imgInp" /> </form> Page_Load Event on TestPageLOAD.aspx.cs if(Request.Files["imgInp"] != null) { HttpPostedFile MyFile = Request.Files["imgInp"]; //Setting location to upload files string TargetLocation = Server.MapPath("~/pics/"); try { if (MyFile.ContentLength > 0) { //Determining file...
Yeah, they are deprecated. You can use Volley which is recommended by Google Dev. Volley offers the following benefits: Automatic scheduling of network requests. Multiple concurrent network connections. Transparent disk and memory response caching with standard HTTP cache coherence. Support for request prioritization. Cancellation request API. You can cancel a...
c#,json,serialization,json.net,http-post
Cause of Error: I solved the issue, actually what happening in original string you can see the new line so when this string pass into the string variable then .Net environment put \r\n on every new line and when i serialize from the newton.json library it put one more slash...
javascript,php,checkbox,http-post,reset
just add id to checkbox. change <input type="checkbox" name="free" ... to <input type="checkbox" name="free" id="free" ... add document.getElementById("free").checked = false; in function clearform() function clearform() { document.getElementById("results").innerHTML = ""; document.getElementById("results").style.visibility = "hidden"; document.getElementById("searchform").reset(); document.getElementById("free").checked = false; } ...
objective-c,json,ios7,http-post
There is way to much code. The substringToIndex and substringFromIndex are wrong, should not be in the code. Use the literal syntax for the dictionaries: NSDictionary *jsonDict = @{@"jsonData":@{@"password":password, @"empId":userName}}; NSData* jsonData = [NSJSONSerialization dataWithJSONObject:jsonDict options:0 error:&error]; ...
android,http-post,android-volley
Use the code given below and let me know if you are facing any issue JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.POST, url, null, new Response.Listener<JSONObject>() { @Override public void onResponse(JSONObject response) { Log.d(TAG, response.toString()); pDialog.hide(); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { VolleyLog.d(TAG, "Error: " + error.getMessage());...
Apologies for being such a dumb .... the above solution worked on restart !! android device is receiving the post response string of the POST query !!! ...
I see the same behavior in my sample test. If you want to control if they are encoded and still use the HTTPClient you must check - 'Use multipart/form-data for POST'. With the Java implementation during a POST you can control if parameters are encoded. However, HTTPClient will always encode...
asp.net-mvc,database,angularjs,asp.net-web-api,http-post
I would suggest doing this in your web-api server side. You can construct an exception and throw it. Some pseudo-code: [Route("api/employee/insert/")] public void Post(Employee employee) { if (ModelState.IsValid) { // verify doesn't already exist if(...item-already-exists...) { var resp = new HttpResponseMessage(HttpStatusCode.Conflict) { Content = new StringContent("Employee already exists!")), ReasonPhrase =...
asp.net-mvc,angularjs,http-post
You should return data as json e.g. public ActionResult Search(string searchText = "") { return Json(new { Foo = "Hello" }, JsonRequestBehavior.AllowGet); } $http.post('/Home/Search', { searchText: text }). success(function (data, status, headers, config) { $scope.pms = data.Foo; }); Now, in your case, you have a list, so you need to...
I am sure it depends on the Android version. Remember that you should not perform any interent activity in the main thread.You should use AsyncTask or Hanlders. In older versions of Android it was allowed to run internet consuming threads in the main one , but since 4.0 it was...
Your URL is calling Personas function in apiController.But in your code the function is having some different name .Thats why you are getting the error.Change your function name to Personas.It will work
angularjs,google-chrome,laravel,http-post,laravel-5
Change "X-XSRF-Token" to "X-CSRF-TOKEN". Note the difference between "XSRF" and "CSRF". From the documentation: "Note: The difference between the X-CSRF-TOKEN and X-XSRF-TOKEN is that the first uses a plain text value and the latter uses an encrypted value, because cookies in Laravel are always encrypted. If you use the csrf_token()...
you are calling "httpclient.execute(..)" twice: HTTPRESPONSE = httpclient.execute(HTTPPOST); ResponseHandler<String> responseHandler = new BasicResponseHandler(); final String response = httpclient.execute(HTTPPOST, responseHandler); remove one of them should solve your issue :)...
ajax,asp.net-mvc,http-post,postback,form-submit
Post Back Browser Handling - The only advantage I can think of is that the browser will handle redirects and progress loading for you. You don't need to write the logic to redirect users or show a loading bar. AJAX Asynsconous - With AJAX you're getting asyncronous calls so the...
Set the PostBackUrl property for the control to the URL of the page to which you want to post the ASP.NET Web Forms page. Remove action and add PostBackUrl into Button.Instead name use ID property value. In Default.aspx <form id="form1" runat="server" method="post"> <div> <asp:TextBox ID="TextBox1" name="txtUname" runat="server" Width="180px"></asp:TextBox> <asp:TextBox ID="TextBox2"...
asp.net-mvc,asp.net-mvc-3,http-post
If you are using RedirectToAction(), then you're application is redirecting your browser's request to another URL. So, if you were to look at the network activity... Your initial POST will respond with a "302 Found" (assuming successful). Then, a URL is provided for a redirected request to occur. So, if...
android,http-post,android-volley
Your return String respuesta is set asynchronously. The I/Server response:﹕ 1 that you're seeing is actually the response that you're getting back from the first button press. You should move your log into the onResponse public void onResponse(String s) { respuesta = s; //todo add log and logic here }...
hash,http-post,digital-signature,integrity,authenticity
Both HMAC and Digital signature provides integrity and authentication: integrity - because both of them based on hash. HMAC is hash-based message authentication code. Digital signature is encrypted hash of some message. authentication - because HMAC uses symmetric secret key, and digital signature uses assymetric private key. Secret/private keys can...
The content type needed to be Enum.HttpContentType.ApplicationUrlEncoded. In addition, I appended "data=" to the front of my JSON string. local json = HS:JSONEncode(chatLog) chatLog = {} json="data="..json print(json) print(HS:PostAsync( URL, json, Enum.HttpContentType.ApplicationUrlEncoded )) ...
The content-type HTTP header field describes the internet media type of the payload. So yes, it it's plain xml, it could be "text/xml" or "application/xml". There's nothing wrong with that, "even" in POST requests.
c#,asp.net-mvc-5,http-post,modelstate
As @StephenMuecke pointed out in the comments of the OP. I just needed to remove the field from the View: @Html.HiddenFor(m => m.Tags[i].Id) Now the ModelState.IsValid returns true....
render :text => request.raw_post this part says "render the text that is the raw XML post back to the browser" - so if you want it not to render the XML - then don't have this line. if you want to just render a 200, then just render a...
ruby,arrays,json,http-post,attask
This would work but your url format would have to be like this /attask/api/resvt?updates=[{"endDate":"2014-12-25T22:59:00:163-0700","startDate":"2014-12-24T23:00:00:163-0700","userID":"4ee8cfec000d2cd780c3ccf059cdc23b"},{"endDate": "2014-12-26T22:59:00:163-0700","startDate":"2014-12-26T23:00:00:163-0700","userID":"4ee8cfec000d2cd780c3ccf059cdc23b"}]&method=POST&sessionID={sessionID} The problem you will run into is this will erase all existing time off already in the system. one solution is to pull all time-off from attask first...
android,android-asynctask,http-post
Here: postD.doInBackground("1111"); You are calling doInBackground method using class object which will also work on main ui Thread. To run doInBackground in background thread you need to start AsyncTask using AsyncTask.execute method. do it as: public void aboutPage(View view) throws IOException { postD=new PostData(); postD.execute("1111"); } See more about AsyncTask...
I have got the reason why i am getting this error. i just checked out this link and came to know i shouldn't use the code like this. Instead i should use Thread and handlers to handle the HTTP calls. Well Thanks everybody for your assistance. :)
edit: I wrote a detailed post on how to post data from Ionic to PHP and you can view it here. In the index.html file you have: ng-click="signUp(userdata) but then in the app.js file you have this: $scope.signup = function () { instead of something like: $scope.signup = function (userdata)...
I have solved the problem by checking my web service in browser. The problem was in my services.php file. There was an error about log file creation and this error was returning a non JSON response that causing the request to fail. My complate working code is here: NSMutableDictionary *dictionary...
c#,asp.net,rest,http-post,yahoo
I spend nearly a week in finding the answer. i finally got the thing which is giving error. I forgot to implement the note in yahoo docs which says "Note: The Authorization: Basic authorization header is generated through a Base64 encoding of client_id:client_secret per RFC 2617." I added two lines...
c#,oauth-2.0,http-headers,http-post,boxapiv2
I think you need to set the header before you write the postData and close the request stream. This appeared to work for me: static void Main(string[] args) { HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.xhaus.com/headers"); request.Method = "POST"; request.ServicePoint.Expect100Continue = false; request.ContentType = "application/x-www-form-urlencoded"; request.Timeout = 10000; request.Headers.Add("Authorization: Bearer_faKE_toKEN_1234"); string postData =...
Response.Redirect() only redirects the page. It doesn't forward any header information whatsoever. You'll need to set up a cross-page PostBack. https://msdn.microsoft.com/en-us/library/ms178139(v=vs.140).aspx or http://www.codeproject.com/Tips/604553/Postback-and-Cross-Page-Posting-in-ASP-NET Should give you some guidance. Or you can set up the button like this: <asp:Button ID="btnSubmit" runat="server" Text="Login" PostBackUrl="/page2.aspx" style="height: 29px" /> ...
After following many posts and tutorials for more than 24 hours I got to know that I am not sending my URL parameters correctly. And also I learned that REST API call using ApacheHttpClient is comparatively easier. I resolved my HTTP error code 400 and got the response back from...
When you are encoding url your url becomes like below http%3A%2F%2Fyahoo.com Dont encode untill you have something special in it. Your programm is also throwing class cast exception HttpsURLConnection con = (HttpsURLConnection) obj.openConnection(); Above should be like below HttpURLConnection con = (HttpURLConnection) obj.openConnection(); Below is working programm. package com.ds.portlet.library; import...
javascript,c#,asp.net,asp.net-mvc,http-post
It’s always a good practice to have at least the validation on the controller, this way you’re sure that your application is NOT receiving invalid data. The validation on client side is also important because you can provide a good feedback for the client when this one takes your forms...
clojure,http-post,paypal-ipn,undertow,immutant
I don't think this is necessarily a problem with Immutant handling a POST. The problem occurs during the dispatch to the IPN handler, which is attempting to invoke reset on Undertow's InputStream. I would expect the stream's markSupported method to return false. It's not clear to me why reset is...
This can be solved easily. This is a json array. so we can use jsonArray and we can parse through it.
First you need to go to your repo, and click through this sequence: Settings -> Webhooks & Services -> Add webhook Then paste the url where github will submit data for each new commit. You can find examples of payload in example. Then implement the logic needed in the backend...
java,json,jackson,http-post,parse-error
mlpdemo\mlpdemoins is an invalid string you can't use it in JSON . But you can use mlpdemo\\mlpdemoins easily. below code works fine for me : String jsonData = "{ \"provider\" : null , \"password\" : \"a\", \"userid\" : \"mlpdemo\\\\mlpdemoins\" }"; ObjectMapper mapper=new ObjectMapper(); System.out.println(mapper.readTree(jsonData)); It will produce this output JSON...
c#,asp.net-mvc,http-post,html.beginform
No, you can't. Only input, select and textarea controls values are posted to server. You can set in background a hidden input control with span value but you can't expect span to be automatically posted.
python,python-requests,http-post
It doesn't look like a POST request - when you click on hyperlinks, the browser sends a GET request. (Well, the removeLoginCookie function could override it and send a POST request instead.) Also, determine what the cookie name is and then call something like that (depending on the how removeLoginCookie...
php,json,google-api,http-post,google-plus
Turns out the code I was using above doesn't work any more, Google made a change in 2013 to block it being used, the code I'm using now to get the approximate share count is below. $vHtml = @file_get_contents( "https://plusone.google.com/_/+1/fastbutton?url=".urlencode("http://www.google.com")); $vDoc = new DOMDocument(); @$vDoc->loadHTML($vHtml); $vCounter = $vDoc->getElementById('aggregateCount'); echo $vCounter->nodeValue;...
asp.net,asp.net-web-api,http-post,asp.net-5
Add contentType to your ajax setting object, JSON.stringify your doc object, post json string to server: var doc = { DocumentId: 1 }; var jsonDoc = JSON.stringify(doc); jQuery.ajax('api/test', { type: 'POST', data: jsonDoc, contentType: 'application/json' }) .done(function(data, status, jqr) { alert(status); }) It should works....
java,android,json,http-post,android-volley
the android volley team maybe add it later . but for now you can do this : creat your class and extends JsonArrayRequest then you should overide : @Override protected Map<String, String> getParams() throws AuthFailureError { HashMap<String, String> params = new HashMap<String, String>(); params.put("name", "value"); return params; } then make...
asp.net-mvc,asp.net-mvc-5,http-post
It seems you are using cookie less session, so the session ID must be placed in the URL, If you perform a redirection by using URL Rewrite Module, the session won't work. So, you'll need to enable cookie to make the URL clean.
You are not passing the headers to Request You need at least specify the content-type (as you are doing when you call curl) Would be something like this: req = urllib2.Request(url, jsonString, {'Content-Type': 'application/json'}) ...
java,http,http-post,apache-camel
As isim mentioned above, following works for me. The idea is to parse a given url fist and to encode it again afterwards. This avoids double encoding. import java.io.UnsupportedEncodingException; import java.net.*; public static String getEncodedURL(String urlString) { final String encodedURL; try { String decodedURL = URLDecoder.decode(urlString, "UTF-8"); URL url =...
django,django-forms,http-post,http-redirect
You can use the Django session to achieve that.Here is the example by using your code. def register(request): if request.method == 'POST': if the_form.is_valid(): my_id = the_form.cleaned_data['myid'] email_addr = the_form.cleanedJ_data['emailaddr'] request.session['registration'] = {'my_id': my_id, 'email_addr': email_addr } request.session['form-submitted'] = True return HttpResponseRedirect(reverse('polls:registration_success')) def registration_success(request): if not request.session.get('form-submitted', False): # handle...
android,http-post,stackexchange-api
Got the solutions. We should pass 5 parameters to upvote a question. List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(5); nameValuePair.add(new BasicNameValuePair("key", key)); nameValuePair.add(new BasicNameValuePair("access_token", accessToken)); nameValuePair.add(new BasicNameValuePair("filter", "default")); nameValuePair.add(new BasicNameValuePair("site", "stackoverflow")); nameValuePair.add(new BasicNameValuePair("preview", "false")); Also, the http response is in JSON format (expected), but it is in Gzip...
Try following, request.post({ uri: oauth_token_uri , headers: { 'Content-Type': 'application/x-www-form-urlencoded', 'Authorization': oauth_code }, body: querystring.stringify(postData) }, function(err,res, body){ var parsedResponseBody = JSON.parse(body); console.log("Access Token:" + parsedResponseBody.access_token); }); You are getting the response in String format. You will first need to parse that response in JSON object....
java,android,android-activity,android-asynctask,http-post
I suggest you try Handler and Handler.Callback. Below I made it simple example.. import android.app.Activity; import android.os.AsyncTask; import android.os.Bundle; import android.os.Handler; import android.os.Handler.Callback; import android.os.Message; public class MainActivity extends Activity implements Callback { Handler handler; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); handler = new Handler(this); Proxy proxy =...
django,validation,http-post,django-rest-framework
Since the "class User" mentioned that the email field is mandatory What email field? You only told Django REST framework that there is a username and password field, so that is all it expects and validates. If you want the email field to be required, you are going to...
javascript,firefox,firefox-addon,http-post,tamper-data
Your question borders on being too broad, so I will give only an overview on how to do this, but not a copy-paste-ready solution, which would take a while to create, and would also deny you a learning experience. Observers First of all, it is possible for add-ons to observe...
The part you didn't include in your server code: 3- Server gets the request, posts back a response You need something like: char buf[N]; ssize_t len; len = recv(sock, buf, sizeof(buf) - 1, 0); if (len > 0) { buf[len] = '\0'; /* save to file */ } after accept()...
With codeigniter You can load the view into a variable like this: $html = $this->load->view('vehiclec/vehicle.html',array(),true); die($html); Just a note here, vehicle.html is wrong, codeigniter loads views from php files so the view file should be vehicle.php and the call "vehicle/vechicle" The boolean "true" in the last parameter of the view...
ruby-on-rails,angularjs,cordova,http-post,ionic-framework
Managed to solve this using the cordovaFileTransfer.upload method. The rails end point was also filtering params and looking for a post object, with a image string, and only an image string was being provided. The following code is now working Angular factory making post request: .factory('Posts', function($http, $cordovaFileTransfer) { var...
"Inside the post function what exactly should be written." Look at the SyncInvoker API. Look at the different post methods. You will choose one of these, depending on what type of response you want. The Entity argument can simply be written as Entity.json(yourRequestObject), which automatically configures the request as...
As Mark Ma mentioned, you can get it done without leaving the standard library by utilizing urllib2. I like to use Requests, so I cooked this up: import os import requests dump_directory = os.path.join(os.getcwd(), 'mp3') if not os.path.exists(dump_directory): os.makedirs(dump_directory) def dump_mp3_for(resource): payload = { 'api': 'advanced', 'format': 'JSON', 'video': resource...
c#,http,http-post,http-post-vars
According to microsoft here: http://www.asp.net/web-api/overview/formats-and-model-binding/parameter-binding-in-aspnet-web-api You have to add "[FromBody]" in the parameter list. You can only have one of these types of parameters. Also in the chrome post extension under headers you need to enter: Name: Content-Type Value: application/json...
If you want to write max 1 value (the first condition which is met), use elseifs instead of ifs. if (!empty($_POST['location_to'])) { echo ...; } elseif (!empty($_POST['location_from'])) { echo ...; } elseif (!empty($_GET['id'])) { echo ...; } ...
Sounds like your server is not configured to allow POST requests to that URL. But you need a way to verify that. If you don't already have a REST testing plugin for your browser, find a plugin that will allow you to enter POST request data, download it and install...
c#,http-headers,http-post,webclient
I went with tcpclient and everything is working great.
rest,ruby-on-rails-4,xmlhttprequest,http-post,net-http
My guess is that you have configured your email parsing service to POST the data to a URL which is only accessible from your local system, for instance a pow.cx style ".dev" URL. The reason this works using your test utility is I'm assuming the test client is also on...
java,http-post,apache-httpclient-4.x
You need to use a BasicHttpEntityEnclosingRequest that contains a SerializableEntity. Basically, it would look something like this: BasicHttpEntityEnclosingRequest postRequest = new BasicHttpEntityEnclosingRequest("POST", "uri"); postRequest.setEntity(new SerializableEntity(yourObject, false)); ...
javascript,http,meteor,http-post,spotify
You need to use params instead of data. Thus, your code would be: HTTP.post("https://accounts.spotify.com/api/token", { params: { grant_type : "authorization_code", code : authCode, redirect_uri : Router.routes['redirect_spotify'].url() }, headers: { 'Authorization' : "Basic " + CryptoJS.enc.Base64.stringify(CryptoJS.enc.Utf8.parse("xxxx:yyyyy")), 'Content-Type':'application/x-www-form-urlencoded' } }, function(error, result) { ... }); ...
c#,asp.net,asp.net-mvc,razor,http-post
If I were you I would create a strongly typed view model to represent your data. One to represent each item with the properties within them. public class FooModel { public string Text { get; set; } public string Country { get;set;} public int ProductsID { get; set; } public...
angularjs,http,oauth-2.0,http-post
You have syntax error, therefore JS wont make the HTTP Post request, Try this: $http.post(myURL, 'grant_type=password&username=' + userName + '&password=' + passWord, { headers: { 'Content-Type': 'application/x-www-form-urlencoded', 'Authorization': 'Basic ' + btoa(secretWord) } }). success(function (response) { console.log(response.data); }). error(function (response) { console.log(response.status); }); ...
c#,httpwebrequest,http-post,jira,httpwebresponse
I fount the solution. The problem lied in permissions on Jira. After double checking with admins my code worked perfectly.