How convert unsigned int to unsigned char array

Tag: c++,c

I just need to extract those bytes using bitwise & operator. 0xFF is a hexadecimal mask to extract one byte. For 2 bytes, this code is working correctly:

#include <stdio.h>

int main()
{
    unsigned int i = 0x7ee;
    unsigned char c[2];

    c[0] = i & 0xFF;
    c[1] = (i>>8) & 0xFF;

    printf("c[0] = %x \n", c[0]);
    printf("c[1] = %x \n", c[1]);


    return 0;
}

output:

c[0] = ee;
c[1] = 7;

What should I do for 4 bytes to work correctly?

unsigned int i = 0x557e89f3;
unsigned char c[4];

my code:

unsigned char c[4];
         c[0] = i & 0xFF;
         c[1] = (i>>8) & 0xFF;
         c[2] = (i>>16) & 0xFF;
         c[3] = (i>>24) & 0xFF;
         printf("c[0] = %x \n", c[0]);
         printf("c[1] = %x \n", c[1]);
         printf("c[2] = %x \n", c[2]);
         printf("c[3] = %x \n", c[3]);

Best How To :

#include <stdio.h>

int main()
{
    unsigned int i = 0x557e89f3;
    unsigned char c[4];

    c[0] = i & 0xFF;
    c[1] = (i>>8) & 0xFF;
    c[2] = (i>>16) & 0xFF;
    c[3] = (i>>24) & 0xFF;

    printf("c[0] = %x \n", c[0]);
    printf("c[1] = %x \n", c[1]);
    printf("c[2] = %x \n", c[2]);
    printf("c[3] = %x \n", c[3]);


    return 0;
}

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c++

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