matlab,signal-processing,quantization

You can certainly compute this in real number space, but you risk hitting precision problems (depending on starting point). If you're interested in studying orbits, you may prefer to work in a rational fraction representation. There are more efficient ways to do this, but the following code illustrates one way...

algorithm,colors,imagemagick,image-manipulation,quantization

You say, that the 'dominant' color was 'that piercing azure of the eyes'. You also say, that you want as a result 'that saturated azure being one of' the 5-6 colors in your extracted palette. You finally want 'a color that is actually in the image, not the blurred mean...

signal-processing,transformation,quantization

you have no gain by doing so, since you do not have more information. Low level example: you have a bit so it can be one or zero: b = [0 1]. Now you store that bit in 2 bit field. It will still have the value 0 or 1,...

mpeg,image-compression,quantization

This is because inter-frames contains only error residuals after subtracting predicted image from source image. Such residuals have almost uniform frequency distribution (if prediction ie. motion estimation is made correctly). For these frames we use uniform quantization matrices. In contrast, intra-frames have very high power of low frequencies, they are...

d3.js,charts,quantile,quantization

A quantize scale won't work in this case, as your domain and range are not split uniformly. Instead, you can use a threshold scale. Here's an example: var dollars = d3.format("$,d"), data = d3.range(100).map(function(d, i) { return { revenue: parseInt(Math.random() * 1000000000), title: "Company " + i, sector: "Sector "...

python,opencv,k-means,quantization

Change: ret,label,center=cv2.kmeans(Z,K,None,criteria,10,cv2.KMEANS_RANDOM_CENTERS) to: ret,label,center=cv2.kmeans(Z,K,criteria,10,cv2.KMEANS_RANDOM_CENTERS) (Deleted None)...

matlab,signal-processing,pcm,quantization

For the first two code lines I prefer, Fs = 10; L = 10; t = (0 : L - 1) / Fs; x = 0.3 * cos(2 * pi * t); where Fs is sampling frequency, L number of samples and t shows the time. Note that x is...

matlab,binary-data,nonlinear-functions,quantization

this piece of your code is completely wrong ,you change s(k) but you use s(k+1), it means that changing s(k) has not any effect! for k =1: N if s1(k)== -1 s1(k) = 0; end b(k) = 0.5*s1(k+1) + 0.5*b(k+1); end true one is: for k =1: N+1 if s1(k)==...

matlab,quantization,lab-color-space

It turns out that I've found the solution :D And the good thing is: The code is relatively simpler! In the main program labImage = applycform(rgbImage, makecform('srgb2lab')) labImage = lab2double(labImage) L = labImage(:, :, 1) a = labImage(:, :, 2) b = labImage(:, :, 3) bins_L = 10 bins_a =...