while opening the page getting error there is no row at position 0

Tag: c#,asp.net,oracle10g

I am trying to open feedback form but showing below error
"There is no row at position 0." I have already checked database, there is a row for this query "select zzfname from sap_empmst where pernr = "

Here is my code...

public partial class feedback : System.Web.UI.Page
{
DataAccess Getdata=new DataAccess();
OracleConnection con = new OracleConnection("Data Source=cluster;User ID=ocgpis;Password=pisocg;unicode=true");
OracleConnection con1 = new OracleConnection("Data Source=oragc;User ID=ipcltos;Password=ipcltos;unicode=true");
//OracleConnection con = new OracleConnection("Data Source=10.127.240.231/ocgpis;User ID=ocgpis;Password=pisocg;unicode=true");
//OracleConnection con1 = new OracleConnection("Data Source=10.127.240.216/ipcldb;User ID=ipcltos;Password=ipcltos;unicode=true");
OracleConnection con2 = new OracleConnection("Data Source=cluster;User ID=RGSS;Password=RGSS;unicode=true");
string strMessage = ""; int mins_now = 0;
protected void Page_Load(object sender, EventArgs e)
{
    Label1_pl.Text = Session["UserID"].ToString();
    string sqlstr = "select zzfname from sap_empmst where pernr = '" +  Label1_pl.Text + "'";
    DataSet ds = new DataSet();
    OracleDataAdapter adp = new OracleDataAdapter(sqlstr, con1);
    adp.Fill(ds);
    string zzfname = ds.Tables[0].Rows[0].ItemArray[0].ToString();
    Label2_name.Text = zzfname;
}

Please help, thanks in advance

Best How To :

Try this

Error Says that Your are accessing a row which is Not present so,

Always Check For whether Row exists in DataSet/DataTable using RowCount

protected void Page_Load(object sender, EventArgs e)
{

if(!Page.IsPostBack)
{
    Label1_pl.Text = Session["UserID"].ToString();
    string sqlstr = "select zzfname from sap_empmst where pernr = '" +  
    Label1_pl.Text + "'";
    DataSet ds = new DataSet();
    OracleDataAdapter adp = new OracleDataAdapter(sqlstr, con1);
    adp.Fill(ds);

    if(ds!=null)
    if(ds.Tables[0].Rows.Count>0)
{
    string zzfname = ds.Tables[0].Rows[0]["zzfname"].ToString();
    Label2_name.Text = zzfname;
}


}

}

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