Numbers starting with 0 are octal in c/c++. Octal = 000012345 Decimal= 0×8⁸+0×8⁷+0×8⁶+0×8⁵+1×8⁴+2×8³+3×8²+4×8¹+5×8⁰ = 5349 Binary = 1010011100101 Hex = 14E5 ...

You use octal or hexadecimal because there isn't a way to specify decimal codes inside a character literal or string literal. Octal was prevalent in PDP-11 code. These days, it probably makes more sense to use hexadecimal, though '\0' is more compact than '\x0' (so use '\0' when you null...

The standard C library has conversion functions for this purpose: NSString* octal = @"247"; unsigned long value; sscanf([octal UTF8String], "%lo", &value); NSString* decimal = [@(value) stringValue]; decimal now contains the converted base 10 value....

Try typing 0644 in your python2 shell. It will give you a different number because it is octal. In python3, the 0o signifies an octal number. python2: >>> 0644 420 >>> python3: >>> 0644 File "<stdin>", line 1 0644 ^ SyntaxError: invalid token >>> 0o644 420 >>> New in python3:...

c,printf,decimal,octal,format-specifiers

011 is an octal value and its decimal equivalent is 9. Preceding integer literal with 0 indicates octal value. Use %o specifier in printf to print the value in octal.

c#,escaping,octal,string-conversion

There are a number of steps involved in the conversion: Extract the individual octal numbers (such as 354) from the source string. Convert each octal string representation to its decimal equivalent as a byte. Decode the byte sequence as UTF-8. Here's a sample implementation: string source = @"\354\202\254\354\232\251\354\236\220\354\203\201\354\204" + @"\270\354\240\225\353\263\264\354\236\205\353\240\245";...

Have you tried long long int This program int main(int argc, char** argv) { cout << sizeof(int) << endl; cout << sizeof(long int) << endl; cout << sizeof(long long int) << endl; return 0; } gives 4 4 8 showing you need long long int to get 64 bits Change...

binary,decimal,data-conversion,octal

First of all, make sure that number you are converting into Decimal and Octal is actually 'Binary' and not 'Binary Coded Decimal (BCD)'. Usually when the number is grouped into 4 binary digits, it represents a BCD instead of just binary. So, once you make sure its actually binary and...

-0777 is treated by the compiler as an octal number (base 8) whose decimal value is -511 (-(64*7+8*7+7)). -777 is a decimal number.

069 is not a valid octal number, and neither are several others, including 018. Python is pointing you to 097 however, the first number starting with 0 that is not a valid octal number. Your console wrapped the error message and you interpreted the error message as pointing at the...

Using string conversion functions is pretty horrible in my option. How about something like this instead: func octalToDecimal(var octal: Int) -> Int { var decimal = 0, i = 0 while octal != 0 { var remainder = octal % 10 octal /= 10 decimal += remainder * Int(pow(8, Double(i++)))...

Integers that start with zero are consider octal. Because octal integers only use numbers from 0 to 8 everything from the 9 on are ignored. So 00445790 becomes 004457 which is 2351 in decimal....