javascript,angularjs,timeout,intervals
You need to wrap it in a closure function, pass in the i variable, and then it will become available within the scope of that new function.. e.g. for(var i = 0; i < 10; i++) { (function(i){ // i will now become available for the someMethod to call $timeout(function()...
Disclaimer This is probably best done outside of SQL For Those That Like Painful Queries You could create a query that attempts to decide whether there is a row elsewhere in the table that overlaps the end column. If there is not then try to find out how much time...
postgresql,datetime,translation,intervals,postgresql-8.4
I think no. sorry. day, month etc are field in type interval. it will be in English. like you don't expect use "vybrac" instead of select :) But you can have locale in time values, yes. td=# set lc_time TO pl_PL; SET td=# SELECT to_char(to_timestamp (4::text, 'MM'), 'TMmon'); to_char ---------...
sql,oracle,oracle11g,intervals
EDIT: Added union to include the final missing row Some thing like this may work. Assuming the input data is in table a, with b as (select level-1 lev from dual connect by level <= 60 ), v as ( select start_date, value current_value, lead(value) over (order by start_date) next_value...
jquery,if-statement,intervals,clearinterval
So currently, your code is going to run something like this order: window.intervalcount = 0; // Interval is defined here var interval = setInterval(function () { intervalcount += 1; $("#feedback").text(intervalcount); }, 1000); // will be 0 still if(intervalcount > 5) { clearInterval(interval); } // 1 second after the interval is...
c++,algorithm,boost,intervals,boost-icl
As I surmised, there's a "highlevel" approach here. Boost ICL containers are more than just containers of "glorified pairs of interval starting/end points". They are designed to implement just that business of combining, searching, in a generically optimized fashion. So you don't have to. If you let the library do...
javascript,intervals,event-listener
You can add and remove the event listener as desired: function processMotion(e) { // your code here to process devicemotion events } function addMotionListener() { window.addEventListener("devicemotion", processMotion); } function removeMotionLisener() { window.removeEventListener("devicemotion", processMotion); } So, just call addMotionListener() when you want to start listening to motion. Then call removeMotionListener() when...
javascript,timer,setinterval,intervals
function fooBar(foo,delay){ var i=1; setInterval(function(){ if (i%(foo+1) ==0){ console.log("BAR"); } else { console.log("foo"); } i++; //set i back to 0. not necessary, though if (i==(foo+1)){ i=0; } },delay); } fooBar(3,1000);//number of "foo"s , delay in ms ...
vb.net,visual-studio-2010,charts,intervals
You can enable the MinorGrid property chart.ChartAreas(0).AxisY.MinorGrid = True to show the horizontal lines in between the powers of 10 like shown bellow. But there is a limitation in showing the value for each subdivision. They can only appear in fixed intervals by using the Interval property of the LabelStyle....
Grouping it by 4 using awk Min awk 'NR%4==1' file 2 7 13 19 Max awk 'NR%4==0' file 6 12 18 To get the min and max value. awk 'ORS=NR%4?FS:RS' file | awk '{for (i=1;i<=NF;i++) {min=$i<min||!min?$i:min; max=$i>max||!max?$i:max} print min,max;min=max=0}' 2 6 7 12 13 18 19 19 First awk group...
You could use DatePeriod for this. DatePeriod will take a DateTime object as a start date, for the first parameter, a DateInterval object as the interval on which to repeat, for the second parameter, and a DateTime object or integer representing the ending date or number of recurrences for the...
You can use foverlaps in data.table: library(data.table) C.DT <- data.table(C) C.DT[, A1:=A] # required for `foverlaps` so we can do a range search # `D` and `E` are your interval matrices I1 <- data.table(cbind(data.frame(D), idX=LETTERS[1:4], idY=NA)) I2 <- data.table(cbind(data.frame(E), idX=NA, idY=LETTERS[16:19])) setkey(I1, X1, X2) # set the keys on our...
c++,computational-geometry,intervals,skip-lists
Suggest using CGAL range trees: Wikipedia says interval trees (1-dimensional range trees) can "efficiently find all intervals that overlap with any given interval or point"....
python,matplotlib,coordinates,mouse,intervals
There are some built in tools to provide blocking mouse input (see plt.ginput). The other option is to roll your own. The easiest way to do this is to make a helper class to store the clicked values: class ClickKeeper(object): def __init__(self): self.last_point = None def on_click(self, event): self.last_point =...
Move the click handler inside the anonymous function, so that it will have the same scope as the timer variable. You can then add this within the click handler: clearInterval(timer); Snippet $(function() { var timer; var secs = 0; var mins = 0; var timeField = document.getElementById("time"); timeField.innerHTML = "00:00";...
Change > and < to >= and <= in your SUMPRODUCT. You can also try COUNTIFS formula - should work faster. With the following sample layout: Enter in C3 and drag it down: =COUNTIFS($A$1:$G$1,">=" &A3,$A$1:$G$1,"<="&B3) ...
qt,serial-port,intervals,qtserialport
In general readyread signal would be emitted even if one byte is received. But the response time depends on many factors like the driver, CPU load or how much the Qt event-loop is busy. When a receive is detected in the serial port, all data in the driver buffer will...
java,date,sum,intervals,subtraction
I found exactly what I needed: Ranges, from the guava-libraries. Works like this: Range<Date> a = Range.closed( new GregorianCalendar(2015, 0, 1).getTime(), new GregorianCalendar(2015, 0, 20).getTime()); Range<Date> b = Range.closed( new GregorianCalendar(2015, 0, 5).getTime(), new GregorianCalendar(2015, 0, 10).getTime()); Range<Date> c = Range.closed( new GregorianCalendar(2015, 0, 11).getTime(), new GregorianCalendar(2015, 0, 14).getTime()); Range<Date>...
javascript,python,logic,intervals,overlapping
Python solution for any number of intervals regardless of order of the numbers in the interval. It'll either return True, min t value, max t value or False, t value, t value. def in_interval(intervals): if len(intervals) == 0: return False, None, None min_t = min(intervals[0]) max_t = max(intervals[0]) for interval...
You can try library(dplyr) df1 %>% mutate_each(funs(as.Date(., '%d/%m/%Y')), matches('start|end|date')) %>% mutate(drug.end= as.Date(ifelse(is.na(drug.end), End.date, drug.end),origin='1970-01-01'), Event= as.integer((Diag_date >= Drug.start & Diag_date<=drug.end) & !is.na(Diag_date))) #%>% #mutate_each(funs(format(., '%d/%m/%Y')), matches('start|end|date')) # ID Diag_date Treatment End.date Drug.start drug.end Event #1 1 <NA> 0 2002-03-15 2002-01-01 2002-02-01 0 #2 1 <NA> 1 2002-03-15 2002-02-01 2002-03-01 0...
As the 'date' column have only week days and without any breaks, we can use gl/paste to create week index. This doesn't depend on the nrow of the dataset i.e. even if the nrow is not a multiple of 5, it will work. dataset$week <- paste('Week', as.numeric(gl(nrow(dataset),5, nrow(dataset)))) Other option...
javascript,video,youtube,intervals,track
Here is a demo, I think the variables and functions have names explicit enough to understand everything, but if you have any question or problem, go ahead and ask. One thing I have to mention is that it won't be exact. If your interval gets executed once per second and...
You want to implement numpy.histogram() for dates: import numpy as np times = np.fromiter((d['first_alerted_time'] for d in example_table), dtype='datetime64[us]', count=len(example_table)) bins = np.fromiter(date_range(start_date, end_date + step, step), dtype=times.dtype) a, bins = np.histogram(times, bins) print(dict(zip(bins[a.nonzero()].tolist(), a[a.nonzero()]))) Output {datetime.datetime(2014, 12, 11, 2, 0): 3, datetime.datetime(2014, 12, 11, 2, 3): 1} numpy.historgram() works...
Turns out this is a reported PHP bug from 2012 that I JUST found while I was making this question: https://bugs.php.net/bug.php?id=62476 That's annoying. Here is a workaround: $date = DateTime::createFromFormat('m/d/Y', '01/01/2016'); $date->add(date_interval_create_from_date_string('59 days')); echo $date->format('m/d/Y')."\n"; ...
c#,algorithm,datetime,intervals
Let's say you store your task in a class like this: public class MyTask { public string name; public DateTime startDt; public DateTime endDt; // ... } The basic idea is to maintain two collections with tasks, one ordered by startDt the scond by endDt. We are going to use...
python,file,input,intervals,overlap
The with block for "bed" is closing the file after the block is complete. But while normally you would embed the open function call inside your with statement like so: with open(B, 'r') as input2 instead you are opening the file only once and then trying to operate on it...
Generally, this kind of problem becomes much easier if you sort the intervals by starting point. Firstly, let us define a function, in order to make things clearer: def overlap( r1, r2 ): left = max(r1[0], r2[0]) right = min(r1[1], r2[1]) over = right - left return (left, right, over)...
You can set the interval output style, but only to one of a few pre-defined formats that are unambigious on input, and that PostgreSQL knows how to parse back into intervals. Per the documentation these are the SQL standard interval format, two variants of PostgreSQL specific syntax, and iso_8601 intervals....
php,datetime,intervals,dateinterval
When using DateInterval() to create an interval you use M for minutes, not i. Also, if there are no seconds you must omit it from the interval declaration: $busts = $ts->add(new DateInterval('PT6M5S')); $lamts = $busts->add(new DateInterval('PT11M')); i is used for getting the number of minutes in a date interval: echo...
You can try test$time <- strptime(with(test, sprintf('%02d:%02d', hour, min)), '%H:%M') test$time[1:5] #[1] "2014-12-05 06:30:00 EST" "2014-12-05 06:31:00 EST" #[3] "2014-12-05 06:32:00 EST" "2014-12-05 06:33:00 EST" #[5] "2014-12-05 06:34:00 EST" Update For aggregating the counts (sum), you could try aggregate(count~ cbind(timeGr=as.character(cut(time, breaks='3 min'))), test, FUN=sum) timeGr count #1 2014-12-05 06:30:00 30.67396...
ios,time,nsdate,intervals,messages
I suggest to use this category. It is very helpful for what you are looking for. For example this line of code: NSString *displayString = [NSDate stringForDisplayFromDate:date]; produces the following kinds of output: - ‘3:42 AM’ – if the date is after midnight today - ‘Tuesday’ – if the date...
algorithm,computational-geometry,intersection,intervals
The idea to assign values is correct. You just need to sort intervals by their minumum value(in increasing order). That is, the solution looks like this: Build a segment tree(with -infinity values in all nodes). Process all intervals in sorted order. For each interval, just assign its value(no matter what...
sql,oracle,plsql,timestamp,intervals
You need to change your HOUR TO MINUTE to match the value you're actually passing: sysdate + INTERVAL '0 02:00:00.0' DAY TO SECOND You might also want to use systimestamp instead of sysdate. You can use a shorter interval literal too if you're always adding exactly two hours: systimestamp +...
javascript,angularjs,intervals
Currently you are cashing the $scope.tabs.length when you invoke the $interval service. If you want to display items that have been added after you call count, you have to check array length within you interval function, something like: interval = $interval(function() { if ($scope.tabs.length-1 > i) { ... } else...
python,coding-style,range,intervals
I use a class with __contains__ to represent the interval: class Interval(object): def __init__(self, middle, deviation): self.lower = middle - abs(deviation) self.upper = middle + abs(deviation) def __contains__(self, item): return self.lower <= item <= self.upper Then I define a function interval to simplify the syntax: def interval(middle, deviation): return Interval(middle,...
vb.net,timer,label,intervals,value
Int32.TryParse initializes the int parameter when it could parse the string to Int32 successfully, otherwise it will be 0. So either the string cannot be parsed because the format is invalid orit is "0". What is it's value? The value frmSettings.Lbl_Error_Millisec_Fin.Text is 0, take note that I've taken that from...
javascript,php,html,intervals,clear
Vanilla javascript: clears input value every 3 seconds setInterval( function() { document.getElementById("my-input").value = ""; }, 3000); <input id="my-input" type="text" /> ...
This is a bit awkward, but the idea is that you unroll the data into a series of opening and closing events. Then you track how many intervals are open at a time. This assume each group doesn't have any overlapping intervals. df <- data.frame(id=c(rep("a",4),rep("b",2),rep("c",3)), start=c(100,250,400,600,150,610,275,600,700), end=c(200,300,550,650,275,640,325,675,725)) sets<-function(start, end, group,...
postgresql,date,casting,intervals
That's because date is actually a function in PostgreSQL. There is an interval function too, but you need to quote it: SELECT "interval"(substring('2015015' from 5)||' days'); It is also possible to specify a type cast using a function-like syntax: typename ( expression ) However, this only works for types whose...
python,python-3.x,calculator,intervals
You are running the while loop until a and x becomes equal while you are actually looking for the intermediate value to be equal to x. You should write the loop like this instead: while float(CR5((a+x)/2.0))!= x: and while float(CR5((b+x)/2.0))!= x: result for x=4: (3.9999, 4.0001) ...
javascript,jquery,html,slideshow,intervals
You can use this example to implement yours.. var interval; $('#stop').click(function(){ clearInterval(interval); }); var slide = function(){ alert("testing setInterval"); } interval = setInterval(slide,2000); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <button id="stop">stop interval</button> ...
You can use a greedy algorithm: Sort all intervals by their end points(in increasing order). Iterate over a sorted array of intervals. When an interval is over, there are two options: It is already covered by some point. Nothing should be done in this case. It is not covered yet....
javascript,jquery,ajax,intervals
var islem; $(document).ajaxComplete(function () { $(".iframeFake").load(function () { clearInterval(islem); islem = setInterval(function () { $('.iframeFake').each(function (event) { console.log(1); }, 1000); }); }); If you want to maintain that there is always one interval, store the variable at a higher scope, and cancel before you create to stop any lingering...
$min15InSecs = 15*60; $min15 = time()-(time()%$min15InSecs)+$min15InSecs; $start = new DateTime(date("Y-m-d H:i", $min15)); $start->add(new DateInterval('PT1H')); $end = new DateTime("2015-05-16 19:00"); $interval = new DateInterval('PT15M'); $period = new DatePeriod($start, $interval, $end); $current_date = date('d-M-Y g:i:s A'); $current_time = strtotime($current_date); foreach ($period as $dt) { echo $dt->format('H:i')."<br>"; } ...
postgresql,time,format,intervals,postgresql-8.4
Use date_trunc(): SELECT date_trunc('second', interval '1 day 14:28:09.00901'); ...
I would approach this using data.tables foverlaps function First, we will convert to data.table objects, create start and end intervals, and sort campus.df by these intervals library(data.table) setDT(task.df)[, `:=`(start = as.POSIXct(paste(Start.Date, Start.Time)), end = as.POSIXct(paste(End.Date, End.Time)))] setkey(setDT(campus.df)[, `:=`(start = as.POSIXct(paste(Start.Date, Start.Time)), end = as.POSIXct(paste(End.Date, End.Time)))], start, end) Then, we could...
algorithm,optimization,intervals
Sort by startpoint, count the number of inversions in the list of endpoints using the mergesort-derived O(n log n)-time algorithm.
It looks like you're trying to get the time part from DATE2 and add it to DATE1? I'm afraid that Oracle doesn't recognize TO_CHAR(date2...) as an INTERVAL literal even though it appears to be in the correct format. I would try this instead (good old-fashioned Oracle date arithmetic): date1 +...
php,variables,delete,intervals
Use the floor() function to remove the fraction after the decimal: $cn = floor($cc/25); ...
c#,vb.net,datetime,intervals,calculated
My pseudo modulus operation: float tolerance = 0.0001f; if((CurTime - StartTime) % IntervalMinutes <= tolerance) { // Do something } ...
sql,oracle,timestamp,intervals
Using localtimestamp rather than systimestamp solved the issue as implicitly converting to a date type to subtract (1/24) loses the time zone.
If the intervals are already sorted and don't overlap: #!/usr/bin/perl use warnings; use strict; use List::MoreUtils qw{ natatime }; my @ary1 = qw(23-44 85-127 168-209); my $diff = 1; my $pair = natatime 2, '...', map({ map { $diff *= -1; $_ + $diff } split /-/ } @ary1), '...';...
angularjs,intervals,angularjs-ui-router
clear your interval on $destroy Try like this $scope.$on("$destroy",function(){ if (angular.isDefined($scope.Timer)) { $interval.cancel($scope.Timer); } }); ...
matlab,for-loop,matrix,indexing,intervals
You don't want to use loops for this in Matlab: VALS = ~(pvals < 2.7613 | pvals > 0.3621405); By the way, to fix your loop (and for every loop you ever make in Matlab) you should pre-allocate memory by just adding the line VALS = zeros(size(pvals)); before you loop....
java,oracle,prepared-statement,intervals
The entire expression INTERVAL '7' DAY is a literal, you cannot simply replace a part of it with a variable (parameter). Use the function NUMTODSINTERVAL(?,'DAY') instead.
r,loops,intervals,mathematical-optimization,maximize
This optimization problem is essentially going to be impossible for any optimizer (such as optimize()) that assumes the objective function is smooth and has a single minimum. You didn't give a reproducible example, but here's an example of an objective function that's just about as ugly as yours: set.seed(101) r...
Try this: $query = "DELETE FROM my_table WHERE DATE_ADD(`time`, INTERVAL 2 HOUR) < NOW()"; It adds two hours to your column value and if it is less then the current time it will be deleted. SQL Fiddle...
You can indeed use Boost ICL, as you suspected. The default interval combining style is "Joining". This is exactly what you need! So, it's home run. Here's a trivial demo with exactly the input events as given in the example. I print the state of the record at each event...
angularjs,cordova,time,intervals,ionic
Most likely the js runtime was unloaded from the device browser for your page (since the user is not looking at it and the device wants to save on battery), that is why it stops working, I don't think it is possible to overcome this completely you could somewhat fake...
Sort the points. Iterate over the points and compute the running sum of the values up to each point. Store the sums in an array. When you want to compute the sum for an interval, find the lower and upper limit by binary search, then look up the lower sum...
One solution is to replace your intervals by a simple id ( a sequence). This should be done for ints and out data.frames. Each id identify one interval. Once you do this the merge is straightforward. ## first I extract the intevals from ints in ordered manner id <- !is.na(ints$minValue)&!is.na(ints$maxValue)...
Try using else if var func = function () { 'use strict'; if (time === 1) { document.getElementById("top-background").style.backgroundColor = "#000"; time += 1; } else if (time === 2) { document.getElementById("top-background").style.backgroundColor = "#aaa"; time += 1; } else if (time === 3) { document.getElementById("top-background").style.backgroundColor = "#d5d5d5"; time -= 2; }...
You can use setInterval. The first parameter is the function you want to be executed and the second one defines the intervals (in milliseconds) on how often to execute the code. In your case 5 minutes = 300 seconds which is 300*1000 milliseconds. setInterval(function() { jQuery.ajax({ url: "/wp-admin/admin-ajax.php", data :...
You need to supply vectors of coordinates x0 and y0 and x1 and y1 which are the x and y coordinates to draw from and to respectively. Consider the following working example: x <- seq(0, 1000, length = 200) y <- seq(0, 80000, length = 200) plot(x,y,type="n") from.x <- c(0,...
I found out that one of the old interval methods was depreciate in iOS 8.0. I found I need to use: notification.repeatInterval = NSCalendarUnit.CalendarUnitWeekOfMonth ...
f#,mapping,intervals,discrete-mathematics
let interval = 10 let index = [6;12;18;24] let value =[101;102;103;104] let intervals = List.map (fun e -> e/interval) index let keys = List.map2(fun e1 e2 -> (e1,e2)) intervals value let skeys = Seq.ofList keys let result = skeys |>Seq.groupBy (fun p -> fst p) |>Seq.map (fun p -> snd...
r,loops,time-series,intervals,percentage
The R time series method ts, which you're trying to use, may be appropriate when there are an equal number of values per unit of time as in the case of months and years where there are 12 months in every year. However, since the number of days in a...
algorithm,binary-search-tree,computational-geometry,intervals,angle
The circularity of angles is not a major obstacle: to instead an interval like [270, 45) that wraps around, instead insert two intervals [270, 360), [0, 45). To implement insertion without wraparound, we can use a binary search tree. This tree tracks the uncovered intervals by mapping each endpoint of...
ruby-on-rails,postgresql,intervals,dst,postgresql-9.4
I've created a function which calculates ended_at by adding duration days to started_at honoring DST changes of a given time zone. Both started_at and ended_at, however, are in UTC and therefore play nice with Rails. It turns started_at (timestamp without time zone, implicit UTC by Rails) to a timestamp with...
actionscript-3,flash,timer,arduino,intervals
It is not entirely clear what you are asking (data being "clustered") but a few things – You are creating a new TextField on every Arduino event and adding them as children. Do you wish to have all the past events display or are you just wanting to display the...
Consider defining your ranges like this: [ { name: 'good', range: [6, Infinity }, { name: 'normal', range: [3, 6] }, { name: 'warning', value: [-6, -3] }, { name: 'danger', value: [-Infinity, -6] } ] With the existing data, you can build such a range like so: var points...
objective-c,cocoa-touch,nstimer,intervals
Make the timer object a member variable. Initially set animation time as 1 second. In the callback invalidate the timer and create a new one with 1 or 4 seconds depending on the counter. @interface ViewController () @property (strong,nonatomic) NSMutableArray *images; @property (strong,nonatomic) UIImageView *animationImageView; { NSTimer *_timer; } @end...
r,string,printf,logic,intervals
Perhaps not as short, but this makes use of the fact that you're actually working with date/time values here and they do not behave like regular numeric sequences strftime(seq( as.POSIXct("2014-01-01 9:20:00"), as.POSIXct("2014-01-01 15:40:00"), by="20 min") , "%H:%M") # [1] "09:20" "09:40" "10:00" "10:20" "10:40" "11:00" "11:20" "11:40" "12:00" # [10]...
javascript,intervals,clearinterval
Problem seems to be in function fadeOut(), at this line: if(opac < 0) {setInterval(fadeIn, fadeInterval)}; //<-- required fadeTiming instead, also missing the assignment Try this: if(opac < 0) { clearInterval(fadeInterval); //make sure if the interval isn't already running fadeInterval = setInterval(fadeIn, fadeTiming); } ...
A big thank you for those you responded, I used your exemples and managed to make em work with my table and my data. Here's the final request : SELECT * from My Table where time(FROM_UNIXTIME(`date`)) > '06:00:00' and `date` > UNIX_TIMESTAMP("2015-05-01 00:00:00") and `date` < UNIX_TIMESTAMP("2015-05-02 00:00:00"); Basically the...
You're looking for cut cut(1:10, c(1, seq(2.5, 10, by=2.5)), include.lowest = T) # [1] [1,2.5] [1,2.5] (2.5,5] (2.5,5] (2.5,5] (5,7.5] (5,7.5] (7.5,10] # [9] (7.5,10] (7.5,10] # Levels: [1,2.5] (2.5,5] (5,7.5] (7.5,10] If you just want the evenly spaced breaks, use seq x <- 0:10 seq(min(x), max(x), len=5) # [1]...
As is suggested by dlask's comment in your question, you can make use of the bisect library: boundaries = [0.009, 380.2, 389.8, 390.2, 399.8, 410.2] values = [None, -39, -94, -39, -60, -39, None] # what you need import bisect values[bisect.bisect_left(boundaries, x)] Assume you can construct boundaries and values with...
sql,datetime,intervals,teradata
There's no HOUR function in Teradata, according to Standard SQL it's EXTRACT: EXTRACT(HOUR FROM timestampcol) And of course you need a aggregate function, but i assume VOLUME will be the alias for a SUM/AVG/COUNT :-)...
c#,multithreading,timer,backgroundworker,intervals
It took me a while, but I found out what was wrong. I'll post you a working code, just in case someone will have the same problem. public partial class Form1 : Form { public int ticks = 0; public bool running = false; public bool push = false; public...
sql,oracle,oracle11g,intervals
An interval of 300 months is exactly the same thing as an interval of 25 years, and they are of the same data type too: year intervals, year-month intervals and month intervals are just three ways of expressing the same type. You're shown +25-00 because one of the representations had...
sql-server,sql-server-2008-r2,intervals
The task you want to achieve is non trivial. A possible solution involves placing all From / To dates in an ordered sequence. The following UNPIVOT operation: SELECT ID, EventDate, StartStop, ROW_NUMBER() OVER (ORDER BY ID, EventDate, StartStop) AS EventRowNum, IsCancel FROM (SELECT ID, IsCancel, [From], [To] FROM Event) Src...
Here's an Rcpp solution. It will be fast and memory efficient (for details see below). First let's define a helper function which calculates all the pairwise distances. If n is the number of intervals to consider, we have n*(n-1)/2 unique pairs of vectors (we don't take the same intervals into...
vb.net,timer,delay,intervals,firing
TextChanged fires every time you change the content of the textbox. So there is no way to block this behavior. Perhaps you could add a button and move the recalculation on the button click event or better add an event handler for the Validating event. This event is triggered when...
javascript,date,datetime,time,intervals
Here's a function that should do what you want. As suggested in the comments, just calculate the time in milliseconds and increment until you reach your stop time. function calculate() { var a = []; var startValue = document.getElementById("startTime").value; var endValue = document.getElementById("endTime").value; var intervalValue = document.getElementById("interval").value; var startDate =...
Looking through the iAd Programming Guide I cannot find any explicit instruction to not periodically hide and display iAds as you are suggesting. To achieve this the best way to do it would be through the use of an NSTimer. I would declare a property: /** A timer used to...
python,numpy,pandas,time-series,intervals
I found an approach that seems to work well: Assuming we can transform our Login/Logout data into two DataFrames indexed by time: Login UserLogin -------- --------- 8:58AM User_2 9:23AM User_3 10:25AM User_1 3:10PM User_3 Logout UserLogout -------- ---------- 1:35PM User_3 4:49PM User_3 5:12PM User_2 6:01PM User_1 Then we can add...