matlab,logarithm,wolframalpha,natural-logarithm

Another option is based on the simpler Wright ω function: a = b - x.*wrightOmega(log(-(c-d)./x) - (c-d)./x); provided that d ~= c + x.*wrightOmega(log(-(c-d)./x) - (c-d)./x) (i.e., d ~= c+b-a, x is 0/0 in this case). This is equivalent to the principal branch of the Lambert W function, W0, which...

algorithm,matrix,eigenvector,wolframalpha

Eigenvectors of a matrix are not unique, and there are multiple possible decompositions; in fact, only eigenspaces can be defined uniquely. Both results that you are receiving are valid. You can easily see that by asking Wolfram Alpha to orthogonalize the second matrix. Run the following query: Orthogonalize[{{1.13168, 0.969831, 1.},...

python,python-2.7,math,wolframalpha

In Python 2.x, int / int returns a int. (truncate number below decimal point) >>> 18111/2 9055 To get the number you want, you need to use float. >>> 18111/2.0 9055.5 Or, you can change the behavior using from __future__ import ... statement: >>> from __future__ import division >>> 18111...

The reason is that Matlab uses double floating-point arithmetic by default. A number as large as 688^79 can't be represented accurately as a double. (The largest integer than can be accurately represented as a double is of the order of 2^53). To obtain the right result you can use symbolic...

python,statistics,median,percentile,wolframalpha

You have 7 numbers which you are attempting to split into quartiles. Because 7 is not divisible by 4 there are a couple of different ways to do this as mentioned here. Your way is the first given by that link, wolfram alpha seems to be using the third. Numpy...

wolfram-mathematica,wolframalpha,wolfram-language

After the usual lots of trial and error that WolframAlpha didn't understand, finally WolframAlpha PrimeOmegaPlot link...

javascript,jquery,xml,api,wolframalpha

so this is suffering from a security mechanism called Cross Origin Scripting. The issue here is that the service you are calling from has not given permission for you to call that resource in an ajax call. To read more look at http://en.wikipedia.org/wiki/Cross-origin_resource_sharing To prove this is happening look at...

WA is correct. In the imaginary component, which is arg(z), there should be a jump from pi to 0 at z=0. The real component is log(|z|). Guess into the blue: Be sure to use arctan2 when computing angles....

wolfram-mathematica,limit,wolframalpha

Limits of a function f along path p depends on which path is taken. You hint at this in the question. If we insert y=x^3 into f, we get the constant 1/2. So the limit of f towards (0,0) along the path y=x^3 is 1/2. Mathematica only computes limits along...