Change the coding of two variables in two data.tables and then merge data.table
From what you describe, you might be looking for rbind, not merge. Try the following: rbind(odd[, time_x := time * 2 - 1], even[, time_x := time * 2])[, time := NULL][] # id emotion learning time_x # 1: 11 4 60 1 # 2: 11 6 50 3 #...
R - converting character variable as.numeric, but in descending alphabetical order
You should be able to just re-factor, based on rev(levels(Mark)): set.seed(10) x <- factor(sample(LETTERS[1:5], 10, TRUE)) x # [1] C B C D A B B B D C # Levels: A B C D as.numeric(x) # [1] 3 2 3 4 1 2 2 2 4 3 as.numeric(factor(x, levels...
r recode a string variable based on a condition
try df<-data.frame(VAR1,N, stringsAsFactors=FALSE)
Recursively recode all project files excluding some directories and preserving permissions
Based on this question, but its solution does not preserve permissions, so I had to modify it. WARNING: since the recursive removal is a part of the solution, use it on your own risk Task: Recursively recode all project files (iso8859-8 -> utf-8) excluding '.git' and '.idea' dirs and preserving...
Recode values omitting NA's
You can do try[try <= .8] <- 5 The NA values will remain as NA Or create a logical condition to exclude the NA values try[try <=.8 & !is.na(try)] <- 5 ...
How to recode a set of variables in a dataframe in R
There's no need for an external function or for a package for this. Just use an anonymous function in lapply, like this: df[recode.list] <- lapply(df[recode.list], function(x) 6-x) Using [] lets us replace just those columns directly in the original dataset. This is needed since just using lapply would result in...
Conditionally Revalue a Factor in R
There is no "6" level in gears to begin with, so you need to create one: levels(mtcars$gear) <- c(levels(mtcars$gear), "6") You can then conditionally assign with the [<- function: mtcars$gear[ mtcars$am==1 ] <- "6" table(mtcars$gear, mtcars$am) 0 1 3 15 0 4 4 0 5 0 0 6 0 13...
Recode in Car package returns unexpected symbol when recoding strings
I was the author of the wordpress document - code is wrong and thanks for flagging the issue. Problem is that car::recode syntax requires a single quote rather than a double quote (or see comment from @MrFlick below on other acceptable syntax). y1 <- recode(y, 'c("Perch", "Goby") = "Perciform" ;...
Recode the same value pattern for all variables in Stata
Let's suppose that you are looking for variables with a certain value label attached. You can retrieve those variables using ds and pass their names to recode. . clear . set obs 2 obs was 0, now 2 . forval j = 1/5 { 2. gen y`j' = _n 3....
R: Recoding several characters into one new factor
Assuming that you wanted to check whether a subset of "countrycodes" are there in each of the "country" variables with the condition that if atleast one of the "countrycode" is present in a particular row, that row will get "1", or else "0". The idea is to create a vector...
how to convert a factor variable into a numeric - using R
r,variables,numeric,data-type-conversion,recode
First, here's why you would have to convert to character before converting to numeric: Lets say we have a factor that contains a handful of numbers x = factor(c(1,2,7,7)) you can inspect how this is represented in R like so: unclass(x) #> [1] 1 2 3 3 #> attr(,"levels") #>...
Recoding variables with NAs in R
You have three different conditions, so it's most natural to express it in three lines: z <- rep(0,nrow(frame)) z[apply(is.na(frame),1,all)] <- NA z[apply(frame==1 ,1,any)] <- 1 # [1] NA 0 1 ...