c#,arrays,string,split,ienumerable
You have to use ToArray() method: string[] result = "bobjoecat".SplitBy(3).ToArray(); // [bob, joe, cat] You can implicitly convert Array to IEnumerable but cannot do it vice versa. ...
python,string,split,integer,type-conversion
The invalid syntax comes from - self.input.value1=(int)word In python, the casting is not the same as in C/C++/Java , instead of using (datetype)variable you have to use datatype(variable) , though that is only for primitive datatypes. For other datatypes, you do not need casting, as python is a dynamically typed...
Here's Java-8 solution: static void getResponse(String input, int level) { Stream.iterate(input, str -> { int pos = str.lastIndexOf('.'); return pos == -1 ? "" : str.substring(0, pos); }).limit(level+1).forEach(System.out::println); } If you know for sure that level does not exceed the number of dots, you can omit the check: static void...
First you have unnecessary escaping inside your character class. Your regex is same as: String pattern = "[(?=)]"; Now, you are getting an empty result because ( is the very first character in the string and split at 0th position will indeed cause an empty string. To avoid that result...
How about first split by [ and then split by ] String str = "[#FF0000]red[#0000FF]blue"; String[] ss = str.split("\\["); String[] sRe = Arrays.copyOfRange(ss, 1, ss.length); for (String s : sRe) { System.out.println(s.split("\\]")[0]); System.out.println(s.split("\\]")[1]); } ...
Is this what you are looking for? full_seq <- 1:100 mysize <- 10 myjump <- 4 myseq <- seq(from=1, to=length(full_seq), by=myjump+mysize-1) full_splitted2 <- c() for (i in myseq) { if ((i+mysize-1) <= length(full_seq)) { full_splitted2 <- c(full_splitted2, full_seq[i:(i+mysize-1)]) } } full_splitted2 <- matrix(full_splitted2, ncol=mysize, byrow=TRUE) full_splitted2: [1,] 1 2 3...
json,mongodb,split,tree,talend
For those who are interrested, I solved this issue by creating my own MongoDBOuput in a tJavaRow. In this way, I am more able to control the creation of my JSON schema. For example (in a tJavaRow): /*Get the MongoDB connection*/ DB db = (DB)globalMap.get("db_tMongoDBConnection_1"); /*Get the collection*/ DBCollection coll...
I placed two buttons in the same span and used CSS to align them together. For example: <span class="x-split-button"> <button class="x-button x-button-main"> About Ron</button> <button class="x-button x-button-main">About Cori</button> </span> I have included the codepen so you can see the code and the DEMO...
You need to use word boundaries. string.split("\\b142\\b|\\D+"); OR Do replace and then split. string.replaceAll("\\b142\\b|[\\[\\]]", "").split(","); ...
Round-robin works and is easy: with open('myfile.txt') as infp: files = [open('%d.txt' % i, 'w') for i in range(number_of_files)] for i, line in enumerate(infp): files[i % number_of_files].write(line) for f in files: f.close() ...
Just split according to the below regex. @"\s+|(?<!\s)(?=-)" DEMO ie, string[] split = Regex.Split(input_str, @"\s+|(?<!\s)(?=-)"); ...
split,floating-point,floating-accuracy
(using double-precision for the examples) I was wondering if it is possible to split somehow x = (I-1.0) + (f + 1.0), namely without floating point rounding error. There is no chance of obtaining such a split for all values. Take 0x1.0p-60, the integral part of which is 0.0 and...
The usual approach for collecting contiguous chunks is to use itertools.groupby, for example: >>> from itertools import groupby >>> blist = ['item1', 'item2', 'item3', '/', 'item4', 'item5', 'item6', '/'] >>> chunks = (list(g) for k,g in groupby(blist, key=lambda x: x != '/') if k) >>> for chunk in chunks: ......
This is a fairly interesting question and something I have seen variations of before. I went ahead and wrote up a general solution for it since it seems like a useful bit of code to keep for myself. There are pretty much only two assumptions I make about the data:...
You can use python's built-in csv module to do this. j = next(csv.reader([string])); Now j is each item delimited by a , and will include commas if the value is wrapped in ". See j[2]....
txtReader.ReadLine(); strips your newline away. From the msdn: The string that is returned does not contain the terminating carriage return or line feed. so you have to add it manually (or just add a space) textLine = textLine + txtReader.ReadLine() + " "; consider using the StringBuilder class for repeated...
r,table,count,split,categories
All consecutive pairs can be represented by two parallel vectors, omitting the last or the first observation x <- V[-length(V)] y <- V[-1] and then cross-tabulating these > xtabs(~ x + y) y x -1 1 -1 7 1 1 0 1 or in slightly different form > as.data.frame(xtabs(~x+y)) x...
There are more than enough splitting answers already, so here is another approach. If your input represents a tree structure, why not parse it to a tree? The following code was automatically translated from VB.NET, but it should work as far as I tested it. using System; using System.Collections.Generic; using...
I would use conditional aggregation with the modulo function: select max(case when seq % 4 = 1 then part_no end) as part_no_a, max(case when seq % 4 = 2 then part_no end) as part_no_b, max(case when seq % 4 = 3 then part_no end) as part_no_c, max(case when seq %...
Kindly find the solution to the problem below along with basic explanation about SPLIT operator: The SPLIT operator is used to break a relation into two new relations. So you need to take care of both conditions , like IF and ELSE: For instance: IF(Something matches) then make Relation1, IF(NOT(something...
You can use a list comprehension to do both splits at once and return a list of lists: >>> a = '{1;5}{2;7}{3;9}{4;8}' >>> [item.split(';') for item in a[1:-1].split('}{')] [['1', '5'], ['2', '7'], ['3', '9'], ['4', '8']] ...
I'm not exactly sure how you want to name your "split" keys, but a generator function should be an easy way to achieve what you want. Look at this example, keeping in mind that the names of the keys are wrong. def gen(d): for k, v in d.items(): yield ('H'...
regex,string,split,google-spreadsheet,string-split
This may get a little 'ugly' but see if this works: =ArrayFormula(iferror(REGEXEXTRACT(" "&A1:A,"^"&REPT("\s+[^\s]+",COLUMN(OFFSET(A1,,,1,6))-1)&"\s+([^\s]+)"))) 6 in the offset denotes the (maximum) number of columns/groups that are outputted. as this is an arrayformula, no 'dragging down' is needed. ...
UPDATE After reading your question again, knowing that your Strings are in the format "ZZZ-numbers-Strings" and you want everything after "ZZZ-numbers-" Then you can do a split with a regex pattern of "ZZZ-\d+-". This will result in a 2-element array and you want the results at index 1. public static...
You may have to define your own function.Here is an example I just tested, hope it is helpful to you(BTW: It is not advisable to implement such kind of functions in mysql. Maybe it is better to let the application servers to compute it instead of mysql :)). DELIMITER $$...
Your logic is backwards. (?=...) is a look-ahead group, not a look-behind. This means that s1.split(/(?=[\]\)]),/); matches only if the next character is simultaneously ] or ) and ,, which is impossible. Try this instead: s1.split(/,(?=[\[\(])/); ...
Try library(splitstackshape) cSplit(data, 'B', ',', 'long') Or using base R lst <- setNames(strsplit(as.character(data$B), ','), data$A) stack(lst) Or library(tidyr) unnest(lst,A) ...
python,python-2.7,split,timedelta,python-datetime
You can use totalseconds() from datetime.timedelta In [4]: t = time.strptime('00:01:25','%H:%M:%S') In [5]: datetime.timedelta(hours=t.tm_hour,minutes=t.tm_min,seconds=t.tm_sec).total_seconds() Out[5]: 85.0 For your example: In [14]: t1='00:01:25' In [15]: t2='00:01:10' In [17]: t1 = time.strptime(t1,'%H:%M:%S') In [18]: t2 = time.strptime(t2,'%H:%M:%S') In [22]:...
Something like: line = it.nextLine(); if (line.contains("specific string")) continue; test = StringUtils.split(line,(",")); Why are you using StringUtils to split a line? The String class supports a split(...) method. I suggest you read the String API for basic functionality....
Is this what you are after? import numpy as np Rxx = np.arange(100) epochs = 10 Rxx_mean = [] epoch_Rxx = np.array_split(Rxx,epochs) for i in range(0,epochs): Rxx_mean.append(np.mean(epoch_Rxx[i])) print Rxx_mean ...
In [18]: L = [(55, 22), (66, 33), (77, 44)] In [19]: a,b = zip(*L) In [20]: a Out[20]: (55, 66, 77) In [21]: b Out[21]: (22, 33, 44) ...
Judging by the OPs answer, "var" is a string, like: var <- c("3, 4, 5", "2, 4, 5", "2, 4", "1, 4, 5") If that is the case, you can consider cSplit_e from my "splitstackshape" package: library(splitstackshape) cSplit_e(data.frame(var), "var", ",", mode = "value", drop = TRUE) # var_1 var_2 var_3...
powershell,split,get-childitem
The result of -split is an array. You only want one field not both (which you get when you use $test0. Try $test0[0]. Or use a more appropriate function for this: $shortnom = $_ -replace ".out$","" or (since $_ is an IO.FileInfo object just use its BaseName property): write-host $_.basename...
What you seem to be looking is for each data like "(number,[1 OR X OR 2])" in text map.put(number, value) You can easily do it with Pattern/Matcher. So you need code like Map<String,String> map = new HashMap<>(); Pattern p = Pattern.compile(regex); Matcher m = p.matcher(data); while(m.find()){ map.put(m.group("number"), m.group("value")); } Your...
Use following method to get the selected options as comma-separated text: $('select').multipleSelect('getSelects', 'text'); To get selected option values as comma-separated string: $("select").multipleSelect("getSelects"); Docs: http://wenzhixin.net.cn/p/multiple-select/docs/#methods...
You can just change your macros so that it will accept two parameters: the namespace name and the class name. Something like #define BASICTYPE_TRAITS(namespaceName, className) \ template <> \ struct DDSTraits<namespaceName::className> \ { \ using TypeSupportImpl = namespaceName::className##Impl; \ using TypeSupport_var = namespaceName::className##TypeSupport; \ }; template <typename T> struct BASICTYPE_TRAITS...
I guess that's what you wanted row[1:3] = row[14].split('/') ...
This will work. First let's build the data. values <- paste0("0000000", 1:4) library(data.table) dt <- data.table(val = sample(values, 10, replace = TRUE)) A for loop is enough to define the new columns. for(level_var in dt[, unique(val)]){ dt[, eval(level_var) := ifelse(val == level_var, level_var, 0)] } ...
What this does is split on either " , " or " /" (note the space characters: space comma space and space forward slash). Your regular expression is absolutely fine if that's what you're intending to replace on. Here's a Regexper visualisation: Update There are no spaces in your string...
I am posting this as an answer mainly not to leave the question answered in the case someone stumbles here in the future and since I've managed to reach the desired behaviour, albeit probably not in a very pythonic way, this might be useful as a starting point from someone...
You can try this: var str = "Hello word" var ary = str.split(/(o)/)); //ary = ['hell', 'o' , ' w', 'o','rd']; ...
You forget to include the ",comma before "game" and also you need to remove the extra colon after display_name display_name\":\"([^\"]*)\",\"game\" or \"display_name\":\"([^\"]*)\",\"game\" Now, print the group index 1. DEMO Matcher m = Pattern.compile("\"display_name\":\"([^\"]*)\",\"game\"").matcher(str); while(m.find()) { System.out.println(m.group(1)) } ...
Just giving a non-regex answer for some variety. You could do the following: String[] MySplit(String str) { bool currency = false; char[] chars = str.ToCharArray(); for(int i = 0; i < str.Length(); ++i) { if(chars[i] == '$') currency=true; else if(currency && chars[i] == ',') { chars[i] = '.'; currency =...
Your code is not wrong. It actually works: >>> x1,x2,x3,x4 = 'xyuv' >>> a1, a2, a3, a4 = raw_input("("+x1+", "+x2+") to ("+x3+", "+x4+")").split() (x, y) to (u, v)1 2 3 4 >>> a1 '1' >>> a2 '2' >>> a3 '3' >>> a4 '4' However: the output (a1,a2,a3,a4) are strings. it...
I was able to properly split the values using the following: If i.Value Like "*on Mission*" Then x = Split(i, " ") For y = 0 To UBound(x) i.Offset(0, y + 1).Value = x(y) Next y End If ...
This uses a different approach to yours. I have set the maximum size for each file to be 1000 bytes for testing purposes: import glob import os dname = './gash' # directory name unit_size = 1000 # maximum file size for fname in glob.iglob("%s/*" % dname): with open(fname, 'rb') as...
I would think that split is likely to be the best approach: var segments = currentUser.split(' '); var firstName = segments[0]; var lastName = segments[segments.length - 1]; var middleName = segments.length === 3 ? segments[1] : undefined; Here, firstName and lastName work regardless of the length of the array, or...
my $secs = 0; while ($output =~ /running time\s+(?:(\d+):)?(\d+(?:\.\d+)?)/g) { $secs += $1*60 if $1; $secs += $2; } ...
Try this... Using Enumerable#each_slice to slice array x value array = [12, 13, 14, 18, 17, 19, 30, 23] array.each_slice(3) array.each_slice(3).to_a ...
You can use split split(df1, grepl('PM', df1$StartTime)) If you need to get a data.frame with two columns lst <- split(df1$StartTime, grepl('PM', df1$StartTime)) setNames(data.frame(lapply(lst, `length<-`, max(lengths(lst)))), c('AM', 'PM')) # AM PM #1 10:22 AM 8:37 PM #2 7:10 AM 3:58 PM #3 10:59 AM 2:48 PM #4 <NA> 6:33 PM Or...
How about: ^([A-Z]+(?: [A-Z]+)+) (.*?)$ You'll have the uppercase words in group 1 and the rest in group 2 If you want to deal with any language: ^(\p{Lu}+(?: \p{Lu}+)+) (.*?)$ ...
You can use dplyr for this: df %>% mutate(new.date = cut.Date(as.Date(Date, format = '%Y-%m-%d'), "month")) %>% group_by(new.date) %>% summarise(count = n()) mutate will create a new column with cutted dates, group_by by month and summarise will count the number of entries. Also, if you need year and abbreviation month, just...
ruby-on-rails,ruby,ruby-on-rails-4,split,string-split
Short and readable: name = "Obama Barack Hussein" puts "#{name.partition(" ").first} - #{name.partition(" ").last}" # Obama - Barack Hussein and if the order of the first and lastname is reversed name = "Barack Hussein Obama" puts "#{name.rpartition(" ").last} - #{name.rpartition(" ").first}" # Obama - Barack Hussein ...
Just a straightforward implementation: string workingDirectory = @"c:\"; var days = new[] { "Su", "Mo", "Tu", "We", "Th", "Fr", "Sa" }; var writers = new Dictionary<string, StreamWriter>(); using (StreamReader sr = new StreamReader(workingDirectory + "data.csv")) { string line; while ((line = sr.ReadLine()) != null) { var items = line.Split(new[] {...
javascript,regex,split,string-split
You should use the ability of split to split on regular expressions and then keep them in the results. To do this, simply put a capturing group in the regexp. In your case, you will "split" on things in double quote marks: pieces = test.split(/(".*?")/) ^^^^^^^ CAPTURE GROUP // ["",...
Your function does not return a value so it returns None as all python functions that don't specify a return value do: def whois(k, i): k = str(k[i]) print (k) whois = subprocess.Popen(['whois', k], stdout=subprocess.PIPE, stderr=subprocess.PIPE) ou, err = whois.communicate() who = str(ou) print (who.find('NetName:')) who = re.split('NetName:', who)[1] who...
performance,hadoop,split,mapreduce
dfs.block.size is not alone playing a role and it's recommended not to change because it applies globally to HDFS. Split size in mapreduce is calculated by this formula max(mapred.min.split.size, min(mapred.max.split.size, dfs.block.size)) So you can set these properties in driver class as conf.setLong("mapred.max.split.size", maxSplitSize); conf.setLong("mapred.min.split.size", minSplitSize); Or in Config file...
php,regex,string,split,explode
Try this: $src='word1&word2 !word3 word4 &word5'; $arr=explode(' ',$src=preg_replace('/(?<=[\w])([&!])/',' $1',$src)); echo join('<br>',$arr); // present the result ... First change any occurence of a group consisting of a single character of class [&!] that is preceded by a 'word'-character into ' $1' (=itself, preceded with a blank) and then explode()the string using...
You are most likely looking for sub or gsub, or possibly strsplit--but definitely not split: mydf[] <- lapply(mydf, function(x) { sub("\\|.*$", "", x) }) mydf ## X.V1 X.V2 X.V3 ## 1 toto peper tomato ## 2 toto peper ognion ## 3 toto ginger lemon ...
string,split,prolog,swi-prolog,punctuation
"split_string" is not standard but, in the implementation I know, you can not. From the ECLIPSe manual: The string String is split at the separators, and any padding characters around the resulting sub-strings are removed. Neither the separators nor the padding characters occur in SubStrings. http://www.cs.uni-potsdam.de/wv/lehre/Material/Prolog/Eclipse-Doc/bips/kernel/stratom/split_string-4.html ** Addendum ** We...
java,regex,string,split,compare
You can use java 8 : final String firstString = "B"; final String secondString = "A,B,C,D,E"; if (Arrays.stream(secondString.split(",")).anyMatch(s -> s.equals(firstString))) { // match } This split the String on ",", and transform the result in a stream, then check if one of the values of the stream is equal to...
Probably easiest solution is not searching for place to split, but finding elements which you want to return. In your case these elements starts " ends with " have no " inside. So you try with something like String data = "\"1\",\"10411721\",\"MikeTison\",\"08/11/2009\",\"21/11/2009\",\"2800.00\",\"002934538\",\"051\",\"New York\",\"10411720-002\",\".\\Images\\b.jpg\",\".\\RTF\\b.rtf\""; Pattern p = Pattern.compile("\"([^\"]+)\""); Matcher m =...
java,android,string,list,split
I suggest you to use Pattern and Matcher classes. The below regex will capture the text present inside curly braces and then it would add them to the list variable. String myString = "A=myPage{a1,b1,c1};B=myPage{a2,b2,c2};C=myPage{a3,b3,c3};"; List<String> list = new ArrayList<String>(); Matcher m = Pattern.compile("\\{([^{}]*)\\}").matcher(myString); while(m.find()) { list.add(m.group(1)); } System.out.println(list); ...
split,google-spreadsheet,string-split
There are many way to do so. One is to split on spaces and discard what is not required. Another is with a formula such as conventional in Excel (count the spaces by comparing the length of the string in full and after substituting spaces with nothing) and feed that...
excel,vba,excel-vba,text,split
So test that : Sub SplitValues() Dim aSplit As Variant With ActiveSheet For I = 2 To Cells(.Rows.Count, "D").End(xlUp).Row aSplit = Split(Cells(I, "D"), " ", 2) 'Write in D and E columns (erase data already in D) Cells(I, "D") = aSplit(0) Cells(I, "E") = aSplit(1) 'Write in E and F...
The extra whitespace is a newline. Each row except the last technically contains all of the text contents you see, plus a newline. You can easily get rid of it by e.g. $string = rtrim(fgets($handle)); Also, fgets($fp); makes no sense since there's no variable $fp, should be fgets($handle); given your...
c#,visual-studio-2010,visual-studio,visual-studio-2012,split
You should show us what code you already have, then ask how to approach the part that you cannot solve. I suggest you to store a list of headers, and a list or dictionary of rows. This way you could check if a header already exists. For example: using System;...
The answer by CapelliC is perfect. Just to explain: When you have a Prolog clause like this: foo([H|T], [H|Z]) :- foo(T, Z). which you then call like this: ?- foo([a,b,c], L). from: foo([H| T ], [H|Z]) with H = a, T = [b,c], L = [a|Z] call: foo([a|[b,c]], [a|Z]) which...
You found a bug! System.out.println(s.split("abc82")); // [abc, 8] System.out.println(s.split("abc8")); // [abc] This is the method that Splitter uses to actually split Strings (Splitter.SplittingIterator::computeNext): @Override protected String computeNext() { /* * The returned string will be from the end of the last match to the * beginning of the next one....
You can use Regex for this. import re s = 'this1234is5678it' re.split('(\d+)',s) Running example http://ideone.com/JsSScE Outputs ['this', '1234', 'is', '5678', 'it'] Update Steve Rumbalski mentioned in the comment the importance of the parenthesis in the regex. He quotes from the documentation: If capturing parentheses are used in pattern, then the...
Since DEL is your shell variable, you should be using something like: info1=$(echo $STR | awk -v delimeter="$DEL" '{split($0,a,delimeter)} END{print a[1]}') ...
I would like to split on any number of consecutive spaces, tabs, and commas. You could use re.split() to split by a regular expression. >>> import re >>> s = '0 0 .1 .05 .05 0. 0. .01' >>> re.split(r'[\s,]+', s) ['0', '0', '.1', '.05', '.05', '0.', '0.', '.01']...
php,regex,split,html-parsing,explode
You are in the right path. You have to set the flag PREG_SPLIT_DELIM_CAPTURE in this way: $array = preg_split('/(<img .*>)/i', $string, -1, PREG_SPLIT_DELIM_CAPTURE); With multiple tag edited properly the regex: $string = 'Text <img src="hello.png" > hello <img src="bye.png" /> other text.'; $array = preg_split('/(<img[^>]+\>)/i', $string, -1, PREG_SPLIT_DELIM_CAPTURE); This will...
excel,vba,excel-vba,split,substring
If you one use Split function, you will love it -> https://msdn.microsoft.com/en-us/library/6x627e5f%28v=vs.90%29.aspx Look for this example: Sub TestSplit() Dim String1 As String Dim Arr1 As Variant String1 = "TL-18273982; 10MM" Arr1 = Split(String1, ";") Debug.Print "TEST1: String1=" & String1 Debug.Print "TEST1: Arr1(0)=" & Arr1(0) Debug.Print "TEST1: Arr1(1)=" & Arr1(1) String1...
You can use array_chunk() Documentation: http://php.net/manual/en/function.array-chunk.php It will split an array into a multi-demential array of "chunks." For you, you want every chunk to be 1 variable in size. $Alphabet = array('a','b','c','d'); $Chunked = array_chunk($Alphabet, 1); // Chunk the Alphabet array in 1 size chunks print_r($Chunked); This will produce: Array...
Could not figure out a regex solution, but here's a non-regex solution. It involves parsing numbers (not in curly braces) before each comma (unless its the last number in the string) and parsing strings (in curly braces) until the closing curly brace of the group is found. If regex solution...
Just add the other cases as extra possiblities using |: $tests = array('FooBar', 'fooBar', 'Foobar', 'FooBar1', 'FooBAR', 'FooBARBaz', '1fooBar', '1FooBar', 'FOOBar'); foreach($tests as $test){ echo $test . " => " . split_camel_case($test) . "<br />"; } function split_camel_case($root){ return implode(' ', preg_split('/(?<=[a-z])(?![a-z])|(?<=[0-9])(?![0-9])|(?<=[A-Z])(?=[A-Z][a-z])/', $root, -1, PREG_SPLIT_NO_EMPTY)); } ...
This ought to do it: String string = "N,591;F\"Vendor Number\",86;F\"Vendor Name\",143;F\"Claim Number\",82;"; String[] s = string.split("\""); System.out.println(s[1]); System.out.println(s[3]); System.out.println(s[5]); Output: Vendor Number Vendor Name Claim Number If the number of column labels is not known, choose every alternate index....
undefined method split' for nil:NilClass` The error is because the life of last variable has ended in the if-else loop and you are trying to access last outside the if-else loop in this line number = last.split('-')[1].to_i. You need to tweak your code like this def generate_asset_number company =...
If you want to work with files instead of strings in memory, here is another answer. This version is written as a function that reads lines and immediately prints them out until the specified number of delimiters have been found (no extra memory needed to store the entire string). def...
c#,asp.net,string,split,string-split
string [] arr = input.Replace("T23:00:00.000Z","").Split(new string[] {","},StringSplitOptions.None); ...
regex,powershell,replace,split
Leveraging the power in PowerShell we can turn the output of pnputil into an object array that will make it much easier to parse the data you are looking for (since it appears you are looking for something specific). Each entry is a group of variables with a blank line...
Using tr actually was easier, as show in e.g. this question. Here's the command echo $PATH | tr ':' '\n' ...
One way to achieve the task, i.e. to split a page at a certain point (i.e. all content above a limit to be included and everything below to be excluded) would be to prepend a clip path. You can use this method: void clipPage(PDDocument document, PDPage page, BoundingBox clipBox) throws...
Change your code a little to use positive lookbehind. String[] stringArray = string.split("(?<=</xml>)"); O/P : <xml attributes>some xml code</xml> <xml attributes>some xml code</xml> <xml attributes>some xml code</xml> <xml attributes>some xml code</xml> ...
regex,r,split,tm,text-analysis
You can use strsplit to split your document , then recreate the corpus again : Corpus(VectorSource( strsplit(as.character(documents[[1]]), ## coerce to character "I want to split after this line!!!", fixed=TRUE)[[1]])) ## use fixed=T since you have special ## characters in your separator To test this , we should first create a...
Just pass the count as second parameter inside the split function. >>> s = "238 NEO Sports" >>> s.split(" ", 1) ['238', 'NEO Sports'] ...
arrays,string,scala,split,scala-collections
Use split with -1 argument. string.split(",",-1) This behavior comes from Java (since Scala uses Java Strings). Here is the documentation directly out of Javadoc. ...
One method is to export the data and use another tool. If the strings are not too long, you can do something like this: create table common_name_frog as select f.id, substring_index(substring_index(common_name, ', ', n.n), ', ', -1) as Common_name from (select 1 as n union all select 2 union all...
You're pretty much there already! A few more lines after new = row[4].split(",") are all you need. for i in range(len(new), 4): new.append('') newrow = row[0:4] + new + row[5:] print('|'.join(newrow)) Edit 2: addressing your comments below in the simplest way possible, just loop through it twice, looking for the...
You can use the re.split function with the re.IGNORECASE flag (or re.I for short): >>> import re >>> test = "hI MY NAME iS FoO bar" >>> re.split("foo", test, flags=re.IGNORECASE) ['hI MY NAME iS ', ' bar'] >>> ...
I'm not sure the accepted answer will generally do what you show on your graphs. I certainly can't get it to produce the correct answer! Generally you will always get alternating maxima and minima with edge cases of none of one or both. You need to look at all the...
you can use Split and SelectMany var result = Array.SelectMany(x => x.Split(new[] { '(', ')' }, StringSplitOptions.RemoveEmptyEntries)).ToArray(); ...