The above two values are not equal because they are of different types. Let's say I have this table: | Name | Age | | John | 22 | | Phil | 25 | Now I want to read the cell (2,1). >>> cell1 = sheet.cell(1,0) >>> print cell1 text:u'John'...
python,html,django,export-to-excel,xlrd
Try using xlwt, it worked for me, i also faced the same problem. By using this u need not to have any html template, python itself will convert ur integer into string and write the resulting into excel sheet. Follow this link. http://djangotricks.blogspot.in/2013/12/how-to-export-data-as-excel.html
First, in Excel the values were listed as text, not as numbers. I changed that first and got rid of all values in the file that were not numbers. Then I split at the colon and reassigned the values as floats.
Per the documentation, xlrd supports only seven types of cell value (Cell.ctype), including XL_CELL_NUMBER 2 (float) There is no separate ctype for integers. All numerical types (including dates, which are ctype == xlrd.XL_CELL_DATE) from Excel will be represented as float objects in Python. You can check if they are equal...
Try split the value first: # Create CBSA list CBSAlist = [] for value in sheet.col(1): CBSAlist.append(float(str(value).split(":")[1])) print CBSAlist Result [1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0, 11.0] ...
I think your problem is not accounting for the zero-based index. last_row = curr_sheet.nrows returns the number of rows in the worksheet, so accessing the last row requires: skip_val = curr_sheet.cell_value(last_row-1, 1) The first element in Python is indexed by 0, so the first element of a list mylist would...
You could groupby on Column1 and then take Column3 to apply(list) and call to_dict? In [81]: df.groupby('Column1')['Column3'].apply(list).to_dict() Out[81]: {0: [1], 1: [2, 3, 5], 2: [1, 2], 3: [4, 5], 4: [1], 5: [1, 2, 3]} ...
python,excel,python-2.7,xlrd,xlwt
I don't think it's possible with xlwt only. Use xlrd (Sheet.nrows) or xlutils. Example from xlutils docs: >>> from xlutils.tests.fixtures import make_sheet >>> sheet = make_sheet(( ... ('X',' ',' ',' ',' '), ... (' ',' ',' ','X',' '), ... (' ',' ',' ',' ',' '), ... ('X',' ',' ',' ','...
A set is going to give you an unordered collection of unique values. If you have duplicate cells in your spreadsheet, only the first one will be added to the set, the rest will be discarded. Based on your comments, it sounds like you're just doing some debugging, but if...
python-2.7,maya,xlrd,xlwt,pymel
Figured it out on my own. If you are opening an excel doc to read from and save over while utilizing os, xlrd, xlwt and xlutils... You must follow these instructions (which probably could have been solved by someone who knew less than me ;) ). import all the important,...
python,excel,python-requests,xlrd
Your problem isn't with reading the Excel file, but with parsing the content out of it. Notice that your error was thrown from the Requests library? requests.exceptions.InvalidSchema: No connection adapters were found for <url> From the error we learn that the URL you take from each cell in your Excel...
You can try to open workbook but in try/except block to catch XLRDError exception in case if file format not supported: >>> from xlrd import open_workbook, XLRDError >>> try: ... book = open_workbook('test.txt') ... except XLRDError as e: ... print e ... Unsupported format, or corrupt file: Expected BOF record;...
python,excel,while-loop,xlrd,xlwt
Ok, I found the answer: elif answer =="empty": while i<=(sh.nrows-1): cell_type = sh.cell_type(i,0) cell_x=sh.cell_value(i,0) new_cell=[] . . db1.write(i,0,new_cell) i+=1 I'm still not exactly sure why my previous answers were wrong but I sucked it up and used the same format as the "rows" loop. I think this code actually removes...
python,encoding,xlrd,import-from-excel
What are they using to generate that file ? They are using some Java Excel API (see below, link here), probably on an IBM mainframe or similar. From the stack trace the writeaccess information can't decoding into Unicode because the @ character. For more information on the writeaccess information of...
You are trying to convert an object row, which is a list of xlrd.sheet.Cell elements to a numpy array straight away. That won't work the way you want it to. You'll have to do this the long way and go over each of the columns too: while curr_row < num_rows:...
Looks like xlrd.open_workbook() accepts file_contents argument as well, so maybe as follows? xlrd.open_workbook(file_contents=cstringio_var.getvalue()) ...
df['file'] = 'abc.xlsx' df['group'] = 'first' ...
python,google-app-engine,python-2.7,google-cloud-storage,xlrd
I should read the documentation with more attention before asking stuff... To provide xlrd with an open file, instead of a filename, I have to give a filecontent. This is done by: archivo=cloudstorage.open('/bucket/workbook.xlsx') wb = xlrd.open_workbook(file_contents=archivo.read()) ...
If you're not dealing with large Excel worksheets, or any problematic data types (such as one described in the section Dates in Excel spreadsheets), you can simplify reading all rows into a single list, pop the header values for the insert columns, then call Cursor.executemany once to insert all values...
I just tried this and it seems to work for your sample data: all_data = [] excel = xlrd.open_workbook(excel_dir+ excel_file) sheet_0 = excel.sheet_by_index(0) # Open the first tab prev_row = [None for i in range(sheet_0.ncols)] for row_index in range(sheet_0.nrows): row= [] for col_index in range(sheet_0.ncols): value = sheet_0.cell(rowx=row_index,colx=col_index).value if len(value)...
xlwt.write accept style informations as its third argument. Unfortunately, xlrd and xlwt use two very different XF object format. So you cannot directly copy the cell's style from the workbook read by xlrd to the workbook created by xlwt. The workaround is the use an xlutils.XLWTWriter to copy the file,...
python,python-3.x,typeerror,urllib,xlrd
xlrd.open_workbook() can only open excel files. However, the xlfile object created by xlfile = urlopen(DJIA_URL).read() is not an excel file, so xlbook = xlrd.open_workbook(xlfile) won't open. xlfile created by the above way was an object of class "bytes". The fact can be seen by the command print(type(xlfile)) and that should...
python,python-2.7,excel-2010,xlrd,openpyxl
One thing is clear: The file you're trying to open has a different format than its extension suggests. As you already know, Excel file formats include (but are not limited to) xls and xlsx. The Excel 2003 format (xls) is a binary format. This means that if you open a...
Yes, it's absolutely possible. That is indeed a lot of data to be in an Excel file. By default, xlrd loads the entire workbook into memory. If your workbook is a .xls file, you can use the on_demand parameter to only open worksheets as they are needed: import xlrd def...
xlrd's observed behavior reminds me of python's slicing notation, which is like this: +---+---+---+---+---+ | H | e | l | p | A | +---+---+---+---+---+ 0 1 2 3 4 5 -5 -4 -3 -2 -1 (given a string of "HelpA" -- that's from the official docs) So, if...
If you know the specific color index of the cells with yellow background, you can check the background.pattern_colour_index value of the cell style. Note that it is important to pass formatting_info=True to the open_workbook(): import xlrd file_location = "/home/myuser/excel.xls" workbook = xlrd.open_workbook(file_location, formatting_info=True) sheet = workbook.sheet_by_index(0) for row in range(sheet.nrows):...
Assuming that each source file has only one sheet: import xlwt as xlwt from os.path import join import xlrd output = xlwt.Workbook() path = r'C:\data_path\\' xls1 = 'file1.xls' xls2 = 'file2.xls' xls3 = 'file3.xls' Sheet1 = 'file1_data' Sheet2 = 'file2_data' Sheet3 = 'file3_data' names = [Sheet1, Sheet2, Sheet3] dataset =...
The issue is that even if you change the loop variable j inside the loop, that change would be overwritten with the next value from range() function. An example to show this - >>> for i in range(10): ... print(i) ... i = 1000 ... 0 1 2 3 4...
To avoid conflicts between parallel Python 2 and Python 3 installations, only the versioned pip3 and pip3.4 commands are bootstrapped by default You can try sudo pip3 install xlrd or sudo pip3.4 install xlrd to use the Python 3.4, see docs here https://docs.python.org/3/whatsnew/3.4.html#bootstrapping-pip-by-default...
excel,python-2.7,ms-access,xlrd,comtypes
A parameterized query allows parameters to be substituted for the values of a column, but not for table and column names themselves. You will need to use string formatting for that, as in db.Execute("ALTER TABLE MY_TABLE ADD COLUMN [{0}] TEXT(50)".format(cell_value)) ...
The idea is to, first, read the header into the list. Then, iterate over the sheet rows (starting from the next after the header), create new dictionary based on header keys and appropriate cell values and append it to the list of dictionaries: from xlrd import open_workbook book = open_workbook('forum.xlsx')...
python,excel,formatting,xlrd,openpyxl
Since you said you are used to working in Bash, I'm assuming you're using some kind of Unix/Linux, so here's something that will work on Linux. Before pasting the code, I'd like to point a few things: Working with Excel in Unix (and Python) is not that straightforward. For instance,...
python,excel,many-to-many,relationship,xlrd
t = [ ["a1","a2"], ["a1","a3"], ["a1","ax"], ["ax","b1"], ["ax","bx"], ["bx","b3"] ] import itertools def find_matches(t,key): return list(itertools.chain(*[[v] if not v.endswith("x") else find_matches(t,v) for k,v in t if k == key])) print find_matches(t,"a1") you could treat your list as an adjacency matrix of a graph something like t = [ ["a1","a2"], ["a1","a3"],...
You are only initializing data OrderedDict once outside all the loops, and inside it seems like you keep changing the values for the same keys again and again , this would keep changing the same OrderedDict object, and at end you are append the same OrderedDict object into data_list. You...
xlrd will load your worksheet file into memory at the time you call the open_workbook() method. Any changes made to the worksheet file after you call open_workbook() are not automatically reflected in the object in memory. If you take a look at the xlrd source code on Github, in particular...
As Mathias said, the str() cast is failing because it's trying to decode in ascii a unicode string u'\u2211' whereas it should use for instance 'utf-8'. Since s.cell(row, column) returns a float, an int or some unicode string, you'd better to either don't change the format or convert everything in...
You can read the entire file into memory using: data = urllib2.urlopen(url).read() Once the file is in memory, you can load it into xlrd using the file_contents argument of open_workbook: wb = xlrd.open_workbook(url, file_contents=data) Pass the url in as the filename as the documentation states it might be used in...
If I understand correctly, you want to take a multi-row XLS and output that as a single-row CSV. If so, this is causing you to output multiple CSV rows: for rownum in xrange(sh1.nrows): wr.writerow(sh1.row_values(rownum)) That code steps through each row in your XLS and creates a corresponding row in your...
I run your program on Ubuntu/Linux and it runs fine. I will recommend to follow my instructions for installing the xlrd on your Windows machine. From here download the latest version of the xlrd. Then extract the file, and using the command prompt in the new xlrd directory type: python3...
I have modified the code I gave as a question and have got what I needed actually, def getSheetName(file_name): pointSheetObj = [] import xlrd as xl TeamPointWorkbook = xl.open_workbook(file_name) pointSheets = TeamPointWorkbook.sheet_names() for i in pointSheets: pointSheetObj.append(tuple((TeamPointWorkbook.sheet_by_name(i),i))) so if the list (of tuple) pointSheetObj is iterated we have name of...
np.array(list_for_hist) converts all items in list_for_hist to a common dtype. When list_for_hist contains both floats and strings, np.array returns an array containing all strings: In [32]: np.array(list_for_hist) Out[32]: array(['8.0', '19.0', '4.0', '4.0', '8.0', '3.0', '13.0', '', '10.0', '7.0', '17.0', '16.0', '8.0', '6.0', '13.0', '8.0', '7.0', '11.0', '12.0', '13.0', '4.0', '6.0',...
The answer is very basic "because there is no such syntax in python" if "%s" in X: foo() simply means "do foo() if the string '%s' is an element of collection X". So if X = [ '%s', 'koala', 100 ] then it will be true, but it has nothing...