Use a subquery: SELECT t.* FROM (SELECT data_temperature, data_address_seo, datetime_logged FROM weather WHERE data_address_seo = 'street-28-postal-code-city-country' ORDER BY datetime_logged DESC LIMIT 2 ) t ORDER BY datetime_logged; ...
You are accessing the string array by byte not by 'logical character' To better understand this example breaks the string first as an array of runes and then prints the rune backwards. http://play.golang.org/p/bzbo7k6WZT package main import "fmt" func main() { msg := "The quick brown 狐 jumped over the lazy...
#include <stdio.h> #include <stdlib.h> #include<string.h> char* rev(char[] ); main() { char a[80],b,*c; int l,sum,i,v,pos=0; puts("give a string and a character"); scanf("%s",a); scanf(" %c",&b); sum=0; i=0; while(a[i]!='\0') { if(a[i]==b) sum=sum+1; i=i+1; pos=pos+1; } printf("the char %c exists %d times in the string\n",b,sum); c=rev(a); printf("the original string is: \n"); puts(a); printf("the reversed...
python,search,dictionary,reverse
You can write simple lambda for this: d={"a":5, "bf": 55, "asf": 55} search_key = lambda in_d, val: (k for k,v in in_d.items() if v == val) for k in search_key(d, 55): print(k) # since the lambda returns generator expression you can simply print # the keys as follows: print(list(search_key(d, 55)))...
apache,url,parameters,proxy,reverse
So I eventually got it to work the way I wanted with mod_rewrite #Check if string already exists RewriteCond %{QUERY_STRING} !(.*parameter.*) [NC] #Add the string and keep hidden from user with [P] RewriteRule ^/(.*)$ public.url/$1?parameter=value [P] Hope someone else finds this useful...
The source code for the reverse method looks like this: def reverse(self, copy=True): """Return the reverse of the graph. The reverse is a graph with the same nodes and edges but with the directions of the edges reversed. Parameters ---------- copy : bool optional (default=True) If True, return a new...
python,loops,while-loop,reverse
I would say to make the while loop act like a for loop. firstList = [1,2,3] secondList=[] counter = len(firstList)-1 while counter >= 0: secondList.append(firstList[counter]) counter -= 1 ...
The main problem with the current setup, is that it doesn't check if the shift causes bits to go 'off'. Using a byte as example, the number 12 would be: 00001100 Meaning the maximum number of bytes that could be shift to the left is 4. Vice versa, using your...
Your code is actually working as intended; it reverses the list just fine. The reason it prints None is because list.reverse is an in-place method that always returns None. Because of this, you should be calling reverse on its own line: def func4(x): x.reverse() print(x) e = ['baby','egg','chicken'] func4(e) Now,...
There are a few notable issues, the first is with your while-loop in the reverseWordInAString(String) method... while(i<=length){ if(array[i]!=' '){ i++; } else{ reverseString(array, start, i-1); start = i+1; } } This loop will result in an infinite loop, because when you detect a space, you never increment the i, meaning...
linux,reverse,file-manipulation
You're almost there - tac writes to stdout so you can simply redirect the output somewhere handy: find .... \; > newfoo.txt If you want each file reversed and written to the same location, something like this will do: find . -type f -exec sh -c 'tac "$1" > "$1"-new'...
use array_slice $latest_arr = array_slice($products, 3); Edit : To preserve keys by the way, set the fourth argument to true...
powershell,powershell-v2.0,reverse,batch-rename
This should get the job done. $Path = "C:\Users\Test" $regex = "^(Spring|Summer|Fall|Winter)\s+\d{4}$" Get-ChildItem $Path | Where-Object {$_.PSIsContainer -and $_.Name -match $regex} | Rename-Item -NewName {$split = $_.Name -split "\s+"; "{0} {1}" -f $split[1],$split[0]} We use that regex to filter out the folder that fit your convention. Should be a little...
var reversedStr = string.Join(",", strSubjectIDs.Split(',').Reverse()); ...
javascript,jquery,arrays,reverse
It is working fine see output below var arr = [{"myId":"7d8f72c3f070736caf399df0a8211f5ei324410"},{"myId":"963d01cfa92a4f9d3cb755c7d3822e68i1744695"},{"myId":"5994f40a1b2fd9ff69d4e4551d18766ci2977900"},{"myId":"25bb4db94056ec38ba7ed1ee96e90006i2956275"},{"myId":"7720ec9200d5a6f5d16a447bc5ff7f2ci1080950"},{"myId":"f8a21d90a3adb464e7c3782471e1455bi3087305"}]; console.log(arr); arr.forEach(function(e){ document.body.innerHTML+=e.myId+"<br/>"; }) arr.reverse();...
c#,performance,for-loop,parameters,reverse
As @Dai pointed out, the second and third statements must be evaluated at the end of each iteration. This behaviour is detailed in §8.8.3 of the C# language specification. Paraphrased, it says about a for ( initialiser; condition; iterator; ) { ... } statement: A for statement is executed as...
To find these, you can use some data.table functions, like this: > dt <- data.table(V1 = c("A", "A", "B", "B", "N","P"), V2 = c("B","C","A","F","P","N")) > dt V1 V2 1: A B 2: A C 3: B A 4: B F 5: N P 6: P N > dt1 <- dt[,...
c++,string,pointers,return,reverse
In function rev array char p[25]; is a local object of the function. After exiting the function it will not be alive and in general can be destroyed, that is the memory occupied by it can be overwritten by other object or function. So the returned pointer to the first...
python,class,stack,queue,reverse
This will work. Your queue is composed of a list, so you can use slice syntax on the list to get a reversed version of the queue. class Queue: def __init__(self): self.items = [] def enqueue(self, item): self.items.append(item) def __str__(self): '''Allow print to be called on the queue object itself'''...
spring,routing,reverse,thymeleaf
Since version 4.1, Spring Framework provides a way to generate routes to resources from templates (i.e. reverse routing in views). You can check the reference documentation on the subject, but it's basically using auto-generated named routes for that. I don't know if Thymeleaf supports this in its standard dialect, but...
regex,oracle,oracle11g,substring,reverse
Oracle only allows 9 backreferences so you won't be able to use \10 or higher. However, why not take your string and reverse each of the groups? For example: create table test ( v varchar(100) ); insert into test values ('363031393634816909877808647715885542447721'); select v, regexp_replace(v, '([0-9]{4})', '\1 ') as v_replaced from...
java,this,reverse,doubly-linked-list
Here's why: lst2 = lst.reverse(); You're calling reverse() on lst so lst is going to be reversed. Then you assign the result ot lst2 which is going to be reserved as well. The solution is to make a deep copy of lst, assign it lst2 and call lst2.reverse(); Instead of...
list,function,haskell,monads,reverse
It is indeed not possible to create an unsequence function using monads alone. The reason is: You can safely and easily create a monadic structure from a value using return. However, it is not safe to remove a value from a monadic structure. For example you can't remove an element...
python,class,python-2.7,reverse
[::-1] is a slice. object.__reversed__() is instead used by the reversed() function, and is only applicable to sequences (objects that provide both a __len__ and a __getitem__ method. If you don't supply __reversed__, the function uses those __len__ and __getitem__ methods to access indices in reverse. __reversed__ must itself return...
#include <stdio.h> #include <string.h> #include <conio.h> int main(void){ char A[81][81] = {0}; int t=0,j=1,k=0,l; puts("Input a sentence (max 80 character)"); scanf("%80[^\n]", A[0]);//'gets' has already been abolished, it should explore a different way. while (A[0][t] != '\0'){ if(A[0][t] == ' '){ ++j; k=0; while(A[0][t] == ' ')//Skip spaces ++t; } else...
There's no need for an external function or for a package for this. Just use an anonymous function in lapply, like this: df[recode.list] <- lapply(df[recode.list], function(x) 6-x) Using [] lets us replace just those columns directly in the original dataset. This is needed since just using lapply would result in...
list,prolog,reverse,palindrome
Why not pal([]). pal([_]). pal(Pal) :- append([H|T], [H], Pal), pal(T). ...
I guess you can do something similar to this: >>> ip = '12.34.56.78' >>> reversed = '.'.join(ip.split('.')[::-1]) >>> reversed '78.56.34.12' And if you want to drop the last one: >>> ip = '12.34.56.78' >>> reversed = '.'.join(ip.split('.')[::-1][:-1]) >>> reversed '78.56.34' ...
java,integer,int,overflow,reverse
As pointed out in a prior answer, the problem can be attacked through calculating the inverse modulo 2^32 of the known divisor. java.math.BigInteger has a modInverse method that can be used. As also pointed out in the answer, numbers that are not prime relative to the the modulo base do...
I've now programmed a solution for the above mentioned problem which was easier than I initially thought it would be. I found several articles about how one can forge a CRC. That means how to patch data that way that the calculated CRC value will have a predefined value. Using...
Indices in most languages start with 0, so the last character index will be the length - 1
python,django,django-templates,reverse,django-urls
Pass the url name in the url template tag: "{% url 'cal_main' year|add:'1' %}" ...
ios,animation,reverse,apple-watch
As mentioned in the docs for WKInterfaceImage (https://developer.apple.com/library/prerelease/ios/documentation/WatchKit/Reference/WKInterfaceImage_class/#//apple_ref/occ/instm/WKInterfaceImage/startAnimatingWithImagesInRange:duration:repeatCount:), all you have to do is supply a negative value to duration.
If you just want to reverse the list at the end, use reverse/2: fib(N, F) :- fib(N, 0, [1], FRev), reverse(FRev, F). If you want to built the list in the reversed order, you would have to rethink the clauses. One solution is to use last/2 and append/3 to put...
The reason reverse = True is not working is that you have a return statement right before the check: return (xs, ys) The code after the return statement is never executed. Additionally, reverse() reverses the list in place and returns None, so x and y will end up being None....
from first link of googling "man nsupdate reverse": Adding records Here are examples of how to add A, CNAME, and PTR records. One must specify the TTL (time-to-live) of records (in seconds) when they are added. update add www1.example.com 86400 a 172.16.1.1 update add www.example.com 600 cname www1.example.com. send update...
If you want to simulate reverse, you must modify the list passed as a parameter to you function, not simply use a new list in your function. When you write list=list[::-1] the local copy of the original parameter points to a new list. You should do instead : def rev(l):...
I'm guessing your set commands all live within a parenthetical code block (such as a for loop), and you aren't employing delayed expansion when you should be. If that's the case, you can probably fix your existing code this way: setlocal enabledelayedexpansion set "rest2=!t1!" set "t1=!t3!" set "t3=!rest2!" Just so...
k should be initialized as - int k = i + rand()%(n-i); ...
c++,arrays,loops,for-loop,reverse
Oups ! First version is bad because you put two loops to the result will not be what you expect : each char of rev will successively receive all the chars from wrd and end with wrd[0] ! This first version should be (with one single loop) : s=strlen(wrd) -...
haskell,tuples,reverse,huffman-coding
As you have said yourself, you need to use the reverse function. Wherever you have your code to form the list of tuples, encapsulate that code in a reverse function using brackets (reverse(code)) or reverse $ <code> and the result will be the reverse. Hope this helps!...
To implement a reverse function, you need to use an accumulator. Here is how you might implement this (in this case, tail is the accumulator): (defun revappend (list tail) (cond ((null list) tail) (t (revappend (cdr list) (cons (car list) tail))))) Then, implement reverse in terms of revappend: (defun reverse...
Store each input in a List<String> and iterate in reverse order on your array for the output. This is a transformed version of your initial main(). public static void main(String[] args) { List<String> out = new ArrayList<String>(); try { Scanner console = new Scanner (System.in); System.out.println("> "); String input =...
android,layout-manager,reverse,recyclerview
from the docs for setReverseLayout Used to reverse item traversal and layout order. This behaves similar to the layout change for RTL views. When set to true, first item is laid out at the end of the UI, second item is laid out before it etc. For horizontal layouts, it...
A magical array is one where an operation performed on it does more than simply alter the contents. The only built-in array that has magic is @ISA, and that is in a very non-obvious way. As the sentence implies, a magical array is mostly a tied array, See tie and...
You can just do the following , you can check for reverse with word == word[::-1] that word[::-1] is reverse indexing : filename=raw_input("enter the file name: ") with open(filename) as f : for line in f: for word in line.split() : if word == word[::-1]: print word ...
You can add array_reverse() to reverse your array. This will do the trick for you. $gallery_images = array_reverse(array_values(get_children('pos_type=attachment&post_mime_type=image&post_parent=' . $gallery->ID)));...
php,string,permutation,reverse,explode
You can pop the last element off the end of the array and then unshift it back to the beginning: function last_word_first($name) { $x = explode(' ', $name); array_unshift($x, array_pop($x)); return implode(' ', $x); } echo last_word_first("secondname firstname"), "\n"; echo last_word_first("secondname1 secondname2 firstname"), "\n"; Another option is a regular expression:...
java,linked-list,reverse,listiterator
A ListIterator uses indexes to identify which element to start at. In the Oracle docs for LinkedList, it says: All of the operations perform as could be expected for a doubly-linked list. Operations that index into the list will traverse the list from the beginning or the end, whichever is...
The cons :: operator takes an element as left-hand argument and a list as right-hand argument. Here, you do the opposite which does not work. The right way to add an element at the element at the end of a list is to use list concatenation: let rec reverse l...
else{ value <<= 1;//<-- Value has been changed before it can be used reverseBits( value , c - 1 ); putchar( value & mask ? '1' : '0' ); if( c % 8 == 0 ){ putchar( ' ' ); }//end if }//end else replace with else { reverseBits(value...
If last added you mean last in list, it should be [-5:]. for example: In [22]: a =[1,2,3,4,5,6,7,8,9,10] In [23]: a[:5] Out[23]: [1, 2, 3, 4, 5] In [26]: a[-5:] Out[26]: [6, 7, 8, 9, 10] What exactly are you interest in RequestContext? RequestContext is to return specific values in...
java,arrays,string,order,reverse
You can transform your string into Stringbuilder and it had reverse method. And its always better to use foreach rather than for, untill there is actuall need. public String[] reverseString(String[] words) { String[] t = new String[words.length]; for (String wordTemp : words) { StringBuilder sb = new StringBuilder(wordTemp); t[i] =...
Using append: delete([A, B, C | End], Middle, [A, B, C, X, Y, Z]) :- append(Middle, [X, Y, Z], End). Test run: ?- delete([1,2,3,4,5,6,7,8], L1, L2). L1 = [4, 5], L2 = [1, 2, 3, 6, 7, 8] ?- delete([1,2,3], L1, L2). false. ...
Try this code. And operation is used to extract the bits that are same. I don't know C# so I can't type the exact code. The logic is take a random bit mask and AND the bits of c with that bitmask and inverse of that bitmask. The resulting two...
If a string has 4 characters, you'll get the first one via charAt(0), and the last one via charAt(3), because the index is zero based. So your loop would start at 3 and ends at 0, and not start at 4.
Your indentation is misleading. What you meant is: int reverse(int a[], int key) { int i = sizeof(a) - 1; while (i >= 0) { if (a[i] == key) { return i; } i--; } return -1; } What you wrote is equivalent to: int reverse(int a[], int key) {...
you can use reverse() directly instead of using a temporary variable to hold your array data. jsfiddle demo $.each($('textarea[name=source]').val().split('\n').reverse(), function(e){ alert(this); }); ...
python,regex,python-2.7,stack,reverse
stack.push places the given element/argument on top of stack. For you case the element/argument is whole list. You need to push each element of list seperately. So, replace: stack.push(j.split(' ')) by: for i in j.split(): stack.push(i) ...
Not sure what SQL server you're on, but hopefully this works on any (tested on MSSQL). If you look at the documentation for LIKE, you see that the wildcard you need is _ (underscore). Operators in SQL, in general, can be used both ways (i.e. both field LIKE constant and...
you could use fliplr, but it operates on each index of the cell instead of the whole cell. To wrap it all in one line, use cellfun recelldata = cellfun(@(x) fliplr(x), celldata,'UniformOutput', false) >>'BA' 'EB' 'CB' ...
python,reverse,large-files,readfile
import re p = re.compile(r'#@#@#@#@#@#@#@(?!.*?#@#@#@#@#@#@#@)(.*)$', re.DOTALL) test_str = "#@#@#@#@#@#@#@ \nTime:12:00 PM, CPU:12.0,RAM:12334321,Network:1231231233,....\n#@#@#@#@#@#@#@\nTime:12:01 PM, CPU:14.0,RAM:12354621,Network:1239864833,....\n#@#@#@#@#@#@#@\nTime:12:02 PM, CPU:9.0,RAM:12398781,Network:1231598697,....\n#@#@#@#@#@#@#@\nTime:12:02 PM, CPU:9.0,RAM:12398781,Network:1231598697,....\nasasdas\ndsa\nd\n\nasd" re.findall(p, test_str) Here instead of test_str you can use file.read().See demo....
java,arrays,algorithm,generics,reverse
If you mean that you want to do it manually without using Collections.reverse (that code shouldn't even compile btw, reverse needs a List as parameter), just traverse the array from the beginning to the middle swapping elements at the opposite sides of the range: public E[] reverse() { for (int...
width = int(input("Please enter a width: ")) i = 0 while i < width*2: if i < width: print("-" * i+ " *" * (width-i) + "-" * i) else: print("-" * ((2*width-i) -1) + " *" * (i - width + 1) + "-" * ((2*width-i) -1)) i +=...
Add ORDER BY id ASC to sql_qrp....
java,ssh,reverse,jsch,ssh-tunnel
There is an example gist that shows how to do it here: https://gist.github.com/ymnk/2318108#file-portforwardingr-java The method you want to look at is session.setPortForwardingR() session.setPortForwardingR(rport, lhost, lport); ...
You should use range or better xrange: for i in xrange(len(text)): new_list.append(string_list[len(text) - 1 - i]) ...
You start with 123456789 (num) and 0 (reversenum). Then, you multiply reversenum by 10: it remains 0. num % 10 is the remainder when num is divided by 10: this is 9, which becomes reversenum. num is then divided by 10, but integer division gets the floor of fractional results,...
java,file,bytearray,reverse,corruption
After writing all close fos. This ensures that everything is written to disk. Then read the bytes from the file, for which there exists a simple function: byte[] bytes = Files.readAllBytes(Paths.get("...")); ...
LC_ALL='en_US.UTF-8' (your code) echo "${#reverse}" 10 LC_ALL='C' (your code) echo "${#reverse}" 16 I think you must just have a localization/encoding problem in your environment. I suspect that would even effect rev, although it's a nonstandard utility so I can't say for sure. This works fine for me: rev() { local...
<?php $array = array(1, 2, 3, 4); $size = sizeof($array); for($i=$size-1; $i>=0; $i--){ echo $array[$i]; } ?> ...
You can use Eloquent's reverse() function for collections. public function index() { $products = Product::with('owner', 'memberInfo'); $products = $products->reverse()->paginate($this->perPage); return View::make('layouts.sales', array('products' => $products, 'status' => 'all')); } ...
Try this: int main() { vector<int>numbers; int i = 0; for (int i=1; i <= 100; ++i) { numbers.push_back(i); } for(int i=100;i>0;--i) { cout << numbers[i-1] << endl; } } ...
c,recursion,linked-list,reverse,elements
The assignment p = prev does not update the front pointer in your LIST. When you call lst_print(l) you are starting at the old front of the list which is the new back, hence the reason why it will stop after a single iteration. Instead, you should update the front...
c,arrays,string,pointers,reverse
1) Since your iteration starts with for(i = strlen(src); i >= 0; i--) { it assigns 0 to the dest, thus terminating the string. So printf() prints nothing as it sees the 0 terminator. You can re-write it as: for(i = strlen(src) - 1; i >= 0; i--) { *(dest+j)...
java,data-structures,linked-list,reverse
You have two problem inside your code. The first one is that the node that you pass to the method doesn't change outside the method, it still point to 1! The second problem is inside the while loop... you do something like temp1->2, temp2->3 after that 2->1 and 1->3 at...
You cannot just chain method calls like that in JavaScript. The later calls will be invoked on the return value of the previous call, not on the original object. myArray.shift() returns the (formerly) first element of the array. It does not return the (original or the modified) array (reverse does...
You should realize that at the end of the while loop count stores the length of the string entered.For example if you input hello count holds 5.But the last element of the string will be at count-1 index and not at count index as indexing starts from 0. So you...
django,django-templates,reverse,django-urls
p.name is an empty string in your template. While myp url requires at least one alphanumeric character as the argument.
It problem is your if(a[i] == " ") condition is not satisfied for the last word var a = "who all are coming to the party and merry around in somewhere"; res = ""; resarr = []; for (i = 0; i < a.length; i++) { if (a[i] == "...
I have found the solution for the above problem. There is a printer setting called 'Tear Off' which if enabled automatically reverses the feed for every print to the starting position of the next receipt. Thus, this does not require any software change. It can be easily handled by making...
EDIT: Well, right as I posted the question I found the answer, if it might help anybody, here it is let rev my_list = let rec rev_list list = function | Empty -> list | Item (first, rest) -> rev_list (Item (first, list)) rest in rev_list Empty my_list ...
java,sorting,order,reverse,comparator
Using a comparator would be the correct approach here in order to avoid the overhead of reversing an array. If the classes you are comparing implement Comparable you can just reverse the order of the comparison. obj2.compareTo(obj1). A way to visualize this is to think of the two objects as...
I'm not sure where have you found a Module.Map, maybe it is part of your homework? So, I will presume, that you're talking about OCaml standard module Map. General information Maps in OCaml are implemented using balanced binary trees. Trees, by itself do not have order, because their structure are...
python,list,reverse,assign,python-internals
CPython list slice assigment will convert the iterable to a list first by calling PySequence_Fast. Source: https://hg.python.org/cpython/file/7556df35b913/Objects/listobject.c#l611 v_as_SF = PySequence_Fast(v, "can only assign an iterable"); Even PyPy does something similar: def setslice__List_ANY_ANY_ANY(space, w_list, w_start, w_stop, w_iterable): length = w_list.length() start, stop = normalize_simple_slice(space, length, w_start, w_stop) sequence_w = space.listview(w_iterable) w_other...
java,equals,reverse,stringbuilder,stringbuffer
Use this in your if condition if(p.toString().equals(p.reverse().toString())) ...
Recursive reversal can be written slightly simpler. std::string reverse(std::string s) { return s.empty() ? s : reverse(s.substr(1)) + s[0]; } or in place void reverse(std::string& s, int a, int o) { if (a < o) { std::swap(s[a], s[o]); reverse(s, a + 1, o - 1); } } Edit: If you...
javascript,prototype,this,reverse
My problem comes when writing a similar property for String... The main issue here is that strings are immutable in JavaScript; you cannot change a string in place. Because of that, it's impossible to define a rev method that would behave like this: var a = 'abc'; a.rev(); //...