binary,overflow,addition,twos-complement,underflow

It seems like whenever you have 3 carries in a row, it drops a 1. Same with the next one, 15 + 7. It isn't doing the carry correctly. 11 <- carry 0011 = 3 +0111 = 7 1010 = 10 ...

algorithm,bit-manipulation,formula,twos-complement,ones-complement

you cannot calculate any formula with numbers in 2 different bases, you have to use their decimal representation (or an other representation you can handle) I'll give it a try in dec: 1042 (base 5) = 1* 5^3 + 4* 5^1 + 2 = 125 + 20 + 2 =...

binary,overflow,twos-complement,complement

Short answer: if you are performing arithmetic on fixed-width binary numbers, using two's complement representation for negative numbers, then yes, you ignore the one-bit overflow. Long Answer: You can consider each ith bit in n-bit two's complement notation have place value 2^i, for 0 <= i < n - 1,...

1000 0000 0000 0000 (binary) = -2^15 is the lowest you can get :)...

javascript,bitwise-operators,twos-complement,ones-complement

Note - I don't think this is the problem, but it's a problem. You've left off a set of { } else { document.getElementById("binary").innerHTML = aNumber.toString(2); document.getElementById("ones").innerHTML = (~aNumber).toString(2); document.getElementById("twos").innerHTML = (-aNumber).toString(2); } Without those, the second two lines were outside the scope of influence of the if else statement,...

java,binary,byte,twos-complement

(-128 + 0x100) = (256 - 128) = 128 = 0b10000000 Integer.toBinaryString(0b10000000) = "10000000" "10000000".substring(1) = "0000000" ...

I'm assuming we're dealing with 8-bit registers here. Both numbers you mentioned can be encoded by the bitvector 10010110. When you read it as an unsigned number, it means 150. When you read it as a two's complement signed number, it means -106. Does a number, if within a certain...

You can't. Those interpretation schemes are not encoded themselves in the data. Machine don't usually implement two kinds of integer representation on hardware level thoug, so you can safely assume the number is being represented the same way all other integers in the context are. ...in the case it's some...

To summarize, you want IsClassEAddress(InetAddress address) to return true if the address is between 240.0.0.0 and 255.255.255.254 inclusive. This takes 2 lines of code: public static Boolean IsClassEAddress(InetAddress address) { int curAddr = GetIntInetAddress(address); return ((curAddr & 0xF0000000) == 0xF0000000) && (curAddr != 0xFFFFFFFF); } ...

c++,c,arrays,twos-complement,memset

Oddly, the reason this works with -1 is exactly the same as the reason that this works with zeros: in two's complement binary representation, -1 has 1s in all its bits, regardless of the size of the integer, so filling in a region with bytes filled with all 1s produces...

python,floating-point,sensor,twos-complement,texas-instruments

On disk and in memory integers are stored to a certain bit-width. Modern Python's ints allows us to ignore most of that detail because they can magically expand to whatever size is necessary, but sometimes when we get values from disk or other systems we have to think about how...

binary,overflow,addition,signed,twos-complement

Overflow occurs only when correct answer cannot be interpreted using given number of bits.An extra bit is required to interpret the answer right.Consider the following example of byte numbers addition: +70 in binary 01000110 +80 in binary 01010000 On addition :10010110 1 in the MSB(most significant bit) indicates that answer...

java,binary,bit-manipulation,twos-complement,sign-extension

Using a bit mask is the standard solution to disable sign extension when converting a byte to an int. You'll just have to accept this slice of Java ugliness. int result = 0 | (b & 0xFF); ...

break down the problem -- 1. how to print the bit, and 2. how to determine the bit's value You already know how to determine the bit's value, you test bit 15 and keep shifting the other bits into position 15. How are you expected to "prompt the user" to...