I have an Array like this.
scala> var x=Array("a","x,y","b")
x: Array[String] = Array(a, x,y, b)
How do I change the separator comma in array to a :. And finally convert it to string like this.
String = "a:x,y:b"
My aim is to change the comma(separators only) to other separator(say,:), so that i can ignore the comma inside second element i.e, x,y. and later split the string using : as a delimiter
Your question is unclear, but I'll take a shot.
To go from:
val x = Array("a","x,y","b")
to
"a:x,y:b"
You can use mkString:
x.mkString(":")
According to the docs https://github.com/rails/strong_parameters#permitted-scalar-values: The permitted scalar types are String, Symbol, NilClass, Numeric, TrueClass, FalseClass, Date, Time, DateTime, StringIO, IO, ActionDispatch::Http::UploadedFile and Rack::Test::UploadedFile. To declare that the value in params must be an array of permitted scalar values map the key to an empty array: params.permit(:id => []) If...
You can use a simple array based test like var validCodes = ['IT00', 'O144', '6A1L', '4243', 'O3D5', '44SG', 'CE64', '54FS', '4422']; function validItems(items) { for (var i = 0; i < items.length; i++) { if (validCodes.indexOf(items[i]) == -1) { return items[i]; } } return ''; } var items = ["IT00",...
Pretty fundamentally - CSV is an array based data structure - it's a vaguely enhanced version of join. But the thing you need for this job is print_hr from Text::CSV. First you need to set your header order: $csv->column_names (@names); # Set column names for getline_hr () Then you can...
I executed ur code. Just add numberView.setTextColor(Color.BLACK); and it will work! :)...
php,mysql,arrays,variables,multidimensional-array
The explode function is being used correctly, so your problem is further up. Either $data[$i] = mysql_result($result,$i,"data"); isn't returning the expected string "2015-06-04" from the database OR your function $data[$i] = data_eng_to_it_($data[$i]); isn't returning the expected string "04 June 2015" So test further up by echo / var_dump after both...
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You need to use brackets notation to access property by variable: function myFunc( array, fieldToCompare, valueToCompare ) { if( array[fieldToCompare] == "Thiago" ) alert(true); } And wrap name in quotes: myFunc( myArray, 'name', "Thiago" ); ...
c++,string,c++11,memory,standards
Section 21.4.1.5 of the 2011 standard states: The char-like objects in a basic_string object shall be stored contiguously. That is, for any basic_string object s, the identity &*(s.begin() + n) == &*s.begin() + n shall hold for all values of n such that 0 <= n < s.size(). The two...
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Arrays in C++ don't allow this syntax. What you should do is something like this: char[2] id; if( sx1272.packet_received.length > 5 ) { id[0] = sx1272.packet_received.data[4]; id[1] = sx1272.packet_received.data[5]; } ...
As PM 77-1 suggests, consider using the built–in Array.prototype.sort with Date objects. Presumably you want to sort them on one of start or end: jobs.sort(function(a, b) { return new Date(a.ys, a.ms-1) - new Date(b.ys, b.ms-1); }) ...
Use stoi, it's the modern C++ version of C's atoi. Update: Since the original answer text above the question was amended with the following error message: ‘stoi’ was not declared in this scope Assuming this error was produced by g++ (which uses that wording), this can have two different causes:...
To get your desired output, this will do the trick: var file = "a|b|c|d, a|b|c|d, a|b|c|d, a|b|c|d, a|b|c|d"; var array = file.split(", ") // Break up the original string on `", "` .map(function(element, index){ var temp = element.split('|'); return [temp[0], temp[1], index + 1]; }); console.log(array); alert(JSON.stringify(array)); The split converts...
javascript,arrays,loops,foreach,innerhtml
Just take a variable for the occurrence of even or odd numbers. var myArray = function (nums) { var average = 0; var totalSum = 0; var hasEven = false; // flag if at least one value is even => true, otherwise false nums.forEach(function (value) { totalSum = totalSum +...
c,arrays,segmentation-fault,initialization,int
In your code, int i is an automatic local variable. If not initialized explicitly, the value held by that variable in indeterministic. So, without explicit initialization, using (reading the value of ) i in any form, like array[i] invokes undefined behaviour, the side-effect being a segmentation fault. Isn't it automatically...
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ios,string,swift,unicode,character
When a type isn't specified, Swift will create a String instance out of a string literal when creating a variable or constant, no matter the length. Since Strings are so prevalent in Swift and Cocoa/Foundation methods, you should just use that unless you have a specific need for a Character—otherwise...
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Here is a way using an intermediate hash-of-hash The h ends up looking like this {"Alaska"=>{"Rain"=>"3", "Snow"=>"4"}, "Alabama"=>{"Snow"=>"2", "Hail"=>"1"}} myArray = [["Alaska","Rain","3"],["Alaska","Snow","4"],["Alabama","Snow","2"],["Alabama","Hail","1"]] myFields = ["Snow","Rain","Hail"] h = Hash.new{|h, k| h[k] = {}} myArray.each{|i, j, k| h[i][j] = k } p [["State"] + myFields] + h.map{|k, v| [k] + v.values_at(*myFields)} output...
javascript,string,concatenation
Type Casting. It converts the type to string If variable current.condition_field is not of string type, by adding '' at the end of it converts it to string. var field = current.condition_field + ''; So, field is always string. Thanks to @KJPrice: This is especially useful when you want to...
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If you want a sequence of int, then use a vector<int>. Using the key_char string, the values of the chars in it will serve as the initial value of the ints. std::vector<int> key_num(key_char.begin(), key_char.end()); Then, iterate over each character of key_num and convert it to the equivalent int value for...
Your question is unclear, but I'll take a shot. To go from: val x = Array("a","x,y","b") to "a:x,y:b" You can use mkString: x.mkString(":") ...
string,excel,if-statement,comparison
We need an Array formula. In G2 enter: =NOT(ISERROR(MATCH(1,--EXACT(F$2:F$7,E2),0))) and copy down. Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. Note: The curly brackets that appear in the Formula Bar should not be typed....
javascript,jquery,html,arrays,contains
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Your first regular expression has a black slash followed by the letter b because of that @. The second one has the character that represents backspace. Just put an @ in front string bound = @"\b"; ...
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I'm sad that this question hasn't been answered, and upon that, I can't upvote it from it's -8 cause I don't have enough reputation. It seems downvoting is getting too unwarranted here. OP is just looking for an answer, which can be answered here and found online, he has tried...
python,regex,string,loops,twitter
Store slangNames and riskNames as sets, split the strings and check if any of the words appear in both sets slangNames = set(["Vikes", "Demmies", "D", "MS", "Contin"]) riskNames = set(["enough", "pop", "final", "stress", "trade"]) d = {1: "Vikes is not enough for me", 2:"Demmies is okay", 3:"pop a D"} for...
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c#,string,immutability,method-chaining
Is it true that when you chain string functions, every function instantiates a new string? In general, yes. Every function that returns a modified string does so by creating a new string object that contains the full new string which is stored separately from the original string. There are...
ruby-on-rails,arrays,ruby,multidimensional-array
dup does not create a deep copy, it copies only the outermost object. From that docs: Produces a shallow copy of obj—the instance variables of obj are copied, but not the objects they reference. dup copies the tainted state of obj. If you are not sure how deep your object...
php,arrays,codeigniter,foreach
You can use active record as below. $arrResult = $this->db ->where('id','foo') ->where_in('result',array(1,2)) // alternative to above condition //->where('(result = 1 OR result = 2)') ->get('mytable') ->result_array(); foreach($arrResult as $result){ // run code based on $result; } ...
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You cannot store key-value pair in array. Use object to store key-value pair. See comments inline in the code. var obj = {}; // Initialize the object angular.forEach(data, function(value, key) { if (value.start_date > firstdayOfWeek && value.start_date < lastdayOfWeek) { if (obj[value.firstname]) { // If already exists obj[value.firstname] += value.distance;...
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