I have an Array like this.
scala> var x=Array("a","x,y","b")
x: Array[String] = Array(a, x,y, b)
How do I change the separator comma in array to a :. And finally convert it to string like this.
String = "a:x,y:b"
My aim is to change the comma(separators only) to other separator(say,:), so that i can ignore the comma inside second element i.e, x,y. and later split the string using : as a delimiter
Your question is unclear, but I'll take a shot.
To go from:
val x = Array("a","x,y","b")
to
"a:x,y:b"
You can use mkString:
x.mkString(":")
The valid range of indices of an array with N elements is [0, N-1]. Thus instead of for example this loop for (int i=1; i <= n; i++) ^^^^ ^^^^^^ you have to write for ( int i = 0; i < n; i++ ) As you used operator new...
I executed ur code. Just add numberView.setTextColor(Color.BLACK); and it will work! :)...
Updated: This will check for the existence of a sentence followed by special characters. It returns false if there are no special characters, and your original sentence is in capture group 1. Updated Regex101 Example r"(.*[\w])([^\w]+)" Alternatively (without a second capture group): Regex101 Example - no second capture group r"(.*[\w])(?:[^\w]+)"...
If you want a sequence of int, then use a vector<int>. Using the key_char string, the values of the chars in it will serve as the initial value of the ints. std::vector<int> key_num(key_char.begin(), key_char.end()); Then, iterate over each character of key_num and convert it to the equivalent int value for...
You can use .map, like so var data = [ 'h', 'e', 'l', 'l', 'o', ' ' ]; var indices = [ 4, 0, 5, 0, 1, 2, 2 ]; var res = indices.map(function (el) { return data[el]; }); console.log(res); The map() method creates a new array with the results...
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Change you show function to this function show() { var content="<b>Your Plans For the Day:</b><br>"; for(var i = 0; i < Name.length; i++) { content += "Name " + Name[i]+"<br>"; } for(var i = 0; i < Date.length; i++) { content += "Date" + Date[i]+"<br>"; } for(var i = 0;...
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c,arrays,segmentation-fault,initialization,int
In your code, int i is an automatic local variable. If not initialized explicitly, the value held by that variable in indeterministic. So, without explicit initialization, using (reading the value of ) i in any form, like array[i] invokes undefined behaviour, the side-effect being a segmentation fault. Isn't it automatically...
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When a type isn't specified, Swift will create a String instance out of a string literal when creating a variable or constant, no matter the length. Since Strings are so prevalent in Swift and Cocoa/Foundation methods, you should just use that unless you have a specific need for a Character—otherwise...
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We need an Array formula. In G2 enter: =NOT(ISERROR(MATCH(1,--EXACT(F$2:F$7,E2),0))) and copy down. Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. Note: The curly brackets that appear in the Formula Bar should not be typed....
ruby-on-rails,arrays,ruby,multidimensional-array
dup does not create a deep copy, it copies only the outermost object. From that docs: Produces a shallow copy of obj—the instance variables of obj are copied, but not the objects they reference. dup copies the tainted state of obj. If you are not sure how deep your object...
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Just take a variable for the occurrence of even or odd numbers. var myArray = function (nums) { var average = 0; var totalSum = 0; var hasEven = false; // flag if at least one value is even => true, otherwise false nums.forEach(function (value) { totalSum = totalSum +...
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You cannot store key-value pair in array. Use object to store key-value pair. See comments inline in the code. var obj = {}; // Initialize the object angular.forEach(data, function(value, key) { if (value.start_date > firstdayOfWeek && value.start_date < lastdayOfWeek) { if (obj[value.firstname]) { // If already exists obj[value.firstname] += value.distance;...
Your question is unclear, but I'll take a shot. To go from: val x = Array("a","x,y","b") to "a:x,y:b" You can use mkString: x.mkString(":") ...
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Section 21.4.1.5 of the 2011 standard states: The char-like objects in a basic_string object shall be stored contiguously. That is, for any basic_string object s, the identity &*(s.begin() + n) == &*s.begin() + n shall hold for all values of n such that 0 <= n < s.size(). The two...
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