Serialize/Deserialize class containing byte array property into XML
c#,.net,xml,serialization,.net-4.0
As you've noticed, there are lots of characters that may not be present in an XML document. These can be included in your data, however, using the proper escape sequence. The default settings of the XmlTextReader cause it to mishandle this -- I think it interprets the escape sequences prematurely,...
XElement.Value is stripping XML tags from content
c#,.net,xml,xml-parsing,xelement
As others have said, this format is truly horrible, and will break as soon as the XML embedded in the JSON will contain double quotes (because in the JSON they will be encoded as \", which will make the XML invalid). The JSON should really be embedded as CDATA. Now,...
Error when building an XDocument
You can ignore pretty much all your code, the issue is just this: XDocument people = new XDocument("Persons"); You can't create an XDocument containing a string, you need to add an element: XDocument people = new XDocument( new XElement("Persons", original.XPathSelectElements(xpathFilterDups))); ...
HTMLPurifier without XML declaration
you need cut result string $n = strlen('<?xml encoding="utf-8" ?>'); $content_text_fixHTML = substr($H->purify($content_text), $n); ...
Multiply arrays by arrays in JAVA
Something like this? import java.util.ArrayList; import java.util.Collections; import java.util.List; public class MatrixCross { public static void cross(String[]... matrix){ cross(0,matrix, Collections.EMPTY_LIST); } private static void cross(int index,String[][] matrix, List<String> result){ if (index >= matrix.length){ System.out.println("<test>"); int i = 1; for (String str : result) { System.out.println(" <test_"+i+">"+str+"</test_"+i+">"); i++; } System.out.println("</test>"); }...
XQuery XML insert
xml,xslt,xquery,transformation,osb
You need to make a recursive copy (see the Identity Template pattern), and if the current node is a match (is a pairs element, with a matching key), then you also have to generate 2 elements after. This stylesheet does exactly that: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="keys" select="document('so-001-keys.xml')/myFieldData"/> <xsl:template match="node()">...
PowerShell XML formatting issue
You're missing a set of parentheses (()) at the end of $XmlWriter.WriteEndElement: $xmlWriter.WriteStartElement("Disk$count") # Add tag for each drive $xmlWriter.WriteElementString("DriveLetter","$DriveLetter") # Write Drive Letter to XML $xmlWriter.WriteElementString("DriveSize","$DriveSize") # Write Drive Size to XML $xmlWriter.WriteElementString("DriveFreeSpace","$DriveFreeSpace") # Write Drive Free Space to XML $xmlWriter.WriteEndElement() # <-- Closing Drive Tag - don't forget...
Convert contents of an XmlNodeList to a new XmlDocument without looping
c#,xml,xpath,xmldocument,xmlnodelist
If you're happy to convert it into LINQ to XML, it's really simple: XDocument original = ...; // However you load the original document // Separated out for clarity - could be inlined, of course string xpath = "//Person[not(PersonID = following::Person/PersonID)]" XDocument people = new XDocument( new XElement("Persons", original.XPathSelectElements(xpath) )...
XSLT get all nodes with text
It's unclear to me what location is, but this sample: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output indent="yes"/> <xsl:template match="/"> <sample> <xsl:call-template name="interpret_text"> <xsl:with-param name="location" select="."/> </xsl:call-template> </sample> </xsl:template> <xsl:template name="interpret_text"> <xsl:param name="location"/> <xsl:for-each select="$location//text()"> <xsl:if...
Clean and convert HTML to XML for BaseX
html,xml,converter,xquery,basex
BaseX has integration for TagSoup, which will convert HTML to well-formed XHTML. Most distributions of BaseX already bundle TagSoup, if you installed BaseX from a Linux repository, you might need to add it manually (for example, on Debian and Ubuntu it's called libtagsoup-java). Further details for different installation options are...
Create XSD based on root element
Using XSL 2.0 you can have multiple output documents and can define every file name, file content, etc. Default java support for XSL 2.0 is far from perfect, so I use the incredible Saxon (you can download saxon-he here, unzip it and add saxon9he.jar to your project). This is the...
XML-XSLT-XPATH : How to convert multiple XML elements to a string, separated by semicolon
you could use something like: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="text"/> <xsl:template match="/"> <xsl:text>UserNames: "</xsl:text> <xsl:value-of select="/Users/user/username" separator=";"/> <xsl:text>"
</xsl:text> <xsl:text>Names: "</xsl:text> <xsl:value-of select="/Users/user/name" separator=";"/>...
XML Schema 1.0 “All” with multiple same elements?
You're blocked by a non-orthogonality of XML Schema. You'd think that the following should work: <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="top"> <xs:complexType> <xs:sequence> <xs:all> <xs:element name="A" minOccurs="0"/> <xs:element name="B" minOccurs="0"/> <xs:element name="C" minOccurs="0"/> <xs:element name="D" minOccurs="0"/> </xs:all> <xs:element name="E" minOccurs="1"...
How to calculate max string-length of a node-set?
<xsl:variable name="max_a_width"> <xsl:for-each select="data"> <xsl:sort select="string-length(@a)" data-type="number" /> <xsl:if test="position() = last()"> <xsl:value-of select="string-length(@a)" /> </xsl:if> </xsl:for-each> </xsl:variable> This is the general method of picking from an ordered list of derived values in XSLT 1.0. If you want to pick the minimum/maximum from actual (natively sortable) values, you can take...
Javascript - accessing an object with duplicate names
I actually looked around and figured out how to do this. I found it under a different topic but figured that I might help anyone else with this specific question. To get to these multiple array items, you have to put in the index like this: console.log(jsonXML.ProfileGroup.File["0"].Profile.WayPt["0"].distance); When iterating through...
Fixed element in android?
You need a FrameLayout. In a FrameLayout, the children are overlapped on top of each other with the last child being at the topmost. activity_main.xml <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" xmlns:fab="http://schemas.android.com/apk/res-auto" android:layout_width="match_parent" android:layout_height="match_parent" android:fitsSystemWindows="true"> <LinearLayout android:layout_width="match_parent" android:layout_height="match_parent"...
Transform XML to another XML using XSL based on some condition
Your xsl is not valid This one is correct and gives you the result expected <?xml version="1.0" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:element name="parent"> <xsl:apply-templates select="/root/gereratorList/generator"/> </xsl:element> </xsl:template> <xsl:template match="generator"> <xsl:if test="id='10'"> <xsl:element name="child"> <xsl:element name="test"> <xsl:value-of select="A"/>...
How to parse comment from XML with XMLEventReader?
You can use javax.xml.stream.events.Comment.getText() to get the string data of a comment, or the empty string if it doesn't exist: ((javax.xml.stream.events.Comment) event).getText() ...
Chunking XML with XMLStreamReader failing
Here is the solution: ClassPathResource classPathResource = new ClassPathResource("samples/form2/data/test.xml"); XMLInputFactory xmlInputFactory = XMLInputFactory.newFactory(); xmlInputFactory.setProperty(XMLInputFactory.IS_COALESCING, true); XMLStreamReader xmlStreamReader = xmlInputFactory.createXMLStreamReader(classPathResource.getInputStream()); JAXBContext jaxbContext = JAXBContext.newInstance(EntityRecordData.class); Unmarshaller unmarshaller = jaxbContext.createUnmarshaller(); int eventType = xmlStreamReader.next();...
Remove XML Node text using XSLT
Here's one way: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:strip-space elements="*"/> <!-- identity transform --> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="c"> <xsl:apply-templates/> </xsl:template> </xsl:stylesheet> Here's another:...
Split XML into multiple files using xslt on string length
I only need the 2 files. legacy.xml (bookIds not 10 in length) & current.xml (bookIds with length of 10). Then I would suggest you do it this way: XSLT 2.0 <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/books"> <books> <xsl:copy-of select="book[string-length(bookId)=10]" /> </books> <xsl:result-document href="file:/C:/devFiles/legacy.xml"> <books> <xsl:copy-of...
How to store a string in xml file and use it in _Layout in MVC
c#,xml,asp.net-mvc,asp.net-mvc-4
Sourced: from this link The web.config (or app.config) is a great place to store custom strings: in web.config: <appSettings> <add key="message" value="Hello, World!" /> </appSettings> in cs: string str = ConfigurationSettings.AppSettings["message"].toString(); ...
C# XML: System.InvalidOperationException
Is "User Info" and "Course Data" is a different entity. If it is so, I think you may encapsulate them in one entity. XmlTextWriter writer = new XmlTextWriter(path, System.Text.Encoding.UTF8); writer.WriteStartDocument(true); writer.Formatting = Formatting.Indented; writer.Indentation = 4; writer.WriteStartElement("My Entity"); /* It is a biggest one*/ writer.WriteStartElement("User Info"); writer.WriteStartElement("Name"); writer.WriteString(userName); writer.WriteEndElement(); writer.WriteStartElement("Tutor...
XML, XSL namespaces
To produce a valid output HTML document you just need to add exclude-result-prefixes="xsi xslFormatting" on the <ins:stylesheet> (root) element of your stylesheet. But indeed in your stylesheet you don't use the xsi and xslFormatting namespaces anywhere. Thus you could also modify your stylesheet by removing these namespaces declarations, leading you...
XML values of the same attribute in different elements cannot repeat
You can use xs:unique to constrain Reference_number to be unique: <?xml version="1.0" encoding="utf-8"?> <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="Items"> <xs:complexType> <xs:sequence> <xs:element maxOccurs="unbounded" name="Item"> <xs:complexType> <xs:sequence> <xs:element name="Name" type="xs:string" /> <xs:element name="Reference_number" type="xs:string" />...
group siblings by identifying the first node of a certain type in sequence
Try it this way: <xsl:key name="kFirstText" match="*[not(self::type1[not(preceding-sibling::*[1][self::type1])])]" use="generate-id(preceding-sibling::type1[not(preceding-sibling::*[1][self::type1])][1])"/> This excludes the "leader" nodes from the group retrieved by the key....
Magento simplexml_load_string() error location
It's something related with /var/www/html/app/code/core/Mage/Core/Model/Layout/Update.php so I would edit that file and I would go to the line 450. Just before that line write: Mage::log(print_r($filename, true)); Make sure that your logging is enabled and refresh the page. After that, take a look to var/log/system.log. The last xml is probably what...
ImageView inside scrollview (Android)
use android:fillViewport="true" for scroll view and change ImageView scale type to android:scaleType="fitXY" <RelativeLayout android:layout_width="match_parent" android:layout_height="match_parent" android:gravity="bottom" > <ScrollView android:id="@+id/scroll" android:fillViewport="true" android:layout_width="fill_parent" android:layout_height="fill_parent"> <RelativeLayout android:id="@+id/relativeLayout1" android:layout_width="match_parent" android:layout_height="match_parent" > <ImageView...
Reading data from an XML File Using R
If you're willing to give xml2 a go, you can get to begin in a few lines: library(xml2) library(magrittr) # get a vector doc <- read_xml("~/Dropbox/Data.xml") doc %>% xml_find_all("//d1:event/d1:begin", ns=xml_ns(doc)) %>% xml_text() %>% as.numeric() ## [1] 0.24 0.73 1.25 1.75 2.24 2.75 3.27 3.76 4.30 4.77 5.28 5.78 6.32 6.82...
Deserializing or parse XML response in Symfony2
php,xml,symfony2,deserialization,jmsserializerbundle
It depends on your intention. If you want to directly push part or all of the XML to an entity/document object for saving to a database then the JMSSerializerBundle can do this very smartly and is definitely the best way to do it. If however you just want to extract...
R readHTMLTable failed to load external entity [duplicate]
In the link that I mentioned in the comment, you can find solutions using RCurl and httr package. Here, I provide the solution using rvest package. library(rvest) kk<-html("http://en.wikipedia.org/wiki/List_of_S%26P_500_companies")%>% html_table(fill=TRUE)%>% .[[1]] //table 1 only head(kk) Ticker symbol Security SEC filings GICS Sector GICS Sub Industry Address of Headquarters 1 MMM 3M...
XML Post from form using curl PHP
$data = array( "line1" => "sample data", "line2" => "sample data 2", ); $data_string = json_encode($data); $url = "http://test.com/webservicerequest.asmx"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); // set url to post to curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HTTPHEADER, array( 'Content-Type: application/json', 'Content-Length: ' . strlen($data_string))...
C# Validate DataSet filled with DGV data as XML
c#,xml,validation,datagridview,xsd
If the question is why can't the file be deleted, it is because the XmlReader has the file open - call read.Close() before trying to delete the file.
Java XPath returns single result instead of NodeSet
My guess is that you make a mistake while processing the result NodeList. Try the following approach: NodeList results = (NodeList) xpath.evaluate(..); for (int i = 0; i < nodelist.getLength(); i++) { Node node = (Node) nodelist.item(i); ... } ...
Converting XSD 1.1 to 1.0 - Validation Error
You can't get this to work with XSD 1.0. An "all" is not allowed as part of a choice. That's actually true in 1.1 as well. But what are you actually trying to achieve? You've got a choice with only one branch, which is obviously redundant, except that it specifies...
Sequence number for static and dynamic rows in XSLT 2.0
Would this XSLT do: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text" /> <xsl:strip-space elements="*"/> <xsl:template match="/*"> <xsl:apply-templates select=".//line"/> </xsl:template> <xsl:template match="line"> <xsl:variable name="pos" select="position() + (3 * count(preceding::data))"/> <xsl:value-of select="concat(format-number($pos, '00000 '), ., '
')"/> </xsl:template> <xsl:template...
About sorting based on the counting of subelements
You can use a key in order to count the properties in the sort instruction. A stylesheet containing the following: <xsl:key name="p" match="property" use="@agency"/> <xsl:template match="/immo"> <result> <xsl:for-each select="agency"> <xsl:sort select="count(key('p', @name))"/> <res id="{ @name }" count="{ count(key('p', @name)) }"/> </xsl:for-each> </result> </xsl:template> when applied to the following input: <immo>...
What is the xpath for retrieving all attribute nodes (whatever be the attributes name) with a specified value?
Well //@* gives you all attribute nodes, add a predicate //@*[. = 'zzz'] and you have all attribute nodes with the value zzz.
XMLPullParser black diamond question marks with certain characters
android,xml,character-encoding,xmlpullparser,questionmark
Content encoding and character encoding are not the same thing. Content encoding refers to compression such as gzip. Since getContentEncoding() is null, that tells you there's no compression. You should be looking at conn.getContentType(), because the character encoding can usually be found in the content-type response header. conn.getContentType() might return...
type conversion performance optimizable?
c#,xml,csv,optimization,type-conversion
IEnumerable<string> values = new List<string>(); values = … Probably not going to be a big deal, but why create a new List<string>() just to throw it away. Replace this with either: IEnumerable<string> values; values = … If you need values defined in a previous scope, or else just: Enumerable<string> values...
Parsing XML array using Jquery
javascript,jquery,xml,jquery-mobile
EMI and CustomerName are elements under json so you can use .find() to find those elements and then text() to get its value. $(data).find("json").each(function (i, item) { var heures = $(item).find("CustomerName").text(); var nbr = $(item).find("EMI").text(); console.log(heures); }); .attr() is used to get the attribute value of an element like in...
tcl tdom parsing failed due to special charecters in xml tags
If you mean the ampersand, it is not in a tag, it is in the text that appears between two tags. The reason people choose to use XML for data interchange is that it's a standard, and there's lots of software around to handle it. That advantage disappears entirely if...
Xml schema regex to not allow white spaces alone
You're on the right track using <xs:whiteSpace> restriction, but the value should be preserve in order to not modify the original whitespace. You can use this pattern: [\w\d ]*[\w\d][\w\d ]* The central part ([\w\d]) says that a letter or a digit must appear. Before and after that compulsory alphanumeric character,...
Get XML node value when previous node value conditions are true (without looping)
UPDATE Using an XDocument vs an XmlDocument, I believe this does what you're asking without using loops. This is dependent on the elements being in the order of <PhoneType> <PhonePrimaryYN> <PhoneNumber> string xml = "<?xml version=\"1.0\"?>" + "<Root>" + " <PhoneType dataType=\"string\">" + " <Value>CELL</Value>" + " </PhoneType>" + "...
Using LINQ to reference XML local Xelements
You always have the option to create extension methods to find elements by local name. Whether you like it or not, you have to "use an if within the foreach," that's an ovherhead you'll have to accept. This implementation is in terms of LINQ but you could always write it...
Retrieving an XML node value with TSQL?
Here is the solution: DECLARE @xml xml SELECT @xml = '<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <SOAP-ENV:Body> <webregdataResponse> <result>0</result> <regData /> <errorFlag>99</errorFlag> <errorResult>Not Processed</errorResult> </webregdataResponse> </SOAP-ENV:Body> </SOAP-ENV:Envelope>' declare @table table...
List view not returning to original state after clearing search
java,android,xml,android-activity,android-listfragment
You are operating on the original data instead of filtered data. You should maintain a reference to original data and use the filtered data for all other purposes. So that the original data is displayed when search is cleared. Replace all usages of mData with mFilteredData as below and only...
Convert meters to foot in xml data via xsl transformation
There are several issues with your approach. For example, instead of: <node><xsl:value-of select="node"/></node> which creates empty node elements (because your node elements are empty), you should be using something like: <node><xsl:copy-of select="@*"/></node> and instead of: <xsl:for-each select="/tag"> which selects nothing, because tag is not a child of the / root...
Is complexity of scala.xml.RuleTransformer really exponential?
This will be not a very rigours analysis, but the problem seems to be with the BasicTransformer's transform(Seq[Node]) method[1]. The child transform method will be called twice for a node which is changed. Specifically in your example all the nodes will be called twice for this reason. And you are...
how to make xml values comma seperated using XPath, XQuery in Sql Server
SQL Server does not implement the xPath function string-join, so you would need to adopt a two step process, the first would be to extract all the terms to rows using nodes(); SELECT n.value('.', 'VARCHAR(100)') AS parsedString FROM #temp AS t CROSS APPLY t.Response.nodes('/error/description2') r (n); Which gives you your...
Change attribute value of an XML tag in Qt
I guess, but I think your XML is only present in your memory. You have to trigger somethink like tsFileXml.WriteToFile(filename) to store your changes to a file on your filesystem.
Error during deserializing XML
c#,xml,serialization,deserialization
Use the [XmlElement] attribute: [XmlElement(ElementName = "StyleProperties", Namespace="http://schemas.datacontract.org/2004/07/PPT_Styles_Tool")] public class StyleProperties { //... Also, if you use the XmlSerializer to serialize, then you should use the XmlSerializer to deserialize. Not the DataContractSerializer....
Add XElement dynamically using loop in MVC 4?
This is the complete code [HttpPost] public ActionResult SURV_Answer_Submit(List<AnswerQuestionViewModel> viewmodel, int Survey_ID, string Language) { if (ModelState.IsValid) { var query = from r in db.SURV_Question_Ext_Model.ToList() join s in db.SURV_Question_Model on r.Qext_Question_ID equals s.Question_ID where s.Question_Survey_ID == Survey_ID && r.Qext_Language == Language orderby s.Question_Position ascending select new { r, s };...
How get value from property file to input in springConfig.xml
Look at this line of your stack trace: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'mailSender' defined in class path resource [springConfig.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type 'java.lang.String' to required type 'int' for property 'port'; nested exception is java.lang.NumberFormatException: For input...
how to insert the xml data to sql server using c#?
sql,xml,stored-procedures,sql-insert
You have a few options: You can read the XML nodes before inserting into the database, and insert normalized table column values. You can shred the XML in a stored procedure, by passing the XML string as an input parameter. You can read up on how to shred the XML...
How to set up XPath query for HTML parsing?
It is important to inspect the string returned by page.text and not just rely on the page source as returned by your Chrome browser. Web sites can return different content depending on the User-Agent, and moreover, GUI browsers such as your Chrome browser may change the content by executing JavaScript...
XSLT How to remove style from div and td tags
To remove some nodes start with the identity transformation template <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> then add an empty template for the nodes to be removed: <xsl:template xmlns:xhtml="http://www.w3.org/1999/xhtml" match="xhtml:div/@style | xhtml:li/@style | xhtml:td/@style | xhtml:span/@style"/> ...
Collect strings after a foreach loop
Yep, you need to do the adding within the loop. I'd use a List<string> as it supports LINQ: XmlNodeList skillNameNodeList=SkillXML.GetElementsByTagName("name"); List<string> skills = new List<string>(); foreach (XmlNode skillNameNode in skillNameNodeList) { skills.Add(skillNameNode.Attributes["value"].Value); } ...
How to convert XML into PDF/A using java api?
You can use Apache FOP API and you need to write XSLT style for your output PDF. This API will help to convert your XML and XSLT stylesheet into PDF/PDF-A.
XSL transformation outputting multiple times and other confusion
1) Your template is applied to 3 elements, and for each of them, loops over all the parents li elements (yes, for each of them, ask all the li elements, children of the grand-father of the current content, which are all the 3 li elements, each time). 2) Because that's...
XSL - iterate through elements and update based on the node index from another xml file
An XSL transformation that meets your requirement may be like the following: <?xml version="1.0" encoding="utf-16" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml"/> <!-- the update source file: --> <xsl:param name="usource" select="'updatesource.xml'"/> <xsl:template match="Material"> <!-- Material's position: --> <xsl:variable name="pos"> <xsl:value-of select="count(preceding::Material)+1"/> </xsl:variable>...
Ruby on Rails posting to an API using javascript via a proxy
javascript,ruby-on-rails,ruby,xml,api
Net::HTTP is Ruby's built in library for sending HTTP requests. Rails also has built in features for serializing models to XML. Lets say you bind your form to a User model: class User < ActiveModel::Base # attr_accessor is not needed if these are real DB columns. attr_accessor :firstname attr_accessor :surname...
Giving a prepared SOAP response by Java
Sure you can. Even within the same Java program. Use Java HTTP Server. few lines of code and you have functional http server.
Adding Post data to XML String
You need to add " around the value not single '. $XPost = "<MinPrice>{$_POST['first_name']}</MinPrice>"; with dobule quote you can do this $XPost = "<MinPrice>".$_POST["first_name"]."</MinPrice>"; Change your code like that. $strXml = '<?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <SubmitLead...
simplexml_load_file to file creating an empty file
simplexml_load_file() itself returns an object on success, not a string, while file_put_contents() as a second argument expects a string to be written. So you're trying to save an object instead of raw string. In this scenario you can simply do something like this: $xml = file_get_contents($signedUrl); $file = "c:/wamp/www/products.xml"; file_put_contents($file,...
Unable to construct Document object from xml string
As Arthur Elrich pointed out in the comments, you should make the factory namespace aware and provide a namespace context to the XPath instance. DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); factory.setNamespaceAware(true); DocumentBuilder builder = factory.newDocumentBuilder(); Document document = builder.parse( new InputSource(new StringReader(...))); XPath xpath = XPathFactory.newInstance().newXPath(); xpath.setNamespaceContext(new MyNamespaceContext()); String s = xpath.evaluate("//location:address/text()",...
How to extract efficientely content from an xml with python?
python,xml,python-2.7,pandas,lxml
There are several things wrong here. (Asking questions on selecting a library is against the rules here, so I'm ignoring that part of the question). You need to pass in a file handle, not a file name. That is: y = BeautifulSoup(open(x)) You need to tell BeautifulSoup that it's dealing...
Adding custom style to button in styles.xml gives error
You can switch rendering target version < 22. Try it once. You can install android versions from these steps as shown in screenshots. ...
Concatenate two XML templates in Python
One (unorthodox) way of doing it is like so: template1 = \ ''' <ParentTag> <orders orderid="%s"> <unitprice>%s</unitprice> <quantity>%s</quantity> </orders>%s </ParentTag> ''' template2 = \ ''' <details> <productid>%s</productid> <productname>%s</productname> </details> ''' Code: output = "" if (condition is met): output += output % template1(orderid, unitprice, quantity, "") else: output += template1...
Extracting XML data from CLOB
Use xmltable. Data setup: create table myt( col1 clob ); insert into myt values('<ServiceDetails> <FoodItemDetails> <FoodItem FoodItemID="6486" FoodItemName="CARROT" Quantity="2" Comments="" ServingQuantityID="142" ServingQuantityName="SMALL GLASS" FoodItemPrice="50" ItemDishPriceID="5336" CurrencyName="INR" CurrencyId="43"/> </FoodItemDetails> <BillOption> <BillDetails TotalPrice="22222" BillOption="cash"/> </BillOption> <Authoritativeness/> </ServiceDetails>' ); commit; Query:...
xpath query seem to be failing
$str = '<root><Pages> <copyright>me inc. 2015,</copyright> <author>Me</author> <lastUpdate>2/1/1999</lastUpdate> <Home>--------------------</Home> <About>--------------------</About> <Contact>------------------</Contact> </Pages></root>'; $xml = simplexml_load_string($str); $result = $xml->xpath('//Pages/*[(name() = "Home") or following-sibling::Home]'); if ($result === false) { $this->parseError(); //To return xml Error code...
Tagging values in HTML document for automated extraction
If you are using them as meta-documents and they are sent to the parser, then converted as HTML and as long as the converted HTMLs do not have any irrelevant tags, it is fine! So, if the following code: <requirement> THE REQUIREMENT HERE </requirement> Gets converted into something like: <!--...
Altering XML file format in C#
It sounds like your XML is coming straight from your database, which means you need to transform it into something else based on the structure you have presently. While you could learn XSLT, you could also do this using LINQ to XML, querying the document you have parsed in order...
Adding a child attribute to the parent element in xslt 1.0
It's difficult to provide an answer without seeing the input. I believe you need to do something like the following: XSLT 1.0 <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common" extension-element-prefixes="exsl"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="visualChildren"> <xsl:variable name="bundles"> <xsl:call-template name="create-bundles"> <xsl:with-param name="n" select="4" />...
How to get xml Nodes which are in lower case using XSLT 1.0
All you need is the identity template to copy existing nodes... <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> Then another template to ignore nodes that aren't lower-case. In XSLT 1.0 this can be done by using the translate statement, to translate uppercase letters to lowercase, and checking if the result...
XSLT for-each statement not iterating proper amount of times
Try it this way? <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/template/L"> <html> <body> <ul> <xsl:for-each select="Q"> <li> <xsl:value-of select="text()"/> <ul> <xsl:for-each select="R"> <li> <xsl:value-of select="."/> </li> </xsl:for-each> </ul> </li> </xsl:for-each> </ul> </body> </html> </xsl:template> </xsl:stylesheet> Explanation: When...
Which LiftResponse class is appropriate for returning an XML based file format?
JsonResponse and PlainTextResponse are helpers that ultimately return an InMemoryResponse. You can see the source code here and here respectively. You will notice that PlainTextResponse sets a mimetype of "text/html" which is not necessarily correct for XML. There is also an XmlResponse type that you can investigate here and which...
Update SQL Server table using XML data
You have 2 errors in your xml: First is nonmatching root tags. Second, more important, you are quering nodes('/Aprroval/Aprrove'), but inner tag is Approve not Aprrove. Fiddle http://sqlfiddle.com/#!3/66b08/3...
finding file in root of wpf application
c#,xml,wpf,visual-studio,relative-path
First, ensure that the file is definitely copied into your output ./bin/ directory on compile: This worked perfectly for me in my WPF application: const string imagePath = @"pack://application:,,,/Test.txt"; StreamResourceInfo imageInfo = Application.GetResourceStream(new Uri(imagePath)); byte[] imageBytes = ReadFully(imageInfo.Stream); If you want to read it as binary (e.g. read an image...
Load XML to list using LINQ [duplicate]
Make a base class which will have id,x,y,z, and have Vendors,Bankers and Hospitals extend it. Then you can have a collection of the base class, and add to it the classes that inherit from it....
Ninject generic type xml binding
You want to bind open generic types, so this type definition should do the trick: <bind service="Base.IJsonProvider`1, Base" to="Base.JsonProvider`1, Base" name ="Config"/> ...
Remove all nodes in a specified namespace from XML
Iterating through elements then through attributes seems not too hard to read : var xml = @"<?xml version='1.0' encoding='UTF-8'?> <root xmlns:test='urn:my-test-urn'> <Item name='Item one'> <test:AlternativeName>Another name</test:AlternativeName> <Price test:Currency='GBP'>124.00</Price> </Item> </root>"; var doc = XDocument.Parse(xml); XNamespace test = "urn:my-test-urn"; //get all elements in specific namespace and remove doc.Descendants() .Where(o => o.Name.Namespace...
removing a parent node dependig upon child node using xslt
i want an xslt template which removes the other event node along with child nodes in which other event type value is OriginalCommitDateTime. The standard method to exclude specific nodes is to start with the identity transform template to copy all nodes as the rule, then add an empty...
Python Resize Multiple images ask user to continue
Change your final loop to: for idx, image in enumerate(imgPath): #img resizing goes here count_remaining = len(imgPath) - (idx+1) if count_remaining > 0: print("There are {} images left to resize.".format(count_remaining)) response = input("Resize image #{}? (Y/N)".format(idx+2)) #use `raw_input` in place of `input` for Python 2.7 and below if response.lower() !=...
How to use XDocument to get attributes and add them to a List
The attributes you're trying to get aren't attribute of Payments element. You need to go one level deeper to get them. Try this way : ...... doc = XDocument.Load(reader); var data = doc.Root .Elements() .Elements("Payments"); foreach(var d in data) { var patti = d.Element("Patti"); list1.Add(new List<string>() { patti.Attribute("Rent").Value, patti.Attribute("Water").Value, patti.Attribute("Electricity").Value,...
Remove an XML node by its content
Actually the program as posted originally works fine, there is just one small error: "ParentNode.RemoveChild()" should be called on node instead of doc.
Selecting data in XSL from different sections of XML
i haven't tried it .. but i think a leading '/' is missing here : <xsl:value-of select="root/generatorList/generator/E"/> try this please : <xsl:value-of select="/root/generatorList/generator/E"/> otherwise the xslt engine is trying to find a relative path "root/generatorList/generator/E" starting at the matched element (/root/fiberList/fiber) of the template but there is no /root/fiberList/fiber/root/generatorList/generator/E....
Ruby- get a xml node value
Try to use css instead of xpath, this will work for you, doc = Nokogiri::XML(response.body) values = doc.css('Name').select{|name| name.text}.join',' puts values => Ram,Sam ...
xml.etree.ElementTree.Element.remove not removing all elements
This demonstrates the problem: >>> root = ET.fromstring("<a><b /><c><d /></c></a>") >>> for e in root: ... print(e) ... <Element 'b' at 0x7f76c6d6cd18> <Element 'c' at 0x7f76c6d6cd68> >>> for e in root: ... print(e) ... root.remove(e) ... <Element 'b' at 0x7f76c6d6cd18> So, modifying the object that you are iterating affects the...