Copying edges BOOST graph c++
c++,boost,graph,subgraph,isomorphism
You've falling victim to the most vexing parse: Graph testg(); declares a function. Don't feel bad. It took me a while to see this. o.O Just write Graph testg; or if you want something that almost always does what you mean: Graph testg {}; Do feel bad about using namespace...
Spanning tree of directed graph with networkx
python,graph,networkx,minimum-spanning-tree,subgraph
You can get the edges in G that appear in the MST T with a simple comprehension: E = set(T.edges()) # optimization [e for e in G.edges() if e in E or reversed(e) in E] You can then build a new graph from this....
Graphviz render nodes in subgraph, why?
It looks like the following works: digraph { a; subgraph cluster_mysubgraph { b; } a->b; } So, there might be some rule like: "declare nodes in subgraph, beware of declaring edge in subgraphs because that tends to make nodes to be attached to that subgraph (unless they are already attached...
using property maps for equivalence in vf2_sub_graph_iso
c++,boost,subgraph,equivalence,isomorphism
Ok, let's dissect the documentation. In order to pass non-default implementations for EdgeEquivalencePredicate and VertexEquivalencePredicate you need the second overload: bool vf2_subgraph_iso(const GraphSmall& graph_small, const GraphLarge& graph_large, SubGraphIsoMapCallback user_callback, const VertexOrderSmall& vertex_order_small, const bgl_named_params<Param, Tag, Rest>& params) This means you need at least a parameter to match vertex_order_small and params....
Graphviz: arranging clusters left-to-right with contents top-to-bottom
In this case rankdir=LR is working better as the horizontal columns are more important and ranking is the only ordering mechanism. Oordering orthogonally to rank may be achieved by the order of appearence and is difficult for complex graphs especially with clusters. digraph { rankdir=LR; nodesep=0.5; edge [ constraint=false ];...
Any library or proposed solution for subgraph (path) matching within a graph?
java,graph,pattern-matching,subgraph
The Levenshtein distance measures the difference between two sequences by counting the number of single-element editions needed to change one sequence into the other. If you store the vertex sequence of each path in a list or array you can calculate the distance using the following implementation (assuming you have...
Neo4J: find a sub-graph of arbitrary depth with nodes connected by a given set of relations?
This query will return just the nodes, as you stated in your question: MATCH (n)-[:FRIEND_OF|COLLEAGUE_WITH*]->(m) RETURN n, m; If you also want the relationships: MATCH (n)-[r:FRIEND_OF|COLLEAGUE_WITH*]->(m) RETURN n, r, m; ...
Graphviz edges not discernible / edge labels overwritten
graphviz,overlap,rank,dot,subgraph
Answers from both ssteve and emden were very useful and have been upvoted. (thank you both!) I am incorporating input from both and answering this question in its more complex version. I still do not feel like the solution is perfect, but it is the best I can generate so...
Error with subgraph in igraph package
If you pass a number as a vertex id to the induced.subgraph function, it will be accessing the vertices by number (in your graph numbers 1 through 23), leading to the "Invalid vertex ID" error due to indices like 26, 29, and 30. You want to actually refer to vertices...
Hungarian algorithm in PHP with multiple assignments
php,algorithm,assign,subgraph,pairing-heap
So I finally found a valid way to achieve what was described in before. The solution: We make a column for each slot that is possibly given away. A cours has a amount of slots. We should have a number of columns, which is the sum of each amount of...
subgraph and graph connectivity in boost
c++,boost,graph,connectivity,subgraph
well, here is two examples: test if graph g1 is a subgraph of g2 (by giving g1 and g2 as a function parameter): #include <boost/graph/adjacency_list.hpp> #include <boost/graph/vf2_sub_graph_iso.hpp> using namespace std; using namespace boost; struct my_callback { template <typename CorrespondenceMap1To2, typename CorrespondenceMap2To1> bool operator()(CorrespondenceMap1To2 f, CorrespondenceMap2To1 g) const { return false;...