JSONObject keySet() function not there?
java,android,jsonobject,keyset,missingmethod
See the @hide annotation * @hide. */ public Set<String> keySet() { return nameValuePairs.keySet(); } ...
JSON doesn't work on Android Lollipop
android,json,android-asynctask,android-5.0-lollipop,jsonobject
Okay, so after looking for an answer it seems the problem isn't with my code, the problem is with android 5. I tried many tutorials of JsonArray/JsonObject, downloaded their samples etc but nothing worked. Also, I've witnessed a growing number of developer who suffer from the same problem. Thanks to...
Retrofit not parsing JSONObject
android,parsing,retrofit,jsonobject
You need to create a response object public class UserResponse { private User responseData; private String message; private boolean success; } And change your callback to return a UserResponse public interface RetrofitService { @FormUrlEncoded @POST("/login") public void login(@Field("email_id") String emailId, @Field ("password") String password, Callback <UserResponse> callback); } NOTE: You...
Get value from JSONArray
android,json,parsing,jsonobject
The way to do it is: JSONArray cast = obj.getJSONArray("data3"); String[] string_array = new String[](); for (int i=0; i<cast.length(); i++) { string_array[i] = cast.getString(i); retVal.data3.set(i, string_array[i]); } Try this. This will work....
How to get given Bellow value from json data?
android,arrays,json,jsonobject
You should really look into How to parse JsonObject / JsonArray in android. Please put your code of also what you have tried because people are here to help solve error/problem not to do coding. Here is code from which you can Parse your json JSONObject jsonObject = new JSONObject();...
JSONObject toString sometimes throw a ConcurrentModificationError
I was able to resolve this. The problem was message.put("message", tempObject.toString()); The method call tempObject.toString() leads to an iteration through the list (presumption) and the message.put(...) leads to accessing the resultant string. Sometimes this leads to ConcurrentModificationException. I was able to resolve it by doing it in two lines and...
Android Incorrect value when converting String to StringEntity
android,string,http-post,jsonobject
Try using URL Connection : public JSONObject readJSONFromURL(String urlString, JSONObject param){ String response = null; JSONObject jObject = null; try { URL url = new URL(urlString); URLConnection conn = url.openConnection(); conn.setDoOutput(true); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("dmode", param.toString())); OutputStream os = conn.getOutputStream(); BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));...
How to use JSONObject effective in your android project
There are millions of implementation and usecase about JSON+Android. I use gson in order to de/serialize an object as below. It is more reliable than sequence-sensitive Parcelable conversion for me. public static String toJson(Object obj){ Gson gson = new Gson(); return gson.toJson(obj); } public static Object fromJson(String json, Class clazz)...
Get a String from an Array in JSON in Android Studio
java,android,arrays,json,jsonobject
If you want to get "Yuliem" you can do this: String json = "{\"id\":[{\"id\":\"2\",\"name\":\"Yuliem\"}],\"success\":1,\"message\":\"Product successfully created.\"}"; JSONObject obj = new JSONObject(json); JSONArray array = (JSONArray) obj.get("id"); JSONObject innerObj = (JSONObject) array.get(0); Log.d("User's name: ",innerObj.get("name")); ...
Fragment crashes with Parcel: unable to marshal value error when onPause method is called
android,android-fragments,serializable,jsonobject
Well I managed to figure a way out of this, it may not be the most standard of way of doing things but it actually solved my problem and might help others to some extent. What I did was instead of converting the JSONArray that was received from the API...
Android JSON ListView import
android,json,import,arrays,jsonobject
You can use JSONArray post_id = new JSONArray(jsonStr); instead of JSONObject jsonObj = new JSONObject(jsonStr); // Getting JSON Array node post_id = jsonObj.getJSONArray(TAG_POSTID); because jsonStr you get is a JSONArray...
How to create a dynamic JSONObject?
thanks for your response I've manage to solve this problem as follow: JSONObject outerObject = new JSONObject(); JSONArray outerArray = new JSONArray(); JSONObject [] innerObject = new JSONObject[4]; for(int i =0; i<3; i++) { innerObject[i]=new JSONObject(); innerObject[i].put("id", "id of "+i); innerObject[i].put("url", "url of "+i); innerObject[i].put("Definition", "Definition of "+i); outerArray.put(innerObject[i]); }...
Google Map markers and JSON object
javascript,json,google-maps,marker,jsonobject
From your current code you would then need to loop through the markers with a for loop like so and add a marker to the map: var data = '{"markers":[{"k":48.80686346108517,"B":1.494140625},{"k":50.28933925329177,"B":14.326171875},{"k":43.70759350405294,"B":21.357421875},{"k":30.977609093348686,"B":11.337890625},{"k":40.58058466412761,"B":-0.87890625},{"k":48.45835188280866,"B":1.318359375}]}'; function createMarkerBasedOnFetchedPosition(fetchedMarkersPosition) { var jsonData = JSON.parse(fetchedMarkersPosition); for (var i = 0; i <...
JSON parsing with dynamic JSON object name?
Finally got the solution, at the time of debugging, string shows all data doesn't matter how much it is, but in JSONObject all data is available but it doesn't shows while debugging.When retrieved the data from JSONObject i got all fields which are not shown in debugger.
Android JSONObject to ListView
android,listview,android-listview,android-arrayadapter,jsonobject
As you are using just a single text field in your code you need not make a custom Adapter just for that as you can use Android's ArrayAdapter. ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1, listdata.toArray()); menu_list.setAdapter(adapter); This snippet uses default Android List layout and a TextView which will take...
how to get JSON representation of Java Objects in JAX-RS layer in java EE 7?
json,java-ee,gson,java-ee-7,jsonobject
JAX-RS will convert your objects to JSON, no need to do it manually. I.e., the following code: @GET @Path("/books") @Produces(MediaType.APPLICATION_JSON) public Response getBooks() { List<Book> listOfBooks = getMiscService().getbooks(); return Response.status(Response.Status.OK).entity(listOfBooks).build(); } ...will produce a JSON like: [ { "title": "Book1", "author": "Foo", ... }, { "title": "Book2", "author": "Bar", ......
In HttpURLConnection Why don't JSONObject as Params work but String as Params are working
java,php,android,httpurlconnection,jsonobject
I reckon the problem here is not at the Java side, If the parameters is of fixed type like in json in your case, the JSON Object as POST params method will work if collected this way on the php side: <?php $json = file_get_contents('php://input'); $obj = json_decode($json); print_r($obj); print_r("this...
NoClassDefFoundError: org/json/JSONObject - Hadoop MapReduce
json,maven,hadoop,noclassdeffounderror,jsonobject
You can use jackson to process json. <repositories> <repository> <id>codehaus</id> <url>http://repository.codehaus.org/org/codehaus</url> </repository> </repositories> <dependencies> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-mapper-asl</artifactId> <version>1.8.5</version> </dependency> </dependencies> or google's gson <dependency>...
JSONObject cannot be converted to JSONArray and vice versa?
Your JSON consists of an object. That object contains an array named results. The array contains object elements. Each object in the array contains an object named geometry. That object contains an object named location. That object contains lat and lng floating-point values. So, your code should look something like...
Is this a valid JSONObject & if yes then how do I iterate to get all the values
The json string seem to be legit. Here's some code to parse it. I'm using json-simple-1.1.1.jar downloaded from here: https://code.google.com/p/json-simple/downloads/detail?name=json-simple-1.1.1.jar&can=2&q= import org.json.simple.JSONArray; import org.json.simple.JSONObject; import org.json.simple.parser.JSONParser; public class JsonExample { public static void main(String[] args) throws Exception { System.out.println("Starting example..."); String str =...
Uncaught SyntaxError - Get the value of an object that is in another object
I'm wondering how you ever came up with that JSON string. {"test":"testvalue", "test2":"{"boxcolor":"bg-white", "iconcolor":"bg-aqua"}"} ^ ^ Here's the fixed code: var testData = '{"test":"testvalue", "test2":{"boxcolor":"bg-white", "iconcolor":"bg-aqua"}}'; testFunction(testData); function testFunction(data) { var obj = JSON.parse(data); alert(obj.test2.boxcolor); // bg-white } ...
Java GSON: Getting the list of all keys under a JSONObject
You can use JsonParser to convert your Json into an intermediate structure which allow you to examine the json content. String yourJson = "{your json here}"; JsonParser parser = new JsonParser(); JsonElement element = parser.parse(yourJson); JsonObject obj = element.getAsJsonObject(); //since you know it's a JsonObject Set<Map.Entry<String, JsonElement>> entries = obj.entrySet();//will...
Parse JSON of two dimensional array in JAVA
java,arrays,json,parsing,jsonobject
The JSON you've got is for an array, not an object. You probably want JSONArray array = new JSONArray(jsonString); Full sample code: import org.json.*; public class Test { public static void main(String[] args) { String json = "[[\"1\",\"100\"],[\"2\",\"200\"],[\"3\",\"300\"]]"; JSONArray array = new JSONArray(json); JSONArray first = array.getJSONArray(0); System.out.println(first.getString(1)); // Prints...
accessing arrays in json object without using keys
javascript,json,arrays,jsonobject
This should populate the cities array: var data = { China: ["Guangzhou","Fax"], Majorette: ["Fungous","Godzilla"], Bhutan: ["Thimphu","Parr","Photofinishing"] } var cities = []; for(var i in data){ if(data.hasOwnProperty(i)){ for(var j in data[i] ){ if(data[i].hasOwnProperty(j)){ cities.push(data[i][j]); } } } } console.log(cities); JSFIDDLE Demo...
Java - Retrieve values of variable type from JSONObject
Apply this to receive all the data types in string format occupation = firstResult.getJSONObject("job").get("occupation").toString(); ...
How to show jsonarray value in android
android,json,arrays,jsonobject
How do i convert it into jsonobject. e.g "name":["The name field is required."] You dont need to convert these JSONarrays to JSONobjects. when you found "[]" means its array and "{}" means its object. In your case first convert your total json to JSONobject then retrive its value from its...
java jdbc how can I properly add data into JsonObject
I have made changes in such a way to build the JSONArray from SQL output. JSONObject jo = new JSONObject(); Connection conn = DB.getConnection(); ResultSet rs; PreparedStatement ps = conn.prepareStatement("select city,state from zips limit 2"); rs = ps.executeQuery(); JSONArray ja = new JSONArray(); while (rs.next()) { jo.put("city", rs.getString("city")); jo.put("state", rs.getString("state"));...
Accessing Json objects
javascript,html,json,angularjs,jsonobject
As per my understanding of your problem the following is the answer for your question . Your html code like this <div ng-app="myApp" ng-controller="myController"> <table> <tr> <th>Type</th> <th>Shape</th> </tr> <tr ng-repeat="(key ,value) in list.Kind"> <td>{{key}}</td><td>{{value.shape}}</td> </tr> </table> </div> After that your javascript like this var myApp = angular.module("myApp", []); myApp.controller("myController",...
How to parse this JSON file to some ArrayList?
android,arrays,json,parsing,jsonobject
There are several ways to do this, but I'll post the way I feel like makes the most sense. If you don't mind putting this in separate arrays you can do this: String stringOfJSONCode = <read in the JSON here>; JSONObject json = new JSONObject(stringOfJSONCode); Iterator<String> iter = json.keys(); while...
Why does android not have a function for putting a String value into a JSONObject?
Refer to this link http://developer.android.com/reference/org/json/JSONObject.html JSONObject put(String name, Object value) Maps name to value, clobbering any existing name/value mapping with the same name. Datatype Object is the root class of the Java class hierarchy. All non-primitive types (including arrays) inherit either directly or indirectly from this class. Therefore jsonObject.put("name", "myname");...
Use of JSONObject and JSONArray in Jmeter
arrays,json,variables,jmeter,jsonobject
You could trt with this snippet: if(${i}%(${bufferSize}*${sample}-1)==0 && ${i}!=0 || ${i}==${totalNumber}-${endOfDb}){ vars.put("json",vars.get("json")+part.toString()); JSONArray records= new JSONArray("["+vars.get("json")+"]"); log.info(records.toString()); //records.put(tempArray); JSONObject kinesis = new JSONObject(); kinesis.put("records",records); kinesis.put("streamName","kinesis"); vars.put("jsonBuffer",kinesis.toString()); vars.put("json",""); } ...
What is the difference between JSONObject accumulate and put?
I saw the Java Source Code for JSONObject and the difference between accumulate and put is that with accumulate(String key,Object Value), if there exists some value for "key" then the Object is checked for being an array, if it is an array then the "value" is added to the array...
Using Java 8 Optional with JSONObject?
json,java-8,optional,jsonobject
It is not refactorable in a nicely way to Optionals in this case. Why? getJSONObject() method will never return null. If there is no value associated with provided key, it will throw JSONException. Optional monad was designed for handling nulls and not exceptions. Those checks are necessary in this case....
JSON character encoding in javascript different from java
java,javascript,json,unicode,jsonobject
There are two different things happening: Unicode encoding and JSON string escaping. Per 2.5 Strings of the JSON RFC: .. All Unicode characters may be placed within the quotation marks except for the characters that must be escaped .. Any character may be escaped. If the character is in the...
The type or namespace name 'Json' does not exist in the namespace 'System' (are you missing an assembly reference?)
That package is discontinued and shouldn't be used any more. If you have a console application, I could recommend two options: JSON.NET. Not a part of the .NET Framework itself, but much faster than Microsofts implementation; Microsofts implementation of the JavaScriptSerializer. Both are capable of reading and writing JSON. I...
How to make Custom ArrayList using JsonObject values?
Try this.. JSONObject jsonObject = new JSONObject(response.toString()); JSONObject jsonOb=jsonObject.getJSONObject("LocationMatrix"); Log.e(TAG,"jsonOb :"+jsonOb.toString()); Iterator i = jsonOb.keys(); while (i.hasNext()) { try { String key = i.next().toString(); String j = jsonOb.getString(key); locationList.add(new Location(Integer.parseInt(key), j)); } catch (JSONException e) { e.printStackTrace(); } } ...
How to extract values from JSONObject in android
android,json,arrays,jsonobject,android-json
Hope this may help you JSONObject jsonObject=new JSONObject(result); jsonObject=jsonObject.getJSONObject("1"); Double lat=jsonObject.getDouble("latitude"); Toast.makeText(getBaseContext(),""+ lat, Toast.LENGTH_LONG).show(); ...
JSON parsing with multiple data
javascript,json,parsing,jsonobject
Something must have gone wrong in creating this string. Yes, it's valid JSON, but it has a different format than you think, because you escape control characters like " and [, ]. Try this string instead: [ { "obj":{ "markers":[ { "k":47.040182144806664, "B":0.52734375 }, { "k":50.90303283111257, "B":10.37109375 }, { "k":52.53627304145945,...
Why the use of ampersand in parsing JSON data when specifiying error in Swift? [duplicate]
json,swift,parsing,jsonobject,nsjsonserialization
& is required for in-out parameters. I hope you are aware that your app will crash if it doesn't receive a JSON dictionary. Which is very likely to happen if you are behind a paywall, for example. So your app is likely to crash if I try it in a...
How to separate item from JsonObject within StringBuilder?
java,android,stringbuilder,jsonobject
Use this: try { JSONObject job = new JSONObject(sb.toString()); int Status = job.getInt("Status"); String SessionId = job.getString("SessionId"); } catch (JSONException e) { // Handle error } Reference: http://developer.android.com/reference/org/json/JSONObject.html...
convert json object to specific json array
javascript,json,arrays,jsonobject
You're close: var seriesValues = []; for (var abc in objJSON.yAxis) { seriesValues.push({name: abc, data: objJSON.yAxis[abc]}); } That will make a javascript array. If you need it as a JSON string then append: var myString = JSON.stringify(seriesValues); ...
JSONArray only returns 1 put?
What put does is set the key (the first parameter) to the value (the second parameter). So, first you set json.Country to Ireland and json.Capital to Dublin. Next, you overwrite json.Country and set it to Spain, and continue to do so until finally, the Country and Capital are overwritten to...
JSON Parsing creating error
jsonResponse actually doesn't hold the "ratings" object. It is inside each object in the "movies" array. You need something like this: for (int i=0; i<movies.length(); i++) { try { JSONObject movie = movies.getJSONObject(i); JSONObject ratingsobj = movie.getJSONObject("ratings"); String audrating = ratingsobj.get("audience_score").toString(); audscore.add(audrating); } catch (Exception e) { audscore.add("Unavailable"); } }...
Google Map fetch dynamic LatLng index
javascript,google-maps-api-3,latitude-longitude,jsonobject
var lat = this.getPosition().lat(); var lng = this.getPosition().lng(); Generally there are getters and setters for many things in GM, and you should look for those in the docs before going into the inspector....
How to write json object in json file in sdcard in android [closed]
Just get a String from the JSONObject and write it into the file like this: String content = json.toString(); FileWriter fw = new FileWriter("path"); BufferedWriter bw = new BufferedWriter(fw); bw.write(content); bw.close(); You will of course need to catch/throw exceptions and so on....
Error Parsing JSON file in Android
java,android,json,arrays,jsonobject
You are trying to get JSONArray of "questionAnswers" from "data" instead of "survey" String yourJSONString = "{"code":1,"data":{"survey":{"id":null,"questionAnswers":[{"id":null,"min":"1","max":"5","step":"0.1","last":"4.7","text":"I am happy at work today","key":"Mood","testQuestionId":"1","datetime":"2014-04-29 15:47:02","answer":"4.7","testAnswerId":null}]}}}"; JSONObject jObj_main = new JSONObject(yourJSONString); JSONObject jOb_data = jObj_main.getJSONObject("data"); JSONObject jOb_survey = jOb_data.getJSONObject("survey");...
How to iterate over JSON Object and get the values for each key
This should do the trick: function extract(data){ return Object.keys(data).map(function(x){ return data[x].filter(function(z){return z!==null;}); }); } Here is the fiddle to play with. For explanation of map, take a look at MDN If you want to flatten the data, you could extend it to: function flatten(data){ return Object.keys(Object.keys(data).map(function(x){ return data[x].filter(function(z){return z!==null;}); }).reduce(function(o,n){...
Json Parsing nested array
look closely at data[0]: posts contains an array of two strings that say "[object Object]", not two objects. How are you parsing the json? oh, and your syntax is correct for extracting the username from the nested objects...
Unterminated object when converting a String to JSON
java,android,json,escaping,jsonobject
Problem caused because of = sign near by actionResult as well as actionResult not surrounded with double quotes and you didn't close json string properly. Replace Json String With: { "responseData": { "emotion":"", "lastinput":{"actionResult":{"value":{"label":"green","key":"1"},"result":"success","action":"displayClickableList"}, "answer":"Sorry, I did not understand.", "link": { "href":"", "target":"" }, "extraData": { }, "responseSession": { "id":"c4a5ef257851a991eb32c69132c9",...
How to pass an actual object (i.e. reference to an object) to a directive?
javascript,angularjs,angularjs-directive,jsonobject
At the moment, you aren't referencing an actual object, only a property on the attrs construct that will return a string. There are a couple of ways you could pull in an actual reference. Using scope.$eval //Target object will be pulled in if it exists on the scope // this...
extract string from a json object
json,extjs,textfield,jsonobject
The scope within your select function no longer contains datajson. To continue to use this.datajson you can pass the required scope into the function using bind Ext.application({ name: 'Fiddle', datajson: { 'name': 'Hello' }, displayName: function (combo, record, index) { Ext.getCmp('name').setValue((this.datajson.name)); }, launch: function () { Ext.create('Ext.form.Panel', { title: 'Contact...
Spring rest client + camunda rest api: postForObject only accept camunda.bpm JSONObject but JacksonMessageConverter only takes javax JsonObject
spring,resttemplate,jsonobject
After some research on how MappingJackson2HttpMessageConverter actually works and taking a closer look at Camunda REST API's request content format, I found that the problem lies in Jackson converter not able to parse anything that doesn't starts with the ArrayList start token "[". Since I have to pass a request...
Working with JSON object Facebook Graphapi
android,json,facebook-graph-api,jsonobject
Since data is inside of friends. Try this JSONObject friends= object.getJSONObject("friends"); JSONArray data = friends.getJSONArray("data"); ...
Android JsonObject parsing string with double quotes
Just trim out the quotes: authorization = authorization.substring(1, authorization.length() - 1)
Android: Rest api returns incomplete response
In your code "doc list" log could be truncated. "total records" is an Integer so it's truncated. To log "jsonObj" the only way is to store it in a file. You have to add permission to write external storage: <manifest ...> <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" /> ... </manifest> And then put your...
how i can send json object from server to jsp and received a response on jsp
java,javascript,json,jsp,jsonobject
Yes, that's right JSON.parse(data) resulted in an error. Also wrap your script in a document.ready function $(function(){ ... }); to be sure that the DOM is ready before you access it. The rest of your code is working. I just commented the parameters to the server because I have no...
How to iterate JSON object properly?
javascript,iteration,jsonobject
Try this code. Ensure you have parsed the json string. And use array map function to get all names. var jsonString = '{"data":{"pkg":[{"name":"ThisIsName1","FRONTPAGE":"n","IP":"n","MAXSQL":"1","MAXPOP":"unlimited"},{"name":"ThisIsName2","FRONTPAGE":"n","IP":"n","MAXSQL":"0","MAXPOP":"unlimited"},{"name":"ThisIsName3","FRONTPAGE":"n","IP":"n","MAXSQL":"0","MAXPOP":"unlimited"}]},"metadata":{"version":1,"reason":"OK","result":1,"command":"listpkgs"}}'; var jsonData = JSON.parse(jsonString); var names =...
JsonObject from PHP to Android + security
php,android,json,security,jsonobject
Server response is came in JSONArray so no need to convert in JSONObject just build JSONArray from server response and return as JSONArray instead JSONObject from makeHttpRequest : JSONArray jsonArray = jsonParser.makeHttpRequest(EVENTS_URL, "POST", params); ...
Adding a JSON Object under another JSON Object for Android
android,arrays,json,jsonobject
If this is the end of your code, JSONObject solutions = new JSONObject(); solutions.put("solutions", 20); JSONObject refundable = new JSONObject(); refundable.put("refundable","false"); then the issue is you're never actually adding the objects to your request object. Also, those are values and not JSONObjects, so you should replace it with: requests.put("solutions", 20);...
Android as a Client, Server using Spring annotation,communication in JSON format,error while receiving in server
android,spring-annotations,jsonobject
You should create on server side a class that looks like this public class UserDetails { private String id; private String password; private String username; public String getId() { return id; } public void setId(String id) { this.id = id; } ... // other two getter setter } And then...
Why is JSONObject.accumulate() affecting the values of other keys?
The problem is in your method that calls addCounters(). The reference you're passing in the parameter long[] counters is being initialized once to new long[2] and mistakenly reused. You must initialize the variable to a new long array each time you execute the sorting algorithm.
Can't parse JSON formatted response from server
The problem is that you are trying to parse the next level also. When you parse from JSON to an object, it will parse all levels. You get an object containing objects, not an object containing JSON strings that needs to be parsed. Just get the object from the property:...
new JSONObject() lead to ERROR if json starts with [] instead of {} in Java/windows 7?
If it starts with a square bracket then it's not a JSON object, it's a JSON array.
Parsing JSON Android ArrayList
java,android,json,arraylist,jsonobject
If I understand you correctly, you want to create an ArrayList of your POJO? I assume you have getters and setters inside your POJO class. Initialize an ArrayList somewhere near the top like this private ArrayList<CholesterolInformation> mCholesterol; Now, parse through your json like this JSONobject data = new JSONObject(jsonStringData); JSONArray...
How to compare two JSON strings when the order of entries keep changing [duplicate]
java,json,string,equals,jsonobject
Jackson Json parser has a nice feature that it can parse a Json String into a Map. You can then query the entries or simply ask on equality: import com.fasterxml.jackson.databind.ObjectMapper; import java.util.*; public class Test { public static void main(String... args) { String input1 = "{\"state\":1,\"cmd\":1}"; String input2 = "{\"cmd\":1,\"state\":1}";...
Unable to get the value of JSONObject in android
android,json,arrays,jsonobject
Do this way Replace these two lines LessonTemplateArrayList.setVideo(customFieldsObject.getString("wpcf-video").replace("\\", "")); LessonTemplateArrayList.setIconImage(customFieldsObject.getString("wpcf-icon").replace("\\", "")); With LessonTemplateArrayList.setVideo(customFieldsObject.getJSONArray("wpcf-video").getString(0)); LessonTemplateArrayList.setIconImage(customFieldsObject.getJSONArray("wpcf-icon").getString(0)); ...
Passing a org.json.simpleJSONArray to an Intent in Android as an Extra
java,android,json,android-intent,jsonobject
If you have to use org.json.simple.*, here is the solution to convert java Strings that look like JSONArrays into parseable JSONObjects String searchResponseJSON = API.search(term, location); JSONParser parser = new JSONParser(); JSONObject response = null; try { response = (JSONObject) parser.parse(searchResponseJSON); } catch (ParseException pe) { System.out.println("Error: could not parse...
How to store all json object values in arraylist?
android,json,android-edittext,jsonobject
Try this: ArrayList<Integer> minqtyList = new ArrayList<Integer>(); JSONArray array = ck.getJSONArray(BULKPRICE_LIST); for (int i = 0; i < array.length(); i++) { JSONObject row = array.getJSONObject(i); int minqty = row.getInt("minqty"); minqtyList.add(minqty); } In your code, you need to edit this portion like that: bulkprice = ck.getJSONArray(BULKPRICE_LIST); allqtys=new ArrayList<String>(); // initialisation must...
JsonObject in Java
headers should be a JSONArray, not JSONObject. An object is a set of name-to-value mappings, an array is a linear collection. JSONArray headers = new JSONObject(); headers.add("ID"); headers.add("Organization Name"); headers.add("Submission Date"); headers.add("Status"); JSONObject organizationsHJ = new JSONObject(); organizationsHJ.put("headers", headers); array.add(organizationsHJ ); ...
(iOS) Add data from json in array
ios,objective-c,arrays,jsonobject
Depending on the JSON, the object returned from [NSJSONSerialization JSONObjectWithData] is either an NSArray or NSDictionary. If objectAtIndex doesn't work, chances are you are dealing with an NSDictionary. The safest way to go is to check which one it is in your code: if([strResult isKindOfClass:NSArray.class]) { // Do something that...
How to get a ParseFile from JSONArray (retrieved from CloudCode parse.com) in Android
android,json,parse.com,arrays,jsonobject
whats the mimetype of the data you stored as file on parse? Normally when you upload to parse you provide a file name to the parse api (including ".typ" ) that will indicate a mimetype to any subsequent GET requests. Those gets can just wrap http protocol with the parse...
JSONObject inside JSONArray
The JSONArray contains one JSONObject. When you jsonArray.put(jsonObject); you are adding it to the JSONArray, not to the JSONObject in the JSONArray. This will add the jsonObject to the first JSONObject in your JSONArray jsonArray.getJsonObject(0).put("events",jsonObject.get("events")); ...
get data from JSONObject according to a key
javascript,html,json,jsonobject
JSFiddle here HTML <table align='center' > <tr> <td> <select id='listSelect' onChange="updateList()"> <option value='' selected >All</option> <option value='Admin'>Admin</option> <option value='Client'>Client</option> <option value='Regulator'>Regulator</option> </select></td> </tr> </table> <div id="result"></div> JS var jsonObj = { "headerContent": [ { "...": "..." } ], "bodyContent": [ { "userId": "user_1", "userName":...
Android Volley JSON response
android,json,android-volley,jsonobject,postman
The problem was in Postman caching It's better to disable the parameter "Auto save request" in the settings....
In Java, is there a way I could go from JSONObject to JSONStringer, or vice versa?
Maybe there are much better solutions, but at least you have two choices: 1.after building json object inside a method which calls JSONString.endObject(); you can use JSONObject class to add other key/values or modify existing ones: JSONStringer json = new JSONStringer(); json.object(); json.key("stuff").value("1") .key("name").value("2") .key("type_name").value("3") .key("type").value("4"); json.endObject(); //after calling the...
Map put not working Java
hashmap,put,jsonobject,linkedhashmap
Luca, please describe more clearly what you have in your structure at the end of your test, {"Key" : { } } doesn't mean much, what kind of Object is the {} value? Looking at this series.put(serieObject.getSerie_instance(), serieObject); serieObject seems to have at least that weirdly named getSerie_instance key and...
Joda DateTime Json date format issue
json,datetime,gson,jodatime,jsonobject
In the JS/Jquery, I used var endTimestamp = new Date(data[i].endTimestamp.iMillis); ...
Cannont resolve symbol JSONObject (Android Studio)
android,json,android-studio,jsonobject
I´ll respond to the future, if someone has the same error: I did this (Thaks to Bigdestroyer): File -> Invalidate caches/Restart -> Invalidate and Restart You can try to delete ~/.gradle/caches directory to force re-download the dependencies. Now its works perfect. Thanks !!!! ...
trying to get table row count value but got Error converting result java.lang.NullPointerException: lock == null
javascript,php,android,json,jsonobject
i've finally solve my problem, first i create a config.php for connection to the database <?php $username = "root"; $password = ""; $host = "localhost"; $dbname = "smkkimmanuel2"; $options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'); try { $db = new PDO("mysql:host={$host};dbname={$dbname};charset=utf8", $username, $password, $options); } catch(PDOException $ex) { die("Failed to...
Getting a JSONObject from a JSONArray?
Change this section : for(int x = 0; x < retorno.length(); x++){ JSONObject jsoObject = retorno.getJSONObject(x); JSONObject jsoLocal = jsoObject.getJSONObject("Local"); JSONObject jsoTipoLocal =jsoObject.getJSONObject("TipoLocal"); } To for(int x = 0; x < retorno.length(); x++){ JSONObject jsoObject = retorno.getJSONObject(x); if(jsoObject.has("Local")) { JSONObject jsoLocal = jsoObject.getJSONObject("Local"); } if(jsoObject.has("TipoLocal")) { JSONObject jsoTipoLocal = jsoObject.getJSONObject("TipoLocal");...
passing json reply from webservice to variables
java,android,json,arrays,jsonobject
You are getting response in JSONObject and you are trying to get it in JSONArray.. thats why you are getting error.. Try this way... try { JSONObject result = new JSONObject(response); if(data.has("ValidateLoginResult"){ JSONArray array = result.getJSONArray("ValidateLoginResult"); for (int i = 0; i < array.length(); i++) { JSONObject obj = array.getJSONObject(i);...