Why Does Math.pow(x,y) Count as a Double?
You'll have to do this: int levelMeal = (int) (5*(Math.pow(2,level-1))); ^ this is a cast As you can see in the documentation, Math.pow() returns a double by design, but if you need an int then an explicit cast must be performed....
power expressed as a ** b on Android
You can use a ^ b instead of a ** b, see Expression Builder's code for reference, it's one of the "builtin operators". To transition between both, you can use String.replace, which returns a copy of the input String....
Calculating pow with doubles gives wrong results
You're just hitting rounding errors. There's nothing you can do about this, except revert to an integer-based approach whenever the inputs are integers. You could condition on whether the inputs are integers, and if so then use integer arithmetic; if not, then use doubles. But using exp and log will...
Does Java's Math.pow round off the result?
java,math,floating-accuracy,pow
because it casts long to double System.out.println((double)999999999999999999L); outputs: 1.0E18 and System.out.println((long)(double)999999999999999999L); outputs: 1000000000000000000 why is that ? ...
Why is pow(x, y, z) more efficient than (x ^ y) % z? [duplicate]
pow(x,y,z) is usually implemented like this (Java): int pow(int x, int y, int mod) { long res = 1, p = x; while (y > 0) { if (y%2 == 1) { res = (res*p)%mod; } p = (p*p)%mod; y /= 2; } return (int)res; } It has O(log y)...
Javascript self made pow with modulo
The overflow is occurring in this line: return (r * r) % mo; Refer to the answers to this question for some simple algorithms to implement a*a mod n without overflow. I've adapted one of the answers to Javascript below: function addmod(x, y, n) { // Precondition: x<n, y<n //...
How to uninstall pow (node) on mac osx
Please run this command curl get.pow.cx/uninstall.sh | sh You are missing uninstall.sh in your terminal command(from your screen shot)...
Java/Android pow precision/scale like in Windows calculator
java,android,math,precision,pow
omg... I speend a few days on this. I have tried many algorithms and none of them don't worked... And then I wrote in my function: pow(new BigDecimal(3), new BigDecimal("8.73")) // <-- this is String in 2 argument (good) NOT: pow(new BigDecimal(3), new BigDecimal(8.73)) // <-- this is double in...
pow function not working properly in Code::Blocks IDE
printf("Hello world! %d\n",pow(2,2)); "The output of this code should be Hello world! 4 right?" No. As this is undefined behavior, anything can happen. As @Mureinik posted what likely happens in this errant situation, you could have a possible understanding of why you saw 0. But in the end, C does...
pow(1,0) returns 0? [closed]
pow() returns a double type. You need to use %f format specifier to print a double. Using inappropriate format specifier for the supplied argument type causes undefined behaviour. Check chapter ยง7.21.6.1 of the C standard N1570 (C11). (Yes, this has nothing specific to C89, IMHO)...
Swift's pow() function won't accept Doubles as arguments
swift,generics,pow,downcasting,type-constraints
why is it complaining about this? Because pow returns Double. And Double is not identical to T. The error message is misleading, but it means "Cannot find pow that accepts (Double, Double) and returns T type" I think you are misunderstanding "cast" in Swift. In Swift as does not...
Raising number to fractional power java [duplicate]
3/7 is evaluated to 0, since you are dividing two integers, so Math.pow(num, pow) becomes Math.pow(num, 0.0) which is 1.0. Change it to 3.0/7 in order to get a floating point result....
Nth power of m for big numbers
This is not very difficult to do without using external libraries. Store the digits of the number in a vector and multiply digit by digit (like you do in paper). Example: power(12,23): Store as start->1->2->end step 1 result: start->1->4->4->end step 2 result: start->1->7->2->8->end and so on... ...
pow function c++ error
The easiest (and fastest) way to get powers of two is shifting - the CPU is using binary anyway, so it can just add a few extra zeroes on the end for you. So instead of pow(2, i) you would write (1 << i)....
Power big float numbers (100.33^360)
From the PHP GMP documentation page: These functions allow you to work with arbitrary-length INTEGERS using the GNU MP library. In other words, no floating point allowed. GMP itself can do floating point but it appears that the PHP interface to it doesn't use its full power. You can use...
Calculate power with very big exponents in java
In cryptography c = m^e (mod n) where c is the cipher text, n is your max value that can be represented. Modulus operation is needed. In addition to that, for large numbers exponentiation Exponentiation by squaring is used. pow operation implements this algorithm. Code is here. Cryptography implementation is...
Understanding rounding with pow / base 10
// we will multiply by 10^$round, then get the floor value of that amount then divide by 10^round. ## -> if it does problems, switch back to floor() It says it right in the code what it does! And yes - changing $round = 3; will work. However DON'T...
C++ POW(X,Y) X negative double and Y negative double, gives nan as result
I am guessing that you made a typo in SciLab. You must have written -0.89 ^ -0.67 Which means you did -(0.89 ^ -0.67) = -(1.08). If you instead typed (-0.89) ^ -0.67 You would have gotten the answer -0.5504 - 0.9306i. The negative root of a negative number is...
Java pow BigInteger implementation
java,cryptography,biginteger,pow,exponent
You can simplify the code and this will also make it faster x^y / x^z = x^(y - z) so BigInteger yab = y.pow(ab.intValue()); BigInteger ycb = y.pow(cb.intValue()); BigInteger ans = (yab.divide(ycb)).mod(p); can be simplified to BigInteger yabc = y.pow((int) (ab.longValue() - cb.longValue())); BigInteger ans = yabc.mod(p); or BigInteger and...
Convert a very large base n number to bytes
python,algorithm,python-3.x,integer-overflow,pow
Is there a version of math.pow that doesn't overflow? Try using the built-in exponentiation operator, **. AFAIK it doesn't have the same limitations that math.pow does. >>> math.pow(8,342) Traceback (most recent call last): File "<stdin>", line 1, in <module> OverflowError: math range error >>> 8**342...
What is the equivalent for bigint.pow(a) in Go?
Use Exp with m set to nil. var i, e = big.NewInt(16), big.NewInt(2) i.Exp(i, e, nil) fmt.Println(i) // Prints 256 Playground: http://play.golang.org/p/0QFbNHEsn5...
Are there any built-in .NET alternatives for using power of a number (Math.Pow) without errors?
The BigInteger structure has a Pow method. This structure resides in the System.Numerics namespace, and was introduced in .NET Framework 4.0. You need to add a reference to the System.Numerics assembly before using it. using System; using System.Numerics; public static class Program { public static void Main(string[] args) { Console.WriteLine(BigInteger.Pow(17,...
mathematics - exponentation in php - simple script
isset($input) will always return true because $input is still set even if empty... So, !empty($input) will return true only if $input is not (see exclamation !) empty and therefore seems to me like a better choice....
Java Math.pow is not working [duplicate]
1/2 is 0, due to integer division, so Math.pow(16, (1/2) is Math.pow(16, 0), which is 1.0. In order for 1/2 to be evaluated using floating point division, you have to cast either 1 or 2 to double : System.out.println(Math.pow(16, ((double)1/2))); Or use double literal in the first place : System.out.println(Math.pow(16,...
Why can't I use integers in the pow() function?
Can you use integer as arguments to pow function?` Yes, you can. The integer value is implicitly converted to a floating point value of the right type. In your case: SquaredIV = pow(&InputVar, 2); the problem is &InputVar is not of an integer type but of a pointer type...