r,datetime,vector,seconds,minute

From help("difftime") If units = "auto", a suitable set of units is chosen, the largest possible (excluding "weeks") in which all the absolute differences are greater than one. units = "auto" is the default. So for a difference of 1 and 61 seconds, if you were to choose minutes, difftime(c((t+1),...

var t1 = new Date(2015, 05, 25, 2, 0, 0, 0) var t2 = new Date(2015, 05, 20, 5, 0, 0, 0) var diff = t1.getTime() - t2.getTime() var secondsFromT1ToT2 = diff / 1000; var secondsBetweenDates = Math.abs(secondsFromT1ToT2); console.log(secondsBetweenDates) # 421200 ...

java,time,milliseconds,seconds

System.currentTimeMillis() is from January 1, 1970. It will take today's time and subtract it from midnight January 1, 1970. That is why it is so many seconds.

I think it will vary between devices in any case, so you're better off not using some sort hardcoded delay before switching activities. Better to use a method such as the one described here to see if the camera is available (released by your first activity in your case) before...

java,timestamp,difference,milliseconds,seconds

It sounds like you just need to convert the results into double before the division: // This will work double differenceMillis = currentMillis - oldMillis; double differenceSeconds = differenceMillis / 1000; // This will *not* work double differenceSecondsBroken = (currentMillis - oldMillis) / 1000; In the latter code, the division...

Create a simple function - function seconds_to_days($seconds) { return $seconds/86400; } ...

javascript,math,time,seconds,minute

Use Math.round() for subtracting 6.75 from travelTime. This is will round to the nearest whole number.

python,datetime,time,dry,seconds

Don't return False to indicate an error. False == 0.0 in Python. 0.0 is a valid result for "0:0:0:0.0". You could allow exceptions to propagate instead: def to_sec(timedelta_string, factors=(1, 60, 3600, 86400)): """[[[days:]hours:]minutes:]seconds -> seconds""" return sum(x*y for x, y in zip(map(float, timedelta_string.split(':')[::-1]), factors)) Or if you need to suppress...