json,flask,one-to-many,flask-sqlalchemy
So with the help of @dirn I got it to work by acessing the backref posts that I have made in the Post class under the category which was backref=db.backref('posts', lazy='dynamic')) In my route category/<name>/posts/ which is kind of which will look like @api.route('/category/<int:id>/posts/') def get_category_posts(id): category = Category.query.get_or_404(id) page...
c#,entity-framework,lazy-loading,virtual,one-to-many
Question 2: this is because you use the [Required] attribute. In this case you ask to the framework (not only EF) to handle the required constraint. If you want to apply the constraint only at EF level you should use the fluent API: public class testEF : DbContext { public...
java,hibernate,annotations,one-to-many
In the 'Project' class, the code is: @OneToMany(mappedBy = "project_id") private List<Work> works; And, in the 'Work' class, the code is: @ManyToOne @JoinColumn(name = "project_id") private Project project; //var name should match with mappedBy name in other class The names in ('mappedBy="project_id") and the variable name in the other class...
php,laravel-4,datatables,eloquent,one-to-many
Use method call books(): $user = User::find(1); $user->books(); // relation object $user->books; // dynamic property First books() returns a relation object, that you can chain Eloquenr\Builder or Query Builder methods on. Second books is a dynamic property - the query is automatically executed and its result is stored in the...
You can't share an external foreign key between two separate collections. You currently have "areas" column in Area representing whether the Area is in Connection.areas, and also representing whether the Area is in Worker.areas. If it had a value in that column how would it know which collection it relates...
SELECT pat.product_sku FROM product_attribute_tb pat INNER JOIN product_tb pt ON pat.product_sku = pt.product_sku GROUP BY pat.product_sku HAVING SUM((attribute_name = 'colour' AND attribute_value = 'red') OR (attribute_name = 'size' AND attribute_value = 'L')) >= 2; see it working live in an sqlfiddle Each boolean expression like (attribute_name = 'colour' AND attribute_value...
mysql,cakephp,many-to-many,one-to-many,cakephp-3.0
Solution In the ProjectsTable: $this->hasMany('Images', [ 'foreignKey' => 'project_id', 'joinType' => 'INNER' ]); In the ProjectsController: $project = $this->Projects->get($id, [ 'contain' => ['Categories', 'Users', 'Tags', 'Images'] ]); In the Projects > view.ctp <?php foreach ($project->images as $images): ?> <p><?= h($images->image_path) ?></p> <?php endforeach; ?> ...
symfony2,doctrine2,one-to-many,setter,getter
It looks like you forgot the root part of your namespace 'Pso'. You have to execute : app/console doctrine:generate:entities Pso/ProjectBundle/Entity/Mandator ...
mysql,database,postgresql,insert,one-to-many
First, consider normalizing your schema. Here is an in-depth discussion of EAV storage on dba.SE. With your given design, this does the job: INSERT INTO "User_Detail" ("Usr_Name", "Property", "Value") SELECT "Name", 'Uni', '0000' FROM "User"; In Postgres, I would also advise not to use mixed-case identifiers....
c#,.net,linq,odata,one-to-many
Finally I could do with this query: var dataServiceQuery = (DataServiceQuery<WhseEmployee>)_context.Company.Where(c => c.Name == companyName) .SelectMany(c => c.WhseEmployee); ...
java,mysql,jpa,eclipselink,one-to-many
JPA methods require that the model use managed entities, while you seem to be attempting to associate a managed entity to something outside the context. This is a bad practice, and JPA is required to throw exceptions as it cannot tell what you intend it to do with the unmanaged...
database,symfony2,doctrine,one-to-many,dql
That's correct behavior. A collection is returned by $user->getClients(), not a single object. Doctrine's collections do not proxy method calls to their members. There are two ways to solve your problem: The simpler one. Rely on Doctrine's lazy load. Let's say you use data like this: foreach ($client as $user->getClients())...
mysql,database,join,relational-database,one-to-many
You can achieve this by SELECT STUD.id,STUD.name,GROUP_CONCAT(SUB.subject) as subject FROM students AS STUD LEFT JOIN subjects AS SUB ON STUD.id=SUB.student_id GROUP BY STUD.id; Actually it gives correct result when you have group by some column in sql it will returns only first record in group so for your desired result...
symfony2,doctrine2,associations,one-to-many,query-builder
There is a selector called SIZE(), which should do the trick. More to read here. Try something like this: $this ->createQueryBuilder('object') ->leftJoin('object.children', 'children') ->where('SIZE(object.children) = 0') ->getQuery() ->getResult(); ...
mysql,many-to-many,relationship,one-to-many
This should do the job: SELECT * FROM computer c LEFT OUTER JOIN model m ON m.ModelName = c.ModelName LEFT OUTER JOIN brand b ON b.BrandID = m.BrandID You may want to change the returned fields as per your requirements. Good luck with the project. === Update - To order...
Try this: SELECT p.id AS pid, p.title AS p_title, p.cat, p.mpn, b.id AS bid, b.name AS brand, COUNT(DISTINCT s.id) AS num_sku, COUNT(gbp.id) AS num_price FROM mt_product AS p INNER JOIN mt_brand b ON p.brand_id = b.id INNER JOIN mt_sku s ON p.id = s.product_id INNER JOIN mt_price gbp ON s.id...
I fixed it by adding the following sql restriction. String features = "1,4,5"; int featureSize = 3; DetachedCriteria criteria = DetachedCriteria.for(Product.class, "product"); criteria.add(Restrictions.sqlRestriction(String.format("(SELECT COUNT(*) FROM product_feature pf where pf.feature_id in(%s) and pf.product_id={alias}.id)=%d", features, featureSize))); This ensures, that the product has ALL three features, not only one or two....
hibernate,one-to-many,one-to-one
You forgot the @ManyToOne annotation on WalletData.user. And the mappedBy attribute should be user, since that's the field which constitutes the other side of the association. Bidirectional OneToMany associations are described in the documentation. Read it: http://docs.jboss.org/hibernate/orm/4.3/manual/en-US/html_single/#d5e5564...
grails,relationship,one-to-many
I've solved this issue with the following code. I hope that someone gives me a comment about it. receiptInstance.healthServices.collect().each { //I've tried to use receiptInstance.healthServices.clear() //but Set remains with all items //delete item from Set receiptInstance.healthServices.remove(it) //delete item from DB it.delete() } //save with flush to commit the delete if...
php,zend-framework2,one-to-many,datamapper,apigility
I have finally found a solution. (Thanks once again @ poisa for his solution suggestion on GitHub.) In short, the idea is to enrich the (projects) list items with nested (image) items lists on the hydration step. I actually don't really like this way, since it's too much model logic...
ruby-on-rails,ruby,activerecord,associations,one-to-many
The issue with your code is that you're updating 2 objects: share_location AND location, but saving only share_location. To save both objects, you can: if @share_location @share_location.is_valid = false @share_location.save @share_location.location.owner_id = new_owner_id @share_location.location.save end OR if you want to save associated models automatically, you could use :autosave option on...
mysql,flask,sqlalchemy,one-to-many,alembic
Thanks to dirn, pointing out the duplicate, I've added: __table_args__ = (db.UniqueConstraint('account_id', 'name', name='_account_branch_uc'), ) to my Branch class, and then pushed it to the database with alembic via: def upgrade(): op.create_unique_constraint('_account_branch_uc', 'branch', ['name','account_id']) I will note, though, that since I added this constraint manually via alebmic, I'm not certain...
java,vector,relationship,one-to-many
You could use a Map for relation between one key to many objects. import java.util.*; public class Test { private static String[] val1 = { "q", "w", "e", "r", "t", "y" }; private static String[] val2 = { "u", "i", "o", "p", "[", "]" }; public static void main(String[] args)...
c#,entity-framework,one-to-many,model-binding,junction-table
If you want to create an one-to-many relationship between those two entities your model would be like this: public class PageConfig { public int Id {get;set;} //navigation property public ICollection<Image> ScrollerImages {get;set;} } public class Image { public int Id {get;set;} //FK public int? PageConfigId {get;set;} //navigation property public PageConfig...
php,laravel,eloquent,relationship,one-to-many
Your relations are wrong, change them to: // User public function account() { return $this->hasManyThrough('Account', 'Workspace', 'user_id', 'workspace_id'); } // Account // use camelCase for relations public function accountUrl() { // I assume you have account_url_id on accounts table // If it's opposite, then use hasOne return $this->belongsTo('AcountUrl', 'account_url_id', 'id');...
java,sqlite,orm,one-to-many,many-to-one
I believe the behavior you're observing is the default behavior, but you should be able to change it and make the underlying History objects be persisted by default. On your @OneToMany annotation in Project, try specifying the cascade field as cascade = CascadeType.PERSIST (assuming you're using javax.persistence.OneToMany). See the documentation...
php,symfony2,doctrine2,one-to-many,query-builder
When you specify multiple FROMs, later one will overwrite the previous ones. So, instead of writing: $queryBuilder ->select('pm', 'c') ->from('MySpaceMyBundle:PointsComptage', 'pc') ->from('MySpaceMyBundle:ParametresMesure', 'pm') ->leftJoin('MySpaceMyBundle:Compteurs', 'c', 'WITH', 'pm.compteurs = c.id') ->where('pc.id = c.pointsComptage ') ->andWhere('pc.id = :id') ->setParameter('id', $id); I believe you need something like this: $queryBuilder ->select('pc', 'c', 'pm') ->from('MySpaceMyBundle:PointsComptage',...
I think your problem is because you are not mapping the FKs as you should. Try this: public class ServingChoice { //... [ForeignKey("Product")] public int ProductId { get; set; } [ForeignKey("Choice")] public int ChoiceId { get; set; } public Product Product { get; set; } [InverseProperty("ServingChoices")] public Product Choice {...
java,hibernate,many-to-many,one-to-many,many-to-one
This should be the correct mapping of the entities (database tables and columns are ok) //Order entity @OneToMany(mappedBy = "order", cascade = CascadeType.ALL) private List<Items> items; //item entity @ManyToOne @Column(name = "order_fk") private Order order; //Return entity @OneToMany(mappedBy = "return") private List<Items> items; //item entity @ManyToOne @Column(name = "return_fk") private...
Try this: a_all = A.objects.all().annotate(b_count =Count('b')) This will add a new field b_count with every object of A. Then in your template you can do something like {% for a in a_all %} {{a.name}} : {{ a.b_count }} <br> {% endofr %} ...
python,django,one-to-many,one-to-one
You're SellPost model requires a User. SellForm form has no user field. What are your post variables?
ios,swift,core-data,one-to-many
Sorry because I'm really tired I couldn't read everything. But from what I've read, you want to get the citizens of a country which should be a NSSet. To get that you can simply do: let contacts = yourArrayOfCountries.flatMap { $0.citizensOfCountry.allObjects as! [Contacts] } According to your comment: let contacts...
django,django-models,one-to-many
I'm not really clear on how you assign messages to tasks. However, if you need the ability to have multiple elements on each side of a relationship, you should use a ManyToManyField, not a ForeignKey. Depending on what you are actually doing, you should be able to validate the correct...
java,hibernate,postgresql,one-to-many
Try using the following: cascade={CascadeType.PERSIST, CascadeType.MERGE} I believe the behavior you're seeing (though i'm not 100% certain) is that when you call merge on non persisted child objects the entity manager knows there are associated objects but because they're not part of the persisted context the default constructor of Foo...
php,symfony2,doctrine2,one-to-many
Try using the doctrine2 ORM functionality for Ordering To-Many Associations like this: /** * @var ArrayCollection[SubjectTag] * * @ORM\OneToMany(targetEntity="SubjectTag", mappedBy="subject") * @ORM\OrderBy({"position" = "ASC"}) * @Assert\Count(max = 10, maxMessage = "You can't create more than 10 tags.") * @Assert\Valid() */ protected $subjectTags; Hope this help...
python,django,one-to-many,many-to-one
You need to set a foreign key in your model Video this class Video(models.Model): environment = models.ForeignKey(Environment) ...
ruby-on-rails,forms,nested,one-to-many
I would suggest you to prepare two addresses in new action, add them to the use and then in the form reneder it with foreach. I found this kind of solution here : http://api.rubyonrails.org/classes/ActionView/Helpers/FormHelper.html#method-i-fields_for Since you have multiple addresses I think foreach is way to go. ...
hibernate,one-to-many,criteria-api
I finally found the answer, just use two roots: CriteriaBuilder cb = entityManager.getCriteriaBuilder(); CriteriaQuery<POS> cq = cb.createQuery(POS.class); Root<POS> posRoot = cq.from(POS.class); Root<Supplier> supplierRoot = cq.from(Supplier.class); cq.where(cb.and( cb.equal(supplierRoot.get(Supplier_.suppliertId), supplierId), cb.equal(posRoot.get(POS_.posId), posId))); cq.select(posRoot); ...
Start with a POJO which contains the name and id. In this class, it would also contain all the transactions as a List The sort order should be managed by the model, to this end, I'd add all the "name" objects to a List and use the Collections.sort and Comparator...
asp.net-mvc,entity-framework,one-to-many,many-to-one,asp.net-mvc-scaffolding
Don't rely too heavily on the scaffolding. The whole point is that it gives you a base to work from; it's not the be-all-end-all to your view. You can and should modify the scaffolding to suit your needs, and honestly, more often than not, it's easier just to start from...
spring,hibernate,jpa,one-to-many
This is because by specifying mappedBy="doctor" in the DoctorEntity class @Entity public class DoctorEntity { @OneToMany(mappedBy = "doctor", cascade = CascadeType.ALL) @JsonManagedReference private Collection<PatientEntity> patients = new ArrayList<PatientEntity>(); public DoctorEntity() { } } you are saying that DoctorEntity is no more the owner of the one-to-many relationship. PatientEntity is the...
mysql,sql,inner-join,one-to-many,foreign-key-relationship
When you need to perform SELF-JOIN, you have to give an alias to the copy of your table being joined. Please find the query below - here both sides were aliased: SELECT history_AB.pKey FROM history AS history_AB INNER JOIN history AS history_CD ON history_AB.pKey = history_CD.pKey WHERE (history_AB.fieldName = 'A'...
.net,sql-server,entity-framework,relational-database,one-to-many
Sorry, but I'm afraid is not possible include a condition in a relationship configuration. But, as a partial solution, I suggest you add a NotMapped property to your User class. Your model would be like this: public class User { ... public virtual ICollection<Book> Books{get; set;} [NotMapped] public IEnumerable<Book> AlreadyReadedBooks...
java,jpa,repository,one-to-many
It seems a bug to me in the caching mechanism. I would report it to Spring. As a working workaround the OP confirmed the removing @Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE).
php,laravel,delete,eloquent,one-to-many
First off define without success, because it says nothing, and the code you're showing should work. Anyway, I would suggest different approach, for using Eloquent save in a loop isn't the best way: public function postDelete($position) { DB::transaction(function () use ($position, &$deleted) { // run single query for update $position->users()->update(['position_id'...
python,django,django-models,one-to-many,django-queryset
You can use QuerySet.count through comments attribute (related_name). Use the following in the view function: comment_count = specific_story.comments.count() # do something with `comment_count` UPDATE Use .comments.count in template: {% for story in stories %} ... {{ story.comments.count }} ... {% endfor %} ...
ruby-on-rails,model,callback,one-to-many
You could add an initialize method to the User model after_initialize :init def init self.role =>'my_default_role' end ...
You could put the columns that you want into the group_concat(): SELECT A.*, GROUP_CONCAT(CONCAT_WS(',', '(', B.b_id, B.col1, b.col2, ')') SEPARATOR ';') as b_list FROM A LEFT JOIN B ON B.a_id = A.a_id GROUP BY A.a_id; This will give you comma-separated values in parentheses, separated by a semicolon....
Use FIND_IN_SET(). Example: SELECT * FROM pages WHERE FIND_IN_SET('1', pages) From the documentation: FIND_IN_SET(str,strlist) Returns a value in the range of 1 to N if the string str is in the string list strlist consisting of N substrings. A string list is a string composed of substrings separated by “,”...
python,django,django-queryset,one-to-many
The correct query does not include the _set part: Group.objects.filter(translatedfoo__language_code='x', translatedfoo__country='y') Search for "reverse" on this doc page for more details....
php,laravel,eloquent,one-to-many,eager-loading
You are just selecting what relations to pull back with that query. What you want is to select the customers where a relation has some property Try: $customers = Customer::whereHas('students', function($q) { $q->where('STATUS', '=', 'FULL'); })->get(); Further reading: http://laravel.com/docs/4.2/eloquent#querying-relations...
Unfortunately there is no sync method for one-to-many relations. It's pretty simple to do it by yourself. At least if you don't have any foreign key referencing links. Because then you can simple delete the rows and insert them all again. $links = array( new Link(), new Link() ); $post->links()->delete();...
java,hibernate,jpa,orm,one-to-many
If myClass is detached but the studentList was already intialized: Override @Transactional public void addStudentToClass(MyClass myClass, Student student) { myClass.getStudentList().add(student); classDao.update(myClass); } If myClass is detached but the studentList has not been previously initialized: Override @Transactional public void addStudentToClass(MyClass myClass, Student student) { MyClass attachedMyClass = classDao.merge(myClass); attachedMyClass.getStudentList().add(student); }...
entity-framework,ef-code-first,one-to-many
you should try : var user = new ApplicationUser() { UserName = "SuperPowerUser", Email = "[email protected]", EmailConfirmed = true, Forename = "Derek", Surname = "Rivers", DateCreated = DateTime.Now.AddYears(-3), OrganisationUnit = ou }; With your syntax (only provinding a FK) you assume that the Organisation exists....
php,symfony2,doctrine2,one-to-many
Isn't it better to make Fiddle::addTemplate($template) method, which will add template to collection ($this->templates->add($template)) and set link to self ($template->setFiddle($this)). AFAIK, it is recommended way if Fiddle is an aggregation root of your model.
ios,core-data,one-to-many,nsfetchrequest
Normally you'd have a Core Data relationship on Person that points to the Education entity, configured as to-many. Then once you have an instance of Person, you just look up the value of that relationship like you'd look up the value of any property. You get back a collection of...
What you are asking for is not that hard. Some of your thinking is getting in the way. First, one almost never iterates in SQL. SQL is not that kind of language. Everything in SQL is done via sets of something. Your approach can be: Identify the set of rows...
You need to persist your TypePurchase entity before you persist your Purchase Entity. The following example is an extension to the User-Comment example of this chapter. Suppose in our application a user is created whenever he writes his first comment. In this case we would use the following code: <?php...
hibernate,spring-mvc,jpa,orm,one-to-many
In addition to binding the name correctly you need to do two things to get the orders to persist. 1 specify cascade options on the relationship 2 set both sides of the relationship public class Customer { @Id @GeneratedValue private Integer customerId; private String customerName; @OneToMany(mappedBy = "customer", cascade =...
java,jpa,many-to-many,one-to-many,hibernate-cascade
I think there is an issue in inserting, please note each project has one project leader, so if you put another leader to project, the old one will be deleted and new one will be inserted, I wrote small program about your issue: package leader; import java.io.Serializable; import javax.persistence.*; /**...
You should create a function to return order children. function GetItems($idOrder) { return $this->db->get_where("orderitems", "idOrder" => $idOrder)->array_result(); } After that, you will remove the JOIN with the orderitems table. And then you should get the array_result of your query and iterate with it by foreach and attach the children in...
entity-framework,mapping,one-to-many,code-first,asp.net-web-api2
Yes, you do. A telephone number is linked to a user through the foreign key. You need to specify whose telephone number is it, by specifying the user's id. The very fact that your constraint was broken was caused by one of the following possible reasons: not nullable foreign key...
php,mysql,one-to-many,auto-increment,identifier
insert_last_id returns the last inserted ID of the very same SQL session/connection (see MySQL manual). - The SQL server does not know about your pages. As long as the connection/session is not shared there are no problems (such as race conditions). It's also possible to get the last inserted ID...
hibernate,exception,jpa,one-to-many,joincolumn
The correct way would be (not what OP wants) You could [email protected] annotation (note the plural instead of the singular), thus joining the : @Entity @Table(name = "TABLE_A") @IdClass(TableAPk.class) public class TableA implements Serializable { private static final long serialVersionUID = 1L; @Id @Column(name = "COLUMN_1", nullable = false,...
jpa,delete,annotations,one-to-many,many-to-one
Like my last thought suggested, i had to fill the list of the parent myself. So now there are no more errors. I changed this method: public static void addTagValue(final TagValue value) throws Exception { manager.getTransaction().begin(); manager.persist(value); manager.getTransaction().commit(); } to: public static void addTagValue(final TagValue value) throws Exception { manager.getTransaction().begin();...
class,swift,structure,one-to-many
I'd be using structs not classes for my data model. Structs and Classes I wouldn't use optionals unless I really had to, and there are a few use cases where you have to. I also wouldn't be using implicitly unwrapped optionals at all... i.e. ! It's an 'exclamation' for a...
entity-framework,one-to-many,code-first,one-to-one,relationships
The problem is in the configuration of your one-to-one relationship because one end must be principal and second end must be dependent. When you are configuring this kind of relationship, Entity Framework requires that the primary key of the dependent also be the foreign key.So, don't map UsuarioId as FK,...
ruby-on-rails,postgresql,callback,migration,one-to-many
I think it makes sense to handle this functionality as part of the main app, and not within migration, as there seem to be a significant chunk of functionality to handle. Probably best to handle it as part of an after_create callback in the Lead model, and use a class...
SELECT project_id, repo_id FROM User_Works_on AS u JOIN Follows_user AS fu ON u.user_id = fu.user_id JOIN Follower_Works_on AS f ON fu.follower_id = f.follower_id DEMO...
php,mysql,foreign-keys,one-to-many
You need to change the order you do things because before you can insert into the Master_Catalog_{$CompName} table, the company must exist in the Companies table due to your foreign key constraint. As well you don't allow nulls on the Company_ID which means you also need to include it in...
php,doctrine2,domain-driven-design,one-to-many,referential-integrity
Ensuring a clean Domain model means you ignore everything db related, like one to many relationships. Your parent/child issue is a smell, a hint that you're using db driven design. At the Domain level, the Aggregate Root (AR) acts as the 'parent', although the term is wrong. An Aggregate represents...
.net,many-to-many,entity-framework-6,one-to-many,ef-fluent-api
You can use a navigation property and set the Dependents table in the model: public class Title { public int Id { get; set; } public string Name { get; set; } public virtual ICollection<Person> Dependents { get; set; } } public class Person { public int Id { get;...
java,hibernate,null,one-to-many,many-to-one
Looking at the code, the problem might be when isNewPO is true you first save the PO and after that you set that parent object to the relationship. This means that at the time of persisting PO, relationships don't have their PO set, leading to NULL being inserted in PARENT_OBJECT_ID...
java,hibernate,caching,one-to-many,singleinstance
I think the way you have modeled this, you should not be doing this: personType.p.pid=2 As you're changing referential data on the hibernate managed models, I think you would want to do this: personType.p=smith Where smith is a reference to the Person object with ID 1...
SELECT c.cakeName FROM `cakes` c LEFT JOIN `chef` ch on (ch.id=c.idChef) GROUP BY ch.name ...
ios,core-data,memory-management,one-to-many
There are NUMEROUS disadvantages to not specifying an inverse. You will have poorer performance, Core Data will need to work harder and you risk integrity issues. Always, always, always have an inverse relationship. Even if you will never use it, Core Data will. You will not have a memory issue...
Are your CoreDataGeneratedAccessors auto-generated or typed? If I have relations i.e. @property (nonatomic, retain) NSSet *rooms; my code is generated with the item name and not the Entity name - (void)addRoomsObject:(Room *)value; (recognize the s in Rooms). If it's not this, take a look at your model (correct connection between...
spring,jpa,persistence,spring-boot,one-to-many
That's exactly as it should be. If you wish to avoid a circular reference, use the @JsonBackReference annotation. This prevents Jackson (assuming you're using Jackson) from going into an infinite loop and blowing your stack. If you want the ID instead of the entity details, then create getProductID & getCategoryID...
orm,sails.js,one-to-many,waterline,sails-mongo
you need to tell sails to populate the creator show: function(req, res, next) { Author.findOne(req.param('id').populate('creator').exec(function foundAuthor(err, author) { console.log(author.creator); res.view({ author: author, }); }); } ...
symfony2,object,for-loop,twig,one-to-many
I left some typos indeed (i just corrected them). I happen to have found the solution. I had issues with the way my entities were mapped. This is where I found some useful tips http://obtao.com/blog/symfony2-issues-you-do-not-understand/
oracle,hibernate,hql,condition,one-to-many
The contract of league.getTeams() is to return the teams of the league. And the method will always return that, whatever the way you found the league. Your query returns all the leagues which have at least a team starting with S. The query you need is something like select l,...
I was finally able to achieve this in PIG using the TO_MAP function.
c#,asp.net-mvc-4,entity-framework-6,one-to-many
The best way is to add an foreign key property, despite whether you really would prefer to or not. The problem here is that you're posting the whole related model, or more correctly not posting the whole related model, because the only property being posted is it's id. This results...
ruby-on-rails,ruby,rest,activerecord,one-to-many
Take a look at merit gem. Even if you want to develop your own badge system from scratch this gem contains plenty of nice solutions you can use. https://github.com/merit-gem/merit
node.js,mongodb,sails.js,one-to-many,sails-mongo
It seems like you are passing JSONs for style and brewery. To be honest I never tried to populate multiple models with 1 request like this. Is this really a feature of Sails? If yes, it still probably tries to create a category every time, which causes the uniqueness issue....
php,symfony2,doctrine2,doctrine,one-to-many
Assuming that your dump function is symfony/var-dumper and not a custom function Question 1 Yes, nested collection are not displayed by default by dump function, its about performance. This is not a Doctrine related issue. Your data are loaded here. You can play around with advanced use of var-dumper, like...
The query is fine as is. It's returning enough data for you to iterate through and build the array you want. $data = array(); // could be any type of loop here. whatever returns data from your query while($row=mysql_fetch_array($result)) { $data['habit_id'] = $row['habit_id']; // the in_array check ensures there are...
In the first example you have person_id columns in Hotel and Apartment tables, which means you will have separate record in Hotel or Apartment tables for each person, which doesn't seem like what you intend to do. So the foreign key should be moved to Person table. So the next...
sql,associations,one-to-many,varray
If one row in T can belong to more than one row in A, the normal way is to create a link table: create table A_TO_T ( TID foreign key references T(TID), AID foreign key references A(AID), primary key (TID, AID) ); A link table is also called a junction...
doctrine2,doctrine,one-to-many,single-table-inheritance,bidirectional
You do not need to have a "collars" column on the pet table. It is a one-to-many relationship, so the only table that need to "know" about pets are the collar table. A bidirectional relationship does not mean you need two columns on two tables. Your map seems correct....
c#,database,entity-framework,one-to-many
The issue that you're having is that you don't initialize your ValidValues property to a list. By default, those types of properties initialize to null unless you specify differently. The best approach is to add that initialization to your constructor of that object. public StoreColumnName() { this.ValidValues = new List<StoreValidValue>();...
php,mysql,many-to-many,one-to-many
I found an answer while reading a few days later. I learned about joins and realized that they were exactly what I was looking for.
java,jpa,one-to-many,jointable
EDIT: Sorry my bad I missed the fact that you have extra columns in the Join table, so just need to decompose the ManyToMany association between ProductModel and LanguageCountry into two OneToMany associations. Your code should look like: in ProductModel class: @OneToMany private List<ProductModelI18n> ProductLanguages; In LanguageCountry class: @OneToMany private...