binary,numbers,32-bit,ieee-754,ieee

Since i will assume you already know the Standard we can convert as following , Convert your number to base 2 1011.01000 Shift this binary number 1.01101000 2**3 (shifted by 3) add exponent 127+3=130 convert 130 to binary format 10000010 And so we have sign * 2^exponent * mantissa Sign...

Heiko Oberdiek (hyperref's author) said that there should not be any bookmarks in the PDF if the bookmark=false option really is being used and to check the .log file to ensure this is so. He can help further once the question is moved to tex.stackexchange.com Also, try compiling the bare_conf.tex...

because wireless(WLAN) network is not as reliable as wired(IEEE 802.3) network

For the first case, the exact result of the multiply is half way between 1.0 and the largest double that is less than 1.0. Under IEEE 754 round-to-nearest rules, half way numbers are rounded to even, in this case to 1.0. In effect, the rounding of the result of the...

There is no universal rule about what order bytes should be in a multi-byte structure. The little-endian approach would put the four-byte number 0x01020304 into bytes in the order 0x04, 0x03, 0x02, 0x01. The big-endian approach would put the same four-byte number into bytes in the order 0x01, 0x02, 0x03,...

PLI 1.0 is old (it has been around since the mid-1980s according to the LRM), it was depreciated in IEEE Std 1364-2005 § 1.6 Deprecated clauses: IEEE Std 1364-2005 deprecates the Verilog PLI TF and ACC routines that were contained in previous versions of this standard. These routines were described...

c++,optimization,floating-point,compare,ieee

The expression *(int*)&value > 0 tests if value is any positive float, from the smallest positive denormal (which has the same representation as 0x00000001) to the largest finite float (with representation 0x7f7fffff) and +inf (which has the same representation as 0x7f800000). The trick detects as positive a number of, but...