chunk of data into fixed lengths chunks and then add a space and again add them all as a string

Tag: regex,list,join,ironpython,findall

I have got hex values as a85b080040010000. I want it to be as a8 5b 08 00 40 01 00 00. I have done it by using below code. But I have to work with very large data. So I want computed time to be very low.

import binascii
import re

filename = 'calc.exe'
with open(filename, 'rb') as f:
    content = f.readline()

text = binascii.hexlify(content)
text1 = binascii.unhexlify(text)
length1 = 32
length2 = 16

list = re.findall('.{%d}' % length1, text)
list1 = re.findall('.{%d}' % length2, text1)

d = []
for i in range (0, len(list), 1):
    temp = ""
    l = re.findall('.{%d}' % length2, list[i])

    s = l[0]
    t = iter(s)
    temp += str(' '.join(a+b for a,b in zip(t, t)))

    temp += "  "

    s = l[1]
    t = iter(s)
    temp += str(' '.join(a+b for a,b in zip(t, t)))
    temp += "  | " + list1[i]
    print temp

Best How To :

You can simply do

x="a85b080040010000"
print re.sub(r"(.{2})",r"\1 ",x)

x="a85b080040010000"

print " ".join([i for i in re.split(r"(.{2})",x) if i])

Get element starting with letter from List

java,android,list,indexof

The indexOf method doesn't accept a regex pattern. Instead you could do a method like this: public static int indexOfPattern(List<String> list, String regex) { Pattern pattern = Pattern.compile(regex); for (int i = 0; i < list.size(); i++) { String s = list.get(i); if (s != null && pattern.matcher(s).matches()) { return...

regex - Match filename with or without extension

regex,logstash-grok

This is about as simple as I can get it: \b\w+\.?\w* See demo...

Why cant I refer to a random index in my 4D list, while I know it exists?

c#,list,for-loop,dimensions

Based on your code where you're filling your 4D list: List<string> Lijst1D = new List<string>(); Lijst2D.Add(Lijst1D); Here you're creating new List<string> and adding it to parent 2D list. But Lijst1D itself doesn't contains any elements (you haven't added anything to it), so Lijst4D[0] will throw that IndexOutOfRangeException as well as...

why java API prevents us to call add and remove together?

java,list,collections,listiterator

You're reading the wrong documentation: you should read ListIterator's javadoc. It says: Throws: ... IllegalStateException - if neither next nor previous have been called, or remove or add have been called after the last call to next or previous Now, if you want a reason, it's rather simple. You're playing...

REGEX python find previous string

python,regex,string

Updated: This will check for the existence of a sentence followed by special characters. It returns false if there are no special characters, and your original sentence is in capture group 1. Updated Regex101 Example r"(.*[\w])([^\w]+)" Alternatively (without a second capture group): Regex101 Example - no second capture group r"(.*[\w])(?:[^\w]+)"...

How do I read this list and parse it?

python,list

Your list contains one dictionary you can access the data inside like this : >>> yourlist[0]["popularity"] 2354 [0] for the first item in the list (the dictionary). ["popularity"] to get the value associated to the key 'popularity' in the dictionary....

PHP Regular Expressions Counting starting consonants in a string

php,regex

This is one way to do it, using preg_match: $string ="SomeStringExample"; preg_match('/^[b-df-hj-np-tv-z]*/i', $string, $matches); $count = strlen($matches[0]); The regular expression matches zero or more (*) case-insensitive (/i) consonants [b-df-hj-np-tv-z] at the beginning (^) of the string and stores the matched content in the $matches array. Then it's just a matter...

ZipList with Scalaz

list,scala,scalaz,applicative

pure for zip lists repeats the value forever, so it's not possible to define a zippy applicative instance for Scala's List (or for anything like lists). Scalaz does provide a Zip tag for Stream and the appropriate zippy applicative instance, but as far as I know it's still pretty broken....

Finding embeded xpaths in a String

java,regex

Use {} instead of () because {} are not used in XPath expressions and therefore you will not have confusions.

Regex pass dynamic values with boundry

c#,regex,string,boundary

Your first regular expression has a black slash followed by the letter b because of that @. The second one has the character that represents backspace. Just put an @ in front string bound = @"\b"; ...

Store regex pattern as a string in PHP when regex pattern contains both single and double quotes

php,regex

The quotes are an issue but not the issue you are running into when you escape them. Your delimiter is terminating your regex just before the closing a which is giving you the unknown modifier error. It appears you don't have error reporting on though so you aren't seeing that....

Python match whole file name, not just extension

python,regex,nsregularexpression

You're not capturing the whole filename in the group. You can also use noncapturing groups with (?:...). .*\.(rom|[0-9]{3})+ # from this (.*\.(?:rom|[0-9]{3})) # to this ...

Regex not working in HTML5 pattern

regex,html5

The pattern attribute has to match the entire string. Assertions check for a match, but do not count towards the total match length. Changing the second assertion to \w+ will make the pattern match the entire string. You can also skip the implied ^, leaving you with just: <input pattern="(?!34)\w+"...

How to match words in 2 list against another string of words without sub-string matching in Python?

python,regex,string,loops,twitter

Store slangNames and riskNames as sets, split the strings and check if any of the words appear in both sets slangNames = set(["Vikes", "Demmies", "D", "MS", "Contin"]) riskNames = set(["enough", "pop", "final", "stress", "trade"]) d = {1: "Vikes is not enough for me", 2:"Demmies is okay", 3:"pop a D"} for...

Patterns (preferably java) find floor space in sq ft

java,regex,pattern-matching

I would try with: Pattern regex = Pattern.compile("(?<= )\\d(\\d*[,\\.]?\\d+)*(?=[ .]?sq)"); where: (?<= ) - there is space before \d - starts with digit (\d*[,\.]?\d+)* - next is digit or digits, there could be comma or point with more digits - and it can repeats like in 100,000,000 (?=[ .]?sq) -...

Please can someone help me understand the exec method for regular expressions?

javascript,regex

I don't understand why it would give me two hellos back? Because the first entry in the array is the overall match for the expression, which is then followed by the content of any capture groups the expression defines. Since the expression defines one capture group, you get back...

How to create the javascript regular expression for number with some special symbols

javascript,regex

This matches all given examples as well: ^\$?\d+(?:[.,:]\d+)?%?$ See it in action: RegEx101 Please comment, if adjustment / further detail is required....

How many characters are visible like a space, but are not space characters?

php,regex

You can make use of a Unicode category \p{Zs}: Zs Space separator $string = preg_replace('~\p{Zs}~u', ' ', $string); The \p{Zs} Unicode category class will match these space-like symbols: Character Name U+0020 SPACE U+00A0 NO-BREAK SPACE U+1680 OGHAM SPACE MARK U+2000 EN QUAD U+2001 EM QUAD U+2002 EN SPACE U+2003 EM SPACE...

Regex that allow void fractional part of number

c#,regex

Just get the dot outside of the captruing group and then make it as optional. @"[+-]?\d+\.?\d*" Use anchors if necessary. @"^[+-]?\d+\.?\d*$" ...

represent an index inside a list as x,y in python

python,list,numpy,multidimensional-array

According to documentation of numpy.reshape , it returns a new array object with the new shape specified by the parameters (given that, with the new shape, the amount of elements in the array remain unchanged) , without changing the shape of the original object, so when you are calling the...

Identify that a string could be a datetime object

python,regex,algorithm,python-2.7,datetime

What about fuzzyparsers: Sample inputs: jan 12, 2003 jan 5 2004-3-5 +34 -- 34 days in the future (relative to todays date) -4 -- 4 days in the past (relative to todays date) Example usage: >>> from fuzzyparsers import parse_date >>> parse_date('jun 17 2010') # my youngest son's birthday datetime.date(2010,...

Sort when values are None or empty strings python

python,list,sorting,null

If you want the None and '' values to appear last, you can have your key function return a tuple, so the list is sorted by the natural order of that tuple. The tuple has the form (is_none, is_empty, value); this way, the tuple for a None value will be...

javascript replace dot (not period) character

javascript,regex,replace

Try using the unicode character code, \u2022, instead: message.replace(/\u2022/, "<br />\u2022"); ...

group indices of list in list of lists

python,list

Use collections.OrderedDict: from collections import OrderedDict od = OrderedDict() lst = [2, 0, 1, 1, 3, 2, 1, 2] for i, x in enumerate(lst): od.setdefault(x, []).append(i) ... >>> od.values() [[0, 5, 7], [1], [2, 3, 6], [4]] ...

Update list of items in c#

c#,linq,list,updates

I would do something like this: (for ordinairy lists) // the current list var currentList = new List<Employee>(); currentList.Add(new Employee { Id = 154, Name = "George", Salary = 10000 }); currentList.Add(new Employee { Id = 233, Name = "Alice", Salary = 10000 }); // new list var newList =...

How to Match a string with the format: “20959WC-01” in php?

php,regex

$pattern = '! ^ # start of string \d{5} # five digits [[:alpha:]]{2} # followed by two letters - # followed by a dash \d{2} # followed by two digits $ # end of string !x'; $matches = preg_match($pattern, $input); ...

Extracting strings from HTML with Python wont work with regex or BeautifulSoup

python,regex,parsing,beautifulsoup,python-requests

In order to match the string with a literal backlash, you need to double-escape it in a raw string, e.g.: re.search(r'@CAD_DTA\\">(.+?)@[email protected]@CAD_LBL',result.text) ^ ^ In order to get the index of the found match, you can use start([group]) of re.MatchObject IDEONE demo: import re obj = re.search(r'@CAD_DTA\\">(.+?)@[email protected]@CAD_LBL', 'Some text [email protected]_DTA\\">I WANT...

How to write RegEx for inserting line break for line length more than 30 characters?

regex

Find what: ^(.{30}) Replace with: \1\n ...

Swing regular expression for phone number validation

java,regex

To only allow digits, comma and spaces, you need to remove (, ) and -. Here is a way to do it with Matcher.find(): Pattern pattern = Pattern.compile("^[0-9, ]+$"); ... if (!m.find()) { evt.consume(); } And to allow an empty string, replace + with *: Pattern pattern = Pattern.compile("^[0-9, ]*$");...

Regular Expression for whole world

regex,c#-4.0,vb6

You can use: Public\s+Const\s+g(?<Name>[a-zA-Z][a-zA-Z0-9]*)\s+=\s+(?<Value>False|True) demo ...

Regex with whitespaces and preceding zeros

regex,sas

You can use this simplified regex: /^[\s0]*11\s*$/ ...

match line break except line begin with spcific word or blank line

regex,notepad++

Try this regex: (?<=[a-zA-Z])(\n) I used parentheses to capture the newline character. https://regex101.com/r/zS9pB4/3...

How do I isolate the text between 2 delimiters on the left and 7 delimiters on the right in Python?

python,regex,string,split

You can use python's built-in csv module to do this. j = next(csv.reader([string])); Now j is each item delimited by a , and will include commas if the value is wrapped in ". See j[2]....

Match a pattern preceded by a specific pattern without using a lookbehind

regex,eclipse,lookahead

A work-around for the lack of variable-length lookbehind is available in situations when your strings have a relatively small fixed upper limit on their length. For example, if you know that strings are at most 100 characters long, you could use {0,100} in place of * or {1,100} in place...

Warning: preg_match_all(): Unknown modifier '\' [duplicate]

php,regex,warnings

Use a different set of delimiters for the regex. For example, you can write preg_match_all('~[^/\s]+/\S+\.(jpg|png|gif)~', $string, $results ...

MySQL substring match using regular expression; substring contain 'man' not 'woman'

mysql,regex

A variant of n-dru pattern since you don't need to describe all the string: SELECT '#hellowomanclothing' REGEXP '(^#.|[^o]|[^w]o)man'; Note: if a tag contains 'man' and 'woman' this pattern will return 1. If you don't want that Gordon Linoff solution is what you are looking for....

jQuery / Regex: How to compare string against several substrings

jquery,regex,string,substring,substr

You could convert this to a slightly more maintainable format, without getting into regular expressions. This is one way to use an array to accomplish your goal: // Super-quick one-liner: var str = '2042038423408'; var matchCount = $.grep(['12', '23', '34', '45', '56', '67', '78', '89', '90', '01'], function(num, i) {...

Python regular expression, matching the last word

python,regex,list

Use the alternation with $: import re mystr = 'HelloWorldToYou' pat = re.compile(r'([A-Z][a-z]*)') # or your version with `.*?`: pat = re.compile(r'([A-Z].*?)(?=[A-Z]+|$)') print pat.findall(mystr) See IDEONE demo Output: ['Hello', 'World', 'To', 'You'] Regex explanation: ([A-Z][a-z]*) - A capturing group that matches [A-Z] a capital English letter followed by [a-z]* -...

Does there exist an algorithm for iterating through all strings that conform to a particular regex?

c#,regex,algorithm

Let's say the domain is as following String domain[] = { a, b, .., z, A, B, .. Z, 0, 1, 2, .. 9 }; Let's say the password size is 8 ArrayList allCombinations = getAllPossibleStrings2(domain,8); This is going to generate SIZE(domain) * LENGTH number of combinations, which is in...

Regex to remove `.` from a sub-string enclosed in square brackets

c#,.net,regex,string,replace

To remove all the dots present inside the square brackets. Regex.Replace(str, @"\.(?=[^\[\]]*\])", ""); DEMO To remove dot or ?. Regex.Replace(str, @"[.?](?=[^\[\]]*\])", ""); ...

BeautifulSoup: Parsing bad Wordpress HTML

python,html,regex,wordpress,beautifulsoup

At least, you can rely on the tag names and text, navigating the DOM tree horizontally - going sideways. These are all strong, p and span (with id attribute set) tags you are showing. For example, you can get the strong text and get the following sibling: >>> from bs4...

Get all prices with $ from string into an array in Javascript

javascript,regex,currency

It’s quite trivial: RegEx string.match(/\$((?:\d|\,)*\.?\d+)/g) || [] That || [] is for no matches: it gives an empty array rather than null. Matches $99 $.99 $9.99 $9,999 $9,999.99 Explanation / # Start RegEx \$ # $ (dollar sign) ( # Capturing group (this is what you’re looking for) (?: #...

Reg ex matching a word

regex

You could use a negative lookahead which will exclude those having _FX following the initial alpha string ^ABD_DEF_GHIJ(?!_FX)(?:_\d{8})?$ see example here...

Implementing a dictionary function to calculate the average of a list

python,list,dictionary

I think you want something more like: print("Enter positive, negative or zero to determine the average: ") # get list of values/numbers from the user values = [i for i in iter(lambda: int(input("Enter a number (-9999 to end): ")), -9999)] -9999 is the sentinel value to break the loop def...

List of tuples from (a, all b) to (b, all a)

python,list,python-2.7,tuples

You can use collections.defaultdict: tups = [ ('a1',['b1','b2','b3']), ('a2',['b2']), ('a3',['b1','b2']) ] d = collections.defaultdict(list) for a, bs in tups: for b in bs: d[b].append(a) Then: >>> d.items() [('b1', ['a1', 'a3']), ('b2', ['a1', 'a2', 'a3']), ('b3', ['a1'])] ...

Get number from string

regex

Use \d+ to match one or more digits. \b(?:http:\/\/)?(?:www\.)?example\.com\/g\/(\d+)\/\w put http:// and www. inside a capturing or non-caturing group and then make it as optional by adding ? quantifier next to that group. For both http and https, it would be (?:https?:\/\/)? DEMO...

How can I iterate through nested HTML lists without returning the “youngest” children?

javascript,jquery,html,list,loops

You could just check the nesting level by counting parents $("ul li").each(function() { if ( $(this).parents('ul').length < 3 ) { // do stuff } }); FIDDLE To make it more dynamic one could simply find the deepest nesting level and filter based on that var lis = $("ul li"); var...

Java - Enforce TextField Format - UX - 00:00:00;00

java,regex,user-interface

How about using JFormattedTextField with MaskFormatter. JFormattedTextField formattedTextField = new JFormattedTextField("00:00:00;00"); try { MaskFormatter maskFormatter = new MaskFormatter("##:##:##;##"); maskFormatter.install(formattedTextField); } catch (ParseException e) { e.printStackTrace(); } More info at http://docs.oracle.com/javase/tutorial/uiswing/components/formattedtextfield.html Demo code: JFrame frame = new JFrame(""); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JPanel panel = new JPanel(); JFormattedTextField...

Validate part of mail suffix

c#,regex

You can use this regex to test. It will ensure that after the @ there is .xx. but may also match the string @.xx.* .*@[^.]*[.]xx[.] Or this one to ensure that there is at least one character before and after the @. [email protected][^.]+[.]xx[.] ...