3 parameter Weibull fit in .NET
c#,.net,statistics,distribution,weibull
You don't necessarily need a 3-parameter Weibull. Your non-failing data is called right-censored and requires survival analysis. A straightforward maximum likelihood approach should work here using just a 2-parameter Weibull model.
R: unexpected behavior of the fdwm() function (evmix package)
r,distribution,modeling,mixture-model,weibull
This error message is entirely as expected. When you run this program it provides a followup warning message: "numerical integration failed, ignore previous messages, optimisation will try again" which implies you can simply ignore this error from the "integrate" function. Why is this normal? Well that explanation needs some background...
Fit distribution to given frequency values in R
r,distribution,estimation,probability-density,weibull
Here is a better attempt, like before it uses optim to find the best value constrained to a set of values in a box (defined by the lower and upper vectors in the optim call). Notice it scales x and y as part of the optimization in addition to...
Fiting Weibull using R2OpenBUGS
R parameterizes the Weibull using shape (=2 in your case) and scale (=10) by default: BUGS uses shape and lambda, where lambda=(1/scale)^shape. So you should expect lambda to be approximately (1/10)^2=0.01, which is close to your median of 0.0093. This question on CrossValidated, and this paper in the R Journal,...