c++,performance,modulo,micro-optimization,bitwise-and

Which uses more or less memory is highly dependant on the instruction encoding, but n & 1 can be many times faster [1], if the compiler doesn't optimised n % 2 to the same thing. Of course, many compilers will indeed make this optimisation (or one that may do the...

First, there are no any options for module couse this is just an operation like adding or dividing. You do it if you want and not do if don't want. And if you want do it only once you can use boolean flag: class Game { bool isScoreDivided; int score;...

think the problem should be: x%y=z a) where x,z are knowns y is unknown instead of b) where z is known and x,y are unknowns as stated in OP text anyway for booth cases the easiest but also the slowest way to compute it is brute-force attack example a):...

#include <iostream> void hotdog( int weinerspackages, int bunspackages ){ const int weinersPerPackage = 12; const int bunsPerPackage = 8; const int totalweiners = weinerspackages * weinersPerPackage; const int totalbuns = bunspackages * bunsPerPackage; int leftoverweiners = 0; int leftoverbuns = 0; int amountOfHotdogs = 0; if( totalweiners > totalbuns ){...

a mod m = b mod m ==> (a - b) mod m = 0 ==> (a-b) = k * m for some integer k ==> (a-b) / m = k So m can be any factor of a-b ....

Most people do this with a modulo operator, but it gets awkward to do it if no posts are found, or and even division occurs on the last post. I've expanded on the answer provided here by @The Shift Exchange to do it in a cleaner way. <?php // Get...

If you want a positive result, you can wrap the mod. public static int PositiveMod(int value, int mod) { return ((value % mod + mod) % mod; } int result = PositiveMod(-1, 20); //Returns 19 ...

javascript,angularjs,html-table,modulo

Better solution is to have a if-condition for the repeat ng-if="$index%5" Update: Added - for filling rest of the columns if its less than 5 <span>{{basicInfoCustomFields[$parent.$index+i].name || "-"}}</span> Plunkr Demo var app = angular.module('app', []); app.controller('MainCtrl', function($scope) { $scope.basicInfoCustomFields = [ {"name":"Anto"}, {"name":"Julie"}, {"name":"John"}, {"name":"Doe"}, {"name":"Ray"}, {"name":"Sassy"}, {"name":"Wright"}, {"name":"Fred"}, {"name":"Flintstone"},...

swift,modulo,floating-point-precision,modulus,integer-division

52 goes into 66 1 time evenly with 14 left over. When you divide 66 / 52, you get 1.2692, or 52 / 52 + 14 / 52. So, if you're only after the decimals here, they can be acquired like this (66 % 52) / 52

c++,algorithm,cryptography,rsa,modulo

the problem you are running into is: your integers are too small and will overflow when the values get larger ... fixed size integers for things like RSA ... no good idea unless you happen to have integers with a few thousand bits length... instead of normal ints or even...

javascript,loops,iteration,modulo

I would be more inclined to build a string with the HTML, then post it one time. Try ... var max = 100; var HTML = ["<ul class='list'>"]; for (var i=0,len=max; i<len; i++) { HTML.push("<li>" + i + "</li>"); if (i%10===0 && (i!==0) { HTML.push("</ul>"); HTML.push("<ul class='list'>"); } } HTML.push("</ul>");...

This is a fixed and working example on how to do this: public static void main(String[] args) { char[] array1 = new char[] {'a', 'b', 'c', 'd', 'e', 'y', 'z'}; char[] array2 = new char[] {'a', 'a', 'a', 'a', 'a', 'a', 'a'}; char[] array3 = new char[array1.length]; for (int i...

sql-server,modulo,sql-server-2014

I figured it out Given 20 rows and 4 iterations: Rows 1,5,9,13,17: SELECT ID, Whatever FROM MyTable WHERE ID % 4 = 1 Rows 2,6,10,14,18: SELECT ID, Whatever FROM MyTable WHERE ID % 4 = 2 Rows 3,7,11,15,19: SELECT ID, Whatever FROM MyTable WHERE ID % 4 = 3 Rows...

div and idiv in its current implementations in x86 processors do have an execution time that depends on their operands, but indirectly. It really depends on the magnitude of the result. Dividing such that the result is 0 or 1 is faster (but certainly not fast) than dividing and getting...

If you want to use some original approach then you can write the program the following way.:) #include <iostream> int main() { for ( int i = 1; i <= 100; i++ ) { unsigned mask = ( i % 3 == 0 ) + ( ( i % 5...

It appears from the examples that fn should be included, within the curly brackets: The following example shows the remainder returned by MOD. SELECT DISTINCT {fn MOD(5,3)} AS Remainder FROM Sample.Person returns 2 The following example shows the remainder returned by MOD with a negative dividend. SELECT DISTINCT {fn MOD(-5,3)}...

Short answer: In practice on standard processors, it is 1 because 65537 % 256 == 1. The reason is the one ksmonkey123 explained. Note: If you were writing 127 + 128 because the bounds of a signed char, which is equivalent to char on typical compilers nowadays, are -128 to...

javascript,coffeescript,operators,modulo

I did find the answer in another StackOverflow question and answer Javascript modulo not behaving and I wanted to share it for people who like me only looked for a "CoffeeScript" related explanations and thus have a hard time finding the correct answer. The reason for using a %% b...

mod is not the same in all languages, especially for negative numbers. VB6 (and a whole load of other compilers like C, C++, C#, Java) takes the Fortran interpretation which is the remainder after dividing. Mathematically, this is the wrong interpretation if the number is negative. What you have is...

The meaning of Mod is that you take the remainder after doing the division. 1 fits zero times in 4, so the remainder is 1. Here the wikipedia definition that explains in a little more detail: In mathematics the result of the modulo operation is the remainder of an arithmetic...

Probably because you're using a restricted sublanguage that offers only limited functionality. What Scheme implementation are you using, and are you in some kind of restricted module that doesn't import the standard Scheme procedures? modulo is indeed a standard part of Scheme and is included in any standard Scheme system....

To avoid the negative modulus behaviour you can just make it positive first: i = (i - 1 + range) % range; However this is no good if range is bigger than half of INT_MAX. (or whatever type i is). This seems simpler: i = (i ? i : range)...

Your logic is incorrect. You try something much simpler like: def prime(n) !(2..n-1).detect{|x| n%x == 0} end Here detect will return the first value of x that matches the condition n%x == 0. If none matches nil is returned. Therefore in case of a prime number (2..n-1).detect{|x| n%x == 0}...

modulo,integer-division,cpu-speed,programming-pearls

The modulus/modulo operation is usually understood as the integer equivalent of the remainder operation - a side effect or counterpart to division. Except for some degenerate cases (where the divisor is a power of the operating base - i.e. a power of 2 for most number formats) this is just...

To return the nth number in the sequence, with the max number (e.g) 5 passed in: int getNum(int n, int max) { return (((n+max+1) % (max*2)) - max) * (1-((((n+max+1) / (max*2))%2)*2)); } If it's not important to start at 1, then it can be simplified to this: int getNum(int...

sql,sql-server-2008,tsql,sql-server-2008-r2,modulo

The MOD keyword only exists in the DAX language (tabular dimensional queries), not TSQL Use % instead. Ref: Modulo...

Ok, I assume you are using Advanced Custom Fields (ACF) or something else, because to the best of my knowledge (and Google's) have_rows() is not WordPress function call. If it is the have_rows() from ACF, it returns a boolean, as the name implies. This makes your problem more difficult as...

algorithm,division,modulo,brainfuck,divmod

Here's what happens: # >n 0 d This line, is a comment line telling you what the memory should be like before the operation. Dividend as n, divisor as d. According to the code the next 3 cells should be empty as well, but it is ignored here, assuming you...

The problem is that you've created num_array as a local within convertNumberToArray() and later you return the address of that variable -- once you return from convertNumberToArray() all of its locals are no longer valid. What happens when you do this is undefined. When you see the correct results, you've...

To find "how much i you have to add to make the last digit of a number a 0", you can subtract from 10: int checkDigit = (10 - (sum % 10)) % 10; The second modulo is used for the special case when sum % 10 == 0, because...

Change your condition to : if(((i+1) % 10) == 0){ System.out.println(); } You are printing i+1, so you want to add a line break when i+1 is divisible by 10....

This solution uses allcomb from matlab file exchange. %size n=2 %maximum value m=2 %generate input for allcomb e=cell(1,n^2) e(1:end)={[0:m-1]} %generate all combinations. F=reshape(allcomb(e{:}),[],n,n) F is a 3D-Matrix, to get the first possibility use: squeeze(F(1,:,:)) ...

The problem I am facing is that the function returns key as void *. It does not. It returns nothing (void). The hash result is recorded in the buffer you specify (a pointer to) via last argument. For MurmurHash3_x86_32(), it makes the most sense for that to be a...

You can calculate it by the memoization nCr = (n-1)Cr + (n-1)C(r-1) for M<=5000. You can visit the link for more info http://discuss.codechef.com/questions/3869/best-known-algos-for-calculating-ncr-m

javascript,arrays,modulo,negative-number

You can use n integer n % l integer in (-l, l) n % l + l integer in (0, 2*l) (n % l + l) % l integer in [0, l) In JavaScript, arr[(someInteger % arr.length + arr.length) % arr.length] Alternatively, you can play with flooring, ceiling and truncating:...

We know that: (A*B) % MOD = ((A % MOD) * (B % MOD)) % MOD So (A^n) % MOD = (((A ^ (n/2)) % MOD) * ((A ^ (n/2)) % MOD)) % MOD; And we can do it recursively. So, here is our function: int cal(int pow, int val,...

As a general rule, the modulo and division should satisfy the equation b * (a/b) + a%b == a For positive numbers, it is obvious that this means that a%b must be a positive number. But if a/b is negative, then the result is rounded towards zero. So take for...

mysql,stored-procedures,case,modulo

You're mixing the two ways to use CASE. You either write: CASE WHEN <expression1> THEN <result1>; WHEN <expression2> THEN <result2>; ... END CASE This evaluates each expression, and executes the corresponding result for the first true one. Or: CASE <expression> WHEN <val1> THEN <result1>; WHEN <val2> THEN <result2>; ... END...

There is no clear convention for those cases. Remember the formula for modulo: n = am + b. Usually, it is required that the remainder b is within the interval [0..(m-1)]. This makes it very easy for all natural numbers. For negativ numbers, some conventions want the remainder to be...

1/5 is meaningless when you deal with mod, since it only works with integers. When you write 5^-1 mod 18, it means the modular inverse of 5, in other words "the number by which you have to multiply 5 to get 1 mod 18". 5 * 11 = 55 =...

Some issues with your code: Point 1: scanf("%d\n",&x); should be scanf("%d",&x); Point 2: for(i=0;i<1;i++) this for loop is practically useless. It only iterates one. either use a longer counter, or get rid of the loop. Point 3: It's better to provide a unique seed to your PRNG. You may want...

The % in CMD much like in other microsoft environments is a remainder function - not a true modulo operation. The remainder is accurate here to return -6 for your examples. Using mod in Excel is a true modulo which does return your expected 1. Although it's written for C#,...