java,hibernate,hibernate-mapping,one-to-one,hbmxml
Unfortunately you must specify from which associated entity you want to get the ID value, through the required property property to initialize the foreign generator. So you need to add at least the association from child to parent. Something like this: <hibernate-mapping> <class name="com.rup.example.po.CustomerTempInfo" table="CUSTOMER_TEMPINFO"> <id name="customerId" type="int" column="customer_id"> <generator...
java,hibernate,jpa,orm,one-to-one
If I understood you correctly you want to create/define a relationship between two entities based on a value of some entity's property. The think is that relationship between entities is defined on entities count (how many entities can has the other entity) and not on some entity's property value. However...
For Saving stock object we required Stock stock = new Stock(); stock.setStockCode("4715"); stock.setStockName("GENM"); But for saving stock along with StockDetail you need to set fields for both and to get Id of saved stock( to save with StockDetail as we require to maintain foreign key relationship) it requires the StockDetail.getStock().getId()...
c#,entity-framework,ef-code-first,one-to-one,ado.net-entity-data-model
That exception is launched because you are trying to configure an one-to-one relationship but you are not specifying which end is the principal in the relationship. Principal end is the one which will be inserted first and which can exist without the dependent one. Dependent end is the one which...
What you are asking for is not that hard. Some of your thinking is getting in the way. First, one almost never iterates in SQL. SQL is not that kind of language. Everything in SQL is done via sets of something. Your approach can be: Identify the set of rows...
It doesn't look like Django runs the query until you call the relation class Bar(models.Model): name = models.CharField(max_length=20) class Foo(models.Model): bar = models.OneToOneField(Bar) in shell: In [1]: Bar.objects.create(name='chocolate') Out[1]: <Bar: Bar object> In [2]: Foo.objects.create(bar=Out[1]) Out[2]: <Foo: Foo object> In [3]: from django.db import connection In [4]: connection.queries Out[4]: [{u'sql':...
python,set,one-to-one,relation
Suppose you have: relations = [('a', 'b'), ('b', 'c'), ('c', 'a'), ('c', 'b')] collection = ['a', 'b', 'c'] Then do this: mapping = collections.defaultdict(list) for key, value in relations: mapping[key].append(value) Finally, check these conditions: if (len(mapping) == len(collection) and len(set(itertools.chain.from_iterable(mapping.values()))) == len(collection)): print('A bijection exists') Finding the bijection is left...
In your SomeOtherEntity you specify @PrimaryKeyJoinColumn mapping for ConcreteUser. If you check the documentation of the annotation, you find out that it says: ... and it may be used in a OneToOne mapping in which the primary key of the referencing entity is used as a foreign key to the...
request.user is associated with django-auth User Model user = get_object_or_404(User, username=request.user.username) if user.profile.bool: remember profile in user.profile.bool is from related_name='profile' under your UserProfile Model...
Both approaches are valid and frequently used. The normalization theory of a relational schema would not allow to put all the data in a single table for reasons of data consistency. This would favor a multi-table approach. In the single-table approach you'll end up with a lot of empty (null)...
entity-framework,one-to-many,code-first,one-to-one,relationships
The problem is in the configuration of your one-to-one relationship because one end must be principal and second end must be dependent. When you are configuring this kind of relationship, Entity Framework requires that the primary key of the dependent also be the foreign key.So, don't map UsuarioId as FK,...
If you want to execute ALTER TABLE statment you sould truncate the table in the first place. Because Mysql can not add the constraint to the existing rows according to the error log : #1452 - Cannot add or update a child row: a foreign key constraint fails...
c#,entity-framework,inheritance,ef-code-first,one-to-one
I think you can resolve your problem with this model: public class GeoInfo { public int Id { get; set; } public double CoordX { get; set; } public double CoordY { get; set; } } public class Person { public int Id { get; set; } public string Name...
django,serialization,django-rest-framework,one-to-one
You can create custom serializer fields to create your custom PersonSerializer. You can add fields to get values from Enviroment. class PersonSerializer(serializers.HyperlinkedModelSerializer): interests = serializers.CharField(source='profile.interests') researchLines = serializers.CharField(source='profile.researchLines') loginName = serializers.CharField(source='profile.loginName') # --- FIELDS FOR enviroment class Meta: model = Person fields = ('interests', 'researchLines', 'loginName', #-- enviroment fields )...
mysql,delete,relational-database,relationship,one-to-one
Add similar foreign key to admin table - ALTER TABLE user ADD CONSTRAINT FK_user_admin_user_id FOREIGN KEY (id) REFERENCES admin(user_id) ON DELETE CASCADE ON UPDATE RESTRICT; Now, you can remove rows from user or admin table, and related records will be removed. Use FOREIGN_KEY_CHECKS variable to add new records, e.g. -...
php,laravel,eloquent,laravel-5,one-to-one
You receive null for because your relation definition is wrong. Your profile model should be public function user() { return $this->belongsTo('App\User','user_id'); } The error is because you are trying to get the user object from a collection. Since you have used get() to retrieve data you are receiving a collection...
laravel,eloquent,foreign-key-relationship,one-to-one
First your users table does not need a pet_id. Drop it. Then Users Model public function pet() { return $this->hasOne('App\Pet'); // Changed form hasMany to hasOne } Pet Model public function user() { return $this->belongsTo('App\User'); } Now create a new User $user = \App\User::create($data); // You need to set $fillable...
mysql,database-design,relationship,one-to-one
As @Walter Mitty is mentioned, a normal solution to the problem will be something like: In the case that such a restructure is not available, then: Is it correct to take the second option? Both 1 & 2 will have some problems, yet both can be applied based on your...
spring,jpa,spring-data-jpa,one-to-one
Hibernate will check, if the id field is null. If so, then it will insert the data, if the id field has a value, Hibernate will do an update to the row with that id. So if you create a new object and copy values from another object, and you...
python,django,one-to-many,one-to-one
You're SellPost model requires a User. SellForm form has no user field. What are your post variables?
sql,database,associations,one-to-one
The best name to give a one-to-one association table is exactly the same as the best name to give any table: whatever is the most meaningful to you and your group. If you feel that a 1-1 cross reference table needs to have a different name than a n-m cross...
django,one-to-one,django-forms
You have to create second form for PrinterAddress and handle both forms in you view: if all((profile_form.is_valid(), address_form.is_valid())): profile = profile_form.save() address = address_form.save(commit=False) address.printer_profile = profile address.save() Of course in the template you need to show both forms under one <form> tag :-) <form action="" method="post"> {% csrf_token %}...
zend-framework2,parent-child,zend-db,one-to-one
The issue that you have is the Table Gateway pattern is only really any good at abstracting database access to a a single database table. It does not in anyway allow for the hydration of entities or management of relationships. Object Relationship Mappers (ORM's), such as Doctrine, solve this problem....
I solved my poroblem. In my BaseDao and BaseService I removed: private Session session = HibernateUtil.getHibernateUtil().getSession(); And I added in all methods in BaseDao and BaseService: HibernateUtil.getHibernateUtil().getSession(); so I removed the two sessions and my method, example create, became: @Override public void create(T t) throws DaoException { HibernateUtil.getHibernateUtil().getSession().save(t); log.info("Create: "...
symfony2,upload,one-to-one,stofdoctrineextensions
i think i solve my problem, here what i've done : $company = new Company(); $form = $this->createFormBuilder($company) ->add('name') ->add('logo', new \cM\ManagementBundle\Form\FileType, array( 'data_class' => 'cM\ManagementBundle\Entity\File' )) ->add('submit','submit') ->getForm() ; if ($this->getRequest()->getMethod() === 'POST') { $form->handleRequest($this->getRequest()); if ($form->isValid()) { $em = $this->getDoctrine()->getManager(); $em->persist($company); $uploadableManager =...
hibernate,one-to-many,one-to-one
You forgot the @ManyToOne annotation on WalletData.user. And the mappedBy attribute should be user, since that's the field which constitutes the other side of the association. Bidirectional OneToMany associations are described in the documentation. Read it: http://docs.jboss.org/hibernate/orm/4.3/manual/en-US/html_single/#d5e5564...
django,foreign-keys,one-to-one,relation
request.user.profile.warrior = warrior request.user.profile.save() ...
You need to annotate the field with a @OneToOne (assuming it isn't a @ManyToOne, i.e. many ClassB can contain many ClassA's) annotation: @OneToOne private ClassB classB; This should be the minimum code needed to properly add the relation between the entities....
c#,entity-framework,ef-code-first,entity-framework-6,one-to-one
I think what you need is a model like this: public class TableA { [Key] public Guid Id { get; set; } public virtual TableB TableB { get; set; } public virtual TableC TableC { get; set; } } public class TableB { [Key] [ForeignKey("TableA")] public Guid Id { get;...
c#,nhibernate,fluent-nhibernate,nhibernate-mapping,one-to-one
OK, with assignable ID we can do it like this. Firstly we should be sure, that the ID is assigned, so we can adjust the getter of the <id> ItemSaleCode like this: public class ItemSaleDetail { string _itemSaleCode; public virtual string ItemSaleCode { get { return _itemSaleCode ?? SaleParent.SaleCode ;...
symfony2,fosuserbundle,one-to-one
Solution: In the end I changed the direction of the relationship between the two entities (Utente and DatiUtente).
java,hibernate,mapping,setter,one-to-one
Getters and setters are called by Hibernate during entity lifecycle, so it isn't guaranteed that this setter won't be called with null value. To avoid this error simply check if the parameter is null public void setProteinData(ProteinData proteinData) { this.proteinData = proteinData; if (proteinData != null) { proteinData.setUser(this); } }...
grails,mapping,gorm,one-to-one
I found out the problem!, hibernate needs one of the duplicated columns to be mapped with insert="false", update="false" To do that on grails you have to add that to the mapping, like this: static mapping = { datasource 'xxxxx' table 'clients' version false id column: 'third_party_rowid' thirdParthy column: 'third_party_rowid', insertable:...
It is really bad practice to have your primary key be foreign key at the same time. Especially when you have @GeneratedValue on it. On closer look, your entities are mapped ok but usersAccounts table needs adjusting. Remove that foreign key constraint from id column, and add new column userId...