ruby-on-rails,model-view-controller,devise
Something like this should do it, this is in courses controller show action (index action should be the list of all courses, show action should be viewing an individual course): class CoursesController < ApplicationController def index @courses = Course.all end def show @course = Course.find(params[:id]) current_user.viewed_courses.create(course: @course) end end One...
ruby-on-rails,model-view-controller,routes
You need to pass the method DELETE as well, otherwise it will perform the simply GET request. Here's how: <%=link_to "Delete Message", delete_path(t), :method => 'delete' %> Remember if you do not mention any method in link_to, the default will be taken as GET. So you have to be explicit...
ruby-on-rails,ruby,model-view-controller
So I believe you've correctly identified that the problem lies within your correct_user method: def correct_user @habit = current_user.habits.missed_days.find_by(id: params[:id]) redirect_to habits_path, notice: "Not authorized to edit this habit" if @habit.nil? end Take a look at your first line, here's what I read in English: Take the current User Get...
Meanwhile I have a hacked solution. In the onInit method of the controller I register to the onmousemove event. Each time the mouse will be moved I can check if there is some data to show. this.getView().attachBrowserEvent("mousemove", function(oEvent) { this.onCheckForMessages(); }); But better solutions are welcome....
python,user-interface,python-3.x,model-view-controller,tkinter
You have two mistakes here: 1 - In your Counter.py file and in your Convert class methods, you are not return the right variables, instead of return celsius you should return self.celsius and same goes for self.fahrenheit 2 - In Controller.py file: self.view.outputLabel["text"] = self.model.convertToFahrenheit(celsius) This will not update the...
php,laravel,model-view-controller,database-connection,views
controller public function show(Project $project) { $technologies = DB::table('technologies') ->select('*') ->where('id', $project->technology_id) ->get(); // you were missing the get method return view('projects.show', compact('project', 'technologies')); } View This will not work in your view: @if ( !technologies() ) @section('content') <h2>{{ $project->name }}</h2> @if($technologies) <ul> @foreach($technologies as $technology) <li><a href="#">{{ $technology->slug }}</a></li>...
html,ruby-on-rails,ruby,ruby-on-rails-4,model-view-controller
To get the full URL, use gig_url(@gig) instead of gig_path(@gig).
ruby-on-rails,model-view-controller
The problem is, you did not call any save after calling the method token_exchange, rewrite your method as following, it will save your transaction def token_exchange exchangeTokenResponse = API.exchange_token(public_token) self.access_token = exchangeTokenResponse.access_token self.accounts = API.set_user(access_token, ['auth']) self.transactions = API.set_user(access_token, ['connect']) self.save end ...
ruby-on-rails,ruby,model-view-controller,cocoon
If the link_to_add_association works, the javascript is loaded correctly. Still a bit confused about what is not working. If clicking the link_to_remove_association does not remove anything visibly from the page, you are missing the correct wrapper-class. By default it should be .nested-fields, but this can be overruled by specifying it...
jquery,html,model-view-controller
$('#listItemCss>li').click(function() { var cid = $(this).find('.cssId').val(); console.log(cid); }); Also, don't use the same id for multiple li elements DEMO See Why is it a bad thing to have multiple HTML elements with the same id attribute?...
javascript,arrays,model-view-controller,ember.js
This would work. Long way (just to improve your computed property code): // controller work.js import Ember from "ember"; export default Ember.Controller.extend({ firstElement: function () { return this.get('model').get('firstObject'); // or this.get('model.firstObject'); }.property('model.[]') }); 1) you set works as model in route, so you could get it as model in controller...
javascript,model-view-controller,ember.js
You can calculate the combined totals in the parent model, like so: total: function() { var amount = 0; this.get('years').forEach(function(item) { amount += item.get('total'); }); return amount; }.property('[email protected]') Where "years" is the child model from the hasMany relationship. This will be dynamically updated any time any of the children change...
php,laravel,model-view-controller,laravel-5
Give a man a fish and you feed him for a day; Teach a man to fish and you feed him for a lifetime Here's Let me say how to debug(fish) in this situation. 1st Step : Make sure that your call is right You can do it by Route::get('yourcall',...
image,codeigniter,model-view-controller,controller,file-get-contents
$data contain array values, you have to use upload_data for ex : $data = array('upload_data' => $this->upload->data()); $data = array( 'image' => file_get_contents( $data ) ); change this to $data = array('upload_data' => $this->upload->data()); $data = array( 'image' => file_get_contents( $data['upload_data'] ) ); or you can directly use upload data...
I think you can use a negated character class [^_]* to add this restriction (also, remove the initial .*, it is redundant, and the first look-ahead is already at the beginning of the pattern, no need to duplicate ^, and it is totally redundant since the total length limit can...
model-view-controller,servicestack
Every request does not get cached in memory, when you're self-hosting it's running the binary dlls and static files that are copied into your /bin folder. You can change Config.WebHostPhysicalPath to change ServiceStack to serve files from your solution folder instead, e.g: SetConfig(new HostConfig { #if DEBUG DebugMode = true,...
php,laravel,model-view-controller,laravel-5
The most common reason behind this issue is that you have not changed the permission of storage folder. Please run the following from your laravel root : chmod -R 755 storage if this doesn't works try chmod -R 777 storage ...
php,mysql,database,codeigniter,model-view-controller
1) You have already added where clause. 2) Also your update is before of your where, meaning your query is executing without the where clause and hence it is updating all the records. public function up_votes($id) { $this->db->set('up', 'up+1', FALSE); $this->db->where('open_id', $id); $this->db->update('country'); // ^^ removed `$id` } ...
ios,objective-c,uitableview,model-view-controller,uibutton
The second option will certainly violate MVC pattern. ViewController works like a glue between your models, views and contains all the business logic. ViewController should receive action then make your api call and put formatted data to your views. Usually in my project I always try to move networking code...
ruby-on-rails,sqlite,model-view-controller
you don't need the = here: <%[email protected] do |t|%>, the equals sign is telling erb to show every message on the view. <% %> Will execute Ruby code with no effect on the html page being rendered. The output will be thrown away. <%= %> Will execute Ruby code and...
ruby-on-rails,ruby,model-view-controller,notifications
How Comment.find_by(notification.user_id) even works? I think correct ways are (first and second are equivalent): Comment.find_by_id(notification.user_id)source Comment.find_by(id: notification.user_id) Comment.find(id: notification.user_id) source If you need just user_id why don't you just write this: notification.user_id instead of Comment.find_by(notification.user_id).user.id...
javascript,model-view-controller
You need to call it as a constructor, and define it as a constuct function: var posAttuale = function() { this.myLat = "myLat"; this.myLng = "myLng"; this.myComune = "myComune"; }; var infoPos = new posAttuale(); ...
python,model-view-controller,wxpython,observer-pattern
The MVC entry in the wxPython wiki gives a good insight how the spearation of concerns could look like. The first (newer) example leverages pypubsub, the older example at the bottom deals with wx.Events alone. While it may or may not conform to the strict MVC paradigma, it shows beautifully...
.net,model-view-controller,parse.com
Yes you can, the ParseQuery class has a method to skip (query.Skip(n)) an amount of objects and also to limit (query.Limit(n)) the amount of objects to be returned by a query. Basically you keep track of the current limit and then just increase the values for skip and limit by...
angularjs,model-view-controller
Think of an Angular app as disconnected from your backend as an Android or iOS app would be. If you're doing it right your entire Angular app is static, with no server side templating (a nice side effect of this is that your Angular app can be pushed to a...
php,codeigniter,model-view-controller
You need to scan your /application/controllers directory and remove file extension from it $controllers = array(); $this->load->helper('file'); // Scan files in the /application/controllers directory // Set the second param to TRUE or remove it if you // don't have controllers in sub directories $files = get_dir_file_info(APPPATH.'controllers', FALSE); // Loop through...
ruby-on-rails,ruby,model-view-controller,notifications,conditional
First of all, according with MVC, you shouldn't make SQL queries in the view's: <% if Comment.find_by(notification.comment_id) == Habit.find(params[:habit_id]) %> bad practice! You should make the Query in the controller and then using the instance variable of the controller(the variable with the @) in the view. Second, params[:habit_id] will only...
linq,entity-framework,model-view-controller,model
You cannot pass complex objects when redirecting using RedirectToAction. It is used for passing the routeValues not the Model. To maintain state temporarily for a redirect result, you need to store your data in TempData. You can refer this for more info: passing model and parameter with RedirectToAction TempData["_person"] =...
model-view-controller,pyqt,qtableview,qabstracttablemodel
As stated in the comment, your model is your list of object. You should subclass QAbstractTableModel to use this list. Here's my code snippet for this: import sys import signal import PyQt4.QtCore as PCore import PyQt4.QtGui as PGui class OneRow(PCore.QObject): def __init__(self): self.column0="text in column 0" self.column1="text in column 1"...
ruby-on-rails,ruby,ruby-on-rails-4,model-view-controller
You can use content_for and yields to create a default in your layout which views can override. # layouts/application.html.erb: <% if content_for?(:banner) %> <%= yield(:banner) %> <% else %> <div id="banner"> <h1>This is the default...</h1> </div> <% end %> /users/signup.html.erb: <%- content_for :banner, flush: true do -%> <!-- move along,...
javascript,jquery,node.js,model-view-controller,sapui5
You mentioned you cannot use the Router mechanism due to company restrictions -- am really curious to know what these restriction are then ;-) -- and toggle the visibility properties of the respective views instead. In that case, I would trigger the OData service in the method where you set...
php,mysql,codeigniter,model-view-controller
Instead of count you use $query->num_rows() MODEL public function up_votes($id,$ip) { $query = $this->db->query("SELECT * FROM voting_ip WHERE open_id_fk='$id' and ip_add='$ip'"); $count= $query->num_rows(); if($count == 0) { $this->db->set('up', 'up+1', FALSE); $this->db->where('open_id', $id); $this->db->update('country'); return TRUE; }else{ return FALSE; } } ...
spring,rest,spring-mvc,model-view-controller
Add: import org.springframework.http.HttpStatus; ...
python,design-patterns,model-view-controller
Passing things as arguments, just like in your code, is the most common solution to problems like this. If you only need the do_this -method, you can even just pass the method: beta = ViewBeta(controller.do_this) ...
c#,.net,model-view-controller,ninject
Yes, you are right. Based from the old svn sources it was in 1.0 - http://ninject.googlecode.com/svn/trunk/src/Core/Binding/Syntax/IBindingConditionSyntax.cs , but at the current version it doesn't exist. In the their actual documentation there are a couple of samples on how you can do conditional binding: attributes\named bindings\when methods. I suppose the closest...
json,extjs,model-view-controller,dynamic
Surely possible. Basically you use your metadata as items and create the form at any time: var metadata = [ { "allowBlank": false, "fieldLabel": "labelText1", "name": "labelName1", "emptyText": null }, { "allowBlank": false, "fieldLabel": "labelText1", "name": "labelName1", "emptyText": null } ]; Ext.create('Ext.form.Panel', { defaultType: 'textfield', width: 300, bodyPadding: 10, renderTo:...
html,ruby-on-rails,ruby,ruby-on-rails-4,model-view-controller
<ul class="dropdown-menu" role="menu" aria-labelledby="dropdownMenu1"> <li role="presentation"><a role="menuitem" tabindex="-1" href="http://www.example.com/gigs?category=Video+and+animation" data-method="get">Show me everything</a></li> <li role="presentation"><a role="menuitem" tabindex="-1" href="http://www.example.com/gigs?subcategory=Intro" data-method="get">Intro</a></li> <li role="presentation"><a role="menuitem" tabindex="-1"...
jquery,ajax,model-view-controller,listbox
Figured out why, apparently I had the same id for every select option...silly me.
asp.net-mvc,asp.net-mvc-4,model-view-controller
Try this: <h4>@Html.Raw(Model.HomePageVM.AboutUsDescOne)</h4> Use this helper with caution though. If a user can edit this block of HTML then you might be making yourself vulnerable to an XSS attack: Text output will generally be HTML encoded. Using Html.Raw allows you to output text containing html elements to the client, and...
ruby-on-rails,ruby,model-view-controller,notifications,comments
This @valuation = Valuation.find_by(self.valuation_id) @user = User.find_by(@valuation.user_id).id Notification.create( valuation_id: self.valuation_id, user_id: @user, comment_id: self, read: false ) should be self.notifications.create( valuation: self.valuation, user: self.valuation.user ) in your migration file set: t.boolean read, default: false in your controller: def index @notifications = Notification.where(:user_id => current_user.id) @notifications.each do |notification| notification.update_attribute(:read, true) end...
ruby-on-rails,ruby,ruby-on-rails-4,model-view-controller,actionmailer
This may work def buyer(gig,user) @gig = gig @email = user.email @name = user.name mail(to: @email, subject: 'box delivery') end def seller(gig, email, name) @gig = gig @email = email @name = name mail(to: @email, subject: 'new box order') end ...
java,swing,design-patterns,model-view-controller,architecture
So, MVC doesn't actually explicitly address persistence. There are really two schools of thought here. Bake it into the model, so that the model becomes "self persisting". Or do it in the controller. Opening it in the view layer is absolutely not accepted practice. There is a definite mixing of...
You have to make sure both projects are deployed. In other words, Project B needs to be deployed in much the same way you deploy Project A. Then, you can simply call the controller route for Project B, using the URL to it, just as if you were calling a...
ajax,asp.net-mvc-4,razor,model-view-controller,model
To make you understand how AJAX FORM works, I created below code - Lets say our model - public class Sale { public string SaleOwner { get; set; } public virtual Account Account { get; set; } } public class Account { public string Name { get; set; } }...
c#,model-view-controller,spark-view-engine
If you override the SparkViewBase, then you need to make sure you have a method there called HTML. The default implementation is: public MvcHtmlString HTML(object value) { return MvcHtmlString.Create(Convert.ToString(value)); } ...
c#,asp.net,asp.net-mvc,model-view-controller
15,000 lines, jeez. Aside from what you've obviously stated about moving the code to the business layer (which you should do), I would also consider forming logical groups of those action methods that belong to a certain set of functions. Once you've got these groups, create separate controllers for each...
ruby-on-rails,model-view-controller,devise
In the model, you can validate for uniqueness... viewed_course.rb class ViewedCourse ... validates :course, uniqueness: { scope: :user, message: "should happen once per user" } ... end It doesn't look like you're using ViewedCourses in your show template. If you do later, you might want to try the find_or_create_by method...
javascript,jquery,angularjs,model-view-controller
I added a comment, but Ill explain here in further details. the plunker you gave shows a simple template change but the controller stay the parent controller or base. you on the other hand want to add unique data and actually render a different page. so if you're using ui-router...
php,templates,model-view-controller
Suppose your template file should also reference the object, since as far as I can see the $humans variable won't automagically jump from the class variable into your method like that. Try this: <?php foreach($this->humans as $human) { ?> <li><?php echo $human ?></li> <?php } ?> ...
php,model-view-controller,view,render
Try replacing return $content with echo $content.
php,codeigniter,model-view-controller
Try using this in your controller: <?php class Payment extends CI_Controller { function sample() { $this->load->model('PortionCreatorModel', 'pc'); // Reference by using $this->pc echo 'OK'; } } Reference: CodeIgniter: Models...
java,model-view-controller,playframework,ebean
According to github Model.Finder is not deprecated, but one of its constructors: /** * @deprecated */ public Finder(Class<I> idType, Class<T> type) { super(null, type); } Make sure you use correct constructor....
java,image,model-view-controller,javafx
You need to inject the element from the FXML file into the controller so that you can access it there. See the tutorial (the section "Add rows to the table", listings 3-14 and 3-16), or the documentation. Basically, you need to add an fx:id="..." attribute to the definition in the...
laravel,model-view-controller,controller,blade
Very vague question, so will be the answer. Please clarify if it's not what you need. Assumptions: You have an Item model that is stored in a DB. In the relevant controller method you add the code below which will find the item with id 1 and will display the...
c#,asp.net,model-view-controller,asp.net-5
[FromServices] is just an MVC concept. It is not available to other parts of the ASP.NET 5 stack. If you want to pass dependencies down the chain you have a few options: Pass the service provider. This is quite an anti-pattern because your objects need to depend on the DI...
php,laravel,model-view-controller,uml,class-diagram
You can simply present a view as a class. Dialog elements can be shown as attributes having types that can be either simple strings (for input fields) or other classes that represent e.g. drop down. Edit Your diagram looks ok. Just add the attributes for the view like +email:Text +password:HiddenText...
ios,objective-c,rest,model-view-controller,afnetworking-2
I dont have anything to say about your MVC(Model–view–controller) correct? I just want to add something that may be useful approach avoiding unwanted crashes.. First is under [[MyAPI sharedInstance] POST:@"auth/" parameters:params success:^(NSURLSessionDataTask *task, id responseObject) { if([responseObject objectForKey:@"id"]) { [[NSUserDefaults standardUserDefaults] setObject:(NSDictionary*) responseObject forKey:USER_KEY]; [[NSUserDefaults standardUserDefaults] synchronize]; result = [responseObject...
php,laravel,model-view-controller
It is fine to pass a model into a view, a good way to do it is like this: public function show($id) { $thing = Thing::findOrFail($id); return view('showAThing')->with('thing', $thing); } Using findOrFail() in this context will throw a 404 error if the item doesn't exist in your database. This is...
ruby-on-rails,ruby,model-view-controller,feed,link-to
To link_to your show page with the code I understand you having you need to resources :activities do resources :valuations end Since it's polymorpic use trackable to find the id and put the line: <%= link_to activity.trackable.name, activity_valuation_path(activity, activity.trackable_id) %> Take this line out from your index: @valuation = Valuation.find(params[:id])...
There are a couple ways you can go about doing this. Templates Create your route. Im assuming a lot about your app here but hopefully you get the picture. If you need help with anything in particular, be sure to update your question with the code youve tried so it...
php,mysql,codeigniter,model-view-controller
You can call your helper in your constructor function __construct() { parent::__construct(); $this->load->helper('url'); } And your ajax url is url: "<?php echo base_url();?>index.php/Welcome/search?>", ...
php,oop,model-view-controller,controller
No, bootstrap file is for initialization. A controller is resoponsible for handling user input (requests in a web environment) and providing him an output (responses in a web environment). A front controller is just a centralized point for handling incomming requests. None of these compoments should have the responsibility of...
javascript,backbone.js,model-view-controller,updatemodel
It appears your model is accessing the DOM. Usually, your view would deal with the DOM, extracting information then updating the model. So for example, create a view with a constructor that: Creates your input elements and put them in an attribute called $el; then Adds $el to the DOM;...
angularjs,model-view-controller,ionic-framework,ionic
Here is the jsfiddle I used ng-repeat to build the select and ng-options to fill them, you then have to use the relative ng-model to get the selections. HTML: <div ng-app ng-controller="MyCtrl"> <select class="select fancy" ng-repeat="(i, item) in items" ng-model="searchOption[i]" ng-options="type.name for type in item.types"></select> <button ng-click="submitIt()">Submit</button> </div> Javascript: function...
ruby-on-rails,ruby-on-rails-4,model-view-controller
Why this is not working? if params[:user][:user_role] render :partial => 'users/mentor' else render :partial => 'users/mentee' end params[:user][:user_role] is nil. You can check it using lots of way: Above your if condition raise params[:user].inspect Why its nil? Reason of this is You are passing new_user_path(user_role: true) user_role true, but user_role...
asp.net,database,exception,model-view-controller
I think that you are providing in your connection string UserName and password, so you can change from Integrated Security=True to Integrated Security=False and if the user 'DB_9CB321_Szklarnia_admin' has rights to connect it will work. When Integrated Security=True the userID and password will be ignored and attempt will be made...
c#,model-view-controller,inversion-of-control,fluentvalidation,light-inject
I am the author of LightInject and maybe you could see if this example works out for you. class Program { static void Main(string[] args) { var container = new ServiceContainer(); container.Register<AbstractValidator<Foo>, FooValidator>(); container.Register<IFooService, FooService>(); container.Intercept(sr => sr.ServiceType.Name.EndsWith("Service"), factory => new ServiceInterceptior(factory)); var service = container.GetInstance<IFooService>(); service.Add(new Foo()); } }...
php,mysql,model-view-controller,zend-framework2
Answer The exchange array method shown below needs to have proper case for the $data array elements. I revised all lines starting with the sample one below to have the proper case. Since ActionItemID is a string it needs to have to the proper case of the ActionItemID. Answer Snippet...
ruby-on-rails-4,activerecord,model-view-controller,scope,parent-child
Not sure whether it's possible, but it will couple most of your app to the default_scope implementation, which IMHO is a very bad idea. You might end up needing to change this implementation down the line, which is going to have pretty high impact. It will also make your unit...
regex,angularjs,validation,model-view-controller
Your regex does not work as expected because you did not use a ^ anchor (although I guess this expression is anchored, but still it is better to play it safe) and you did not enclose the alternatives into a group, and thus 21, 22, 23 are valid values. Here...
java,spring,hibernate,jsp,model-view-controller
You are using PathVariable so you need to declare id in value. E.g. @RequestMapping(value = "/editCase/{id}", method = RequestMethod.GET) ...
java,model-view-controller,design
Go with your feeling and establish that attribute as a synthetic field in your model. So no extra physical field, but put the derivation function down as a getter. In my opinion that's OK, because that getter does only little more than a really dumb field accessor, and the definition...
node.js,model-view-controller,express
You need to initialize your app like this var app = require('express')(); ...
ios,swift,api,model-view-controller,alamofire
Your loadAdInfo method is asynchronous. In the same way you're using a completionHandler to get Alamofire's data from adsForSection to loadInfo, you need to make an handler for loadInfo so you can retrieve the asynchronous response. Something like this: func loadAdInfo(section: String, page: Int, handler: (JSON) -> ()) { NWService.adsForSection(section,...
actionscript-3,flex,model-view-controller,parsley
With a small tweak to the Controller code, we end up with this: [CommandResult(type="view.user.UserEvent", selector="loadUser")] public function handleResult(result:Object):void { trace("this is the command result"); } OR [CommandResult(selector="loadUser")] public function handleResult(result:Object, trigger:UserEvent):void { trace("this is the command result"); } Now this fires, I get an Object with my data in, resolved....
model-view-controller,zend-framework2
This should be fairly simple. Firstly you need to include the two modules in your application.config.php 'modules' => array( 'Module1', 'Module2' ) Then as a very basic example taken from your question: <?php namespace Module2\Model; use Module1\Model\Class1; class Class2 { public function doSomething() { $class1 = new Class1(); $class1->doSomething(); }...
php,codeigniter,model-view-controller
You're missing very basic PHP functionality and knowledge, so I'd advice you to read some coursework on beginner PHP. also, this should fix your problem <textarea name='openletter' id='openletter' style='width: 565px;' rows='8' cols='60'><?php echo $data['openletter'];?></textarea> if you want everything inside an Echo : echo "<textarea name='openletter' id='openletter' style='width: 565px;' rows='8' cols='60'>"....
node.js,model-view-controller,express,view
The EJS readme shows the different tags you can use in your templates. <%= will escape the contents whereas <%- will not, so use the latter.
mysql,ruby-on-rails,ruby,model-view-controller
You can try this. I hope this will help. @user = User.where("id = ?", 4).select( "user_fname, user_lname") ...
vb.net,razor,model-view-controller,model
You need to pass the model instance to the view: Function Details() As ActionResult Dim employee As Employee employee = New Employee employee.EmployeeID = 101 Return View(employee) End Function ...
angularjs,model-view-controller,tabs
What you can do is give a property disabled, and check that on the tab click: $scope.tabs = [{ title: 'One', url: 'coredcplan.html' }, { title: 'Two', url: 'migration.html', disabled: true }, { title: 'Three', url: 'schedule.html' }]; $scope.onClickTab = function (tab) { if(tab.disabled) return; $scope.currentTab = tab.url; } See...
php,model-view-controller,model,constants,phpfox
Set them as constants in the class. From the PHP manual: <?php class MyClass { const CONSTANT = 'constant value'; function showConstant() { echo self::CONSTANT . "\n"; } } ...
ios,swift,oop,model-view-controller,uilabel
Your error is here var callV = ViewController().label You are creating a new instance of ViewController,you should get the reference of the existing one You can pass in a label as input func changeLabel(label:UILabel){ var elementCall = callElements() println("111") label.text = elementCall } Then call modelFrom.callElements(self.label) Update: I suggest you...
angularjs,spring,model-view-controller,data,hateoas
To be truly HATEOAS compliant, the service (spring) needs to provide to the client all the hypermedia controls (links) to perform sorting. The client should never sort by some data field...it should only sort by what sort options are provided to the client by the server. This sorting may itself...
I'm not sure about your question but this is simple example of using such functionality Test.php <?php echo '<a href="../another_test.php/add_to_cart/?id=1231"/>Click Here</a>'; ?> another_test.php <?php class A{ function __construct(){ } function add_to_cart(){ $id = $_GET['id']; return $id; } } $a = new A(); echo $a->add_to_cart();//1231 ...
date,model-view-controller,html-select
Maybe a better way to do this would be to define a property in your model that returns IEnumerable<SelectListItem> (in your model class): public DateTime SelectedDate {get;set;} public IEnumerable<SelectListItem> SeasonDates { get { foreach (var item in seasonDates) yield return new SelectListItem() { Text = item.ToShortDateString(), // or apply your...
scala,model-view-controller,playframework,playframework-2.0,typesafe-activator
You can't use the value of the form as a parameter for the route: @form(routes.Users.updatePassword(userForm.userid.get)) The userid depends on the form and could therefore change. In any case, you would access the userid of the form using userForm("userid") and not userForm.userid (although it might not be what you want/need). A...
ruby-on-rails,ruby,model-view-controller,tags,acts-as-taggable-on
In my opinion, You could use polimorphing. Please, see Active Record Associations In Your case, Model could be next: class Tag < ActiveRecord::Base belongs_to :taggable, polymorphic: true .... class Habit < ActiveRecord::Base has_many :tags, as: :taggable .... class Goal < ActiveRecord::Base has_many :tags, as: :taggable .... And in migrations: create_table...
javascript,jquery,forms,backbone.js,model-view-controller
You can use jQuery's serializeArray to collect all data on submit of the form. serializeArray will return you the array of name and value pair of of all the fields in forms, you can simply iterate over those array values and create the required object then set it to your...
c++,model-view-controller,cmake
It looks pretty normal structure to me. In fact I use the same one in my projects. In the root CMake file you will put: include(Src/Model/CMakelists.txt) and CMakelists.txt might look like this: set(MODEL_HEADERS src/Model/model.hpp) set(MODEL_SOURCES src/Model/model.cpp ${MODEL_HEADERS}) list(APPEND ALL_SOURCES ${MODEL_SOURCES}) source_group("Model" FILES ${MODEL_SOURCES}) Where ALL_SOURCES is the variable from the...
It is done like this: http://docs.sencha.com/extjs/4.2.3/#!/api/Ext.app.Controller-cfg-stores Write your own getter: Ext.define("MyApp.controller.Foo", { extend: "Ext.app.Controller", requires: [ 'MyApp.store.Users', 'MyApp.store.Vehicles' ] getUsersStore: function() { return this.getStore("Users"); }, getVehiclesStore: function() { return this.getStore("Vehicles"); } }); Or shorter Ext.define("MyApp.controller.Foo", { extend: "Ext.app.Controller", stores: ['Users', 'Vehicles'] }); => you can use de storeId, or fullName...
angularjs,model-view-controller
"Unfortunately, the pragmatic answer is: 'it depends.'" The MVC Model is not necessarily "all that it's cracked-up to be." Nevertheless, I suggest that you can meaningfully divide the problem along this line: "'User Interface' ... versus ... 'Not'" For instance: "the entire exchange with the Gentle User, no matter what...
Why not use inheritance? <?php class model { private $db; public function __construct() { $this->initDb(); } private function initDb(); } class c_blog { private $model; public function __construct(){ include( [model_path] ); $this->model = new m_blog(); } public function post_list(){ return $this->model->get_list(); } } class m_blog extends model{ public function __construct()...
javascript,html,model-view-controller,event-handling,javascriptmvc
The problem is that you are not creating 10 button elements as you expect, you are creating only one. When you create the base prototype object var btn = { btnElem: document.createElement('button') } var parent = Object.create(btn); you create a single DOM element. Then you create an object which uses...